I want to append virtual column in SELECT result with the name of total_event which will be total of same type of wait_event_type, As shown in the screenshot I want to sum 'Lock' which will be 18+2 = 20 and add that against all Lock type column.
I have a event_stats table with three columns wait_event_type, wait_event, event_count which holds all the data.
You can use a window function to do this:
SELECT
wait_event_type,
wait_event,
event_count,
SUM(event_count) OVER (PARTITION BY wait_event_type) AS total_event_count
FROM my_table
You can also use group by clause and join
select m.wait_event_type,
m.wait_event,
m.event_count,
t.total_event_count from (select wait_event_type,SUM(event_count) as total_event_count
from my_table group by wait_event_type)t join my_table m on
m.wait_event_type=t.wait_event_type
Related
I want a query that returns a record set of the shaded rows from the table above for each unique case_id by the latest data_level_assinged value. I tried something like this:
SELECT case_id, level, date_level_assigned
FROM table
SORT BY case_id, date_level_assigned DESC;
From reading it looks like I need to use an aggregate function like MAX(data_level_assinged) but am not sure how to do this.
You're almost there.
Using MAX is a good approach.
SELECT b.case_id, a.level, b.date_level_assigned FROM tablename a
JOIN
( SELECT MAX(date_level_assigned) as date_level_assigned, case_id
FROM tablename
GROUP BY case_id
) as b
ON a.case_id = b.case_id AND a.date_level_assigned = b.date_level_assigned
You can do it in this way
I am trying to count distinct values on Z_l based on value by using with clause. Sample data exercise included below.
please look at the picture, the distinct values of Z_l based on X='ny'
with distincz_l as (select ny.X, ny.z_l o.cnt From HOPL ny join (select X, count(*) as cnt from HOPL group by X) o on (ny.X = o.Z_l)) select * from HOPL;
You don't even need a WITH clause, since you just need one single sentence:
SELECT z_l, count(1)
FROM hopl
WHERE x='ny'
GROUP BY z_l
;
I have the table DirectCosts with the following columns:
DetailsID (unique)
InvoiceNumber
ProjectID
PayableID
I need to find the duplicates combinations of payableid and invoicenumber.
How can I adjust the following query so that it accommodates the combination AND displays the list of instead of the count?
SELECT sinvoicenumber, count(*)
FROM exportdirectcostdetails where iprocoreprojectid = 1187294
GROUP BY sinvoicenumber
HAVING COUNT(*) > 2
Is there a way it can display all columns?
Original Question : Why do I get error ed2 should have column name defined
You are having a derived table, so you need to have column names for the derived table.
select ed1.sinvoicenumber,
ed1.ipayableid,
ed2.sinvoicenumber
from ExportDirectCostDetails ed1
inner join
(
SELECT sinvoicenumber, count(sinvoicenumber) AS InvoiceNumberCount
FROM exportdirectcostdetails
where iprocoreprojectid = 1187294
GROUP BY sinvoicenumber
HAVING COUNT(*) > 2
) ed2
on ed1.sinvoicenumber = ed2.sinvoicenumber
Updated Question: How to have all column names
You need to have PARTITION BY clause defined and then apply filter as given below:
SELECT t.* FROM
(SELECT *, count(*) OVER(PARTITION BY payableid,invoiceNumber) AS InvoiceCount
FROM exportdirectcostdetails where iprocoreprojectid = 1187294) as t
WHERE InvoiceCount > 1
I have data in an sqlite db that contains the following columns:
date | name | id | code
all as TEXT (I sourced it from a csv file) and I want to build a query that finds all names that have code ABC120 but not ABC306 nor ABC305 on the same date and group the result GROUP BY name.
How do I do this?
If you want to use GROUP BY you must group by name, date first and set the conditions in the HAVING clause, but also you must use DISTINCT so the results do not contain duplicate names:
select distinct name
from tablename
group by name, date
having sum(code = 'ABC120') > 0 and sum(code in ('ABC305', 'ABC306')) = 0;
You can get the same results with EXISTS:
select distinct t.name
from tablename t
where t.code = 'ABC120'
and not exists (select 1 from tablename where name = t.name and date = t.date and code in ('ABC305', 'ABC306'))
You can use having:
select date, name
from t
where code in ('ABC120', 'ABC306', 'ABC305')
group by date, name
having min(code) = 'ABC120' and max(code) = 'ABC120';
Note: because of the three codes you chose, you could just use max(code) = 120. However, that does not generalize to other code values.
I have a table (lets call it "Items") that contains a set of names, groups and statuses. For example
Name | Group | Status
FF A ON
GG A OFF
HH A UNKN
ZZ B ON
YY B OFF
I am trying to aggregate the status of all records in a given group, by taking the most relevant status (in order by relevance: UNKN, OFF, ON).
Edit 1: These statuses are only examples, and their names and orders could change in my application, so that should be configurable in the query.
For example, if I query for the overall status of Group A, the status should be UNKN, and if I query for Group B, the status should be OFF.
Edit 2: It is possible that there are multiples of the same status for a group. For example two records that are UNKN.
The query I have managed is to select all items from a group. For example Group A:
SELECT Items.[Group], Items.[Status]
FROM Items
WHERE (((Items.[Group])="A"));
Produces:
Name | Group | Status
FF A ON
GG A OFF
HH A UNKN
but I can't boil it down to the single most relevant status for every group. I have tried to use CASE WHEN and IF EXISTS but I can't get it to work. Any input?
Edit 3:
As an example of the desired output for the overall group status:
Group | OverallStatus
A UNKN
B OFF
If you can build another table, a simple solution would be:
Add another table with the values in the order you want.
Then, just build a query like this:
SELECT TOP 1 Table1.*, Table2.VALUE
FROM Table1 INNER JOIN Table2 ON Table1.status = Table2.STATUS
WHERE Table1.group="A"
ORDER BY Tabla2.VALUE DESC
If the status changes or are added new ones, or you need a new order, just refresh the new table.
EDIT
Acording to the new info by OP, the query can be write in another way. The previous query take into account showing all the record in table1.
If you only need the group and the "max" status, you can use something like this:
SELECT A.group, Table2.STATUS
FROM (SELECT Table1.group, Max(Table2.VALUE) AS MaxVALUE
FROM Table1 INNER JOIN Table2 ON Tabla1.status = Table2.STATUS
GROUP BY Table1.group) as A INNER JOIN Table2 ON A.MaxVALUE= Table2.VALUE;
Use conditional aggregation and some other logic:
select grp,
switch(sum(iif(status = "UNK", 1 0) > 0, "UNK", -- any unknowns
sum(iif(status = "OFF", 1, 0) > 0, "OFF", -- any offs
"ON"
) as group_status
from items
group by grp;
This counts the number of each status and then uses that to determine the overall group status. Your question is not really explicit about the rules, but I think these capture what you are trying to do. It should be easy enough to modify for other rules.
Using the "length" as gauge, this should fit Access SQL:
Select *
From Items
Where Items.Name = (
Select Top 1 T.Name
From Items As T
Where T.Group = Items.Group
Order By Len(T.Status) Desc)
Assuming that the status column will have only three distinct values as shown in data example, you can try below query:
SELECT *
FROM ITEMS
WHERE (GROUP,LENGTH(STATUS)) IN (
SELECT GROUP,MAX(LENGTH(STATUS))
FROM ITEMS
GROUP BY GROUP)
Thanks,
Amitabh