I have tables:
tbl-city
id city
---------
1 A
2 B
3 C
tbl-orders
ord_id product_id city date
----------------------------------
1 1 1 12/3/18
2 1 2 13/3/18
3 2 3 12/4/18
4 1 3 14/4/18
5 3 2 11/2/18
6 1 1 15/1/18
7 2 3 15/4/28
I need to get all latest order Id from table orders
by city wise and product wise using date
Like this:
ord_id product_id city
---------------------------
1 1 1
2 1 2
7 2 3
5 3 2
How can I get this?
JOIN/INNER JOIN or any other way?
You can use correlated subquery :
select o.*
from orders o
where date = (select max(o1.date)
from orders o1
where o1.product_id = o.product_id and o1.city = o.city
);
If ord_id increases along with the date (as would be typical), then a simple aggregation works.
select product_id, city, max(ord_id)
from tbl_ord
group by product_id, city;
Otherwise, the typical method would use row_number():
select o.*
from (select o.*,
row_number() over (partition by product_id, city order by date desc) as seqnum
from tbl_ord o
) o
where seqnum = 1;
In older versions of MySQL, a correlated subquery is a good route. But if you want exactly one row per product and city, use ord_id:
select o.*
from tbl_ord o
where o.ord_id = (select o2.ord_id
from tbl_ord o2
where o2.product_id = o.product_id and o2.city = o.city
order by o2.date desc
limit 1
);
Related
I have a table of bank transactions, AccountTransaction, and rows with for e.g.
Amount
Payee_Name
Transaction_ID
Is_Corresponding_Transaction
69.00
Bob Jones
1
1
-69.00
Bob Jones
1
0
25.00
Bill
2
1
-25.00
Bill
2
0
297.00
Sally
3
1
-5.00
Ted
4
1
2.50
Ted
4
0
2.50
Ted
4
0
How do I select only (all) TS like Sally's where the Transaction ID only occurs once?
Bonus points: How do I select TS like Ted's where the sum of all Is_Corresponding_Transaction = 0 != the sum of Is_Corresponding_Transaction = 1 for a given TS_ID?
I was looking and found a Group by or where not exists, but couldn't figure out how to get that to work
Here's an e.g. of what I tried:
select
Full_Name, amount, a.Posted_Date,a.Payee_Name, a.Memo, Accounts.Account_Name
from AccountTransaction a
left join Accounts on Accounts.Account_Code = a.Account_Code
left join users on a.UserId = users.UserId
where not exists (select 1 from AccountTransaction b where a.Transaction_ID = b.Transaction_ID having count(*)>1)
and a.Pending= 0
ORDER by a.Posted_Date desc
Just to expand on Stu's comment. Here is one option that uses the window function
with cte as (
Select *
,NetSum = sum(Amount) over (partition by Transaction_ID)
,NetCnt = sum(1) over (partition by Transaction_ID)
From YourTable
)
Select *
From cte
Where NetSum<>0
or NetCnt<>2
I have two tables, info and transactions.
info looks like this:
customer ID Postcode
1 ABC 123
2 DEF 456
and transactions looks like this:
customer ID day frequency
1 1/1/12 3
1 3/5/12 4
2 4/6/12 2
3 9/9/12 1
I want to know which day has the highest frequency for each postcode.
I know how to reference from two different tables but im not too sure how to reference multiple columns based on their values to other columns.
The output should be something like this:
customer ID postcode day frequency
1 ABC 123 3/5/12 4
2 DEF 456 4/6/12 2
3 GHI 789 9/9/12 1
and so on.
You can filter with a correlated subquery:
select
i.*,
t.day,
t.frequency
from info i
inner join transactions t on t.customerID = i.customerID
where t.frequency = (
select max(t.frequency)
from info i1
inner join transactions t1 on t1.customerID = i1.customerID
where i1.postcode = i.postcode
)
Or, if your RBDMS supports window functions, you can use rank():
select *
from (
select
i.*,
t.day,
t.frequency,
rank() over(partition by i.postcode order by t.frequency desc)
from info i
inner join transactions t on t.customerID = i.customerID
) t
where rn = 1
I don't understand why my query doesn't group results of count by the column I specified. Instead it counts all occurrences of outcome_id in the 'un' subtable.
