SELECT [order id],
pickingdate
FROM td_order1
WHERE sku = xyz
GROUP BY pickingdate,
[order id]
HAVING pickingdate >= Min(pickingdate)
AND pickingdate <= Max(pickingdate)
ORDER BY pickingdate
Is there anything wrong in this query?
What is wrong with the query is that you are using unaggregated columns in the having. My recommendation is to use window functions:
SELECT o.*
FROM (SELECT o.*,
MIN(pickingdate) OVER (PARTITION BY sku) as min_pd,
MAX(pickingdate) OVER (PARTITION BY sku) as max_pd
FROM td_order1 o
WHERE sku = xyz
) o
WHERE pickingdate > min_pd and pickingdate < max_pd
ORDER BY pickingdate;
Modify your condition as :
pickingdate < Max(pickingdate)
to exclude end date
Related
I have the following problem.
Part of a task is to determine the visitor(s) with the most money spent between 2000 and 2020.
It just looks like this.
SELECT UserEMail FROM Visitor
JOIN Ticket ON Visitor.UserEMail = Ticket.VisitorUserEMail
where Ticket.Date> date('2000-01-01') AND Ticket.Date < date ('2020-12-31')
Group by Ticket.VisitorUserEMail
order by SUM(Price) DESC;
Is it possible to output more than one person if both have spent the same amount?
Use rank():
SELECT VisitorUserEMail
FROM (SELECT VisitorUserEMail, SUM(PRICE) as sum_price,
RANK() OVER (ORDER BY SUM(Price) DESC) as seqnum
FROM Ticket t
WHERE t.Date >= date('2000-01-01') AND Ticket.Date <= date('2021-01-01')
GROUP BY t.VisitorUserEMail
) t
WHERE seqnum = 1;
Note: You don't need the JOIN, assuming that ticket buyers are actually visitors. If that assumption is not true, then use the JOIN.
Use a CTE that returns all the total prices for each email and with NOT EXISTS select the rows with the top total price:
WITH cte AS (
SELECT VisitorUserEMail, SUM(Price) SumPrice
FROM Ticket
WHERE Date >= '2000-01-01' AND Date <= '2020-12-31'
GROUP BY VisitorUserEMail
)
SELECT c.VisitorUserEMail
FROM cte c
WHERE NOT EXISTS (
SELECT 1 FROM cte
WHERE SumPrice > c.SumPrice
)
or:
WITH cte AS (
SELECT VisitorUserEMail, SUM(Price) SumPrice
FROM Ticket
WHERE Date >= '2000-01-01' AND Date <= '2020-12-31'
GROUP BY VisitorUserEMail
)
SELECT VisitorUserEMail
FROM cte
WHERE SumPrice = (SELECT MAX(SumPrice) FROM cte)
Note that you don't need the function date() because the result of date('2000-01-01') is '2000-01-01'.
Also I think that the conditions in the WHERE clause should include the =, right?
I'm trying to partition a list of submitted machining jobs by the date they were submitted and return a maximum row number for each partition.
I have tried using Group By, but I want to retain all rows in the result. Partition By does what I need, but I want to display all rows except the maximum row number as blank.
