I have a table which contains Students Attendance, the schema is
StudentId ClassId EventType EventTime
1 1 I 2018-10-31 07:00:00 AM
2 1 I 2018-10-31 07:02:00 AM
1 1 O 2018-10-31 07:31:00 AM
3 1 I 2018-10-31 07:45:00 AM
OutPut
ClassId StudentCount StartTime EndTime
1 2 2018-10-31 07:00:00 AM 2018-10-31 07:10:00 AM
1 2 2018-10-31 07:10:01 AM 2018-10-31 07:20:00 AM
1 2 2018-10-31 07:20:01 AM 2018-10-31 07:30:00 AM
1 1 2018-10-31 07:30:01 AM 2018-10-31 07:40:00 AM
1 2 2018-10-31 07:40:01 AM 2018-10-31 07:50:00 AM
You need to generate the times. One way uses a recursive CTE. Then there are various ways to get the count.
with times as (
select cast('2018-10-31 07:00:00' as datetime) dt
union all
select dateadd(minute, 10, dt)
from times
where dateadd(minute, 10, dt) < '2018-10-31 08:00:00'
)
select t.dt,
(select sum(case when eventtype = 'I' then 1 else -1 end)
from attendance a
where a.EventTime <= t.dt
) as attendance
from times;
Related
So my data looks like this:
DATE TEMPERATURE
2012-01-13 23:15:00 UTC 0
2012-01-14 01:35:00 UTC 5
2012-01-14 02:15:00 UTC 6
2012-01-14 03:15:00 UTC 8
2012-01-14 04:15:00 UTC 0
2012-01-14 04:55:00 UTC 0
2012-01-14 05:15:00 UTC -2
2012-01-14 05:35:00 UTC 0
I am trying to calculate the amount of time a zip code temperature will drop to 0 or below on any given day. On the 13th, it only happens for a very short amount of time so we don't really care. I want to know how to calculate the number of minutes this happens on the 14th, since it looks like a significantly (and consistently) cold day.
I want the query to add two more columns.
The first column added would be the time difference between the rows on a given date. So row 3- row 2=40 mins and row 4-row3=60 mins.
The second column would total the amount of minutes for a whole day the minutes the temperature has dropped to 0 or below. Here row 2-4 would be ignored. From row 5-8, total time that the temperature was 0 or below would be about 90 mins
It should end up looking like this:
DATE TEMPERATURE MINUTES_DIFFERENCE TOTAL_MINUTES
2012-01-13 23:15:00 UTC 0 0 0
2012-01-14 01:35:00 UTC 5 140 0
2012-01-14 02:15:00 UTC 6 40 0
2012-01-14 03:15:00 UTC 8 60 0
2012-01-14 04:15:00 UTC 0 60 60
2012-01-14 04:55:00 UTC 0 30 90
2012-01-14 05:15:00 UTC-2 20 110
2012-01-14 05:35:00 UTC 0 20 130
Use below
select *,
sum(minutes_difference) over(order by date) total_minutes
from (
select *,
ifnull(timestamp_diff(timestamp(date), lag(timestamp(date)) over(order by date), minute), 0) as minutes_difference
from your_table
)
if applied to sample data in your question - output is
Update to answer updated question
select * except(new_grp, grp),
sum(if(temperature > 0, 0, minutes_difference)) over(partition by grp order by date) total_minutes
from (
select *, countif(new_grp) over(order by date) as grp
from (
select *,
ifnull(timestamp_diff(timestamp(date), lag(timestamp(date)) over(order by date), minute), 0) as minutes_difference,
ifnull(((temperature <= 0) and (lag(temperature) over(order by date) > 0)) or
((temperature > 0) and (lag(temperature) over(order by date) <= 0)), true) as new_grp
from your_table
)
)
with output
I have a table that is currently in the following format
ID
Title
CreatedOn
1
Test 1
2021-04-26 08:00:00
2
Test 2
2021-04-26 10:00:00
3
Test 3
2021-04-27 09:00:00
4
Test 4
2021-04-28 14:00:00
5
Test 5
2021-04-28 16:00:00
6
Test 6
2021-04-28 12:00:00
7
Test 7
2021-04-29 13:00:00
8
Test 8
2021-04-30 06:00:00
9
Test 9
2021-05-17 10:00:00
10
Test 10
2021-05-18 19:00:00
11
Test 11
2021-05-18 23:00:00
12
Test 12
2021-05-19 16:00:00
13
Test 13
2021-05-20 07:00:00
14
Test 14
2021-05-21 14:00:00
15
Test 15
2021-05-21 10:00:00
16
Test 16
2021-04-30 10:00:00
What I would like to do is a query that would tell me how many requests have been Monday to Friday per hour. So aggregate all the data into just rows of Monday to Friday.