What am I missing there?
The full structure of my sample database and the query I tried are here:
https://www.db-fiddle.com/f/4HuLpTFWaE2yBSQSzf3dX4/4
CREATE TABLE combination (
combination_id integer,
ticket_id integer,
outcomes integer[]
);
CREATE TABLE outcome (
outcome_id integer,
ticket_id integer,
val double precision
);
insert into combination
values
(510,188,'{52,70,10}'),
(511,188,'{52,56,70,18,10}'),
(512,188,'{55,70,18,10}'),
(513,188,'{54,71,18,10}'),
(514,189,'{52,54,71,18,10}'),
(515,189,'{55,71,18,10,54,56}')
;
insert into outcome
values
(52,188,1.3),
(70,188,2.1),
(18,188,2.6),
(56,188,2),
(55,188,1.1),
(54,188,2.2),
(71,188,3),
(10,188,0.5),
(54,189,2.2),
(71,189,3),
(18,189,2.6),
(55,189,2)
with un AS (
SELECT combination_id, unnest(outcomes) outcome
FROM combination c JOIN
outcome o
on o.ticket_id = c.ticket_id
GROUP BY 1,2
)
SELECT combination_id, cnt
FROM (SELECT un.combination_id,
COUNT(CASE WHEN o.val >= 1.3 THEN 1 END) as cnt
FROM un JOIN
outcome o
on o.outcome_id = un.outcome
GROUP BY 1
) x
GROUP BY 1, 2
ORDER BY 1
Expected result should be:
510 2
511 4
512 2
513 3
514 4
515 4
Assuming, you have these PK constraints:
CREATE TABLE combination (
combination_id integer PRIMARY KEY
, ticket_id integer
, outcomes integer[]
);
CREATE TABLE outcome (
outcome_id integer
, ticket_id integer
, val double precision
, PRIMARY KEY (ticket_id, outcome_id)
);
and assuming this objective:
For each row in table combination, count the number of array elements in outcomes for which there is at least one row with matching outcome_id and ticket_id in table outcome - and val >= 1.3.
Assuming above PK, this burns down to a much simpler query:
SELECT c.combination_id, count(*) AS cnt
FROM combination c
JOIN outcome o USING (ticket_id)
WHERE o.outcome_id = ANY (c.outcomes)
AND o.val >= 1.3
GROUP BY 1
ORDER BY 1;
This alternative might be faster with index support:
SELECT c.combination_id, count(*) AS cnt
FROM combination c
CROSS JOIN LATERAL unnest(c.outcomes) AS u(outcome_id)
WHERE EXISTS (
SELECT
FROM outcome o
WHERE o.outcome_id = u.outcome_id
AND o.val >= 1.3
AND o.ticket_id = c.ticket_id -- ??
)
GROUP BY 1
ORDER BY 1;
Plus, it does not require the PK on outcome. Any number of matching rows still count as 1, due to EXISTS.
db<>fiddle here
As always, the best answer depends on the exact definition of setup and requirements.
A simpler version of #forpas answer:
-- You don't need to join to outcomes in the "with" statement.
with un AS (
SELECT combination_id, ticket_id, unnest(outcomes) outcome
FROM combination c
-- no need to join to outcomes here
GROUP BY 1,2,3
)
SELECT combination_id, cnt FROM
(
SELECT un.combination_id,
COUNT(CASE WHEN o.val >= 1.3 THEN 1 END) as cnt
FROM un
JOIN outcome o on o.outcome_id = un.outcome
and o.ticket_id = un.ticket_id
GROUP BY 1
)x
GROUP BY 1,2
ORDER BY 1
As others have pointed out, the expected result for 514 should be 3 based on your input data.
