I just asked the question about how I eliminate duplicate data in a column
How can I eliminate duplicate data in column
this code below can delete duplicates in a column
with data as
(
select 'apple, apple, apple, apple' col from dual
)
select listagg(col, ',') within group(order by 1) col
from (
select distinct regexp_substr(col, '[^,]+', 1, level) col
from data
connect by level <= regexp_count(col, ',')
)
next question is
now I do not know how to eliminate data in multiple columns
select 'apple, apple, apple' as col1,
'prince,prince,princess' as col2,
'dog, cat, cat' as col3
from dual;
I would like to show
COL1 COL2 COL3
----- ---------------- --------
apple prince, princess dog, cat
You may use such a combination :
select
(
select listagg(str,',') within group (order by 0)
from
(
select distinct trim(regexp_substr('apple, apple, apple','[^,]+', 1, level)) as str
from dual
connect by level <= regexp_count('apple, apple, apple',',') + 1
)
) as str1,
(
select listagg(str,',') within group (order by 0)
from
(
select distinct trim(regexp_substr('prince,prince,princess','[^,]+', 1, level)) as str
from dual
connect by level <= regexp_count('prince,prince,princess',',') + 1
)
) as str2,
(
select listagg(str,',') within group (order by 0)
from
(
select distinct trim(regexp_substr('dog, cat, cat','[^,]+', 1, level)) as str
from dual
connect by level <= regexp_count('dog, cat, cat',',') + 1
)
) as str3
from dual;
STR1 STR2 STR3
------ --------------- --------
apple prince,princess cat,dog
Rextester Demo
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I have 2 cols
ID Value
ab^bc^ab^de
mn^mn^op
I want the output as
ID Value
ab^bc^de
mn^op
Can someone please help me in this.✋ I have around 500 rows in the table.
I tried using stuff and other ways but errors are popping up.
You can use a recursive query and simple string functions (which is much faster than regular expressions, but a little more to type) to split the string and then, in later Oracle versions, can re-aggregate it using LISTAGG(DISTINCT ...:
WITH bounds ( rid, value, spos, epos ) AS (
SELECT ROWID, value, 1, INSTR(value, '^', 1)
FROM table_name
UNION ALL
SELECT rid, value, epos + 1, INSTR(value, '^', epos + 1)
FROM bounds
WHERE epos > 0
)
SELECT LISTAGG(
DISTINCT
CASE epos
WHEN 0
THEN SUBSTR(value, spos)
ELSE SUBSTR(value, spos, epos - spos)
END,
'^'
) WITHIN GROUP (ORDER BY spos) AS unique_values
FROM bounds
GROUP BY rid;
Which, for the sample data:
CREATE TABLE table_name (value) AS
SELECT 'ab^bc^ab^de' FROM DUAL UNION ALL
SELECT 'mn^mn^op' FROM DUAL UNION ALL
SELECT 'ab^bc^ab^de' FROM DUAL UNION ALL
SELECT 'one^two^three^one^two^one^four' FROM DUAL;
Outputs:
UNIQUE_VALUES
ab^bc^de
mn^op
ab^bc^de
one^two^three^four
If you are using earlier versions or Oracle that do not support DISTINCT in the LISTAGG then you can aggregate twice:
WITH bounds ( rid, value, spos, epos ) AS (
SELECT ROWID, value, 1, INSTR(value, '^', 1)
FROM table_name
UNION ALL
SELECT rid, value, epos + 1, INSTR(value, '^', epos + 1)
FROM bounds
WHERE epos > 0
),
words (rid, word, spos) AS (
SELECT rid,
CASE epos
WHEN 0
THEN SUBSTR(value, spos)
ELSE SUBSTR(value, spos, epos - spos)
END,
spos
FROM bounds
),
unique_words ( rid, word, spos ) AS (
SELECT rid,
word,
MIN(spos)
FROM words
GROUP BY rid, word
)
SELECT LISTAGG(word, '^') WITHIN GROUP (ORDER BY spos) AS unique_values
FROM unique_words
GROUP BY rid;
Which gives the same output.