So the query should return
Day
Hour
Count
Monday
08:00
1
Monday
10:00
2
Tuesday
10:00
1
Tuesday
19:00
1
Tuesday
23:00
1
Wednesday
14:00
1
Wednesday
16:00
2
Wednesday
12:00
1
etc.. How do I achieve this?
So far I have the following
SELECT
DATENAME(WEEK, CreatedOn) AS Week,
DATEPART(Hour, CreatedOn) AS Hour,
COUNT(*) AS Requests
FROM [Enterprise32].[dbo].[nav_EmailEstimateRequests]
where CreatedOn > '2021-01-01'
GROUP BY DATENAME(WK, CreatedOn),DATEPART(Hour, CreatedOn)
ORDER BY DATENAME(WK, CreatedOn);
But the above query returns each week so Week 1 up until Week 21. Please guide me in the right direction.
Thank you!
You want weekday for the date part:
SELECT DATENAME(WEEKDAY, CreatedOn) AS Weekday,
DATEPART(Hour, CreatedOn) AS Hour,
COUNT(*) AS Requests
FROM [Enterprise32].[dbo].[nav_EmailEstimateRequests]
WHERE CreatedOn > '2021-01-01'
GROUP BY DATENAME(WEEKDAY, CreatedOn), DATEPART(Hour, CreatedOn), DATEPART(WEEKDAY, CreatedOn)
ORDER BY DATEPART(WEEKDAY, CreatedOn), Hour;
Note: I included DATEPART(weekday, ) in the GROUP BY, so you could use it in the ORDER BY.
I am trying to collapse data that is in a sequence sorted by date. While grouping on the person and the type.
The data is stored in an SQL server and looks like the following -
seq person date type
--- ------ ------------------- ----
1 1 2018-02-10 08:00:00 1
2 1 2018-02-11 08:00:00 1
3 1 2018-02-12 08:00:00 1
4 1 2018-02-14 16:00:00 1
5 1 2018-02-15 16:00:00 1
6 1 2018-02-16 16:00:00 1
7 1 2018-02-20 08:00:00 2
8 1 2018-02-21 08:00:00 2
9 1 2018-02-22 08:00:00 2
10 1 2018-02-23 08:00:00 1
11 1 2018-02-24 08:00:00 1
12 1 2018-02-25 08:00:00 2
13 2 2018-02-10 08:00:00 1
14 2 2018-02-11 08:00:00 1
15 2 2018-02-12 08:00:00 1
16 2 2018-02-14 16:00:00 3
17 2 2018-02-15 16:00:00 3
18 2 2018-02-16 16:00:00 3
This data set contains about 1.2 million records that resemble the above.
The result that I would like to get from this would be -
person start type
------ ------------------- ----
1 2018-02-10 08:00:00 1
1 2018-02-20 08:00:00 2
1 2018-02-23 08:00:00 1
1 2018-02-25 08:00:00 2
2 2018-02-10 08:00:00 1
2 2018-02-14 16:00:00 3
I have the data in the first format by running the following query -
select
ROW_NUMBER() OVER (ORDER BY date) AS seq
person,
date,
type,
from table
group by person, date, type
I am just not sure how to keep the minimum date with the other distinct values from person and type.
This is a gaps-and-islands problem so, you can use differences of row_number() & use them in grouping :
select person, min(date) as start, type
from (select *,
row_number() over (partition by person order by seq) seq1,
row_number() over (partition by person, type order by seq) seq2
from table
) t
group by person, type, (seq1 - seq2)
order by person, start;
The correct solution using the difference of row numbers is:
select person, type, min(date) as start
from (select t.*,
row_number() over (partition by person order by seq) as seqnum_p,
row_number() over (partition by person, type order by seq) as seqnum_pt
from t
) t
group by person, type, (seqnum_p - seqnum_pt)
order by person, start;
type needs to be included in the GROUP BY.
I need help with a problem. Actually, I do not know if it will be possible to solve it directly in SQL.
I have a list of works. Each work has a start date and ending date, with this format
YYYY/MM/DD HH24:MI:SS
I need to calculate the cost of those jobs, the hour price depends on the time intervals in which the work has been done:
Nigth time: 22:00 to 6:00, for example: 20 €/h
Normal time: the rest 17 €/h
So, if I have a sample like this:
wo start end
21 2017/11/16 21:25:00 2017/11/16 22:55:00
22 2017/11/17 05:45:00 2017/11/17 07:05:00
23 2017/11/18 23:00:00 2017/11/19 1:10:00
24 2017/11/17 18:00:00 2017/11/17 19:00:00
I would need to calculate the intervals of the dates between the 22h and 6h and the rest to multiply them by their corresponding price
wo rest(minutes) night(minutes)
21 35 55
22 15 65
23 0 130
24 1 0
Thank for your help in advance.
