select year(date), week(date), sum(bottles_sold)
from LIQUORS_SALES
group by year(date), week(date)
order by year(date), week (date).
above one is the query i used to fetch weekly time series for sum of bottles_sold. But i am getting wrong number of bottles sold in every year first week.
what i observed is sum of bottles sold in additional days of every year are adding to first week of that year.
Ex:- take 2012 which is leap year (366 days) where my first week starts from jan 1st. i have a sales of bottles on 2012-01(1-7 days) week are 200, 2012 - 52 (358-364 days) are 500, now sales in last two days (365th and 366th) are 150 which should actually add to 2013-01 week, but it's adding to 2012-01 where my 2012-01 bottles sold become 350.
how can i fix it? is there anything miss in the sql query i used ? or is there anything i need to change the configurations in grid-gain or something wrong with the ignite database itself?
please help me to fix this, it cause a serious problem to do time series analysis. let me know if you need more information about the issue. Thanks in advance.
You need to stop grouping by year(date), week(date) and start instead grouping by iso_year(date), iso_week(date).
select iso_year(date), iso_week(date), sum(bottles_sold) from LIQUORS_SALES group by iso_year(date), iso_week(date)
Related
I have a table with the sales from last 2 years, and I want to compare the sales from this year with the same natural day last year. For example, Sunday 1st of April 2018 will be compared with Sunday 2nd April 2017.
In order to do that I have created the measure
sales_last_year = CALCULATE(Sales[Revenue]); SAMEPERIODLASTYEAR(DATEADD('Calendar'[Date];+1;DAY)))
And I have created another measure where I have the value from the same day last year:
Prueba_sales_last_year = CALCULATE(Sales[Revenue]); SAMEPERIODLASTYEAR('Calendar'[Date]))
The result is the following:
Sales last year
As you can see the sales per day shows 5.316€ and 3.546€, which is correct, but the total is 111.796 €, which is not correct. However, the measure with the formula without the natural day the sum of the two rows is correct. How could I solve this?
Thank you very much in advance
I just changed the order to calculate the date and it was solved.
sales_last_year = CALCULATE(Sales[Revenue]);DATEADD( SAMEPERIODLASTYEAR('Calendar'[Date]);+1;DAY))
I am trying to produce a query in SQLite where I can determine the average sales made each weekday in the year.
As an example, I'd say like to say
"The average sales for Monday are $400.50 in 2017"
I have a sales table - each row represents a sale you made. You can have multiple sales for the same day. Columns that would be of interest here:
Id, SalesTotal, DayCreated, MonthCreated, YearCreated, CreationDate, PeriodOfTheDay
Day/Month/Year are integers that represent the day/month/year of the week. DateCreated is a unix timestamp that represents the date/time it was created too (and is obviously equal to day/month/year).
PeriodOfTheDay is 0, or 1 (day, or night). You can have multiple records for a given day (typically you can have at most 2 but some people like to add all of their sales in individually, so you could have 5 or more for a day).
Where I am stuck
Because you can have two records on the same day (i.e. a day sales, and a night sales, or multiple of each) I can't just group by day of the week (i.e. group all records by Saturday).
This is because the number of sales you made does not equal the number of days you worked (i.e. I could have worked 10 saturdays, but had 30 sales, so grouping by 'saturday' would produce 30 sales since 30 records exist for saturday (some just happen to share the same day)
Furthermore, if I group by daycreated,monthcreated,yearcreated it works in the sense it produces x rows (where x is the number of days you worked) however that now means I need to return this resultset to the back end and do a row count. I'd rather do this in the query so I can take the sales and divide it by the number of days you worked.
Would anyone be able to assist?
Thanks!
UPDATE
I think I got it - I would love someone to tell me if I'm right:
SELECT COUNT(DISTINCT CAST(( julianday((datetime(CreationDate / 1000, 'unixepoch', 'localtime'))) ) / 7 AS INT))
FROM Sales
WHERE strftime('%w', datetime(CreationDate / 1000, 'unixepoch'), 'localtime') = '6'
AND YearCreated = 2017
This would produce the number for saturday, and then I'd just put this in as an inner query, dividing the sale total by this number of days.
Buddy,
You can group your query by getting the day of week and week number of day created or creation date.
In MSSQL
DATEPART(WEEK,'2017-08-14') // Will give you week 33
DATEPART(WEEKDAY,'2017-08-14') // Will give you day 2
In MYSQL
WEEK('2017-08-14') // Will give you week 33
DAYOFWEEK('2017-08-14') // Will give you day 2
See this figures..
