SQL Server - Split column data and retrieve last second value - sql

Question

I have a column name MasterCode in XYZ Table where data is stored in below form.
.105248.105250.104150.111004.
Now first of all I want to split the data into :
105248
105250
104150
111004
Then after to retrieve only last second value from the above.
So In the above given array, value returned should be 104150.

Answer 1

Use a split string function, but not the built in once since it will return only the values and you will lose the location data.
You can use Jeff Moden's DelimitedSplit8K that will return the item and the item index:
CREATE FUNCTION [dbo].[DelimitedSplit8K]
--===== Define I/O parameters
(#pString VARCHAR(8000), #pDelimiter CHAR(1))
--WARNING!!! DO NOT USE MAX DATA-TYPES HERE! IT WILL KILL PERFORMANCE!
RETURNS TABLE WITH SCHEMABINDING AS
RETURN
--===== "Inline" CTE Driven "Tally Table" produces values from 1 up to 10,000...
-- enough to cover VARCHAR(8000)
WITH E1(N) AS (
SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL
SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL
SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1
), --10E+1 or 10 rows
E2(N) AS (SELECT 1 FROM E1 a, E1 b), --10E+2 or 100 rows
E4(N) AS (SELECT 1 FROM E2 a, E2 b), --10E+4 or 10,000 rows max
cteTally(N) AS (--==== This provides the "base" CTE and limits the number of rows right up front
-- for both a performance gain and prevention of accidental "overruns"
SELECT TOP (ISNULL(DATALENGTH(#pString),0)) ROW_NUMBER() OVER (ORDER BY (SELECT NULL)) FROM E4
),
cteStart(N1) AS (--==== This returns N+1 (starting position of each "element" just once for each delimiter)
SELECT 1 UNION ALL
SELECT t.N+1 FROM cteTally t WHERE SUBSTRING(#pString,t.N,1) = #pDelimiter
),
cteLen(N1,L1) AS(--==== Return start and length (for use in substring)
SELECT s.N1,
ISNULL(NULLIF(CHARINDEX(#pDelimiter,#pString,s.N1),0)-s.N1,8000)
FROM cteStart s
)
--===== Do the actual split. The ISNULL/NULLIF combo handles the length for the final element when no delimiter is found.
SELECT ItemNumber = ROW_NUMBER() OVER(ORDER BY l.N1),
Item = SUBSTRING(#pString, l.N1, l.L1)
FROM cteLen l
;
Then you can use it to split the string and it will return a table like this:
DECLARE #string varchar(100) = '.105248.105250.104150.111004.';
SELECT *
FROM [dbo].[DelimitedSplit8K](#string, '.')
ItemNumber Item
1
2 105248
3 105250
4 104150
5 111004
6
You want only the parts where there actually is an item, so add a where clause, and you want the second from last so add row_number(), and you want the entire thing in a common table expression so that you can query it:
DECLARE #string varchar(100) = '.105248.105250.104150.111004.';
WITH CTE AS
(
SELECT Item, ROW_NUMBER() OVER(ORDER BY ItemNumber DESC) As rn
FROM [dbo].[DelimitedSplit8K](#string, '.')
WHERE Item <> ''
)
And the query:
SELECT Item
FROM CTE
WHERE rn = 2
Result: 104150

Answer 2

If there are always four parts, you can use PARSENAME():
DECLARE #s varchar(64) = '.105248.105250.104150.111004.';
SELECT PARSENAME(SUBSTRING(#s, 2, LEN(#s)-2),2);

Answer 3

Depending on your version of SQL SERVER, you can also use the STRING_SPLIT function.
DECLARE #string varchar(100) = '.105248.105250.104150.111004.';
SELECT value,
ROW_NUMBER() OVER (ORDER BY CHARINDEX('.' + value + '.', '.' + #string + '.')) AS Pos
FROM STRING_SPLIT(#string,'.')
WHERE RTRIM(value) <> '';
It doesn't return the original position like Jeff's splitter, but does compare very favourably if you check Aaron Bertrand's Article :
Performance Surprises and Assumptions : STRING_SPLIT()
Edit:
Added position, but although works in this case may have issues with duplicate values

Answer 4

You can create a SQL server table valued function with parameters stringvalue and delemeter and call that function for the results as expected.
ALTER function [dbo].[SplitString]
(
#str nvarchar(4000),
#separator char(1)
)
returns table
AS
return (
with tokens(p, a, b) AS (
select
1,
1,
charindex(#separator, #str)
union all
select
p + 1,
b + 1,
charindex(#separator, #str, b + 1)
from tokens
where b > 0
)
select
p-1 ID,
substring(
#str,
a,
case when b > 0 then b-a ELSE 4000 end)
AS s
from tokens
)
To call the function
SELECT * FROM [DBO].[SPLITSTRING] ('.105248.105250.104150.111004.', '.') WHERE ISNULL(S,'') <> ''
Output
ID s
1 105248
2 105250
3 104150
4 111004
To get only second value you can write your query as shown below
DECLARE #MaxID INT
SELECT #MaxID = MAX (ID) FROM (SELECT * FROM [DBO].[SPLITSTRING] ('.105248.105250.104150.111004.', '.') WHERE ISNULL(S,'') <> '') A
SELECT TOP 1 #MaxID = MAX (ID) FROM (
SELECT * FROM [DBO].[SPLITSTRING] ('.105248.105250.104150.111004.', '.') WHERE ISNULL(S,'') <> ''
)a where ID < #MaxID
SELECT * FROM [DBO].[SPLITSTRING] ('.105248.105250.104150.111004.', '.') WHERE ISNULL(S,'') <> '' AND ID = #MaxID
Output
ID s
3 104150
If you want 1 as value of ID then you can write your query as shown below in last line of query.
SELECT 1 AS ID , S FROM [DBO].[SPLITSTRING] ('.105248.105250.104150.111004.', '.') WHERE ISNULL(S,'') <> '' AND ID = #MaxID
Then the output will be
ID S
1 104150
Hope this will help you.

Answer 5

Try this
DECLARE #DATA AS TABLE (Data nvarchar(1000))
INSERT INTO #DATA
SELECT '.105248.105250.104150.111004.'
;WITH CTE
AS
(
SELECT Data,ROW_NUMBER()OVER(ORDER BY Data DESC) AS Rnk
FROM
(
SELECT Split.a.value('.','nvarchar(100)') Data
FROM(
SELECT CAST('<S>'+REPLACE(Data,'.','</S><S>')+'</S>' AS XML ) As Data
FROM #DATA
)DT
CROSS APPLY Data.nodes('S') AS Split(a)
) AS Fnl
WHERE Fnl.Data <>''
)
SELECT Data FROM CTE
WHERE Rnk=2
Result
Data
-----
105248
105250
104150
111004

Answer 6

It can also be achieve only using string functions:
IF OBJECT_ID('tempdb..#temp') IS NOT NULL
DROP TABLE #temp
SELECT '.105248.105250.104150.111004.' code INTO #temp UNION ALL
SELECT '.205248.205250.204150.211004.'
SELECT
REVERSE(LEFT(
REVERSE(LEFT(code, LEN(code) - CHARINDEX('.', REVERSE(code), 2)))
, CHARINDEX('.',REVERSE(LEFT(code, LEN(code) - CHARINDEX('.', REVERSE(code), 2)))) -1
)
) second_last_value
FROM #temp
Result:
second_last_value
-----------------------------
104150
204150