I have 2 row data which I want to make it to be 2 column,
I tried union syntax but it didn't work.
Here is the data I have:
breed 1 breed2
I tried to convert it with this sql
select a.breed union a.breed
but it didn't work.
Here is what you want from the SQL:
breed1,breed2
SELECT
[breed1],
[breed2]]
FROM
(
SELECT 'breed1' myColumn
union
select 'breed2'
) AS SourceTable
PIVOT
(
AVG(mySecondColumn) FOR
myColumn IN ([breed1], [breed2]])
) AS PivotTable;
You can use a self join. This needs a way to pair rows together (so if you have four rows you get 1 and 2 in one result and 3 and 4 in the other rather than another combination).
I'm going to assume you have sequentially numbered rows in an Id column and an odd numbered row is paired with the one greater even Id:
select odd.Data as 'First', even.Data as 'Second'
from TheData odd
inner join TheData even on odd.Id+1 = even.Id
where odd.Id % 2 = 1;
More generally for more columns use of pivot is more flexible.
How about an aggregation query?
select min(breed) as breed1, max(breed) as breed2
from t;
Related
I am new to snowflake and trying the count the number of values in a row with separators using SQL. I am not sure how to go about it. I've googled solutions for this but have not been able to find one.
table name: Lee_tab
user
names
id01
Jon;karl;lee;
id02
Abi;jackson;
id03
don;
id04
what I want to achieve
user
names
name_count
id01
Jon;karl;lee;
3
id02
Abi;jackson;
2
id03
don;
1
id04
0
Here is three solutions using REGEXP_COUNT, SPLIT, ARRAY_SIZE, STRTOK_TO_ARRAY (I would use the REGEXP_COUNT one):
SELECT
column1,
column2,
regexp_count(column2, ';')+1 as solution_1,
ARRAY_SIZE(split(column2, ';')) as solution_2,
ARRAY_SIZE(strtok_to_array(column2, ';')) as solution_3
FROM VALUES
('id01','Jon;karl;lee'),
('id02','Abi;jackson'),
('id03','don');
which gives
COLUMN1
COLUMN2
SOLUTION_1
SOLUTION_2
SOLUTION_3
id01
Jon;karl;lee
3
3
3
id02
Abi;jackson
2
2
2
id03
don
1
1
1
It depends on which DataBase you're using, because there are some different
things in syntax. I made your example with using SQLite Browser and I have a result like this one:
SELECT SUM(length(names) - length(replace(names, ';', '')) +1)
AS TotalCount
FROM Lee_tab where id = USER ID
As I know, in Postgres there's no length, it's just len there, so, pay an attention.
My query-it's just a formula to how count values, separated by ;
To get your result, you should learn how to join.
Here is a different answer, using the Snowflake SPLIT_TO_TABLE function. This function splits the string on the delimiter, creating a row for each value, which we lateral join back to the CTE table, finally we COUNT and GROUP BY using standard SQL syntax:
with cte as (
select 'id01' as user, 'Jon;karl;lee' as names union all
select 'id02' as user, 'Abi;jackson' as names union all
select 'id03' as user, 'don' as names
)
select user, names, count(value) as count_names
from cte, lateral split_to_table(cte.names, ';')
group by user, names;
Rewriting json_stattham's answer using Snowflake syntax. Basically, we are just counting the number of separators (semicolons) in the string and adding 1. There is no need to use the SUM() function as in json_stattham's answer.
with cte as (
select 'id01' as user, 'Jon;karl;lee' as names union all
select 'id02' as user, 'Abi;jackson' as names union all
select 'id03' as user, 'don' as names
)
SELECT user, names, (length(names) - length(replace(names, ';'))) + 1 AS name_count
FROM cte;
This is the answer for your query
select user,names,(len(names) - len(replace(names, ';',''))+1) names_count from Lee_tab;
for more understanding check this ,i have done all
https://www.db-fiddle.com/f/BQuEjw2pthMDb1z8NTdHv/0
I have a table that has a field where the contents are a concatenated list of selections from a multi-select form. I would like to convert the data in this field into in another table where each row has the text of the selection and a count the number of times this selection was made.
eg.
