UPDATE 1
I removed return from code and now links work on IOS.
But on android I can't open any app. Any idea?
I am trying to open different apps from my app.
return Linking.openURL(“twitter://“);
return Linking.openURL(“instagram://“);
But it doesn’t work. I configured IOS by documentation. On android doesn’t work too. While...
return Linking.openURL(“tripadvisor://“);
Work just fine.
Any idea why I can’t open other apps.
This is code that I am using (open app if installed or open store with it but sometimes even store doesn't open) what I did wrong:
let appUrl = "instagram://";
Linking.canOpenURL(appUrl).then(supported => {
if (!supported) {
Alert.alert("",
"",
[
{text: "go to store", onPress: this.openStorePress},
{text: "cancel", onPress: () => { }, style: 'cancel'},
],
{ cancelable: false }
);
} else {
return Linking.openURL(appUrl);
}
}).catch(err => {
console.error(err);
});
Your issue is related to the content of the url, twitter:// means nothing for the Android Twitter app, so it will not open.
For example, the following code should work:
Linking.openURL('twitter://timeline')
or
Linking.openURL('instagram://user?username=apple')
You have to find the rights url schemes (documentations are not very clear about it) that may be different between iOS and Android.
Twitter: How can I open a Twitter tweet using the native Twitter app on iOS?
Instagram: https://www.instagram.com/developer/mobile-sharing/iphone-hooks/ (all do not work on Android)
misc: https://pureoxygenlabs.com/10-app-url-schemes-for-marketers/
You have to find the rights URL schemes. Have look at my code
Instagram
Linking.openURL('instagram://user?username=apple')
.catch(() => {
Linking.openURL('https://www.instagram.com/apple');
})
Twitter
Linking.openURL('twitter://user?screen_name=apple')
.catch(() => {
Linking.openURL('https://www.twitter.com/apple');
})
Facebook
Linking.openURL('fb://page/PAGE_ID');
Linking.openURL('http://instagram.com/_u/USER_NAME');
Linking.openURL('http://instagram.com/_p/PICTURE');
Your code looks pretty solid, here's an example of how I open twitter in my app.
const twitterUrlScheme = `twitter://user?screen_name=${twitterUsername}`;
Linking.canOpenURL(twitterUrlScheme)
.then((supported) =>
Linking.openURL(
supported
? twitterUrlScheme
: `https://www.twitter.com/${twitterUsername}`
)
)
.catch((err) => console.error('An error occurred', err));
I think perhaps your issue might be the return Linking.openUrl, I'm not sure you need the return in that statement. Does it work if you remove the return? Otherwise, it might help to move your Alert outside of the then-block from canOpenUrl.
I have used only url and it's working both iOS and android
Linking.openURL('https://www.facebook.com/');
You haven't completed the " fot twitter and instagram, I don't know whether you made the same mistake in app too, if yes, fixing that might solve it.
Try to use a package like:
https://github.com/react-native-community/react-native-share
You can try to use only some of it's functions or look into the native code from there and create some bridge functions in the native code and then export them to be used in JS code.
Note: you will have to use real devices for the tests.
Related
So I added onesignal-expo-plugin and react-native-onesignal to my project, I made everything what was wrote on the website
After this i made a developmen-simulator build for my app
I tested the app on IOS and on Android too, on android i get the notification instantly but on IOS i'm not.
So i checked the notification report on OneSignal dashboard and the ios fall into failed. I checked everything, I added everything what i had to, the p12 file is correct, I did everything multiple times before i write here,
I haven't ejected my ios app because I want to keep expo managing my ios/android application well.
What should I try to fix this issue?
Android works correctly but ios don't and I really need your help!
The in-app message works correctly just the push notification don't
Versions:
"react-native-onesignal": "^4.5.0",
"onesignal-expo-plugin": "^1.3.0",
I don't want to eject my ios code and I saw too many articles and videos how others use it and works. Please help me whats wrong.
