sql oracle get all possible values of a lib table - sql

I am using sql ORACLE
I have a library table:
libid libdescr
1 boss
2 secretary
3 manager
And a table with some info:
id libid descr
1 1 jim
1 2 james
2 1 rony
2 2 fred
2 3 jana
I want to join both, but I have to have all possible values of the library. So my result have to be:
id libid libdescr descr
1 1 bos jim
1 2 secretary james
1 3 manager <null>
2 1 boss rony
2 2 secretary fred
2 3 manager jana
If I do a join
select info.*,lib.libdescr
from info
left join lib
on lib.libid = info.libid
I don't get the row id=1 and libid=3
How can I make sure I have all the possible values?

In your query either you need to use right join or use the below query :
select i.*, l.libdescr from lib l left join info i on l.libid=i.libid;

Use a cross join to generate the rows and a left join to bring in the values from the other table:
select i.id, l.libid, l.libdescr, s.descr
from (select distinct id from someinfo) i cross join
library l left join
someinfo s
on s.id = i.id and s.libid = l.libid;

Related

SQL select with three tables and foreign keys

I have three tables :
field:
f_id
f_start
f_end
1
10
20
2
15
25
3
5
10
person :
p_id
p_name
1
Roger
2
John
3
Alicia
affect :
id
fk_field
fk_person
1
2
1
2
1
2
3
3
3
And I would like to select the dates and the names associated to. Like this
p_name
f_start
f_end
Roger
15
25
John
10
20
Alicia
5
10
I'm new to SQL and I don't know if i have to use JOIN or not... Thanks
You must join all 3 tables on their related columns:
SELECT p.p_name, f.f_start, f.f_end
FROM person p
INNER JOIN affect a ON a.fk_person = p.p_id
INNER JOIN field f ON f.f_id = a.fk_field;
Depending on your requirement you may need LEFT instead of INNER joins, but for this sample data the INNER joins will do.

Select from table 1 unless there is a relationship in 2 other tables

I need to query a name(s) from the Officials table, but exclude that name if the person has the day blocked.
For example, if Sam has blocked 8/21/2021 and 9/11/2021, he should not be selected if the corresponding dates are selected from the Games table. Sam should show up if 9/18/2021 is selected, however. I have 3 tables:
Officials tbl
RefId Name
---------------------
1 Jack
2 Sam
3 Jane
Games tbl Blocks tbl
GameId GameDate BlockId RefId BlockDate
------------------------- ----------------------
1 8/21/2021 1 2 8/21/2021
2 9/11/2021 2 2 9/11/2021
3 9/18/2021 3 3 8/21/2021
Desired Output
----------------------------------
If Game 1 is selected: Jack
If Game 2 is selected: Jack and Jane
If Game 3 is selected: Jack, Sam and Jane
The only 2 tables that are related are the Officials table and Blocks table, with the RefId. I need to compare the BlockDate of Blocks table to GameDate of Games table. I have tried some sql language and this below is obviously not correct, but I'm looking for a way to accomplish what I want to do:
#GameDate datetime,
Select c.Id, c.Name
From Officials c
Where In c.Id And Blocks.BlockDate <> Games.GameDate)
You can do it with NOT EXISTS:
SELECT o.*
FROM Officials o
WHERE NOT EXISTS (
SELECT 1
FROM Blocks b INNER JOIN Games g
ON g.GameDate = b.BlockDate
WHERE b.RefId = o.RefId AND g.GameId = ?
);
See the demo.

SQL query Postgres 12

I'm doing an inner join on a table like this:
SELECT *
FROM patient p
INNER JOIN
vaccine v
ON
p.vaccine_id = v.id
The condition f.vac_1 = mv.id might not been satisfied in the case where a person have not been vaccinated. In such case, I don't want to ignore the row, but instead of displaying the vaccine name (which is the purpose of the inner join) to display an emtpy string.
How can this be done ?
Example
Table vaccinne
id
name
1
Moderna
2
Comirnaty
3
Janssen
Table patient
id
name
vaccine_id
1
john
1
2
kermit
2
3
jessica
I'm looking for a query to produce:
id
name
vaccine_id
1
john
Moderna
2
kermit
Comirnaty
3
jessica
If I understand correctly, you want a left join starting with foo:
SELECT *
FROM foo f LEFT JOIN
vac v
ON f.vac_1 = mv.id

