Sub fails to find long sentences if there is not a space between the period and endnote citations (superscripts) - vba

Question

I have a simple loop (below) that looks for sentences over 30 words long. If found, it adds a comment box to the selected sentence. It worked fine in testing. Then I added some test endnote citations...and it fails to find the long sentences.
However, it only fails when there is no space between the period and the citation superscript. If I add a space, it finds it and works perfectly. The problem is, there is not suposed to be a space between the period and the citation, per the style guide I have to follow at work.
This related Stack thread discusses the need for a space after a period to delineate the end of a sentence. I am assuming the space must be directly after the period, because I have spaces in my citations like this 1, 2, 3
Question
How can I find instances of period+superscript (with no space like this --> This is a sentence.1, 2, 3) and add a space? Ideally I would like this to happen within the below loop so I can remove the space after the comment gets added.
Sub Comment_on_Long_Sentences ()
Dim iWords as Integer
iWords = 0
For Each MySent in ActiveDocument.Sentences
If MySent.Words.Count > iWords Then
MySent.Select
'find and delete space
ActiveDocument.Comments.Add Range:= Selection.Range, Text:= "Long Sentence: " & iWords & " words"
'put the space back
End if
Next MySent
End Sub

Answer 1

There appears to be issues in VBA when trying to access Sentences that end with a superscript character. Your code also has problems with non-declared variables, so I have no idea how it ever worked for you in the first place.
Try this following VBA routine, it works in my environment. Also notice the special handling that I found is required for 1st sentences in paragraphs and when that sentence ends with a superscript character.
Sub Comment_on_Long_Sentences()
Dim doc As word.Document, rng As word.Range, para As word.Paragraph
Dim i As Long
Set doc = ActiveDocument
For Each para In doc.Paragraphs
Debug.Print para.Range.Sentences.Count
For i = 1 To para.Range.Sentences.Count
Set rng = para.Range.Sentences(i)
If i = 1 And rng.Characters.First.Font.Superscript = True Then
rng.MoveStart word.WdUnits.wdSentence, Count:=-1
End If
If rng.words.Count > 30 Then
doc.Comments.Add Range:=rng, Text:="Long Sentence: " & rng.words.Count & " words"
End If
Next
Next
End Sub

Answer 2

Here is an alternative solution. Note the option explicit at the start. Its good VBA practice to put this at the top of every module.
The problem you have is very common. Find something then rather than do a replace, do some other non replace related stuff. The subs to add and remove spaces before citations implement this pattern and are well worth studying.
If you don't understand anything then in the VBA IDE just put your cursor on the relevant keyword and press F1. This will bring up the relevant MS help page.
Option explicit
Sub Comment_on_Long_Sentences()
Dim iWords As Integer
Dim my_sentence As Variant
iWords = 30
AddSpaceBeforeCitations
For Each my_sentence In ActiveDocument.Sentences
If my_sentence.Words.Count > iWords Then
my_sentence.Comments.Add Range:=my_sentence, Text:="Long Sentence: " & iWords & " words"
End If
Next my_sentence
RemoveSpaceBeforeCitations
End Sub
Sub AddSpaceBeforeCitations()
With ActiveDocument.Content
With .Find
.ClearFormatting
.Format = True
.Text = ""
.Wrap = wdFindStop
.Font.Superscript = True
.Execute
End With
Do While .Find.Found
With .Previous(unit:=wdCharacter, Count:=1).characters
If .Last.Text = "." Then
.Last.Text = ". "
End If
End With
.Collapse direction:=wdCollapseEnd
.Move unit:=wdCharacter, Count:=1
.Find.Execute
Loop
End With
End Sub
Sub RemoveSpaceBeforeCitations()
With ActiveDocument.Content
With .Find
.ClearFormatting
.Format = True
.Text = ""
.Wrap = wdFindStop
.Font.Superscript = True
.Execute
End With
Do While .Find.Found
With .Previous(unit:=wdCharacter, Count:=2).characters
If (.Last.Text = ".") Then
.Last.Next(unit:=wdCharacter, Count:=1).characters.Last.Text = vbNullString
End If
End With
.Collapse direction:=wdCollapseEnd
.Move unit:=wdCharacter, Count:=1
.Find.Execute
Loop
End With
End Sub

Answer 3

No matter what approach you take, any code that relies on the VBA .Sentence property or .Word property is going to produce unreliable results. That's because .Sentence has no idea what a grammatical sentence and .Word has no idea what a grammatical word is. For example, consider the following:
Mr. Smith spent $1,234.56 at Dr. John's Grocery Store, to buy 10.25kg of potatoes, 10kg of avocados, and 15.1kg of Mrs. Green's Mt. Pleasant macadamia nuts.
For you and me, that would count as one, 26-word sentence; for VBA it counts as 5 sentences containing 45 words overall. For an accurate word count, use .ComputeStatistics(wdStatisticWords). Sadly there is no .ComputeStatistics(wdStatisticSentences) equivalent for sentences.