I'd also like to suggest that using full field names in the group by and order by clauses makes queries easier to debug and maintain going forward.
You need to join on ticket_id also:
with un AS (
SELECT c.combination_id, c.ticket_id, unnest(c.outcomes) outcome
FROM combination c JOIN outcome o
on o.ticket_id = c.ticket_id
GROUP BY 1,2,3
)
SELECT combination_id, cnt
FROM (SELECT un.combination_id, un.ticket_id,
COUNT(CASE WHEN o.val >= 1.3 THEN 1 END) as cnt
FROM un JOIN outcome o
on o.outcome_id = un.outcome and o.ticket_id = un.ticket_id
GROUP BY 1,2
) x
GROUP BY 1, 2
ORDER BY 1
See the demo.
Results:
> combination_id | cnt
> -------------: | --:
> 510 | 2
> 511 | 4
> 512 | 2
> 513 | 3
> 514 | 3
> 515 | 4
i have 1 table inventory_movement here is data in table
product_id | staff_name | status | sum | reference_number
--------------------------------------------------
1 zes cp 1 000122
2 shan cp 4 000133
i have another table inventory_orderproduct where i have cost date
orderdate product_id cost
--------------------------------
01/11/2018 1 3200
01/11/2018 2 100
02/11/2018 1 4000
02/11/2018 1 500
03/11/2018 2 2000
i want this result
product_id| staff_name | status | sum reference_number | cost
--------------------------------------------------------------
1 zes cp 1 000122 4000
2 shan cp 4 000133 2000
here is my query
select ipm.product_id,
case when ipm.order_by_id is not null then
(select au.first_name from users_staffuser us inner join auth_user au on us.user_id= au.id
where us.id = ipm.order_by_id) else '0' end as "Staff_name"
,ipm.status,
Sum(ipm.quantity), ip.reference_number
from inventory_productmovement ipm
inner join inventory_product ip on ipm.product_id = ip.id
inner join users_staffuser us on ip.branch_id = us.branch_id
inner join auth_user au on us.user_id = au.id
AND ipm.status = 'CP'
group by ipm.product_id, au.first_name, ipm.status,
ip.reference_number, ip.product_name
order by 1
Here is the solution of your question.its working fine.if you like the answer please vote!
SELECT i.product_id,i.staff_name,i.status,i.sum reference_number ,s.Cost
FROM (SELECT product_id,MAX(cost) AS Cost
FROM inventory_orderproduct
GROUP BY product_id ) s
JOIN inventory_movement i ON i.product_id =s.product_id
In the given situation, this should work fine:
Select table1.product_id, table2.staff_name, table2.status, table2.reference_number,
MAX(table1.cost)
FROM table2
LEFT JOIN table1 ON table1.product_id = table2.product_id
GROUP BY table2.product_id, table2.staff_name, table2.status, table2.reference_number
You can use the below query to get MAX cost for products
SELECT i.product_id,i.staff_name,i.status,i.sum reference_number ,s.MAXCost
FROM (SELECT product_id,MAX(cost) AS MAXCost
FROM inventory_orderproduct
GROUP BY product_id ) s
JOIN inventory_movement i ON i.product_id =s.product_id
For Retrieving the cost using the latest date use the below query
WITH cte as (
SELECT product_id,cost
,ROW_NUMBER() OVER (PARTITION BY product_id ORDER BY orderdate DESC) AS Rno
FROM inventory_orderproduct )
SELECT i.product_id,i.staff_name,i.status,i.sum reference_number ,s.Cost
FROM cte s
JOIN inventory_movement i ON i.product_id =s.product_id
WHERE s.Rno=1
You can use below query it will pick the data according to the latest date
WITH result as (
SELECT product_id,cost
,ROW_NUMBER() OVER (PARTITION BY product_id ORDER BY date DESC)
FROM inventory_orderproduct )
SELECT i.product_id,i.staff_name,i.status,i.sum reference_number ,s.Cost
FROM result s
JOIN inventory_movement i ON i.product_id =s.product_id
I want to select the records of the top n groups. My data looks like this:
Table 'runner':
id gid status rtime
---------------------------
100 5550 1 2016-08-19
200 5550 2 2016-08-22
300 5550 1 2016-08-30
100 6050 3 2016-09-01
200 6050 1 2016-09-02
100 6250 1 2016-09-11
200 6250 1 2016-09-15
300 6250 3 2016-09-19
Table 'static'
id description env
-------------------------------
100 something 1 somewhere 1
200 something 2 somewhere 2
300 something 3 somewhere 3
The unit id (id) is unique within the group but not unique in its column, because an instance of the group is generated regularly. The group id (gid) is assigned to every unit but will not generate on more than one instance.
