Combine multiple queries into one query - sql

Question

I am trying to group by clientid and m.id. How can I convert these 2 queries into 1 query?
Query 1
select cs.clientid, count(distinct(m.id)) as cp
into #temp
from call_table cs
join mem_table m
on cs.CLIENTID = m.clientid
join activity_table a
on a.memid = m.id
where a.activity = 'abc'
group by cs.clientid, m.id
Query 2
select clientid, sum(cp) from #temp
group by ClientId
Update
More specifically, I am looking to write this query without using a temp table.

Answer 1

You could group only by clientid
And since no fields from activity_table are selected, an EXISTS can be used instead.
select cs.clientid, count(distinct m.id) as cp
from call_table cs
join mem_table m on m.clientid = cs.clientid
where exists
(
select 1
from activity_table a
where a.memid = m.id
and a.activity = 'abc'
)
group by cs.clientid

Answer 2

Why wouldn't you just write this as:
with temp as (
select cs.clientid, count(distinct m.id) as cp
from call_table cs join
mem_table m
on cs.CLIENTID = m.clientid join
activity_table a
on a.memid = m.id
where a.activity = 'abc'
group by cs.clientid, m.id
)
select clientid, sum(cp)
from temp
group by ClientId;
I can't figure out what the logic should really be, but this seems like the simplest way to combine the queries.
I would speculate that you simply want this query:
select cs.clientid, count(distinct m.id) as cp
from call_table cs join
mem_table m
on cs.CLIENTID = m.clientid join
activity_table a
on a.memid = m.id
where a.activity = 'abc'
group by cs.clientid;
That is, remove m.id from the group by. And this can in turn be simplified to:
select m.clientid, count(distinct m.id) as cp
from mem_table m join
activity_table a
on a.memid = m.id
where a.activity = 'abc'
group by cs.clientid;
Assuming that m.id is unique and non-NULL, this can be further simplified to:
select m.clientid, count(*) as cp
from mem_table m join
activity_table a
on a.memid = m.id
where a.activity = 'abc'
group by cs.clientid;