ID Name dep_id
1 A 1
2 B 2
3 A 1
4 A 2
5 B 2
6 A 2
I think you want to have such a SQL
with tab( ID, Name, dep_id) as
(
select 1,'A',1 union all
select 2,'B',2 union all
select 3,'A',1 union all
select 4,'A',2 union all
select 5,'B',2 union all
select 6,'A',2
)
select name,
count(dep_id) as dept_count
from tab t
group by name
having count(name)>1;
NAME DEPT_COUNT
---- ----------
A 4
B 2
Due to you last edit( which you wanted to add to this answer ), consider grouping also by dept_id :
with tab( ID, Name, dep_id) as
(
select 1,'A',1 union all
select 2,'B',2 union all
select 3,'A',1 union all
select 4,'A',2 union all
select 5,'B',2 union all
select 6,'A',2
)
select name, dept_id,
count(dept_id) as dept_count
from tab t
group by name, dept_id
having count(name)>1;
NAME DEPT_ID DEPT_COUNT
---- ------ ----------
A 2 2
A 1 2
B 2 2
Related
I am trying to write a Query to show Id, Name and No. of department in given Table which are referring more than one department.
ID Name Department
-- ---- ----------
1 Sam HR
1 Sam FINANCE
2 Ron PAYROLL
3 Kia HR
3 Kia IT
Result :
ID Name Department
-- ---- ----------
1 Sam 2
3 Kia 2
I tried using group by id and using count(*), but query is giving error.
How can I do this?
Without seeing your query, a blind guess is that you wrongly wrote the GROUP BY clause (if you used it) and forgot to include the HAVING clause.
Anyway, something like this might be what you're looking for:
SQL> with test (id, name, department) as
2 (select 1, 'sam', 'hr' from dual union
3 select 1, 'sam', 'finance' from dual union
4 select 2, 'ron', 'payroll' from dual union
5 select 3, 'kia', 'hr' from dual union
6 select 3, 'kia', 'it' from dual
7 )
8 select id, name, count(*)
9 from test
10 group by id, name
11 having count(*) > 1
12 order by id;
ID NAM COUNT(*)
---------- --- ----------
1 sam 2
3 kia 2
SQL>
You were right about using count(). You need to group by other columns though and only count unique departments then filter on the number in having clause.
select id, name, count(distinct department) as no_of_department
from table
group by id, name
having count(distinct department) > 1
This can also be done using analytic functions like below:
select *
from (
select id, name, count(distinct department) over (partition by id, name) as no_of_department
from table
) t
where no_of_department > 1
You can use window function with subquery :
select distinct id, name, Noofdepartment
from (select t.*, count(*) over (partition by id,name) Noofdepartment
from table t
) t
where Noofdepartment > 1;
However, you can also use group by clause:
select id, name, count(*) as Noofdepartment
from table t
group by id, name
having count(*) > 1;
Here is my table:
ID Name Department
1 Michael Marketing
2 Alex Marketing
3 Tom Marketing
4 John Sales
5 Brad Marketing
6 Leo Marketing
7 Kevin Production
I am trying to find ID ranges where Department = 'Marketing':
Range From To
Range1 1 3
Range2 5 6
Any help would be appreciated.
This is easy to do with a technique called Tabibitosan.
What this technique does is compare the positions of each group's rows to the overall set of rows, in order to work out if rows in the same group are next to each other or not.
E.g., with your example data, this looks like:
WITH your_table AS (SELECT 1 ID, 'Michael' NAME, 'Marketing' department FROM dual UNION ALL
SELECT 2 ID, 'Alex' NAME, 'Marketing' department FROM dual UNION ALL
SELECT 3 ID, 'Tom' NAME, 'Marketing' department FROM dual UNION ALL
SELECT 4 ID, 'John' NAME, 'Sales' department FROM dual UNION ALL
SELECT 5 ID, 'Brad' NAME, 'Marketing' department FROM dual UNION ALL
SELECT 6 ID, 'Leo' NAME, 'Marketing' department FROM dual UNION ALL
SELECT 7 ID, 'Kevin' NAME, 'Production' department FROM dual)
-- end of mimicking your table with data in it. See the SQL below:
SELECT ID,
NAME,
department,
row_number() OVER (ORDER BY ID) overall_rn,
row_number() OVER (PARTITION BY department ORDER BY ID) department_rn,
row_number() OVER (ORDER BY ID) - row_number() OVER (PARTITION BY department ORDER BY ID) grp
FROM your_table;
ID NAME DEPARTMENT OVERALL_RN DEPARTMENT_RN GRP
---------- ------- ---------- ---------- ------------- ----------
1 Michael Marketing 1 1 0
2 Alex Marketing 2 2 0
3 Tom Marketing 3 3 0
4 John Sales 4 1 3
5 Brad Marketing 5 4 1
6 Leo Marketing 6 5 1
7 Kevin Production 7 1 6
Here, I've given all the rows across the entire set of data a row number in ascending id order (the overall_rn column), and I've given the rows in each department a row number (the department_rn column), again in ascending id order.