fiddle
For example:
Sample data:
SQL> with
2 test (col) as
3 (select 'ab^bc^ab^de' from dual union all
4 select 'mn^mn^op' from dual
5 ),
Split values into rows:
6 temp as
7 (select
8 col,
9 regexp_substr(col, '[^\^]+', 1, column_value) val,
10 column_value lvl
11 from test cross join
12 table(cast(multiset(select level from dual
13 connect by level <= regexp_count(col, '\^') + 1
14 ) as sys.odcinumberlist))
15 )
Aggregate them back, using only distinct values:
16 select col,
17 listagg(val, '^') within group (order by lvl) as result
18 from (select col, val, min(lvl) lvl
19 from temp
20 group by col, val
21 )
22 group by col;
COL RESULT
----------- --------------------
ab^bc^ab^de ab^bc^de
mn^mn^op mn^op
SQL>
Other solutions if your ORACLE version is recent enough to have LISTAGG DISTINCT:
with data(s) as (
select 'ab^bc^ab^de' from dual union all
select 'mn^mn^op' from dual
),
splitted(s, l, r) as (
select s, level, regexp_substr(s,'[^\^]+',1,level) from data
connect by regexp_substr(s,'[^\^]+',1,level) is not null and s = prior s and prior sys_guid() is not null
)
select s, listagg(distinct r, '^') within group(order by l) as r from splitted
group by s
;
And better if you have a PK, use it:
with data(id, s) as (
select 1, 'ab^bc^ab^de' from dual union all
select 2, 'mn^mn^op' from dual
),
splitted(id, l, r) as (
select id, level, regexp_substr(s,'[^\^]+',1,level) from data
connect by regexp_substr(s,'[^\^]+',1,level) is not null and id = prior id and prior sys_guid() is not null
)
select id, listagg(distinct r, '^') within group(order by l) as r from splitted
group by id
;
For the fun, using XML:
with data(s) as (
select 'ab^bc^ab^de' from dual union all
select 'mn^mn^op' from dual
)
select *
from data,
xmltable(
q'{string-join( for $atom in distinct-values((ora:tokenize($X,"\^"))) order by $atom return $atom, "^" )}'
passing s as "X"
columns
column_value varchar2(64) path '.'
)
;
(or fn:tokenize, depending on the DB version)
I need to concatenate two columns from diffrent tables, delimited with ";" into one row without duplicates.
Table 1:
Name
John;Sue
Table 2:
Name
Mary;John
Desired output
Names
John;Sue;Mary
I tried with :
select listagg(a.Name, ';') within group (order by a.Name) as Names
from Table1 a
join Table2 b on a.id = b.id;
but I get "ORA-01489: result of string concatenation is too long" error.
How to do that properly in Oracle?
You can do it with simple string functions:
WITH t1_positions (id, name, spos, epos) AS (
SELECT id,
name,
1,
INSTR(name, ';', 1)
FROM table1
UNION ALL
SELECT id,
name,
epos + 1,
INSTR(name, ';', epos + 1)
FROM t1_positions
WHERE epos > 0
),
t1_strings (id, item) AS (
SELECT id,
CASE epos
WHEN 0
THEN SUBSTR(name, spos)
ELSE SUBSTR(name, spos, epos - spos)
END
FROM t1_positions
),
t2_positions (id, name, spos, epos) AS (
SELECT id,
name,
1,
INSTR(name, ';', 1)
FROM table2
UNION ALL
SELECT id,
name,
epos + 1,
INSTR(name, ';', epos + 1)
FROM t2_positions
WHERE epos > 0
),
t2_strings (id, item) AS (
SELECT id,
CASE epos
WHEN 0
THEN SUBSTR(name, spos)
ELSE SUBSTR(name, spos, epos - spos)
END
FROM t2_positions
)
SELECT id,
LISTAGG(item, ';') WITHIN GROUP (ORDER BY item) AS name
FROM (SELECT * FROM t1_strings
UNION
SELECT * FROM t2_strings)
GROUP BY id;
Which, for the sample data:
CREATE TABLE Table1 (id, name) AS
SELECT 1, 'John;Sue' FROM DUAL;
CREATE TABLE Table2 (id, name) AS
SELECT 1, 'Mary;John' FROM DUAL;
Outputs:
ID
NAME
1
John;Mary;Sue
Note: you can do it with regular expressions; however, for a large dataset, it is likely to be of an order of magnitude slower.
Update
How to do that properly in Oracle?