Original table:
id selections
1 A;B
2 B;D
3 A;B;D
4 C
I would like to get the following out:
selection count
A 2
B 3
C 1
D 2
I could easily do this with split and maps in javascript etc, but not sure how to approach it in SQL. (I use Postgresql) The goal is to use the second table to plot a graph in Google Data Studio.
A much simpler solution:
select regexp_split_to_table(selections, ';'), count(*)
from test_table
group by 1
order by 1;
You can use a lateral join and handy set-returning function regexp_split_to_table() to unnest the strings to rows, then aggregate and count:
select x.selection, count(*) cnt
from mytable t
cross join lateral regexp_split_to_table(t.selections, ';') x(selection)
group by x.selection
I have a table that I would like to unpivot in a SQL statement. It consists of a person and phone 1 through 5. Right now I'm doing a union for each phone but I fear it is causing performance issues.
Columns:
PERSON_GUID,
PHONE_1, PHONE_1_VOICE_FLG,
PHONE_2, PHONE_2_VOICE_FLG,
PHONE_3, PHONE_3_VOICE_FLG,
PHONE_4, PHONE_4_VOICE_FLG,
PHONE_5, PHONE_5_VOICE_FLG
How would I best unpivot the row with performance in mind so that the results are:
PERSON_GUID, PHONE_NO, VOICE_FLG
I prefer UNPIVOT but as for your solution -
Make sure you are using UNION ALL and not UNION.
UNION ALL just spills one query result after the other.
UNION eliminates rows duplications and this is where you pay in performance.
select PERSON_GUID,PHONE_NO,
case right(col,1)
when 1 then PHONE_1_VOICE_FLG
when 2 then PHONE_2_VOICE_FLG
when 3 then PHONE_3_VOICE_FLG
when 4 then PHONE_4_VOICE_FLG
when 5 then PHONE_5_VOICE_FLG
end VOICE_FLG
from t unpivot (PHONE_NO for col in
(PHONE_1,PHONE_2,PHONE_3,PHONE_4,PHONE_5)) u
I have a table that has an integer column from which I am trying to get a few counts from. Basically I need four separate counts from the same column. The first value I need returned is the count of how many records have an integer value stored in this column between two values such as 213 and 9999, including the min and max values. The other three count values I need returned are just the count of records between different values of this column. I've tried doing queries like...
SELECT (SELECT Count(ID) FROM view1 WHERE ((MyIntColumn BETWEEN 213 AND 9999));)
AS Value1, (SELECT Count(ID) FROM FROM view1 WHERE ((MyIntColumn BETWEEN 500 AND 600));) AS Value2 FROM view1;
So there are for example, ten records with this column value between 213 and 9999. The result returned from this query gives me 10, but it gives me the same value of 10, 618 times which is the number of total records in the table. How would it be possible for me to only have it return one record of 10 instead?
Use the Iif() function instead of CASE WHEN
select Condition1: iif( ), condition2: iif( ), etc
P.S. : What I used to do when working with Access was have the iif() resolve to 1 or 0 and then do a SUM() to get the counts. Roundabout but it worked better with aggregation since it avoided nulls.
SELECT
COUNT(CASE
WHEN MyIntColumn >= 213 AND MyIntColumn <= 9999
THEN MyIntColumn
ELSE NULL
END) AS FirstValue
, ??? AS SecondValue
, ??? AS ThirdValue
, ??? AS FourthValue
FROM Table
This doesn't need nesting or CTE or anything. Just define via CASE your condition within COUNTs argument.
I dont really understand what You want in the second, third an fourth column. Sounds to me, its very similar to the first one.
Reformatted, your query looks like:
SELECT (
SELECT Count(ID)
FROM view1
WHERE MyIntColumn BETWEEN 213 AND 9999
) AS Value1
FROM view1;
So you are selecting a subquery expression that is not related to the outer query. For each row in view1, you calculate the number of rows in view1.
Instead, try to do the calculation once. You just have to remove your outer query:
SELECT Count(ID)
FROM view1
WHERE MyIntColumn BETWEEN 213 AND 9999;
OLEDB Connection in MS Access does not support key words CASE and WHEN .
