Vb.Net 2010 - SQL Insert Command with autonumeric value - sql

Question

I'm looking to add a row with an autonumeric value using SQL.
I'm using Studio VB 2010. I have a very simple table with 2 fields:
ID Autonumeric
Model Text field.
constr = "INSERT INTO procedures VALUES('" & txtFName.Text & "')"
cmd = New OleDbCommand(constr, cn)
cn.Open()
Me.i = cmd.ExecuteNonQuery
A message says a parameter is missing,
so my question is...
How can I add in the SQL command this automatic value? (ID)
Should I get the last ID number and +1 ?? I think there's gotta be a simple way to do it.
Thank you.
Update #1
I am now trying parameterized queries as suggested...
I found this example,
Dim cmdText As String = "INSERT INTO procedures VALUES (?,?)"
Dim cmd As OleDbCommand = New OleDbCommand(cmdText, con)
cmd.CommandType = CommandType.Text
With cmd.Parameters
.Add("#a1", OleDbType.Integer).Value = 0
.Add("#a2", OleDbType.VarChar).Value = txtFName.Text
End With
cmd.ExecuteNonQuery()
con.Close()
But still, I'm geting a Syntaxis error.
Any thoughts?
Thanks to you all.
UPDATE #2
This code seems to work if I give the next ID number, but again, how can I do it automatically?
Dim cmdText As String = "INSERT INTO procedures VALUES (?,?)"
Dim cmd As OleDbCommand = New OleDbCommand(cmdText, con)
cmd.CommandType = CommandType.Text
With cmd.Parameters
.AddWithValue("#a1", OleDbType.Integer).Value = 3
.AddWithValue("#a2", OleDbType.VarChar).Value = txtFName.Text
End With
cmd.ExecuteNonQuery()
con.Close()
Any comments? Thanks again.
UPDATE #3 This Code gives me Syntaxis Error
I just put my only one column to update, the second one is the autonumber column, as I was told to try.
Dim Con As OleDbConnection = New OleDbConnection(dbProvider & dbSource)
Dim SQL_command As String = "INSERT INTO procedures (procedure) VALUES ('Model')"
Dim cmd As OleDbCommand = New OleDbCommand(SQL_command, Con)
Try
Con.Open()
cmd.ExecuteNonQuery()
Catch ex As Exception
Throw ex
Finally
Con.Close()
Con.Dispose()
End Try
UPDATE #4 - SOLUTION
I'm putting this code in here in case someone finds it useful.
dbProvider = "PROVIDER=Microsoft.ACE.OLEDB.12.0;Persist Security Info=False;"
dbSource = "Data Source = c:\gastrica\dabase.accdb"
Con.ConnectionString = dbProvider & dbSource
Dim Con As OleDbConnection = New OleDbConnection(dbProvider & dbSource)
Dim SQL_command As String = "INSERT INTO [procedures] ([procedure]) VALUES (?)"
Dim cmd As OleDbCommand = New OleDbCommand(SQL_command, Con)
cmd.CommandType = CommandType.Text
With cmd.Parameters
.AddWithValue("#procedure", OleDbType.VarChar).Value = txtFName.Text
End With
Try
Con.Open()
cmd.ExecuteNonQuery()
Dim varProcedure As String = cmd.Parameters("#procedure").Value.ToString()
MessageBox.Show("Record inserted successfully. Procedure = " & varProcedure)
Catch ex As Exception
Throw ex
Finally
Con.Close()
End Try
Thanks all for your comments and help.

Answer 1

You need to specify the columns:
INSERT INTO procedures (columnname, columnname2) VALUES ('test', 'test');
Here is a sql fiddle showing an example:
http://sqlfiddle.com/#!9/3cf706/1

Answer 2

Try this one:
constr = "INSERT INTO procedures (ID, Model) VALUES (0,'" & txtFName.Text & "')"
'or (not sure)
constr = "INSERT INTO procedures (Model) VALUES ('" & txtFName.Text & "')"
When use 0 as value, in autonumeric fields SQL insert the next number

Answer 3

Thanks for your answers.
I couldn´t do it, it gives me errors. So I end up with a single variable reaching the next Auto Value. Using a simple SQL command.
And then, everything runs good.
vNextAuto = GetDB_IntValue("SELECT TOP 1 * FROM procedures ORDER BY ID DESC", "ID") + 1
Dim SQL_command As String = "INSERT INTO procedures VALUES (?,?)"
Dim cmd As OleDbCommand = New OleDbCommand(SQL_command, Con)
cmd.CommandType = CommandType.Text
With cmd.Parameters
.AddWithValue("#id", OleDbType.Integer).Value = vNextAuto
.AddWithValue("#a2", OleDbType.VarChar).Value = txtFName.Text
End With
Try
Con.Open()
cmd.ExecuteNonQuery()
'Dim id As String = cmd.Parameters("#id").Value.ToString()
'MessageBox.Show("Record inserted successfully. ID = " & id)
Catch ex As Exception
Throw ex
Finally
Con.Close()
Con.Dispose()
End Try