SELECT [Created Date]
,row_number() over(partition by format([Created Date],'d','en-gb') order by [Created Date] desc) AS [Jobs Submitted That Day]
FROM [UK_App].[dbo].[rvxDevMCRequests]
order by [Created Date] desc
Results:
Created Date Jobs Submitted That Day
31/12/2014 1
31/10/2019 1
31/10/2019 2
31/10/2019 3
31/10/2018 1
31/10/2018 2
The order by function is not working correctly, and I can't figure out how to display only the highest row number. I would like it to output this:
Created Date Jobs Submitted That Day
31/12/2014 1
31/10/2018
31/10/2018 2
31/10/2019
31/10/2019
31/10/2019 3
Not an elegant solution:
SELECT [Created Date]
, case when row_number() over(partition by format([Created Date],'d','en-gb') order by [Created Date] desc)
= count(*) over(partition by format([Created Date],'d','en-gb'))
then count(*) over(partition by format([Created Date],'d','en-gb'))
else null end AS [Jobs Submitted That Day]
FROM [UK_App].[dbo].[rvxDevMCRequests]
order by [Created Date] desc
Try this one:
SELECT
a.CreatedDate,
CASE
WHEN y.rnum IS NULL
THEN ''
ELSE
a.JobsSubmitted
END AS JobsSubmitted
FROM
input a
LEFT OUTER JOIN
(
SELECT
x.CreatedDate, x.JobsSubmitted, x.rnum
FROM (
SELECT
a.*,
ROW_NUMBER() OVER(PARTITION BY a.CreatedDate ORDER BY a.JobsSubmitted DESC) AS rnum
FROM
input a
) x
WHERE
x.rnum = 1
) y
ON (
a.CreatedDate = y.CreatedDate
AND a.JobsSubmitted = y.JobsSubmitted
);
SQL Fiddle link for demo: http://www.sqlfiddle.com/#!18/511abf/17
Why are you using format()? There is no reason to convert a date to a string, especially in this case.
One significant issue is that the column [Created Date] has duplicates. When you order by that column, the duplicates can be in any order. In fact, two different order bys on the column in the same query can result in different ordering.
The solution to that is to capture the ordering once in a subquery and then use that:
select [Created Date],
(case when cnt = seqnum then seqnum
end) as [Jobs Submitted That Day]
from (select r.*,
row_number() over (partition by [Created Date] order by [Created Date] desc) as seqnum,
count(*) over (partition by [Created Date]) as cnt
from [UK_App].[dbo].[rvxDevMCRequests]
) r
order by [Created Date] desc, seqnum;
In the above query, seqnum captures the ordering, so it is used for the outer order by.
I am trying to select the max date over the year, but it is not working. Any ideas on what to do?
SELECT a.tkinit [TK ID],
YEAR(a.tkeffdate) [Rate Year],
max(a.tkeffdate) [Max Date],
tkrt03 [Standard Rate]
FROM stageElite.dbo.timerate a
join stageElite.dbo.timekeep b ON b.tkinit = a.tkinit
WHERE a.tkinit = '02672'
and tkeffdate BETWEEN '2014-01-01' and '12-31-2014'
GROUP BY a.tkinit,
tkrt03,
a.tkeffdate
Perhaps you only want it by year and not rolled up by calendar date. For SQL server you can try this.
SELECT
…
MaxDate = MAX(a.tkeffdate) OVER (PARTITION BY a.tkinit, YEAR(a.tkeffdate)))
…
Or you could modify the query above to group by the year instead of date-->
GROUP BY a.tkinit,
tkrt03,
YEAR(a.tkeffdate)
You seem to want only one row and all the columns. Use ORDER BY and TOP:
SELECT TOP (1) tr.tkinit as [TK ID],
YEAR(tr.tkeffdate) as [Rate Year],
a.tkeffdate as [Max Date],
tkrt03 as [Standard Rate]
FROM stageElite.dbo.timerate tr JOIN
stageElite.dbo.timekeep tk
ON tk.tkinit = tr.tkinit
WHERE tr.tkinit = '02672' AND
tr.tkeffdate >= '2014-01-01' AND
tr.tkeffdate < '2015-01-01'
ORDER tr.tkeffdate DESC;
Note that I also fixed your date comparisons and table aliases.
I’m trying to select the pair of product – distribution center attached with the most recent order (based on order date). For one order I can have multiple products, but the whole order will be shipped from one specific distribution center.
How do I select the specific product-distribution center attached with the latest order?