Now, combining the tables and selecting everything or filter by a specific value is easy, but how do I select all records of, for example, the first two groups without directly refering to the group ids?
Expected result would be:
id gid description status rtime
--------------------------------------
300 6250 something 2 3 2016-09-19
200 6250 something 1 1 2016-09-15
100 6250 something 3 1 2016-09-11
200 6050 something 2 1 2016-09-02
100 6050 something 1 3 2016-09-01
Extra Question: When I filter for a timeframe like this:
[...]
WHERE runner.rtime BETWEEN '2016-08-25' AND '2016-09-16'
Is there a simple way of ensuring, that groups are not cut off but either appear with all their records or not at all?
You can use a ROW_NUMBER() to do this. First, create a query to rank groups:
SELECT gid, ROW_NUMBER() over (order by gid desc) as RN
FROM Runner
GROUP BY gid
Then use this as a derived table to get your other info, and use a where clause to filter to the number of groups you want to see. For instance, the below would return the top 5 groups RN <= 5:
SELECT id, R.gid, description, status, rtime
FROM (SELECT gid, ROW_NUMBER() over (order by gid desc) as RN
FROM Runner
GROUP BY gid) G
INNER JOIN Runner R on R.gid = G.gid
INNER JOIN Statis S on S.id = R.id
WHERE RN <= 5 --Change this to see more or less groups
For your second question about dates, you can do this with a subquery like so:
SELECT *
FROM Runner
WHERE gid IN (SELECT gid
FROM Runner
WHERE rtime BETWEEN '2016-08-25' AND '2016-09-16')
Hmmm. I suspect this might do what you want:
select top (1) with ties r.*
from runner r
order by min(rtime) over (partition by gid), gid;
At least, this will get the complete first group.
In any case, the idea is to include gid as a key in the order by and to use top with ties.
you can do the following
with report as(
select n.id,n.gid,m.description,n.status,n.rtime, dense_rank() over(order by gid desc) as RowNum
from #table1 n
inner join #table2 m on n.id = m.id )
select id,gid,description,status,rtime
from report
where RowNum<=2 -- <-- here n=2
order by gid desc,rtime desc
here a working demo
DENSE_RANK looks like a ideal solution here
Select * From
(
select DENSE_RANK() over (order by gid desc) as D_RN, r.*
from runner r
) A
Where D_RN = 1
No need to use ranking functions (ROW_NUMBER, DENSE_RANK etc).
SELECT r.id, gid, [description], [status], rtime
FROM runner r
INNER JOIN static s ON r.id = s.id
WHERE gid IN (
SELECT TOP 2 gid FROM runner GROUP BY gid ORDER BY gid DESC
)
ORDER BY rtime DESC;
The same using CTE:
WITH grouped
AS
(
SELECT TOP 2 gid
FROM runner GROUP BY gid ORDER BY gid DESC
)
SELECT r.id, grouped.gid, [description], [status], rtime
FROM runner r
INNER JOIN static s ON r.id = s.id
INNER JOIN grouped ON r.gid = grouped.gid
ORDER BY rtime DESC;