Create a macro that copy and pastes data - vba

Question

I'm trying to create a macro that opens a file and copy and pastes data from that file into a new excel sheet.
Problem is, the file is updated every month. So I have a sheet on excel where I have copy pasted the path to that file (Instructions and its in cell A2). I want to know how I can adjust my code to open that file, copy its data and close the file. I also want to create a button that I can press to run the macro.
This is my code so far:
Sub ImportData_Click()
'open the source workbook and select the source sheet
Workbooks.Open Filename:="'Instructions!'$A$2" 'this is the part of the
code that I'm having trouble with
Sheets("ABC").Select
' copy the source range
Sheets("ABC").Range("C:AI").Select
Selection.Copy
' select current workbook and paste the values
ThisWorkbook.Activate
Sheets("ABC DUMP").Select
Sheets("ABC DUMP").Range("A:").Select
Selection.PasteSpecial Paste:=xlValues, Operation:=xlNone, SkipBlanks:= _
False, Transpose:=False
'close the source workbook
Windows("'Instructions!'$A$2").Activate
ActiveWorkbook.Close
End Sub

Answer 1

You have several minor syntax errors. With A2 data like:
C:\TestFolder\ABC.xls
this appears to work just fine:
Sub ImportData_Click()
'open the source workbook and select the source
Dim wb As Workbook
Workbooks.Open Filename:=Sheets("Instructions").Range("$A$2").Value
Set wb = ActiveWorkbook
Sheets("ABC").Select
' copy the source range
Sheets("ABC").Range("C:AI").Select
Selection.Copy
' select current workbook and paste the values
ThisWorkbook.Activate
Sheets("ABC DUMP").Select
Sheets("ABC DUMP").Range("A1").Select
Selection.PasteSpecial Paste:=xlValues, Operation:=xlNone, SkipBlanks:= _
False, Transpose:=False
'close the source workbook
wb.Close
End Sub
This can be re-coded to avoid Select

Answer 2

If you define a variable as a string and then set it to equal your filename ('Instructions!'$A$2) you can then use this variable in the workbooks.open function.
Your workbooks.open function also requires a pathname for this workbook; therefore define another variable for your pathname and you should be able to use:
Workbooks.Open Filename:=PathName & Filename