My structure is basically like this:
data.orderdetail table has ordernum, orderdate, distributioncenter
I tried to pull like this, but it doesn’t give me the desired result. I’m using sql server 2008:
SELECT DISTINCT y.OrderNum, y.Product, y.DistributionCenter
, CAST(y.OrderDate AS DATE) AS Orderdate
FROM (SELECT OrderNum, MAX(CAST(Orderdate AS date)) AS orderdate
FROM data.OrderDetail
GROUP BY OrderNum) AS x
INNER JOIN data.OrderDetail AS y
ON y.OrderNum = x.OrderNum
It looks as if you need one more clause in your join Condition
You've got
ON y.OrderNum = x.OrderNum
Which will return all the orders that match the Order number in the subquery
But you'll need
ON y.OrderNum = x.OrderNum
AND y.OrderDate = x.orderdate
Which will return all the orders that match the Order number in the subquery and the maximum date for that order number
SELECT DISTINCT
y.OrderNum,
y.Product,
y.DistributionCenter,
CAST(y.OrderDate AS DATE) AS Orderdate
FROM (
SELECT
OrderNum,
MAX(CAST(Orderdate AS date)) AS orderdate
FROM data.OrderDetail
GROUP BY OrderNum
) AS x
INNER JOIN
data.OrderDetail AS y
ON y.OrderNum = x.OrderNum
AND y.OrderDate = x.orderdate
I believe what you are looking for is row_number. This will partition your result set by OrderNum then rank the sets by the OrderDate. You can then filter off the extra rows in another where clause.
select result.*,
CAST(result.OrderDate as date) as Orderdate,
from (
select y.*,
row_number() over (
partition by y.OrderNum order by CAST(y.OrderDate as date) desc
) rank_
from (
select OrderNum,
MAX(CAST(Orderdate as date)) as orderdate
from data.OrderDetail
group by OrderNum
) as x
inner join data.OrderDetail as y on y.OrderNum = x.OrderNum
) result
where result.rank_ = 1;
select * from
(
SELECT OrderNum, Product, DistributionCenter, OrderDate
, ROW_NUMBER() over (partition by OrderNum order by OrderDate desc) as rownum
FROM OrderDetail
) as xxx
where xxx.rownum = 1
ROW_NUMBER (Transact-SQL)
Try this.
; WITH CTE1
AS (
SELECT
od.OrderNum
, od.Product
, od.DistributionCenter
, CAST(od.OrderDate AS DATE) AS OrderDate
, RowNumber = ROW_NUMBER() OVER (PARTITION BY od.Product, od.DistributionCenter ORDER BY CAST(od.OrderDate AS DATE) DESC)
FROM data.OrderDetail od
)
SELECT
OrderNum
, Product
, DistributionCenter
, OrderDate
FROM CTE1
WHERE RowNumber = 1
I'm creating an SQL statement that will return a month by month summary on sales.
The summary will list some simple columns for the date, total number of sales and the total value of sales.
However, in addition to these columns, i'd like to include 3 more that will list the months best customer by amount spent. For these columns, I need some kind of inline subquery that can return their ID, Name and the Amount they spent.
My current effort uses an inline SELECT statement, however, from my knowledge on how to implement these, you can only return one column and row per in-line statement.
To get around this with my scenario, I can of course create 3 separate in-line statements, however, besides this seeming impractical, it increases the query time more that necessary.
SELECT
DATE_FORMAT(OrderDate,'%M %Y') AS OrderMonth,
COUNT(OrderID) AS TotalOrders,
SUM(OrderTotal) AS TotalAmount,
(SELECT SUM(OrderTotal) FROM Orders WHERE DATE_FORMAT(OrderDate,'%M %Y') = OrderMonth GROUP BY OrderCustomerFK ORDER BY SUM(OrderTotal) DESC LIMIT 1) AS TotalCustomerAmount,
(SELECT OrderCustomerFK FROM Orders WHERE DATE_FORMAT(OrderDate,'%M %Y') = OrderMonth GROUP BY OrderCustomerFK ORDER BY SUM(OrderTotal) DESC LIMIT 1) AS CustomerID,
(SELECT CustomerName FROM Orders INNER JOIN Customers ON OrderCustomerFK = CustomerID WHERE DATE_FORMAT(OrderDate,'%M %Y') = OrderMonth GROUP BY OrderCustomerFK ORDER BY SUM(OrderTotal) DESC LIMIT 1) AS CustomerName
FROM Orders
GROUP BY DATE_FORMAT(OrderDate,'%m%y')
ORDER BY DATE_FORMAT(OrderDate,'%y%m') DESC
How can i better structure this query?
FULL ANSWER
After some tweaking of Dave Barkers solution, I have a final version for anyone in the future looking for help.