Double outer Join

I have table A that looks like this
ID AValue
----------------------
3 Tom
5 John
9 Mike
and table B that looks like this
ID BValue
----------------------
2 Nancy
3 Maria
9 Clara
10 Sophia
I am trying to join both tables to get this result
ID AValue BValue
------------------------------
2 <NULL> Nancy
3 Tom Maria
5 John <NULL>
9 Mike Clara
10 <NULL> Sophia
If i try to left outer join I would miss the records that do not have match in A
and If I try the right outer join i would miss the records that do not have match in B
any other way I can use?
what you need is FULL OUTER JOIN
SELECT ID = coalesce(a.ID, b.ID), AValue, BVlaue
FROM TalbleA a FULL OUTER JOIN TableB b
ON a.ID = b.ID

SQL count 2 equal columns and select other columns

I have a two separate tables, one with vacancies, and one with applications to those vacancies. I want to select a new table which selects from the vacancies table with a number of other columns from that table, and another column that calculates how many applications there are for those vacancies. So my vacancy table looks like this:
ID Active StartDate JobID JobTypeID HoursPerWeek
1 1 2017-02-28 2 CE 0
2 1 2017-02-15 4 CE 40
3 1 2017-02-14 1 CE 40
4 1 2017-02-28 1 CE 48
My applications table looks like this:
ID VacancyID Forename Surname EmailAddress TelephoneNumber
1 1 John Smith jsmith#gmail.com 447777777777
2 2 John Smith jsmith#gmail.com 447748772641
3 2 John Smith jsmith#gmail.com 447777777777
4 2 John Smith jsmith#gmail.com 447700123456
5 4 John Smith jsmith#gmail.com 447400123569
6 4 John Smith jsmith#gmail.com 447400126547
7 4 John Smith jsmith#gmail.com 447555123654
I want a table that looks like this:
ID Active StartDate JobID HoursPerWeek NumberOfApplicants
1 1 2017-02-28 2 0 1
2 1 2017-02-15 4 40 3
3 1 2017-02-14 1 40 0
4 1 2017-02-28 1 48 3
How can I select that table using joins and count the number of applicants where the VacancyID is equal to the ID of the first vacancy table? I have tried:
select Vacancy.ID, VacancyID, count(*) as NumberOfApplications from VacancyApplication
join Vacancy on Vacancy.ID=VacancyID
group by VacancyID, Vacancy.ID
This obviously doesn't select all the other columns and it also does not select ID 3 because there are 0 applications for that - I want ID 3 to be there with a value of 0 as well as all the other columns. How do I do this? I've tried various forms of grouping and selecting but I'm quite new to SQL so I'm not really sure how this can be done.
Use RIGHT JOIN instead of INNER JOIN and count the vacancyid column from vacancyapplication table. For the non matching records you will get count as 0
SELECT v.id, v.Active, v.StartDate, v.JobID, v.HoursPerWeek
Count(va.vacancyid) AS NumberOfApplications
FROM vacancyapplication va
RIGHT JOIN vacancy v
ON v.id = va.vacancyid
GROUP BY v.id, v.Active, v.StartDate, v.JobID, v.HoursPerWeek
Start using Alias names, it makes the query more readable
Hoping, i understood your problem correctly. Please try below query
select Vacancy.ID, VacancyID, count(*) as NumberOfApplications from VacancyApplication
left join Vacancy on Vacancy.ID=VacancyID
group by VacancyID, Vacancy.ID
You can use count as a window function using the OVER clause, thus eliminating he need for group by:
SELECT v.ID,
v.Active,
v.StartDate,
v.JobID,
v.JobTypeID,
COUNT(va.ID) OVER(PARTITION BY v.ID) HoursPerWeek
FROM Vacancy v
LEFT JOIN vacancyapplication va ON(v.ID = va.VacancyID)
Use left join and table aliases:
select v.ID, count(va.VacancyID) as NumberOfApplications
from Vacancy v join
VacancyApplication va
on v.ID = va.VacancyID
group by v.ID;
You seem to want all the columns. You could include them in the group by. However, a correlated subquery or outer apply is simpler:
select v.*, va.cnt
from vacancy v outer apply
(select count(*) as cnt
from VacancyApplication va
where v.ID = va.VacancyID
) va;
This is probably more efficient anyway, especially if you have an index on VacancyApplication(VacancyID).