When trying to order with the query
SELECT ACTT
FROM AIKUcusSaatleri
ORDER BY ACTT
this function not working properly. The result is shown below;
ACTT
0
1040
1042,6
873,8
996,6
996,6
997,6
What is the reason of this problem?
Greetings and thanks in advance.
But these are ordered correctly . . . If you realize that they are strings.
Store numbers as numbers. If you want to sort strings as numbers, you need to convert them. You can try:
order by cast(actt as numeric(20, 2))
That may or may not work with the comma, depending on your database and internationalization settings. It should work if you replace the comma with a decimal point:
order by cast(replace(actt, ',', '.') as numeric(20, 2))
There is no function available with your code, order by is a clause & perhaps you need :
Assuming the SQL Server DBMS if so, then you can do :
SELECT ACTT
FROM AIKUcusSaatleri
ORDER BY LEFT(ACCT, CHARINDEX(',', ACTT)-1);
if , treat as decimal ., then you need to do conversations :
SELECT ACTT
FROM AIKUcusSaatleri
ORDER BY CAST(REPLACE(ACTT, ',', '.') AS NUMERIC(20, 2));
Related
i would make a script that iterate over the records of a table with a cursor
and extract from a column value formatted like that "yyy://xx/bb/147011"
only the final number 147011and to put this value in a variable.
It's possible to do something like that?
Many thanks.
You don't need a cursor for this. You can just use a query. The following gets everything after the last /:
select right(str, charindex('/', reverse(str)) - 1 )
from (values ('yyy://xx/bb/147011')) v(str)
It does not specifically check if it is a number, but that can be added as well.
You can also use the below query.
SELECT RIGHT(RTRIM('yyy://xx/bb/147011'),
CHARINDEX('/', REVERSE('/' + RTRIM('yyy://xx/bb/147011'))) - 1) AS LastWord
If numeric value has exact position defined with sample data, then you can do :
SELECT t.*, SUBSTRING(t.col, PATINDEX('%[0-9]%', t.col), LEN(t.col))
FROM table t;
this is how it is currently sorted:
CRI-SU1
CRI-SU10
CRI-SU11
CRI-SU2
CRI-SU3
CRI-SU4
CRI-SU5
CRI-SU6
CRI-SU7
CRI-SU8
CRI-SU9
I wanted it to be sorted numerically like:
CRI-SU1
CRI-SU2
CRI-SU3
CRI-SU4
CRI-SU5
CRI-SU6
CRI-SU7
CRI-SU8
CRI-SU9
CRI-SU10
CRI-SU11
How do you sort it in SQL?
this is my sql statement...
SELECT systemUnitID FROM systemUnit ORDER BY systemUnitID
If the prefix always reads "CRI-SU", you can try to replace it with the empty string by using replace(). Then cast the result to an integer with cast() and order by the casted value. This should work in many DBMS.
SELECT systemunitid
FROM systemunit
ORDER BY cast(replace(systemunitid, 'CRI-SU', '') AS integer);
SELECT systemUnitID
FROM systemUnit
ORDER BY CAST(REPLACE(systemUnitID, 'CRI-SU', '') As int)
I need to identify repeated numbers( Eg: 1111, 33333333, 5555555555,777777777 etc.) in a column.
How can I do this in sql server without having to hard code every scenario. The max length is 10 of the column. Any help is appreciated.
This will check if the column has all the same value in it.
SELECT *
FROM tablename
WHERE columnname = REPLICATE(LEFT(columnname,1),LEN(columnname))
As Nicholas Cary notes, if the column is numbers you'd need to cast as varchar first:
SELECT *
FROM tablename
WHERE CAST(columnname AS VARCHAR(10)) = REPLICATE(LEFT(CAST(columnname AS VARCHAR(10)),1),LEN(CAST(columnname AS VARCHAR(10))))
Riffing on #Dave.Gugg's excellent answer, here's another way, using patindex() to look for a character different than the first.
select *
from some_table t
where 0 = patindex( '[^' + left(t.some_column,1) + ']' , t.some_column )
Again, this only works for string types (char,varchar, etc.). Numeric types such as int will need to be converted first.
SQL SERVER 2005
SQL Sorting :
Datatype varchar
Should sort by
1.aaaa
5.xx
11.bbbbbb
12
15.
how can i get this sorting order
Wrong
1.aaaa
11.bbbbbb
12
15.
5.xx
On Oracle, this would work.
SELECT
*
FROM
table
ORDER BY
to_number(regexp_substr(COLUMN,'^[0-9]+')),
regexp_substr(column,'\..*');
You could do this by calculating a column based on what's on the left hand side of the period('.').
However this method will be very difficult to make robust enough to use in a production system, unless you can make a lot of assertions about the content of the strings.
Also handling strings without periods could cause some grief
with r as (
select '1.aaaa' as string
union select '5.xx'
union select '11.bbbbbb'
union select '12'
union select '15.' )
select *
from r
order by
CONVERT(int, left(r.string, case when ( CHARINDEX('.', r.string)-1 < 1)
then LEN(r.string)
else CHARINDEX('.', r.string)-1 end )),
r.string
If all the entries have this form, you could split them into two parts and sort be these, for example like this:
ORDER BY
CONVERT(INT, SUBSTRING(fieldname, 1, CHARINDEX('.', fieldname))),
SUBSTRING(fieldname, CHARINDEX('.', fieldname) + 1, LEN(fieldname))
This should do a numeric sort on the part before the . and an alphanumeric sort for the part after the ., but may need some tuning, as I haven't actually tried it.
Another way (and faster) might be to create computed columns that contain the part before the . and after the . and sort by them.
A third way (if you can't create computed columns) could be to create a view over the table that has two additional columns with the respective parts of the field and then do the select on that view.
i have to sum element in a column(SCENARIO1) that is varchar and contain data like (1,920, 270.00, 0, NULL) but when i try to convert data into int or decimal i get this error :
"he command is wrong when converting value "4582014,00" to int type"
here is my request :
select sum( convert( int, SCENARIO1) )
from Mnt_Scenario_Exercice where code_pere='00000000'
any help please
try this
select sum(cast(replace(SCENARIO1, ',', '.') as decimal(29, 10)))
from Mnt_Scenario_Exercice
where code_pere = '00000000';
If you couldn't convert your '4582014,00' into decimal, there's a chance you have different decimal separator on your server. You could look what it is or just try '.'
4582014,00 should be a decimal
try this (I assume that youre query is working) and changed convert(int into decimal)
select sum(convert(decimal(20,2),replace(SCENARIO1, ',', '.'))) from Mnt_Scenario_Exercice where code_pere='00000000'
The problem is due to the fact that the sum function isn't decoding SCENARIO1 as containing a CSV list of numbers. The way the sum function is usually used is to sum a lot of numbers drawn from multiple rows, where each row provides one number.
Try doing it in two steps. In step 1 convert the table into first normal form perhaps by UNPIVOTING. The 1NF table will have one number per row, and will contain more rows than the initial table.
The second step is to compute the sum. If you want more than one sum in the result, use GROUP BY to create groups, and then select a sum(somecolumn). This will yield one sum for each group.
Try this, I haven't got a way to test yet, but I will test and replace if incorrect.
SELECT sum(CAST (replace(SCENARIO1, ',', '') AS INT))
FROM Mnt_Scenario_Exercice
WHERE code_pere = '00000000';
EDIT: You can use a numeric for the cast if you need 4582014,00 to be 4582014.00
SELECT sum(CAST (replace(SCENARIO1, ',', '.') AS NUMERIC(10,2)))
FROM Mnt_Scenario_Exercice
WHERE code_pere = '00000000';