Now that I've done that, we can subtract one from the other (the grp column).
Notice how the number in the grp column remains the same for deparment rows that are next to each other, but it changes each time there's a gap.
E.g. for the Marketing department, rows 1-3 are next to each other and have grp = 0, but the 4th Marketing row is actually on the 5th row of the overall results set, so it now has a different grp number. Since the 5th marketing row is on the 6th row of the overall set, it has the same grp number as the 4th marketing row, so we know they're next to each other.
Once we have that grp information, it's a simple matter of doing an aggregate query grouping on both the department and our new grp column, using min and max to find the start and end ids:
WITH your_table AS (SELECT 1 ID, 'Michael' NAME, 'Marketing' department FROM dual UNION ALL
SELECT 2 ID, 'Alex' NAME, 'Marketing' department FROM dual UNION ALL
SELECT 3 ID, 'Tom' NAME, 'Marketing' department FROM dual UNION ALL
SELECT 4 ID, 'John' NAME, 'Sales' department FROM dual UNION ALL
SELECT 5 ID, 'Brad' NAME, 'Marketing' department FROM dual UNION ALL
SELECT 6 ID, 'Leo' NAME, 'Marketing' department FROM dual UNION ALL
SELECT 7 ID, 'Kevin' NAME, 'Production' department FROM dual)
-- end of mimicking your table with data in it. See the SQL below:
SELECT department,
MIN(ID) start_id,
MAX(ID) end_id
FROM (SELECT ID,
NAME,
department,
row_number() OVER (ORDER BY ID) - row_number() OVER (PARTITION BY department ORDER BY ID) grp
FROM your_table)
GROUP BY department, grp;
DEPARTMENT START_ID END_ID
---------- ---------- ----------
Marketing 1 3
Marketing 5 6
Sales 4 4
Production 7 7
N.B., I've assumed that gaps in the id columns aren't important (i.e. if there was no row for id = 6 (so Leo and Kevin's ids were 7 and 8 respectively), then Leo and Brad would still appear in the same group, with a start id = 5 and end id = 7.
If gaps in the id columns count as indicating a new group, then you could just use the id to label the overall set of rows (i.e. no need to caluclate the overall_rn; just use the id column instead).
That means your query would become:
WITH your_table AS (SELECT 1 ID, 'Michael' NAME, 'Marketing' department FROM dual UNION ALL
SELECT 2 ID, 'Alex' NAME, 'Marketing' department FROM dual UNION ALL
SELECT 3 ID, 'Tom' NAME, 'Marketing' department FROM dual UNION ALL
SELECT 4 ID, 'John' NAME, 'Sales' department FROM dual UNION ALL
SELECT 5 ID, 'Brad' NAME, 'Marketing' department FROM dual UNION ALL
SELECT 7 ID, 'Leo' NAME, 'Marketing' department FROM dual UNION ALL
SELECT 8 ID, 'Kevin' NAME, 'Production' department FROM dual)
-- end of mimicking your table with data in it. See the SQL below:
SELECT department,
MIN(ID) start_id,
MAX(ID) end_id
FROM (SELECT ID,
NAME,
department,
ID - row_number() OVER (PARTITION BY department ORDER BY ID) grp
FROM your_table)
GROUP BY department, grp;
DEPARTMENT START_ID END_ID
---------- ---------- ----------
Marketing 1 3
Sales 4 4
Marketing 5 5
Marketing 7 7
Production 8 8
I don't have the environment currently but you can try something like this
select * from tab1 where id in
(select min(id) from tab1 where Department = 'Marketing'
union
select max(id) from tab1 where Department = 'Marketing')
Hi i am looking for a way to write a SQL statement which will come out with the following results :-
Lets say we have Dept & Emp ID i would like to generate like records from Dept 3 for the first two rows then followed by Dept 2 with one row then continue Dept 3 and so on :
DEPT EMPID
----- ------
3 1
3 2
2 3
3 7
3 8
2 9
Thank You.