You can only use iif() function to count two, three.. values in same columns
SELECT Attendance.StudentName, Count(IIf([Attendance]![Yes_No]='Yes',1,Null)) AS Yes, Count(IIf([Attendance]![Yes_No]='No',1,Null)) AS [No], Count(IIf([Attendance]![Yes_No]='Not',1,Null)) AS [Not], Count(IIf([Attendance]![Yes_No],1,Null)) AS Total
FROM Attendance
GROUP BY Attendance.StudentName;
This question already exists:
Closed 10 years ago.
Possible Duplicate:
SQL Select DISTINCT using CAST
Let me try this one more time... I'm not a sql guy so please bear with me as I try to explain this... I have a table called t_recordkeepingleg with three columns of data. Column1 is named LEGTRIPNUMBER that happens to be a string that starts with the letter Q followed by 4 numbers. I need to strip off the Q and convert the remaining 4 characters (numbers) to an integer. Everyone with me so far? Column2 of this table is named LEGDATE. Column3 is named LEGGROUP.
Here's the input scenario
LEGTRIPNUMBER LEGDATE LEGGROUP
Q1001 08/12/12 0001
Q1001 09/15/12 0002
Q1002 09/01/12 0001
Q1002 09/08/12 0003
Q1002 09/09/12 0002
As you can see the input table has rows where LEGTRIPNUMBER occurs more than once. I only want the first occurrence.
This is my current select statement - it works but returns all rows.
SELECT *,
CAST(
substring("t_RecordkeepingLeg"."LEGTRIPNUMBER",2,4) as INT
) as Num_Trip_Num
FROM "1669"."dbo"."t_RecordkeepingLeg" "t_RecordkeepingLeg"
Where left "t_RecordkeepingLeg"."LEGTRIPNUMBER",1) = 'Q'
I want to modify this so that it only selects ONE occurance of the Qnnnn. When the row gets selected I want to have LEGDATE and LEGGROUP available to me. How do I do this?
Thank you,
Can it be as simple as below? I've just added condiotion on leggroup being 0001
SELECT *,
CAST(substring("t_RecordkeepingLeg"."LEGTRIPNUMBER",2,4) as INT) as Num_Trip_Num
FROM "1669"."dbo"."t_RecordkeepingLeg" "t_RecordkeepingLeg"
Where left ("t_RecordkeepingLeg"."LEGTRIPNUMBER",1) = 'Q'
and "t_RecordkeepingLeg"."LEGGROUP"='0001'
If you have a unique primay key in your table you can do something like the below;
SELECT CAST(
substring("t_RecordkeepingLeg"."LEGTRIPNUMBER",2,4) as INT
) as Num_Trip_Num
FROM "1669"."dbo"."t_RecordkeepingLeg" "t_RecordkeepingLeg"
Where "t_RecordkeepingLeg"."ID" In(
Select Min("t_RecordkeepingLeg"."ID")
From "1669"."dbo"."t_RecordkeepingLeg" "t_RecordkeepingLeg"
Where left ("t_RecordkeepingLeg"."LEGTRIPNUMBER",1) = 'Q'
Group By "t_RecordkeepingLeg"."LEGTRIPNUMBER"
)
Which values of LEGDATE & LEGGROUP do you want for the distinct LEGTRIPNUMBER? there are multiple non-distinct possibilities and the concept of "first occurrence" is only valid with an explicit order.
To get the values where LEGDATE is the earliest for example;
select Num_Trip_Num, LEGDATE, LEGGROUP from (
select
cast(substring(t_RecordkeepingLeg.LEGTRIPNUMBER, 2, 4) as INT) as Num_Trip_Num,
row_number() over (partition by substring(t_RecordkeepingLeg.LEGTRIPNUMBER, 2, 4) order by t_RecordkeepingLeg.LEGDATE asc) as row,
t_RecordkeepingLeg.LEGDATE,
t_RecordkeepingLeg.LEGGROUP
from t_RecordkeepingLeg
where left (t_RecordkeepingLeg.LEGTRIPNUMBER, 1) = 'Q'
) T
where row = 1