Find count in SQL using different set of dates - sql

Question

I have below query to find the counts based on different date fields.
How can I get the result like below expected result?
The query shown is not returning the actual counts like the sample result.
+-------+-----------+------------+-----------+----------+
| WO_id | DateOpen | DateFinish | DateClose | Location |
+-------+-----------+------------+-----------+----------+
| 100 | 16-Dec-18 | 18-Dec-18 | 19-Dec-18 | A |
| 101 | 16-Dec-18 | 18-Dec-18 | 19-Dec-18 | A |
| 102 | 17-Dec-18 | 19-Dec-18 | 20-Dec-18 | C |
| 103 | 10-Dec-18 | 11-Dec-18 | 16-Dec-18 | D |
| 104 | 17-Dec-18 | 19-Dec-18 | 18-Dec-18 | E |
+-------+-----------+------------+-----------+----------+
Query (selection criteria : 16-Dec-2018 data only):
SELECT
COUNT(DateOpen) AS Opened,
COUNT(DateClose) AS closed,
COUNT(DateFinish) AS finished,
Location
FROM
JOB
WHERE
JOB.DateOpen BETWEEN '12/16/2018' AND DATEADD(DAY, 1, '12/16/2018')
OR JOB.DateClose BETWEEN '12/16/2018' AND DATEADD(DAY, 1, '12/16/2018')
OR JOB.DateFinish BETWEEN '12/16/2018' AND DATEADD(DAY, 1, '12/16/2018')
GROUP BY
Location
Expected result:
+--------+----------+--------+----------+
| opened | finished | closed | Location |
+--------+----------+--------+----------+
| 2 | 0 | 0 | A |
| 0 | 0 | 1 | D |
+--------+----------+--------+----------+

Answer 1

There is a trick you can with SUM and CASE, you use case to select 1 when it matches the criteria or 0 otherwise and then sum to "count" those items -- (since summing 0 or null is like not counting something). Here is the codez:
SELECT
SUM(CASE WHEN JOB.DateOpen BETWEEN '12/16/2018' AND DATEADD(DAY, 1, '12/16/2018') THEN 1 ELSE 0 END) AS opened,
SUM(CASE WHEN JOB.DateFinish BETWEEN '12/16/2018' AND DATEADD(DAY, 1, '12/16/2018') THEN 1 ELSE 0 END) AS finished,
SUM(CASE WHEN JOB.DateClose BETWEEN '12/16/2018' AND DATEADD(DAY, 1, '12/16/2018') THEN 1 ELSE 0 END) AS closed,
location
FROM JOB
group by Location

Answer 2

This should get you the results you're looking for. It only returns the rows that match the specific date criteria. The way you have your query currently built will result in it also pulling in rows that match 12/17/2018. You can test it here: https://rextester.com/MHT79618
DECLARE #SelectionDate DATETIME = '12/16/2018'
SELECT
SUM (CASE WHEN DateOpen = #SelectionDate THEN 1 ELSE 0 end) as Opened
,SUM (CASE WHEN DateClose = #SelectionDate THEN 1 ELSE 0 end)as closed
,SUM (CASE WHEN DateFinish = #SelectionDate THEN 1 ELSE 0 end)as finished
,Location
FROM JOB
WHERE JOB.DateOpen = #SelectionDate
or JOB.DateClose = #SelectionDate
or JOB.DateFinish = #SelectionDate
group by Location
edit damn, just saw Hogan answered while I was typing with basically the same answer.

Answer 3

In your original script, you count all rows and I think you might have the incorrect conditions. Please try following script.
create table JOB
(WO_id int,
DateOpen date,
DateFinish date,
DateClose date,
Location varchar(20))
insert into JOB values
(100,'16-Dec-18','18-Dec-18','19-Dec-18','A'),
(101,'16-Dec-18','18-Dec-18','19-Dec-18','A'),
(102,'17-Dec-18','19-Dec-18','20-Dec-18','C'),
(103,'10-Dec-18','11-Dec-18','16-Dec-18','D'),
(104,'17-Dec-18','19-Dec-18','18-Dec-18','E')
;with cte as (
SELECT
CASE WHEN DateOpen = '12/16/2018' THEN 1 ELSE 0 end as Opened,
CASE WHEN DateClose = '12/16/2018' THEN 1 ELSE 0 end as closed,
CASE WHEN DateFinish = '12/16/2018' THEN 1 ELSE 0 end as finished,
Location
FROM JOB )
select sum(Opened) as Opened,sum(closed) as closed,sum(finished) as finished,Location
from cte
WHERE Opened <>0 or closed<>0 or finished <>0
group by Location
/*
Opened closed finished Location
----------- ----------- ----------- --------------------
2 0 0 A
0 1 0 D
*/
Best Regards,
Rachel