I am using SQL and currently have a large table that contains data for 1000's of accounts sorted by date:
ID July 2018 August 2018 September 2018 …
1 10 20 30
2 50 40 10
3 20 10 80
I need to reshape the table so the table is displayed like this:
ID Month Value
1 July 2018 10
1 August 2018 20
1 September 2018 30
: : :
I don't know how to do this or if this is even possible. I have tried to use the pivot function in SQL but I have not been successful. Is there a way to do this?
You can use APPLY :
SELECT t.id, tt.*
FROM table t CROSS APPLY
( VALUES ('July 2018', [July 2018]),
('August 2018', [August 2018]),
('September 2018', [September 2018])
) tt (Month, Val);
You can use unpivot - it will work in MSSQL
select t.id, up.months, up.value
from tablename t
unpivot
(
value
for months in ([July 2018], [August 2018], [September 2018])
) up;
You can try with the help of UNION operator:
select id, 'July 2018' as Month, July2018 as value from <table>
UNION
select id, 'August 2018' as Month, August2018 as value from <table>
UNION
select id, 'September 2018' as Month, September2018 as value from <table>
Related
I have a table of records like this:
Item
From
To
A
2018-01-03
2018-03-16
B
2021-05-25
2021-11-10
The output of select should look like:
Item
Month
Year
A
01
2018
A
02
2018
A
03
2018
B
05
2021
B
06
2021
B
07
2021
B
08
2021
Also the range should not exceed the current month. In example above we are asuming current day is 2021-08-01.
I am trying to do something similar to THIS with CONNECT BY LEVEL but as soon as I also select my table next to dual and try to order the records the selection never completes. I also have to join few other tables to the selection but I don't think that would make a difference.
I would very much appreciate your help.
Row generator it is, but not as you did it; most probably you're missing lines #11 - 16 in my query (or their alternative).
SQL> with test (item, date_from, date_to) as
2 -- sample data
3 (select 'A', date '2018-01-03', date '2018-03-16' from dual union all
4 select 'B', date '2021-05-25', date '2021-11-10' from dual
5 )
6 -- query that returns desired result
7 select item,
8 extract(month from (add_months(date_from, column_value - 1))) month,
9 extract(year from (add_months(date_from, column_value - 1))) year
10 from test cross join
11 table(cast(multiset
12 (select level
13 from dual
14 connect by level <=
15 months_between(trunc(least(sysdate, date_to), 'mm'), trunc(date_from, 'mm')) + 1
16 ) as sys.odcinumberlist))
17 order by item, year, month;
ITEM MONTH YEAR
----- ---------- ----------
A 1 2018
A 2 2018
A 3 2018
B 5 2021
B 6 2021
B 7 2021
B 8 2021
7 rows selected.
SQL>
Recursive CTEs are the standard SQL approach to this type of problem. In Oracle, this looks like:
with cte(item, fromd, tod) as (
select item, fromd, tod
from t
union all
select item, add_months(fromd, 1), tod
from cte
where add_months(fromd, 1) < last_day(tod)
)
select item, extract(year from fromd) as year, extract(month from fromd) as month
from cte
order by item, fromd;
Here is a db<>fiddle.
Sorry I couldn't make the question clearer, let me explain it here.
I have a table that has two columns:
year, ID
------------
2013, 01
2013, 27
2013, 33
2014, 22
2014, 33
2014, 01
2014, 13
2015, 45
2015, 13
2015, 22
What I want to do is the following: check all new IDs that appeared in 2014 from 2013, and all new IDs that appeared in 2015 from 2014, and so on and so forth...
So, from the example above, the expected answer to my query should be a table like:
year, new
-------------
2014, 2
2015, 1
Since in 2014 there are two new IDs in relation to 2013 (22 and 13), and in 2015 there is one new ID in relation to 2014 (45).
Sorry for the horrible formatting, I'm new to this site. Any help is appreciated, thanks.
If I understand correctly, you want lag():
select year, count(*)
from (select t.*, lag(year) over (partition by id order by year) as prev_year
from t
) t
where prev_year is null or prev_year < year - 1
group by year;
You need to find the all codes that didn't exist with a year y - 1 that shower at year y:
with cte as
(
select cast(2013 as int) as year, '01' as id
union select 2013, 27
union select 2013, 33
union select 2014, 22
union select 2014, 33
union select 2014, '01'
union select 2014, 13
union select 2015, 45
union select 2015, 13
union select 2015, 22
)
select year, count(*) from cte a where not exists(select 1 from cte b where a.year -1 = b.year and a.id = b.id)
and a.year -1 in (select distinct year from cte)
group by year
I have data in the following format.
order_no rate jan feb mar ....
1 1200 2 4
2 1000 1 5
3 2400 14 3
Now I want to transpose this table to get the following output.
order_no rate month unit
1 1200 feb 2
1 1200 mar 4
2 1000 jan 1
2 2400 mar 5 and so on..
How can I do this?
You can create a "temporary" normalized view on the data using a cross join:
select o.order_no, o.rate, v.*
from orders o
cross join lateral (
values
('jan', jan),
('feb', feb),
('mar', mar),
...
('dec', dec)
) as v(month, unit)
If you want to exclude the months with no values, you can add
where v.unit is not null
to the query
Online example: http://rextester.com/PBP46544
One simple approach uses UNION:
SELECT order_no, rate, 'jan' AS month, jan AS unit UNION ALL
SELECT order_no, rate, 'feb', feb UNION ALL
...
