Dividing a fixed number over multiple rows by weight - sql

Question

So I have a table that has this structure:
Id - Team - User - Weight
For example: In a team we have the goal to reach 500 calls, so I'd have to spread the 500 calls by weight over each user in the team so I get this structure returned:
Id - Team - User - Weight - # Calls to be made
I know I can do this with a OVER(partition by) and that works perfectly, except for one little detail, there's no way to make half a call.
I'd need this distribution to be without commas.
The basic query:
select Id,Team,User,Weight from CallList
4 ED PEDRO 1
5 RE PEDRO 1
6 PO ROOEIC 0,5
7 PO ROOEIC01 0,5
1 AP APSYSL 0,333333333333333
2 AP APSYSL01 0,333333333333333
3 AP APSYSL02 0,333333333333333
And this is what I would want returned
4 ED PEDRO 1 500
5 RE PEDRO 1 500
6 PO ROOEIC 0,5 250
7 PO ROOEIC01 0,5 250
1 AP APSYSL 0,333333333333333 167
2 AP APSYSL01 0,333333333333333 167
3 AP APSYSL02 0,333333333333333 166

Answer 1

This is an arithmetic problem. The idea is to get a "base" value for each id in a team. Then calculate the excess and incrementally add the excess.
select t.*,
(start_value +
(case when row_number() over (partition by team order by id) <= excess
then 1 else 0
end)
) as calls
from (select t.*,
floor(weight * 500) as start_value,
500 - sum(floor(weight * 500)) over (partition by team) as excess
from t
) t;
This adds the excess from the first row. You seem to want it from the last row. You can achieve that using order by id desc in the row_number().

Answer 2

Simplifying Gordon's logic to remove the Derived Table:
SELECT *
,floor(500 * weight) -- always <= 500
+ CASE -- check if there's a remainder n, if yes split it across n rows
WHEN COUNT(*) -- get a (kind of) random row, using row_number/order you might define a specific row
OVER (PARTITION BY Team
ROWS UNBOUNDED PRECEDING)
<= (500 - SUM(floor(500*weight)) -- remainder calculation
OVER (PARTITION BY Team))
THEN 1
ELSE 0
END
FROM CallList