The solution by Dave Barker worked perfectly with the customer details, however, it made the simpler Total Sales and Total Sale Amount columns get some crazy figures.
SELECT
Y.OrderMonth, Y.TotalOrders, Y.TotalAmount,
Z.OrdCustFK, Z.CustCompany, Z.CustOrdTotal, Z.CustSalesTotal
FROM
(SELECT
OrdDate,
DATE_FORMAT(OrdDate,'%M %Y') AS OrderMonth,
COUNT(OrderID) AS TotalOrders,
SUM(OrdGrandTotal) AS TotalAmount
FROM Orders
WHERE OrdConfirmed = 1
GROUP BY DATE_FORMAT(OrdDate,'%m%y')
ORDER BY DATE_FORMAT(OrdDate,'%Y%m') DESC)
Y INNER JOIN
(SELECT
DATE_FORMAT(OrdDate,'%M %Y') AS CustMonth,
OrdCustFK,
CustCompany,
COUNT(OrderID) AS CustOrdTotal,
SUM(OrdGrandTotal) AS CustSalesTotal
FROM Orders INNER JOIN CustomerDetails ON OrdCustFK = CustomerID
WHERE OrdConfirmed = 1
GROUP BY DATE_FORMAT(OrdDate,'%m%y'), OrdCustFK
ORDER BY SUM(OrdGrandTotal) DESC)
Z ON Z.CustMonth = Y.OrderMonth
GROUP BY DATE_FORMAT(OrdDate,'%Y%m')
ORDER BY DATE_FORMAT(OrdDate,'%Y%m') DESC
Move the inline SQL to be a inner join query. So you'd have something like...
SELECT DATE_FORMAT(OrderDate,'%M %Y') AS OrderMonth, COUNT(OrderID) AS TotalOrders, SUM(OrderTotal) AS TotalAmount, Z.OrderCustomerFK, Z.CustomerName, z.OrderTotal as CustomerTotal
FROM Orders
INNER JOIN (SELECT DATE_FORMAT(OrderDate,'%M %Y') as Mon, OrderCustomerFK, CustomerName, SUM(OrderTotal) as OrderTotal
FROM Orders
GROUP BY DATE_FORMAT(OrderDate,'%M %Y'), OrderCustomerFK, CustomerName ORDER BY SUM(OrderTotal) DESC LIMIT 1) Z
ON Z.Mon = DATE_FORMAT(OrderDate,'%M %Y')
GROUP BY DATE_FORMAT(OrderDate,'%m%y'), Z.OrderCustomerFK, Z.CustomerName
ORDER BY DATE_FORMAT(OrderDate,'%y%m') DESC
You can also do something like:
SELECT
a.`y`,
( SELECT #c:=NULL ) AS `temp`,
( SELECT #d:=NULL ) AS `temp`,
( SELECT
CONCAT(#c:=b.`c`, #d:=b.`d`)
FROM `b`
ORDER BY b.`uid`
LIMIT 1 ) AS `temp`,
#c as c,
#d as d
FROM `a`
Give this a shot:
SELECT CONCAT(o.order_month, ' ', o.order_year),
o.total_orders,
o.total_amount,
x.sum_order_total,
x.ordercustomerfk,
x.customername
FROM (SELECT MONTH(t.orderdate) AS order_month,
YEAR(t.orderdate) AS order_year
COUNT(t.orderid) AS total_orders,
SUM(t.ordertotal) AS total_amount
FROM ORDERS t
GROUP BY MONTH(t.orderdate), YEAR(t.orderdate)) o
JOIN (SELECT MONTH(t.orderdate) AS ordermonth,
YEAR(t.orderdate) AS orderyear
SUM(t.ordertotal) 'sum_order_total',
t.ordercustomerfk,
c.customername
FROM ORDERS t
JOIN CUSTOMERS c ON c.customerid = o.ordercustomerfk
GROUP BY t.ordercustomerfk, MONTH(t.orderdate), YEAR(t.orderdate)) x ON x.order_month = o.order_month
AND x.order_year = o.order_year
ORDER BY o.order_year DESC, o.order_month DESC