Do not store delimited strings and store the data in first normal form (1NF):
CREATE TABLE table1 (id, name) AS
SELECT 1, 'John' FROM DUAL UNION ALL
SELECT 1, 'Sue' FROM DUAL;
CREATE TABLE table2 (id, name) AS
SELECT 1, 'Mary' FROM DUAL UNION ALL
SELECT 1, 'John' FROM DUAL;
Then the query is simply:
SELECT id,
LISTAGG(name, ';') WITHIN GROUP (ORDER BY name) AS name
FROM (SELECT * FROM table1
UNION
SELECT * FROM table2)
GROUP BY id;
db<>fiddle here
Presuming those are names and the result doesn't span over more than 4000 characters (which is the listagg limit) then one option is to do this (read comments within code):
SQL> with
2 -- sample data
3 table1 (id, name) as
4 (select 1, 'John;Sue' from dual union all
5 select 2, 'Little;Foot' from dual),
6 table2 (id, name) as
7 (select 1, 'Mary;John' from dual),
8 --
9 union_jack (id, name) as
10 -- union those two tables
11 (select id, name from table1
12 union
13 select id, name from table2
14 ),
15 distname as
16 -- distinct names
17 (select distinct
18 id,
19 regexp_substr(name, '[^;]+', 1, column_value) name
20 from union_jack cross join
21 table(cast(multiset(select level from dual
22 connect by level <= regexp_count(name, ';') + 1
23 ) as sys.odcinumberlist))
24 )
25 select id,
26 listagg(d.name, ';') within group (order by d.name) as names
27 from distname d
28 group by id;
ID NAMES
---------- ------------------------------
1 John;Mary;Sue
2 Foot;Little
SQL>
If it really spans over more than 4000 characters, switch to XMLAGG; lines #25 onward would be
25 select id,
26 rtrim(xmlagg (xmlelement (e, d.name || ';') order by d.name).extract
27 ('//text()'), ';') as names
28 from distname d
29 group by id;
ID NAMES
---------- ------------------------------
1 John;Mary;Sue
2 Foot;Little
SQL>
You can use a XML-style tecnique before applying LISTAGG() in order to provide writing distinct names such as
WITH t AS
(
SELECT RTRIM(DBMS_XMLGEN.CONVERT(
XMLAGG(
XMLELEMENT(e,name||';')
).EXTRACT('//text()').GETCLOBVAL() ,1),
';') AS name
FROM ( SELECT t1.name||';'||t2.name AS name
FROM table1 t1 JOIN table2 t2 ON t1.id=t2.id )
)
SELECT LISTAGG(REGEXP_SUBSTR(name,'[^;]+',1,level),';')
WITHIN GROUP (ORDER BY 0) AS "Names"
FROM t
CONNECT BY level <= REGEXP_COUNT(name,';')
Demo
I have an Oracle database table with a field called Classification which is VARCHAR. The VARCHAR is a CSV(using semi colons). Example:
;CHR;
;OTR;CHR;ROW;
;CHA;ROW;
;OTR;ROW;
I want to pull all the rows with ONLY a different value in the CSV from the others. It is ok if a row has a previously found value as long as it has a new different value.
For instance from the above dataset it would be:
;CHR;
;OTR;CHR;ROW;
;CHA;ROW;
If I do just:
Select DISTINCT Classification from Table1
I get rows that overlap distinct values due to the overall VARCHAR being Distinct.
I can get all the distinct values using:
select LISTAGG(val,',') WITHIN GROUP ( ORDER BY val ) as final
FROM
(
select distinct trim(regexp_substr("Classification",'[^;]+', 1, level) ) as val
from Table1
connect by regexp_substr("Classification", '[^,]+', 1, level) is not null
ORDER BY val
)
which give me
FINAL
CHA,CHR,OTR,ROW
but am unable to make the link to pull out one record per unique value
Is this possible with SQL?
EDIT: This is a database created by a large corporation and mine purchased the product. Now I am tasked with data mining the backend database for BI and have absolutely no control of the database structure.
No offence but I see many answers in the questions I have researched stating 'Do better database design/normalization' and while I agree MOST I have read have no control over the database and are asking for SO assistance with a problem because of this, not ridicule on bad database design.