SELECT order_no, rate, 'dec', dec
ORDER BY order_no;
Postgres also has CROSSTAB capabilities. But to use that, you have to be really good at SQL, which I'm not.
Try this
Select order_no, rate, 'jan' as month, jan as unit
from tbl
where jan is not null
union all
Select order_no, rate, 'feb' as month, feb as unit
from tbl
where feb is not null
union all
Select order_no, rate, 'mar' as month, mar as unit
from tbl
where mar is not null
order by order_no
This question already has answers here:
Unpivot with column name
(3 answers)
SQL Unpivot multiple columns Data
(3 answers)
Closed 5 years ago.
I have data like below:
Year January Feb March April
2017 20 15 7 25
Is it possible to format the data to
Year Month Value
- 2017 January 20
- 2017 Feb 15
- 2017 March 7
- 2017 April 25
Thanks a lot for your help. I have been trying to achive this for hours but I am not able to.
This is unpivot, but I prefer using apply:
select v.*
from t outer apply
(values (t.year, 'January', t.January),
(t.year, 'Feb', t.Feb),
(t.year, 'March', t.March),
(t.year, 'April', t.April)
) v(year, month, value);
apply implements something called a "lateral join". This is a lot like a correlated subquery that can return multiple columns. Lateral joins are very powerful -- unpivoting is just the beginning of what they do. But unpivoting is one way to start learning about them.
You can use UNPIVOT for this.
DECLARE #T TABLE (Year INT, January INT, Feb INT, March INT, April INT)
INSERT INTO #T VALUES(2017,20,15,7,25)
SELECT [Year], [Month], [Value] FROM #T
UNPIVOT( [Value] FOR [Month] IN( [January], [Feb], [March], [April] ) ) AS UNPVT
Result
Year Month Value
----------- ----------- -----------
2017 January 20
2017 Feb 15
2017 March 7
2017 April 25
I need to get records based on project and year
SELECT
*
FROM
(SELECT
Source,
val,
month
FROM
tbl_OrganicResult
CROSS APPLY
(VALUES ('visitors', visitors),
('UniqueVisitors', UniqueVisitors),
('ReturnVisitors', ReturnVisitors)) cs (Source, val)) A
PIVOT (Max(val)
FOR month IN ([jun], [jul)) pv
I need the records with where condition like
select *
from tbl_OrganicResult
where project = 'Homeocare'
Sample data
ProjectName Month Year visitors UniqueVisitors ReturnVisitors
Homeocare Jun 2015 400 33 22
Homeocare Jul 2015 100 10 8
debug test. Aug 2015 15222 122 120
debug test. Jun. 2015 1500 150 15
debug test. Jul 2015 1400 140 14
I'm getting records like this which is not correct, I mean I'm not getting project wise.
How to add where condition to get like where project - 'homeocare' ?
Getting output like this
Source jun jul
ReturnVisitors 8 120
UniqueVisitors 10 122
Visitors 100 15222
I need records like this
Source jun jul
ReturnVisitors. 22 8
UniqueVisitors. 33 10
Visitors 400 100
Sorry for my mistake of giving wrong data (earlier). Here always getting last 2 records and not used where condition to get records project and year wise.
The where clause should go after the cross apply like this:
SELECT
*
FROM
(
SELECT
Source,
val,
Year,
month
FROM
tbl_OrganicResult
CROSS APPLY
(VALUES ('visitors', visitors),
('UniqueVisitors', UniqueVisitors),
('ReturnVisitors', ReturnVisitors)) cs (Source, val)
WHERE ProjectName = 'Homeocare'
) A
PIVOT ( Max(val) FOR Month IN ([jun], [jul]) ) pv
Unless you only have data for one year in your table this query will get you the max value for a month from any year where you have data recorded for that month, for example if you had 100 visitors in June 15 and 200 visitors in June 14 then the value for June 14 would be selected. This might not be what you want.
I would consider doing something like this instead:
SELECT
Source, [Jun-2015], [Jul-2015]
FROM
(
SELECT
Source,
Val,
MonthYear = CONCAT(Month,'-',Year)
FROM
tbl_OrganicResult
CROSS APPLY
(VALUES ('Visitors', visitors),
('UniqueVisitors', UniqueVisitors),
('ReturnVisitors', ReturnVisitors)) cs (Source, Val)
WHERE ProjectName = 'Homeocare'
) A
PIVOT ( MAX(Val) FOR MonthYear IN ([Jun-2015], [Jul-2015]) ) pv ;
in your case you have three months but you are looking for july in place of june and August in place of july just add alias names for those columns
declare #table table (ProjectName varchar(20), Month varchar(20), Year varchar(20), visitors INT, UniqueVisitors INT, ReturnVisitors INT)
insert into #table (ProjectName,Month,Year,visitors,UniqueVisitors,ReturnVisitors)values
('Homeocare' , 'Jun' , 2015 , 400 , 33 , 22),
('Homeocare' , 'Jul' , 2015 , 100 , 10 , 8),
('debug test', 'Aug' , 2015 , 15222 , 122 , 120 )
SELECT source,JUN as Jul,jul as aug FROM (SELECT Source,
val,
month
FROM #table
CROSS apply (VALUES ('visitors',visitors),
('UniqueVisitors',UniqueVisitors),
('ReturnVisitors',ReturnVisitors)) cs (Source, val)) A
PIVOT (max(val)
FOR month IN ([jun],[Jul],
[Aug])) pv