My code example what I tried just now:
const initialOnesignal = async () => {
OneSignal.setAppId('HIDEN FOR STACKOVERFLOW');
OneSignal.promptForPushNotificationsWithUserResponse();
OneSignal.setNotificationWillShowInForegroundHandler(
notificationReceivedEvent => {
console.log(
'OneSignal: notification will show in foreground:',
notificationReceivedEvent,
);
let notification = notificationReceivedEvent.getNotification();
console.log('notification: ', notification);
const data = notification.additionalData;
console.log('additionalData: ', data);
notificationReceivedEvent.complete(notification);
},
);
OneSignal.setNotificationOpenedHandler(notification => {
console.log('OneSignal: notification opened:', notification);
});
};
And I also tried this way:
useEffect(() => {
OneSignal.setAppId('HIDEN FOR STACKOVERFLOW');
OneSignal.promptForPushNotificationsWithUserResponse(response => {
console.log('Prompt response:', response);
});
OneSignal.setNotificationWillShowInForegroundHandler(
notificationReceivedEvent => {
console.log(
'OneSignal: notification will show in foreground:',
notificationReceivedEvent,
);
let notification = notificationReceivedEvent.getNotification();
console.log('notification: ', notification);
const data = notification.additionalData;
console.log('additionalData: ', data);
// Complete with null means don't show a notification.
notificationReceivedEvent.complete(notification);
},
);
OneSignal.setNotificationOpenedHandler(notification => {
console.log('OneSignal: notification opened:', notification);
});
}, []);
Tried to only add my AppId as well. I guess i tried everyting.
I have tried to regenerate p12 file, try multiple code examples, run on simultaor and on device too.
Tried to use useEffect and simple function as well.
According to expos documentation, if I want user to navigate to another screen after user taps the notification received I should use deep linkedin. thats also the suggested method in all similar posts Ive seen. In my case I just do the following:
useEffect(()=> {
responseListener.current = Notifications.addNotificationResponseReceivedListener(response => {
if (response) {
navigation.navigate("Page 1")
}
});
}, [])
It works fine, when I have app open or closed. I wonder if I just dont understand something and there will be issues as everywhere I read deep linking. Thanks!
I am trying to detect if a user takes a screenshot while using a smartphone app that I have built. I am building my project with React Native.
I have been told that I can possibly prevent screenshots for Android but not for iOS. but can I still detect whether a user attempts to take a screenshot so that I can at least send a warning via Alert?
Thanks in advance
I tried react-native-screenshot-detector but it did not work
you can use this package it supports android&ios screenshot detecting react-native-detector
import {
addScreenshotListener,
removeScreenshotListener,
} from 'react-native-detector';
// ...
React.useEffect(() => {
const userDidScreenshot = () => {
console.log('User took screenshot');
};
const listener = addScreenshotListener(userDidScreenshot);
return () => {
removeScreenshotListener(listener);
};
}, []);
There is no package for it currently.
I'm using Dyson to host a little mock server for my React Native app, and trying to fetch from the server. The server appears to be running well and when I visit my desired url, http://localhost:3000/stations, in my browser, I get a nice JSON response.
In my React Native action, though, I get Network request failed:
export function fetchStations() {
return dispatch => {
dispatch({ type: "GET_STATIONS_START" });
fetch("http://localhost:3000/stations")
.then(res => {
return res.json();
})
.then(json => {
dispatch({ type: "GET_STATIONS_SUCCESS", payload: json.stations });
})
.catch(error => {
console.warn(error);
dispatch({ type: "GET_STATIONS_FAILURE", payload: error });
});
};
}
Using a static local URL works, and using, say, the Google Maps API works (even though it's not what I want, it's just a sample API to try).
I would think I may be calling the url wrong but it works in the browser so that seems doubtful. My guess is that is has something to do with iOS not liking http requests (only accepting https), unless you set some setting somewhere (I've been through this in native iOS development).
If this is the problem, how do I fix it from React Native? Or, what is the actual problem?
PS. I'm using dyson rather than json-server because for some reason I can't get json-server to work. See my other post. Somewhere here :)
I figured it out. The device (simulator) doesn't have access to localhost so I had to set my url to http://127.0.0.1:3000/stations and it works like a dream.
I want to be able to open Skype with a call setup with a specific username from my react-native app. I had planned to use linking to do this, For example:
onLaunchPress = () => {
const { user } = this.props
Linking.openURL('https://skype.com/' + user)
.catch((error) => console.log(error))
})
This is not enough to add the correct query parameters, However I am unable to view the documentation on this as the page doesn't load here:
https://dev.skype.com/skype-uri
Any advice would be greatly appreciated, I am also concerned as to whether this is actually possible given what is posted here:
https://answers.microsoft.com/en-us/skype/forum/skype_web-skype_messms-skype_instamessms/open-skype-for-web-from-a-react-native-app/eef6a4c6-6b05-4566-b9e1-2f13f9d05606
According to this, you should be able to open Skype with the following:
Linking.openUrl('skype:');
You should also be able to pass the User in too with:
Linking.openUrl(`skype:${user}`);