Find count group by id in SQL Server - sql

I need some help to solve this query. I have a table which contains the ages of the passengers who are going to stay in a room which is mentioned below:
Age RoomId
----- ---
1 1
12 1
8 1
19 1
3 2
12 2
18 2
21 3
Also, I have properties table which contains the maximum age of the child and maximum age of the infant. Based on the age of the passenger, I need to segregate them to adult, child, and infant to each of the properties.
Properties table structure
Property Id Maximum_child_age Maximum_infant_age
-------------------------------------------------
1 11 2
Desired output
RoomId Adult Child Infant PropertyId
--------------------------------
1 2 1 1 1
2 2 1 0 1
3 1 0 0 1

Use conditional aggregation :
SELECT
SUM(CASE WHEN pas.age > ppt.Maximum_child_age THEN 1 ELSE 0 END) AS Adult,
SUM(CASE WHEN pas.age BETWEEN Maximum_infant_age AND ppt.Maximum_child_age THEN 1 ELSE 0 END) AS Child,
SUM(CASE WHEN pas.age < ppt.Maximum_infant_age THEN 1 ELSE 0 END) AS Infant,
ppt.id
FROM
passengers pas
CROSS JOIN properties ppt
GROUP BY ppt.id

Cross join the properties and then do conditional aggregation.
SELECT count(CASE
WHEN pa.ages > pr.maximum_child_age THEN
1
END) adult,
count(CASE
WHEN pa.ages > pr.maximum_infant_age
AND pa.ages <= pr.maximum_child_age THEN
1
END) child,
count(CASE
WHEN pa.ages <= pr.maximum_infant_age THEN
1
END) infant,
pr.propertyid
FROM passengers pa
CROSS JOIN properties pr
GROUP BY pr.propertyid;

Related

SQL: SUM OR COUNT with CASE WHEN condition in multiple criteria

Course name
Section number
Course type
MATH 101
1
In person
MATH 101
2
In person
MATH 101
3
Online
MATH 101
4
In person
SOC 101
1
In person
SOC 101
2
In person
SOC 101
3
In person
ENGL 201
1
In person
ENGL 201
2
Online
ENGL 201
3
Online
ENGL 201
4
In person
PHY 101
1
Online
PHY 101
2
Online
From this table, I'd like to count Courses with only an 'In person' course, an 'Online' course, and both course types.
The query I tried is below.
SELECT
SUM(CASE WHEN coursetype = 'Inperson' AND coursetype = 'Online' THEN 1 ELSE 0 END) AS bothtype,
SUM(CASE WHEN coursetype = 'Online' THEN 1 ELSE 0 END) AS Onlineonly,
SUM(CASE WHEN coursetype = 'Inperson' THEN 1 ELSE 0 END) AS Onlineonly
From Course
The result what I expected is
bothtpye
Onlineonly
Inpersononly
2
1
1
but I got
bothtpye
Onlineonly
Inpersononly
0
7
6
Please advise me to get through this.
Thank you.
My solution uses double conditional aggregation.
SELECT SUM (CASE WHEN In_Person > 0 AND Online > 0 THEN 1 ELSE 0 END) as bothtype,
SUM (CASE WHEN In_Person > 0 AND Online = 0 THEN 1 ELSE 0 END) as inpersononly,
SUM (CASE WHEN In_Person = 0 AND Online > 0 THEN 1 ELSE 0 END) as onlineonly
FROM (
SELECT Course_name,
SUM(CASE WHEN Course_type='In Person' THEN 1 ELSE 0 END) as In_Person,
SUM(CASE WHEN Course_type='Online' THEN 1 ELSE 0 END) as Online
FROM Course
GROUP BY Course_name
) tot
DEMO Fiddle
SUGGESTION ( using PL/SQL ! ) :
CREATE PROCEDURE countCourses(OUT bothtype INT,OUT Inpersononly INT,OUT Onlineonly INT)
begin
SELECT COUNT(*) INTO bothtype FROM Course;
select COUNT(*) INTO Inpersononly FROM Course
WHERE courseType = "In person";
select COUNT(*) INTO Onlineonly FROM Course
WHERE courseType = "Online";
end;
call countCourses(#bothtype,#Inpersononly,#Onlineonly);
SELECT #bothtype,#Inpersononly,#Onlineonly;
EXPLICATION :
Creating procedure to store the count of each type of course in OUT variable
Call the procedure with convenient parameters
Select out given parameters

TRIGGER to calculate the total leaves of each left type group by employee

I have 2 tables like this
EmployeeID
LeaveTypeID
1
1
2
2
1
2
1
2
Now I want a TRIGGER that calculate automatically total of type 1 and type 2 in below table
EmployeeID
Type1
Type2
1
1
2
2
0
1
No need for triggers. Just create a view that has the aggregation in it
CREATE VIEW vTotal
AS
SELECT
t.EmployeeID,
Type1 = COUNT(CASE WHEN t.LeaveTypeID = 1 THEN 1 END),
Type2 = COUNT(CASE WHEN t.LeaveTypeID = 2 THEN 1 END)
FROM dbo.YourTable t
GROUP BY
t.EmployeedID;