You could use something like this
SELECT
DEPT,
EMPID
FROM (
SELECT
*,
ceil((row_number() OVER (PARTITION BY dept ORDER BY EMPID ))/ 2::numeric(5,2)) AS multiple_row_dept,
row_number() OVER (PARTITION BY dept ORDER BY EMPID ) AS single_row_dept
FROM
test_data2
) sub_query
ORDER BY
CASE
WHEN DEPT = 2 THEN single_row_dept
ELSE multiple_row_dept
END,
DEPT DESC,
EMPID
single_row_dept specifics which dept should appear only once, in this case its DEPT 2 followed by multiple other departments
First order a table by empid in a subquery,
then calculate a remainder of rowids divided by 3,
then depending on a result of calculation, return 2 or 3, using case expression,
like this
SELECT
CASE REMAINDER( rownum, 3 )
WHEN 0 THEN 2
ELSE 3
END As DeptId,
empid
FROM (
SELECT empid
FROM table1
ORDER BY empid
)
demo: http://sqlfiddle.com/#!4/bd1bb/3
The following code has some limitations:
1) There are only 2 DepId's in the source table
2) Ratio between records having different DepId is exactly 2:1
3) Ordering in one place of the query should be changed depending whether DeptId having more records is naturally greater then the other or not
with t as (
select 3 dept_id, 1 emp_id from dual
union all
select 3, 2 from dual
union all
select 3, 7 from dual
union all
select 3, 8 from dual
union all
select 2, 3 from dual
union all
select 2, 9 from dual)
select dept_id, emp_id
from (select dept_id,
emp_id,
dense_rank() over(partition by dept_id order by in_num + mod(in_num, out_num)) ord
from (select dept_id,
emp_id,
row_number() over(partition by dept_id order by emp_id) in_num,
/*in the following ORDER BY change to DESC or ASC depending on which dept_id has more records*/
dense_rank() over(order by dept_id) out_num
from t))
order by ord, dept_id desc;
DEPT_ID EMP_ID
---------- ----------
3 1
3 2
2 3
3 8
3 7
2 9
For example, I have table:
ID | Value
1 hi
1 yo
2 foo
2 bar
2 hehe
3 ha
6 gaga
I want my query to get ID, Value; meanwhile the returned set should be in the order of frequency count of each ID.
I tried the query below but don't know how to get the ID and Value column at the same time:
SELECT COUNT(*) FROM TABLE group by ID order by COUNT(*) desc;
The count number doesn't matter to me, I just need the data to be in such order.
Desire Result:
ID | Value
2 foo
2 bar
2 hehe
1 hi
1 yo
3 ha
6 gaga
As you can see because ID:2 appears most times(3 times), it's first on the list,
then ID:1(2 times) etc.
you can try this -
select id, value, count(*) over (partition by id) freq_count
from
(
select 2 as ID, 'foo' as value
from dual
union all
select 2, 'bar'
from dual
union all
select 2, 'hehe'
from dual
union all
select 1 , 'hi'
from dual
union all
select 1 , 'yo'
from dual
union all
select 3 , 'ha'
from dual
union all
select 6 , 'gaga'
from dual
)
order by 3 desc;
select t.id, t.value
from TABLE t
inner join
(
SELECT id, count(*) as cnt
FROM TABLE
group by ID
)
x on x.id = t.id
order by x.cnt desc
How about something like
SELECT t.ID,
t.Value,
c.Cnt
FROM TABLE t INNER JOIN
(
SELECT ID,
COUNT(*) Cnt
FROM TABLE
GROUP BY ID
) c ON t.ID = c.ID
ORDER BY c.Cnt DESC
SQL Fiddle DEMO
I see the question is already answered, but since the most obvious and most simple solution is missing, I'm posting it anyway. It doesn't use self joins nor subqueries:
SQL> create table t (id,value)
2 as
3 select 1, 'hi' from dual union all
4 select 1, 'yo' from dual union all
5 select 2, 'foo' from dual union all
6 select 2, 'bar' from dual union all
7 select 2, 'hehe' from dual union all
8 select 3, 'ha' from dual union all
9 select 6, 'gaga' from dual
10 /
Table created.
SQL> select id
2 , value
3 from t
4 order by count(*) over (partition by id) desc
5 /
ID VALU
---------- ----
2 bar
2 hehe
2 foo
1 yo
1 hi
6 gaga
3 ha
7 rows selected.
Say I have a table like the following (I'm on Oracle 10g btw)
NAME VALUE
------ ------
BOB 1
BOB 2
BOB 4
SUZY 1
SUZY 2
SUZY 3
How can I select all rows where value is closest to, but not greater than, a given number. For example if I want to find all the rows where value is closest to 3 I would get:
NAME VALUE
------ ------
BOB 2
SUZY 3
This seems like it should be simple... but I'm having no luck.
Thanks!
SELECT name, max(value)
FROM tbl
WHERE value <= 3
GROUP BY name
This works (SQLFiddle demo):
SELECT name, max(value)
FROM mytable
WHERE value <= 3
GROUP BY name
Based on hagensofts answer:
SELECT name, max(value)
FROM tbl
WHERE value <= 3 AND ROWNUM <=2
GROUP BY name
With ROWNUM you can limit the output rows, so if you want 2 row, then you can limit the rownum.
WITH v AS (
SELECT 'BOB' NAME, 1 value FROM dual
UNION ALL
SELECT 'BOB', 2 FROM dual
UNION ALL
SELECT 'BOB', 4 FROM dual
UNION ALL
SELECT 'SUZY', 1 FROM dual
UNION ALL
SELECT 'SUZY', 2 FROM dual
UNION ALL
SELECT 'SUZY', 3 FROM dual
)
SELECT *
FROM v
WHERE (name, value) IN (SELECT name, MAX(value)
FROM v
WHERE value <= :num
GROUP BY name)
;