Problem: I cannot replace <br> tags with a newline character using Beautiful Soup 4.
Code: My program (the relevant portion of it) currently looks like
for br in board.select('br'):
br.replace_with('\n')
but I have also tried board.find_all() in place of board.select().
Results: When I use board.replace_with('\n') all <br> tags are replaced with the string literal \n. For example, <p>Hello<br>world</p> would end up becoming Hello\nworld. Using board.replace_with(\n) causes the error
File "<ipython-input-27-cdfade950fdf>", line 10
br.replace_with(\n)
^
SyntaxError: unexpected character after line continuation character
Other Information: I am using a Jupyter Notebook, if that is of any relevance. Here is my full program, as there may be some issue elsewhere that I have overlooked.
import requests
from bs4 import BeautifulSoup
import pandas as pd
page = requests.get("https://boards.4chan.org/g/")
soup = BeautifulSoup(page.content, 'html.parser')
board = soup.find('div', class_='board')
for br in board.select('br'):
br.replace_with('\n')
message = [obj.get_text() for obj in board.select('.opContainer .postMessage')]
image = [obj['href'] for obj in board.select('.opContainer .fileThumb')]
pid = [obj.get_text() for obj in board.select('.opContainer .postInfo .postNum a[title="Reply to this post"]')]
time = [obj.get_text() for obj in board.select('.opContainer .postInfo .dateTime')]
for x in range(len(image)):
image[x] = "https:" + image[x]
post = pd.DataFrame({
"ID": pid,
"Time": time,
"Image": image,
"Message": message,
})
post
pd.options.display.max_rows
pd.set_option('display.max_colwidth', -1)
display(post)
Any advice would be appreciated. Thank you for reading.
Just tried and it works for me, my bs4 version is 4.8.0, and I am using Python 3.5.3,
example:
from bs4 import BeautifulSoup
soup = BeautifulSoup('hello<br>world')
for br in soup('br'):
br.replace_with('\n')
# <br> was replaced with \n successfully
assert str(soup) == '<html><body><p>hello\nworld</p></body></html>'
# get_text() also works as expected
assert soup.get_text() == 'hello\nworld'
# it is a \n not a \\n
assert soup.get_text() != 'hello\\nworld'
I am not used to work with Jupyter Notebook, but seems that your problem is that whatever you are using to visualize the data is showing you the string representation instead of actually printing the string,
hope this helps,
Regards,
adb
Instead of replacing after converting to soup, try replacing the <br> tags before converting. Like,
soup = BeautifulSoup(str(page.content).replace('<br>', '\n'), 'html.parser')
Hope this helps! Cheers!
P.S.: I did not get any logical reason why this is not working after changing into soup.
After experimenting with variations of
page = requests.get("https://boards.4chan.org/g/")
str_page = page.content.decode()
str_split = '\n<'.join(str_page.split('<'))
str_split = '>\n'.join(str_split.split('>'))
str_split = str_split.replace('\n', '')
str_split = str_split.replace('<br>', ' ')
soup = BeautifulSoup(str_split.encode(), 'html.parser')
for the better part of two hours, I have determined that the Panda data-frame prints the newline character as a string literal. Everything else indicates that the program is working as intended, so I assume this has been the problem all along.
for some reason direct replace with newline does not work with bs4 you have to first replace with some other unique character (character sequence preferably) and then replace that sequence in text with newline.
try this.
for br in soup.find_all('br'): br.replace_with('+++')
text=soup.get_text().replace('+++','\n)
Related
import requests
from bs4 import BeautifulSoup, NavigableString, Tag
url = "https://www.codewithharry.com"
r = requests.get(url)
htmlContent = r.content
soup = BeautifulSoup(htmlContent, 'html.parser')
print(soup.find('p')['class'])
This code showed me a warning in vs code for the written code and the output that was given was correct so you can just write there as shown below:
print (soup. Find('p')['class']) # type: ignore
Sometimes it show the warning in the terminal in vs code so you can use this to stop the error
The program was intended to search through a table on the web.
