How to get previous 7 days' data from today in SQL Server - sql

Question

I have a DataEntry Table called GuestAddressData(UserId INT, EDate DateTime) with users data. I need to fetch the count of users for today to previous 7 Days. My Query:
SELECT
row_number() over (order by (SELECT 1)) ID,
count(*) Total,
LEFT(Datename(weekday, Cast(EDate as date)), 3) Day
FROM
CRM0001GuestAddressData
WHERE
EDate >= dateadd(week, datediff(d, -1, getdate()-2)/7, -1)
GROUP BY
Cast(EDate as date)
ORDER BY
Cast(EDate as date)
For example if today is Friday then my expected output is:
ID | TOTAL | DAY
------------------------
1 | 78 | Sat
2 | 23 | Sun
3 | 54 | Mon
4 | 17 | Tues
5 | 56 | Wed
6 | 45 | Thus
7 | 78 | Fri - Today
but this is not correct. How to solve it?

Answer 1

You can "generate" a list of seven numbers and use it to build the desired dates. Then left join with your data to get the counts, including zeros:
WITH datelist(num, a, b) AS (
SELECT num, DATEADD(DAY, -num, CAST(CURRENT_TIMESTAMP AS DATE)), DATEADD(DAY, -num + 1, CAST(CURRENT_TIMESTAMP AS DATE))
FROM (VALUES (0), (1), (2), (3), (4), (5), (6)) AS v(num)
)
SELECT 7 - num AS ID, datelist.a AS Day, COUNT(IDBooking)
FROM datelist
LEFT JOIN T_Bookings ON Opened >= datelist.a AND Opened < datelist.b
GROUP BY datelist.a, datelist.num
ORDER BY datelist.a

Answer 2

SELECT
row_number() over (order by dDate) ID,
cnt,
LEFT(Datename(weekday, dDate), 3) Day
from
(Select cast(EDate as Date) as dDate,
count(*) as cnt
FROM (values (0),(1),(2),(3),(4),(5),(6)) t(v)
inner join
CRM0001GuestAddressData gd on datediff(d, gd.Edate, getdate()) = t.v
WHERE
EDate >= dateadd(d, -6, cast(getdate() as date)) and EDate < dateadd(d,1,cast(getdate() as date))
GROUP BY
Cast(EDate as date)) tmp;
Note: You meant to get 7 days from yesterday, right? Nevermind, corrected based on your sample.
DBFiddle demo
EDIT: Having all days:
SELECT
row_number() over (order by dDate) ID,
cnt,
LEFT(Datename(weekday, dDate), 3) Day
from
(Select dateadd(d,-v,cast(getdate() as date)) as dDate,
count(Edate) as cnt
FROM (values (0),(1),(2),(3),(4),(5),(6)) t(v)
left join
CRM0001GuestAddressData gd on Datediff(d,gd.EDate, getdate()) = t.v
GROUP BY
dateadd(d,-v,cast(getdate() as date))) tmp;
DBFiddle Demo