I want to calculate month difference in same table from 2 different columns. In other words, I have 2 different columns that include dates and I would like to see their month difference in Sql Developer. Is there any way to do that?
Thank you.
for mysql : The DATEDIFF function can give you the number of days between two dates.
for oracle: months_between
sample:
SELECT months_between(column1,column2)
FROM Table
for the month differnce the standard sql is DATEDIFF, in this function you must pass 3 params, if you must calculate the difference from 2 columns, c1 and c2, you must do this query
SELECT DATEDIFF(month,c1 , c2)
FROM T
WHERE ...
Here the documentation of datediff https://www.w3schools.com/sql/func_sqlserver_datediff.asp
if you use oracle you can use also
SELECT months_between(c1,c2)
FROM T
WHERE ...
This is the documentation https://docs.oracle.com/cd/B19306_01/server.102/b14200/functions089.htm
Related
I am querying a table that has the date column as follows:
date
2021-03-08 05:05:31+00
2021-03-08 05:10:31+00
How can I select all the rows that contain 05:05 as the hour and minute in SQL? i.e. rows where hour = 05, and minute = 05. In this case it will be the first row.
Q: How can I select all the rows that contain 05:05 as the hour and minute in SQL?
A: For MySQL, look in the MySql Date and Time functions. There, you'll find Extract().
You can use it as follows:
https://www.w3schools.com/sql/func_mysql_extract.asp
Extract the minute from a datetime:
SELECT EXTRACT(MINUTE FROM "2017-06-15 09:34:21");
This assumes that you're storing the column as a "Date" type.
Different RDBMS vendors have different Date/Time functions. You'll have to read the documentation and experiment to determine which syntax to use for your particular DB vendor and your particular table schema.
You Can Use below Query for get Result as per your question .
There is DateName function in SQL and you can put this in your query as below.
CreatedDate is column name..
Example :
Select * from #tmp1 where datename(hour,createdDate)=07 And datename(minute,CreatedDate)=07
I have a table containing the following columns:
stats_date (YYYY-MM-DD)
registered (INT)
opened_form (INT)
Compose a query that will return the total registered, and opened_form by month for the last 3 months. Also a calculated column called conversion_rate which is the registered column divided by the opened_form.
Are you just looking for aggregation? Date/time functions differ significantly among databases, but the idea is:
select year(stats_date), month(stats_date),
sum(registered), sum(opened_form),
sum(registered) * 1.0 / sum(opened_form) as ratio
from t
group by year(stats_date), month(stats_date)
order by min(stats_date);
Of course, your database might have a different way of extracting the year and month from a date.
You can see the ANSI SQL at page 187 to understand how agregation works. To know how to group your column by Month you need to check the documentation of your db, usually is MONTH(COLUMN_NAME).
I have the following table in SQL:
Start - End - Amount **per day**
06.07.2020 10.07.2020 10
08.07.2020 08.07.2020 5
08.07.2020 15.07.2020 20
02.07.2020 06.07.2020 3
Now I want to filter this table by the calendar week. Let's say "where [calendar week] = cw28". cw28 is from the 06th of july to the 12th of july.
With that I'd like to have the sum of the amount of the days that lie between those two dates. One single number.
I'm using MS SQL Server (SQL Express).
I can't figure out how to distinguish (and break down) if one day lays between the two date values or not. And if yes how much I need to sum up.
I tried to make a picture in excel to create a logic from this:
"Logic" in Excel
Can anyone help me with this? :)
Thx and Best!,
Max
Not sure about your exact requirement. But below is the query to get the sum of values between two dates.
select sum(amount_of_days) from table where date_column between '06-JUL-2020' and '07-JUL-2010';
Change the column name and table name according to your requirement
I have two tables with a time column (year-day-month hr:min:sec)
Let's say name of table 1 is plc and column name Collect
Name of table2 is Adm and column name Disc
I want to subtract the time of Collect (2005-01-03 18:10:05) from the disc column (2005-01-03 20:15:10) in day, hours, minutes.
Any help would be appreciated!
I would surely go for the datediff function.
Have a look at this link:
https://msdn.microsoft.com/en-us/library/ms189794(v=sql.90).aspx
If you want, you can select difference in minutes, and then, with the minutes, calculate the days and hours
Use Date() or Datepart() function to fetch the specific part of the date and subtract the two.
You can get more details of the above two at the following link:
https://learn.microsoft.com/en-us/sql/t-sql/functions/datepart-transact-sql
How does Min function work on dates ? If 2 records have the same date and time stamp , the min function returns 1. Does it pull records based on when it was put into the table ?
MIN is an aggregate function so it will return 1 record in your question's case. Since the two records have the same date and timestamp it doesn't matter which date and timestamp are returned (they're the same). Finally, the time the records were inserted is not considered.
MIN() returns the smallest of all selected values of a column. It seems to me that your statement may simply be asking if a minimum exists.
Please post your sql statement.
possibly this is what you need:
SELECT MIN (date) AS "Min Date"
FROM tablename;
Elliot already expained it.
Just a sidenode, if you are using MySQL: MySQL allows to aggregate on a certain column, while fetching other columns without aggregation. (SQL Server does NOT allow that!)
Example:
date | name
2015-03-06 | A
2015-03-06 | B
Using SELECT Min(date), name FROM table on MySQL will return various results.
Sometimes it will be
2015-03-06 | A
sometimes
2015-03-06 | B
Docu:
When using this feature, all rows in each group should have the same
values for the columns that are omitted from the GROUP BY part. The
server is free to return any value from the group, so the results are
indeterminate unless all values are the same.
SQL Server will throw an error, that no aggregation has been performed on column name. See also http://dev.mysql.com/doc/refman/5.0/en/group-by-handling.html
MySQL works this way, cause sometimes grouping on the second column is not really required, for example:
SELECT MAX(id), user_id FROM posts WHERE user_id = 6
(There could be NO other user_id than 6, so aggregation is not required in MySQL - However not paying attention on THIS will lead to wrong results as example one shows.)