I apologize if I offend anyone
There is no parent/child relationship. I cannot see the object layer but I assume these values are changed in the object layer before propagating to the client as there is no link to them in the actual database
Clarification:
I see 2 ways to solve this:
1: One select statement that pulls out 1 row based on a new unique value within the VARCHAR CSV(Classification)
2: Use my select statement to loop through and pull one row containing that value in the VARCHAR CSV(Classification)
Thanks all for the input. I upvoted the ones that worked for me. In the end I will be using the one I developed just because I can easily manipulate the output(to a csv) for what the analyst wishes.
Here's one way to approach it:
Assign row numbers to the original CSV data
Split the CSV -> rows
Now assign the split CSV values row numbers, sorted by the CSV ordering from the first step
Return any rows where the row number for the previous step = 1
Return the distinct list of CSVs
For example:
with tab as (
select ';CHR;' str from dual union all
select ';OTR;CHR;ROW;' str from dual union all
select ';CHA;ROW;' str from dual union all
select ';OTR;ROW;' str from dual
), ranks as (
select row_number() over ( order by str ) rn, tab.* from tab
), rws as (
select trim ( regexp_substr(str,'[^;]+', 1, level ) ) as val, rn, str
from ranks
connect by regexp_substr ( str, '[^;]+', 1, level ) is not null
and prior rn = rn
and prior sys_guid () is not null
), rns as (
select row_number () over (
partition by val
order by rn
) val_rn, r.*
from rws r
)
select distinct str
from rns
where val_rn = 1;
STR
;CHA;ROW;
;OTR;CHR;ROW;
;CHR;
This is an ad Hoc solution proposal if the generic answer yields a suboptimal performance and some restrictions are fullfiled:
all the keys have a fixed length
the maximal number of the keys is known
Than to parse the CSV string you may use this query (add further UNION ALL for longer strings)
with tab as (
select ';CHR;' str from dual union all
select ';OTR;CHR;ROW;' str from dual union all
select ';CHA;ROW;' str from dual union all
select ';OTR;ROW;' str from dual
), tab2 as (
select str, substr(str,2,3) val from tab union all
select str, substr(str,6,3) val from tab where substr(str,6,3) is not null union all
select str, substr(str,10,3) val from tab where substr(str,10,3) is not null)
select * from tab2;
which results in
STR VAL
------------- ------------
;CHR; CHR
;OTR;CHR;ROW; OTR
;CHA;ROW; CHA
;OTR;ROW; OTR
;OTR;CHR;ROW; CHR
;CHA;ROW; ROW
;OTR;ROW; ROW
;OTR;CHR;ROW; ROW
Now you need only to find the first occurence of each key and get all distinct strings with this first occurence.
I'm reusing the approach from the solution of Chris Saxon
with tab as (
select ';CHR;' str from dual union all
select ';OTR;CHR;ROW;' str from dual union all
select ';CHA;ROW;' str from dual union all
select ';OTR;ROW;' str from dual
), tab2 as (
select str, substr(str,2,3) val from tab union all
select str, substr(str,6,3) val from tab where substr(str,6,3) is not null union all
select str, substr(str,10,3) val from tab where substr(str,10,3) is not null),
tab3 as (
select STR, VAL,
row_number() over (partition by val order by str) rn
from tab2)
select distinct str
from tab3
where rn = 1
You were very close since you had already gotten the list of distinct values. Instead of combining them with LISTAGG, you can use that list to find a row that contains that unique value. Below are two separate queries that will return a Classification for each unique value. You can try them both and see which performs better based on the data you have in the table.