single_paper_soup.find('dl').find_all("dt")
returns:
[<dt>Volume:</dt>,
<dt>Month:</dt>,
<dt>Year:</dt>,
<dt>Venues:</dt>,
<dt>Pages:</dt>,
<dt>Language:</dt>,
<dt>URL:</dt>,
<dt>DOI:</dt>,]
However, when I dived into the content by searching text:
single_paper_soup.find('dl').find_all("dt",string = "Year")
it returned nothing:
[]
Both string and text methods returned nothing.
Is there anything wrong with the code?
Searching for a string per string or text needs exact string to match in your case:
soup.find_all("dt",string = "Year:")
There are other options to search for a tag that conatins a string / substring,
Use css selectors and :-soup-contains():
soup.select('dt:-soup-contains("Year")')
Import re and use re.compile() to find your tag with text:
soup.find_all("dt", text=re.compile("Year"))
Example
import requests
import re
from bs4 import BeautifulSoup
html='''
<dt>Volume:</dt>
<dt>Month:</dt>
<dt>Year:</dt>
<dt>Venues:</dt>
<dt>Pages:</dt>
<dt>Language:</dt>
<dt>URL:</dt>
<dt>DOI:</dt>
'''
soup = BeautifulSoup(html)
soup.select('dt:-soup-contains("Year")')
soup.find_all("dt",string = "Year:")
soup.find_all("dt", text=re.compile("Year"))
I am trying to extract the text of this page: https://www.londonstockexchange.com/news-article/ESNT/date-for-fy-2020-results-announcement/14850033 using bs4 and pandas
I start with:
src=requests.get(url).content
soup = BeautifulSoup(src,'xml')
and see that the text I am interested in is wrapped in p tags,
but when I run soup.find_all('p'), the only return I get is the closing paragraph.
How can I extract the paragraph text within? What am I missing?
These are the paragraphs I am trying to extract:
I tried also with selenium using:
chrome_options = webdriver.ChromeOptions()
chrome_options.add_argument("--headless")
chrome_driver = os.getcwd() + "\\chromedriver.exe"
driver = webdriver.Chrome(options = chrome_options, executable_path = chrome_driver)
driver.get(url)
page = driver.page_source
page_soup = BeautifulSoup(page,'xml')
div=page_soup.find_all('p')
[a.text for a in div]
I figured it out.
The body of the site comes from a <script> tag that holds a JSON but with a funky encoding.
That said tag has an id of "ng-lseg-state", which means this is Angular's custom HTML encoding.
You can target the <script> tag with BeautifulSoup and parse it with the json module.
Then, however, you need to deal with Angular's encoding. One way, a bit crude thou, is to chain a bunch of .replace() methods.
Here's how:
import json
import requests
from bs4 import BeautifulSoup
url = "https://www.londonstockexchange.com/news-article/ESNT/date-for-fy-2020-results-announcement/14850033"
script = BeautifulSoup(requests.get(url).text, "lxml").find("script", {"id": "ng-lseg-state"})
article = json.loads(script.string.replace("&q;", '"'))
main_key = "G.{{api_endpoint}}/api/v1/pages?parameters=newsId%3D14850033&a;path=news-article"
article_body = article[main_key]["body"]["components"][1]["content"]["newsArticle"]["value"]
decoded_body = (
article_body
.replace('&l;', '<')
.replace('&g;', '>')
.replace('&q;', '"')
)
print(BeautifulSoup(decoded_body, "lxml").find_all("p")[22].getText())
This outputs:
Essentra plc is a FTSE 250 company and a leading global provider of essential components and solutions.&a;#160; Organised into three global divisions, Essentra focuses on the light manufacture and distribution of high volume, enabling components which serve customers in a wide variety of end-markets and geographies.