Heh. If you really wish it :)
Fifth record (started at 2016-10-30) had been added for testing purposes.
SQL> with
2 src as (select timestamp '2017-11-16 21:25:00' b, timestamp '2017-11-16 22:55:00' f from dual union all
3 select timestamp '2017-11-17 05:45:00' b, timestamp '2017-11-17 07:05:00' f from dual union all
4 select timestamp '2017-11-18 23:00:00' b, timestamp '2017-11-19 1:10:00' f from dual union all
5 select timestamp '2017-11-17 18:00:00' b, timestamp '2017-11-17 19:00:00' f from dual union all
6 select timestamp '2016-10-30 00:00:00' b, timestamp '2016-11-03 23:00:00' f from dual),
7 srd as (select b, f, f - b t from src),
8 mmm as (select min(trunc(b)) b, max(trunc(f)) f from src),
9 rws as (select b + 6/24 + rownum - 1 b, b + 22/24 + rownum - 1 f from mmm connect by level <= f - b + 1),
10 mix as (select s.b, s.f, s.t, r.b rb, r.f rf from srd s, rws r where s.f >= r.b (+) and r.f (+) >= s.b),
11 clc as (select b, f, t, nvl(numtodsinterval(sum((least(f, rf) + 0) - (greatest(b, rb) + 0)), 'DAY'), interval '0' second) d from mix group by b, f, t)
12 select
13 to_char(b, 'dd.mm.yyyy hh24:mi') as "datetime begin",
14 to_char(f, 'dd.mm.yyyy hh24:mi') as "datetime finish",
15 cast(t as interval day to second(0)) as "total time",
16 cast(d as interval day to second(0)) as "daytime",
17 cast(t - d as interval day to second(0)) as "nighttime"
18 from
19 clc
20 order by
21 1, 2;
datetime begin datetime finish total time daytime nighttime
------------------ ------------------ -------------- -------------- --------------
16.11.2017 21:25 16.11.2017 22:55 +00 01:30:00 +00 00:35:00 +00 00:55:00
17.11.2017 05:45 17.11.2017 07:05 +00 01:20:00 +00 01:05:00 +00 00:15:00
17.11.2017 18:00 17.11.2017 19:00 +00 01:00:00 +00 01:00:00 +00 00:00:00
18.11.2017 23:00 19.11.2017 01:10 +00 02:10:00 +00 00:00:00 +00 02:10:00
30.10.2016 00:00 03.11.2016 23:00 +04 23:00:00 +03 08:00:00 +01 15:00:00
A different approach is more brute force one, but it allows to distinct the interval configuration from the reporting.
It goes in three stept:
1) define the rate type for aech minute of the day (change the granularity if required)
create table day_config as
with helper as (
select
rownum -1 minute_id
from dual connect by level <= 24*60),
helper2 as (
select
minute_id,
trunc(minute_id/60) hour_no,
mod(minute_id,60) minute_no
from helper)
select
minute_id,hour_no, minute_no,
case when hour_no >= 22 or hour_no <= 5 then 0 else 1 end rate_id
from helper2;
select * from day_config order by minute_id;
MINUTE_ID HOUR_NO MINUTE_NO RATE_ID
---------- ---------- ---------- ----------
0 0 0 0
1 0 1 0
2 0 2 0
3 0 3 0
4 0 4 0
5 0 5 0
6 0 6 0
7 0 7 0
8 0 8 0
9 0 9 0
Here rate_id means nigth, rate_id 1 means a day.
Advantage is, that you can introduce as much rate types as required.
2) expand the configuration for the required interval e.g. to whole year.
So now we have for each minute of the year the configuration, which rate is to be applied.
create or replace view year_config as
select my_date + MINUTE_ID / (24*60) minute_ts , MINUTE_ID, HOUR_NO, MINUTE_NO, RATE_ID from day_config
cross join
(select DATE '2017-01-01' + rownum -1 as my_date from dual connect by level <= 365)
order by 1,2;
select * from (
select * from year_config
order by 1)
where rownum <= 5;
MINUTE_TS MINUTE_ID HOUR_NO MINUTE_NO RATE_ID
------------------- ---------- ---------- ---------- ----------
01-01-2017 00:00:00 0 0 0 0
01-01-2017 00:01:00 1 0 1 0
01-01-2017 00:02:00 2 0 2 0
01-01-2017 00:03:00 3 0 3 0
01-01-2017 00:04:00 4 0 4 0
3) the reporting is as easy as joining to our config table constraining the interval (half open) and grouping in the RATE.