Query Option 1
WITH
table1 (classification)
AS
(SELECT ';CHR;' FROM DUAL
UNION ALL
SELECT ';OTR;CHR;ROW;' FROM DUAL
UNION ALL
SELECT ';CHA;ROW;' FROM DUAL
UNION ALL
SELECT ';OTR;ROW;' FROM DUAL),
dist_vals (val)
AS
( SELECT DISTINCT TRIM (REGEXP_SUBSTR (classification,
'[^;]+',
1,
LEVEL)) AS val
FROM Table1
CONNECT BY LEVEL < REGEXP_COUNT (classification, ';'))
SELECT val, classification
FROM (SELECT dv.val,
t.classification,
ROW_NUMBER () OVER (PARTITION BY dv.val ORDER BY t.classification) AS occurence
FROM dist_vals dv, table1 t
WHERE t.classification LIKE '%;' || dv.val || ';%')
WHERE occurence = 1;
Query Option 2
WITH
table1 (classification)
AS
(SELECT ';CHR;' FROM DUAL
UNION ALL
SELECT ';OTR;CHR;ROW;' FROM DUAL
UNION ALL
SELECT ';CHA;ROW;' FROM DUAL
UNION ALL
SELECT ';OTR;ROW;' FROM DUAL),
dist_vals (val)
AS
( SELECT DISTINCT TRIM (REGEXP_SUBSTR (classification,
'[^;]+',
1,
LEVEL)) AS val
FROM Table1
CONNECT BY LEVEL < REGEXP_COUNT (classification, ';'))
SELECT dv.val,
(SELECT classification
FROM table1
WHERE classification LIKE '%;' || dv.val || ';%' AND ROWNUM = 1)
FROM dist_vals dv;
I figured it out this way and it runs fast(even once all my joins to other tables are added). Will test other answers as I can and decide best one(others look better than mine if they work as I would rather not use dbms_output)
DECLARE
v_search_string varchar2(4000);
v_classification varchar2(4000);
BEGIN
select LISTAGG(val,',') WITHIN GROUP ( ORDER BY val ) as final
INTO v_search_string
FROM
(
select distinct trim(regexp_substr("Classification",'[^;]+', 1, level) ) as val
from mytable
connect by regexp_substr("Classification", '[^,]+', 1, level) is not null
ORDER BY val
);
FOR i IN
(SELECT trim(regexp_substr(v_search_string, '[^,]+', 1, LEVEL)) l
FROM dual
CONNECT BY LEVEL <= regexp_count(v_search_string, ',')+1
)
LOOP
SELECT "Classification"
INTO v_classification
FROM mytable
WHERE "Classification" LIKE '%' || i.l || '%'
FETCH NEXT 1 ROWS ONLY;
dbms_output.put_line(v_classification);
END LOOP;
END;
I'm using Oracle 11g and I'm having trouble replacing multiple characters based on positions mentioned in a different table. For example:
Table 1
PRSKEY POSITION CHARACTER
123 3 ć
123 9 ć
Table 2
PRSKEY NAME
123 Becirovic
I have to replace the NAME in Table 2 to Bećirović.
I've tried regexp_replace but this function doesn't provide replacing more then 1 position, is there an easy way to fix this?
Here's another way to do it.
with tab1 as (select 123 as prskey, 3 as position, 'ć' as character from dual
union select 123, 9, 'ć' from dual),
tab2 as (select 123 as prskey, 'Becirovic' as name from dual)
select listagg(nvl(tab1.character, namechar)) within group(order by lvl)
from
(select prskey, substr(name, level, 1) as namechar, level as lvl
from tab2
connect by level <= length(name)
) splitname
left join tab1 on position = lvl and tab1.prskey = splitname.prskey
;
Simple solution using cursor ...
create table t1 (
prskey int,
pos int,
character char(1)
);
create table t2
(
prskey int,
name varchar2(100)
);
insert into t1 values (1, 1, 'b');
insert into t1 values (1, 3, 'e');
insert into t2 values (1, 'dear');
begin
for t1rec in (select * from t1) loop
update t2
set name = substr(name, 1, t1rec.pos - 1) || t1rec.character || substr(name, t1rec.pos + 1, length(name) - t1rec.pos)
where t2.prskey = t1rec.prskey;
end loop;
end;
/
I would prefer approach via PL/SQL, but in your tag only 'sql', so I made this monster:
with t as (
select 123 as id, 3 as pos, 'q' as new_char from dual
union all
select 123 as id, 6 as pos, 'z' as new_char from dual
union all
select 123 as id, 9 as pos, '1' as new_char from dual
union all
select 456 as id, 1 as pos, 'A' as new_char from dual
union all
select 456 as id, 4 as pos, 'Z' as new_char from dual
),
t1 as (
select 123 as id, 'Becirovic' as str from dual
union all
select 456 as id, 'Test' as str from dual
)
select listagg(out_text) within group (order by pos)
from(
select id, pos, new_char, str, prev, substr(str,prev,pos-prev)||new_char as out_text
from(
select id, pos, new_char, str, nvl(lag(pos) over (partition by id order by pos)+1,1) as prev
from (
select t.id, pos, new_char, str
from t, t1
where t.id = t1.id
) q
) a
) w
group by id
Result:
Beqirzvi1
AesZ
I have a table with a string which contains several delimited values, e.g. a;b;c.