However, as I've said, this is not the best approach, as I'm not entirely sure how to deal with a bunch of other characters, namely:
&a;#160;
&a;amp;
&s;
just to name a few. But I've already asked about this.
EDIT:
Here's a fully working code based on the answer to my question, mentioned above.
import html
import json
import requests
from bs4 import BeautifulSoup
def unescape(decoded_html):
char_mapping = {
'&a;': '&',
'&q;': '"',
'&s;': '\'',
'&l;': '<',
'&g;': '>',
}
for key, value in char_mapping.items():
decoded_html = decoded_html.replace(key, value)
return html.unescape(decoded_html)
url = "https://www.londonstockexchange.com/news-article/ESNT/date-for-fy-2020-results-announcement/14850033"
script = BeautifulSoup(requests.get(url).text, "lxml").find("script", {"id": "ng-lseg-state"})
payload = json.loads(unescape(script.string))
main_key = "G.{{api_endpoint}}/api/v1/pages?parameters=newsId%3D14850033&path=news-article"
article_body = payload[main_key]["body"]["components"][1]["content"]["newsArticle"]["value"]
print(BeautifulSoup(article_body, "lxml").find_all("p")[22].getText())
I'm trying to find the river level here. Yesterday I got some amazing help to use the first BOLD (strong) text, however today that isn't working because new strong text has appeared BEFORE the river level due to the river being in flood. Is there a way in beautiful soup to harvest the first word in bold ending with an m ?
Cheers!!
This should help u:
import requests
from bs4 import BeautifulSoup
url = 'https://flood-warning-information.service.gov.uk/station/8208'
soup = BeautifulSoup(requests.get(url).content, 'html.parser')
header = soup.find('header',class_ = "intro")
paragraphs = header.find_all('p')
txt = paragraphs[1].strong.text
print(txt)
Output:
1.97m
This also works for the url that u mentioned in ur previous question.
Output for that url:
0.66m
Hope that this helps!
If you want to use a CSS Selector:
import requests
from bs4 import BeautifulSoup
url = 'https://flood-warning-information.service.gov.uk/station/8208'
soup = BeautifulSoup(requests.get(url).content, 'html.parser')
print(soup.select_one('.intro p strong:nth-of-type(1)').text)
Output:
1.97m
I'm trying to extract some text using BeautifulSoup. I'm using get_text() function for this purpose.
My problem is that the text contains </br> tags and I need to convert them to end lines. how can I do this?
You can do this using the BeautifulSoup object itself, or any element of it:
for br in soup.find_all("br"):
br.replace_with("\n")
As official doc says:
You can specify a string to be used to join the bits of text together: soup.get_text("\n")
A regex should do the trick.
import re
s = re.sub('<br\s*?>', '\n', yourTextHere)
Hope this helps!
Also you can use get_text(separator = '\n', strip = True) :
from bs4 import BeautifulSoup
bs=BeautifulSoup('<td>some text<br>some more text</td>','html.parser')
text=bs.get_text(separator = '\n', strip = True)
print(text)
>>
some text
some more text
it works for me.
Adding to Ian's and dividebyzero's post/comments you can do this to efficiently filter/replace many tags in one go:
for elem in soup.find_all(["a", "p", "div", "h3", "br"]):
elem.replace_with(elem.text + "\n\n")
Instead of replacing the tags with \n, it may be better to just add a \n to the end of all of the tags that matter.
To steal the list from #petezurich:
for elem in soup.find_all(["a", "p", "div", "h3", "br"]):
elem.append('\n')
If you call element.text you'll get the text without br tags.
Maybe you need define your own custom method for this purpose:
def clean_text(elem):
text = ''
for e in elem.descendants:
if isinstance(e, str):
text += e.strip()
elif e.name == 'br' or e.name == 'p':
text += '\n'
return text
# get page content
soup = BeautifulSoup(request_response.text, 'html.parser')
# get your target element
description_div = soup.select_one('.description-class')
# clean the data
print(clean_text(description_div))