select b, f,RATE_ID, count(*) minute_cnt
from tst join year_config c on c.MINUTE_TS >= tst.b and c.MINUTE_TS < tst.f
group by b, f,RATE_ID
order by b, f,RATE_ID;
B F RATE_ID MINUTE_CNT
------------------- ------------------- ---------- ----------
16-11-2017 21:25:00 16-11-2017 22:55:00 0 55
16-11-2017 21:25:00 16-11-2017 22:55:00 1 35
17-11-2017 05:45:00 17-11-2017 07:05:00 0 15
17-11-2017 05:45:00 17-11-2017 07:05:00 1 65
17-11-2017 18:00:00 17-11-2017 19:00:00 1 60
18-11-2017 23:00:00 19-11-2017 01:10:00 0 130
The easiest way is probably to get all minutes worked in a recursive WITH clause and then see in which time range the minutes fall. As Oracle doesn't have a TIME datatype unfortunately, we'll have to work with times strings ('00'00' till '23:59').
with shifts as
(
select 'night' as shift, '00:00' as starttime, '05:59' as endtime, 20 as cost from dual
union all
select 'normal' as shift, '06:00' as starttime, '21:59' as endtime, 17 as cost from dual
union all
select 'night' as shift, '22:00' as starttime, '23:59' as endtime, 20 as cost from dual
)
, workminutes(wo, workminute, thetime, endtime) as
(
select wo, to_char(starttime, 'hh24:mi') as workminute, starttime as thetime, endtime
from mytable
union all
select
wo,
to_char(thetime + interval '1' minute, 'hh24:mi') as workminute,
thetime + interval '1' minute as thetime,
endtime
from workminutes
where thetime + interval '1' minute < endtime
)
select
wo,
count(case when s.shift = 'normal' then 1 end) as normal_time,
coalesce(sum(case when m.workminute between '06:00' and '21:59' then s.cost end), 0)
as normal_cost,
count(case when s.shift = 'night' then 1 end) as night_time,
coalesce(sum(case when m.workminute not between '06:00' and '21:59' then s.cost end), 0)
as night_cost,
count(*) as total_time,
coalesce(sum(s.cost), 0)
as total_cost
from workminutes m
join shifts s on m.workminute between s.starttime and s.endtime
group by wo
order by wo;
Output:
WO NORMAL_TIME NORMAL_COST NIGHT_TIME NIGHT_COST TOTAL_TIME TOTAL_COST
21 35 595 55 1100 90 1695
22 65 1105 15 300 80 1405
23 0 0 130 2600 130 2600
24 60 1020 0 0 60 1020
25 4800 81600 2340 46800 7140 128400
(This query looks a lot nicer of course, if you have a real shifts table and don't have to make one up on-the-fly. Also, you may not need all those seven columns I have in my result.)
I have table tblTask with data like below.
TID StartTime Uid WId
1 2011-06-06 09:30:00.000 10 1.5
2 2011-06-06 09:40:00.000 10 2.5
3 2011-06-06 09:50:00.000 10 1.8
4 2011-06-06 09:55:00.000 10 2.5
5 2011-06-06 10:30:00.000 10 1.5
6 2011-06-06 11:30:00.000 11 3.0
I need to write to query to calculate sum(Wid) based on time difference of each Starttime with another starttime having time difference 1 hour or close to 1 hr.
For example take first start time(2011-06-06 09:30:00.000); the nearest start time having <=1 hr is (2011-06-06 10:30:00.000) and the SUM(Wid) is 1.5+2.5+1.8+2.5+1.5 = 9.8. Likewise I need to calculate for all rows.
Desired output will be:
TID StartTime EndTime TimeDIff(Min) Uid WId
1 2011-06-06 09:30:00.000 2011-06-06 10:30:00.000 60 10 9.8
2 2011-06-06 09:40:00.000 2011-06-06 10:30:00.000 50 10 8.3
Does this give you what you need?
SELECT t1.TID, min(t1.StartTime) AS StartTime, MAX(t2.StartTime) AS EndTime,
MAX(DATEDIFF(MI, t1.StartTime, t2.StartTime)) AS [TimeDiff(Min],
t1.Uid, SUM(t2.WId) AS WId
FROM MyTable t1
JOIN MyTable t2 on datediff(MI, t1.starttime, t2.StartTime) BETWEEN 0 AND 60
GROUP BY t1.TID, t1.Uid
ORDER BY t1.TID
This block of code will give you the time difference between StartTime and EndTime
DECLARE #STARTDATE DATETIME = '10:15:45'
DECLARE #ENDDATE DATETIME = '14:00:15'
DECLARE #24DATE DATETIME
SET #24DATE = '23:59:59.000'
IF (#STARTDATE > #ENDDATE)
SELECT DATEADD(SECOND, 1, CONVERT(TIME(0), (#24DATE -(#ENDDATE - #STARTDATE))))
ELSE
SELECT CONVERT(TIME(0), ((#ENDDATE - #STARTDATE)))