Multiple counts and merge columns - sql

Question

I current have a query that grabs the number of parts made per hour between two dates:
DECLARE #StartDate datetime
DECLARE #EndDate datetime
SET #StartDate = '10/10/2018'
SET #EndDate = '11/11/2018'
SELECT
CONVERT(VARCHAR(10), CAST(presstimes AS DATE), 111) AS ForDate,
DATEPART(HOUR, presstimes) AS OnHour,
COUNT(*) AS Totals
FROM
partmasterlist
WHERE
((presstimes >= #StartDate AND presstimes < dateAdd(d, 1, #EndDate))
AND (((presstimes IS NOT NULL))))
GROUP BY
CONVERT(VARCHAR(10), CAST(presstimes AS DATE), 111),
DATEPART(HOUR, presstimes)
ORDER BY
CONVERT(VARCHAR(10), CAST(presstimes AS DATE), 111) ASC;
Output:
Date Hour QTY
---------------------
2018/11/06 11 16
2018/11/06 12 20
2018/11/06 13 29
2018/11/06 14 26
Now I need to add another qty column to count where "trimmingtimes" is set.
I can't figure out how to full join the date and hour columns (e.g. presstimes might have 20qty for Hour 2, but trimmingtimes is NULL for Hour 2);
Input:
ID presstimes trimmingtimes
-----------------------------------------------------------------
1 2018-10-10 01:15:23.000 2018-10-10 01:15:23.000
2 2018-10-10 01:15:23.000 NULL
3 2018-10-10 02:15:23.000 NULL
4 NULL 2018-10-10 03:15:23.000
Output:
Date hour Press QTY T QTY
------------------------------------
10/10/18 1 2 1
10/10/18 2 1 0
10/10/18 3 0 1

Answer 1

I suspect you want something like this:
select convert(date, v.dt) as date,
datepart(hour, v.dt) as hour,
sum(ispress) as num_press,
sum(istrim) as num_trim
from partmasterlist pml cross apply
(values (pml.presstime, 1, 0), (pml.trimmingtime, 0, 1)
) v(dt, ispress, istrim)
group by convert(date, v.dt), datepart(hour, v.dt)
order by convert(date, v.dt), datepart(hour, v.dt);
You can add a where clause for a particular range.