I need to split this string and use its values in a query. For example I have following table:
str
a;b;c
b;c;d
a;c;d
I need to group by a single value from str column to get following result:
str count(*)
a 1
b 2
c 3
d 2
Is it possible to implement using single select query? I can not create temporary tables to extract values there and query against that temporary table.
From your comment to #PrzemyslawKruglej answer
Main problem is with internal query with connect by, it generates astonishing amount of rows
The amount of rows generated can be reduced with the following approach:
/* test table populated with sample data from your question */
SQL> create table t1(str) as(
2 select 'a;b;c' from dual union all
3 select 'b;c;d' from dual union all
4 select 'a;c;d' from dual
5 );
Table created
-- number of rows generated will solely depend on the most longest
-- string.
-- If (say) the longest string contains 3 words (wont count separator `;`)
-- and we have 100 rows in our table, then we will end up with 300 rows
-- for further processing , no more.
with occurrence(ocr) as(
select level
from ( select max(regexp_count(str, '[^;]+')) as mx_t
from t1 ) t
connect by level <= mx_t
)
select count(regexp_substr(t1.str, '[^;]+', 1, o.ocr)) as generated_for_3_rows
from t1
cross join occurrence o;
Result: For three rows where the longest one is made up of three words, we will generate 9 rows:
GENERATED_FOR_3_ROWS
--------------------
9
Final query:
with occurrence(ocr) as(
select level
from ( select max(regexp_count(str, '[^;]+')) as mx_t
from t1 ) t
connect by level <= mx_t
)
select res
, count(res) as cnt
from (select regexp_substr(t1.str, '[^;]+', 1, o.ocr) as res
from t1
cross join occurrence o)
where res is not null
group by res
order by res;
Result:
RES CNT
----- ----------
a 2
b 2
c 3
d 2
SQLFIddle Demo
Find out more about regexp_count()(11g and up) and regexp_substr() regular expression functions.
Note: Regular expression functions relatively expensive to compute, and when it comes to processing a very large amount of data, it might be worth considering to switch to a plain PL/SQL. Here is an example.
This is ugly, but seems to work. The problem with the CONNECT BY splitting is that it returns duplicate rows. I managed to get rid of them, but you'll have to test it:
WITH
data AS (
SELECT 'a;b;c' AS val FROM dual
UNION ALL SELECT 'b;c;d' AS val FROM dual
UNION ALL SELECT 'a;c;d' AS val FROM dual
)
SELECT token, COUNT(1)
FROM (
SELECT DISTINCT token, lvl, val, p_val
FROM (
SELECT
regexp_substr(val, '[^;]+', 1, level) AS token,
level AS lvl,
val,
NVL(prior val, val) p_val
FROM data
CONNECT BY regexp_substr(val, '[^;]+', 1, level) IS NOT NULL
)
WHERE val = p_val
)
GROUP BY token;
TOKEN COUNT(1)
-------------------- ----------
d 2
b 2
a 2
c 3
SELECT NAME,COUNT(NAME) FROM ( SELECT NAME FROM ( (SELECT rownum as ID, REGEXP_SUBSTR('a;b;c', '[^;]+', 1, LEVEL ) NAME
FROM dual CONNECT BY REGEXP_SUBSTR('a;b;c', '[^;]+', 1, LEVEL) IS NOT NULL))
UNION ALL (SELECT NAME FROM ( (SELECT rownum as ID, REGEXP_SUBSTR('b;c;d', '[^;]+', 1, LEVEL ) NAME
FROM dual CONNECT BY REGEXP_SUBSTR('b;c;d', '[^;]+', 1, LEVEL) IS NOT NULL)))
UNION ALL
(SELECT NAME FROM ( (SELECT rownum as ID, REGEXP_SUBSTR('a;c;d', '[^;]+', 1, LEVEL ) NAME
FROM dual CONNECT BY REGEXP_SUBSTR('a;c;d', '[^;]+', 1, LEVEL) IS NOT NULL)))) GROUP BY NAME
NAME COUNT(NAME)
----- -----------
d 2
a 2
b 2
c 3