SQL query to find those customer who have buy all three items ('ring','diamond','brooch')

id item_name cust_id
1 Rolex 5
2 Diamond 33
3 Hublop 1
4 Ring 9
5 Ruby 13
6 Rolex 33
7 Hublop 29
8 Ring 17
9 Belt 21
10 Diamond 9
12 Belt 33
13 Hublop 9
14 Brooch 9
From these table I have to write a query to find those cust_id who have buy all three 'diamond,brooch,ring'
without using intersection ( IN clause will also not work)
You can use sum with a case statement for each item to get how many of that item the client has bought, then filter only customers that have bought at least one of each type of product:
select cust_id from
(select cust_id,
sum(case when item_name = 'Diamond' then 1 else 0 end) as cntDiamond,
sum(case when item_name = 'Brooch' then 1 else 0 end) as cntBrooch,
sum(case when item_name = 'Ring' then 1 else 0 end) as cntRing
from table_name
group by cust_id) as t
where cntDiamond > 0 and cntBrooch > 0 and cntRing > 0
Fiddle

Group by one column and return several columns on multiple conditions - T-SQL

I have two tables which I can generate with SELECT statements (joining multiple tables) as follows:
Table 1:
ID
Site
type
time
1
Dallas
2
01-01-2021
2
Denver
1
02-01-2021
3
Chicago
1
03-01-2021
4
Chicago
2
29-11-2020
5
Denver
1
28-02-2020
6
Toronto
2
11-05-2019
Table 2:
ID
Site
collected
deposited
1
Denver
NULL
29-01-2021
2
Denver
01-04-2021
29-01-2021
3
Chicago
NULL
19-01-2020
4
Dallas
NULL
29-01-2019
5
Winnipeg
13-02-2021
17-01-2021
6
Toronto
14-02-2020
29-01-2020
I would like the result to be grouped by Site, having on each column the COUNT of type=1 , type=2, deposited and collected, all of the 4 columns between a selected time interval. Example: (interval between 01-06-2020 and 01-06-2021:
Site
type1
type2
deposited
collected
Dallas
0
1
0
0
Denver
1
0
2
1
Chicago
1
1
0
0
Toronto
0
0
0
0
Winnipeg
0
0
1
1
How about union all and aggregation?
select site,
sum(case when type = 1 then 1 else 0 end) as type_1,
sum(case when type = 2 then 1 else 0 end) as type_2,
sum(deposited) as deposited, sum(collected) as collected
from ((select site, type, 0 as deposited, 0 as collected
from table1
) union all
(select site, null,
(case when deposited is not null then 1 else 0 end),
(case when collected is not null then 1 else 0 end)
from table2
)
) t12
group by site;
Combine your tables 1 and 2 with a join on Site
Use COUNT(CASE WHEN type = 1 then 1 END) as type1 and a similar construct for type 2
Use COUNT(CASE WHEN somedate BETWEEN '2020-06-01' and '2021-06-01' then 1 END) as ... for your dates

SQL Query. limit an update per rows if condition is X and Y for the same ID number

Have the following table tblTrans where
Trans_ID Trans Sequence Trans_PointsEarned Trans_PointsApplied
4452 1 1 1
4452 2 1 1
4452 3 0 1
4462 1 1 1
4462 2 1 1
4462 3 1 1
4462 4 1 1
4462 5 1 1
9101 1 0 1
9101 2 0 1
9101 3 0 1
9101 4 0 1
(useless table doesnt work)
I need to set the following on another field per every customer ID.
So Customer_OverallPoints
4452 = 2 (doesn't count 0's)
4462 = 4 (I want to cap the points to 4 based on the sequence and transID and customerID)
9101 = 0 (dont count 0's).
This needs to be applied to thousands of records based on customerID and TransID where Trans_Sequence is within the same Trans_ID and it only counts the first 4 rows that have the Trans_pointsEarned = 1.
I tried putting a psuedocode together but it just looked ridicilous and I can't even come up with the logic for this.
Thanks
Assuming that TransId is really the customer id, I think the basic logic is just an aggregation:
select t.TransId,
(case when sum(t.Trans_PointsEarned) > 4 then 4
else sum(t.Trans_PointsEarned)
end) as Customer_OverallPoints
from tblTrans t
group by t.TransId;
You can put this into an update statement as:
update customers c
set Customer_OverallPoints = (select (case when sum(t.Trans_PointsEarned) > 4 then 4
else sum(t.Trans_PointsEarned)
end)
from tblTrans t
where t.TransId = c.CustomerId
);