Day of Week
1-Sunday, 2- Monday, 3-Tuesday, 4-Wednesday, 5-Thursday, 6-Saturday
Week Number
1 - 53 Weeks in a year
This will be the key so that you will have a separate Saturday's in every month.
Hope this can help in building your query.
I'm currently running the following sql statement in JasperReports Server to bring back my data using derived tables.
Select count(createddate) as ModulesCreatedDuringPastWeek,
count(updateddate) as ModulesUpdatedDuringPastWeek,
createddate,
updateddate
from merchendisingmodule
group by merchendisingmodule.createddate, merchendisingmodule.updateddate
However when grouping my data, I am only able to do it in Year, quarter, month and day. However for my report I'm needing the data to be group weeks, and so I was wondering what I will need to add to my code to do this.
DATEADD(D,-DATEPART(weekday,createddate)+1,createddate)
I use this method to prevent issues around the year transitions (week 53 in first days of januari and also in the last days of december, will group days together that are 360 days apart).
I use the first day of the week, instead of week numbers. I can use these dates to group by.
Also this will ensure that every week is 7 days long, instead of the last week of the year being only 3 or 4 days long.
Btw, in this example the first day of the week is sunday.
If your dates include time, use:
CAST(FLOOR(CAST(createddate AS FLOAT)) AS DATETIME)
instead of createddate in the above SYNTAX
I've periods of time every 15 days, MOM and EOM.
What I need to check is if a date value on a date field is prior to the current period minus 1.
For example, if today is 12/29, the period is 12/31, and i need to check
if prior < 12/15
How can i get the EOM (End Of Month, i mean, the last day of the month) and the MOM (Middle of month, it's like every 15th of month) with GETDATE() function without doing a DATEADD with -15 days (because in feb will be fail, and i don't care the month)
Any help or work around will be preciated.
Thanks
If you need the value 15 then put it in your code.
If that is against your company's policies then challenge the person that made that policy. Writing 5 lines of code to replace two characters is not a good coding...
If writing the 5 lines made your application much more flexible then maybe I could understand, but you are still "hard coding" 15 into your comparisons.
Thinking in a work around, what I did it was this:
If actual day < 15 then get the month actual, convert to the first day of the month (01) and minus 1 day. I get the last day of the prior month. (EOM - 1 period)
If actual day > 15, then the prior period (MOM - 1 period) is: 15 of actual month.
It's a query with if structure.
If someone has a better answer, please answer it and I'll be accept it.
Thanks :)
Greetings SQL gurus,
I don't know if you can help me, but I will try. I have several large databases grouped by year (each year in a different database). I want to be able to compare values from a particular week from one year to the next. For example, "show me week 17 of 2008 vs. week 17 of 2002."
I have the following definition of weeks that ideally I would use:
Only 52 weeks each year and 7 days a week (that only takes 364 days),
The first day of the first week starts from January 2nd - which means we do not use January 1st data, and
In leap year, the first day of the first week ALSO starts from the January 2nd plus we skip Feb. 29.
Any ideas?
Thanks in advance.
Best to avoid creating a table because then you have to update and maintain it to get your queries to work.
DatePart('ww',[myDate]) will give you the week number. You may run into some issues though deciding which week belongs to which year - for example if Jan 1 2003 is on Wednesday does the week belong as week 52 in 2002 or week 1 in 2003? Your accounting department will have a day of the week that is your end of week (usually Sat). I usually just pick the year that has the most days in it. DatePart will always count the first week as 1 and in the case of the example above the last week as 53. You may not care that much either way. You can create queries for each year
SELECT DatePart('ww',[myDate]) as WeekNumber,myYearTable.* as WeekNumber
FROM myYearTable
and then join the queries to get your data. You'll loose a couple days at the end of the year if one table has 52 weeks and one has 53 (most will show as 53). Or you can do it by your weekending day - this always gives you Saturday which would push a late week into the following year.
(7-Weekday([myDate]))+[myDate]
then
DatePart('ww',(7-Weekday([myDate]))+[myDate])
Hope that helps
To get the week number
'to get the week number in the year
select datepart( week, datefield)
'to get the week number in the month
select (datepart(dd,datefield) -1 ) / 7 + 1
You don't need to complicate things thinking about leap years, etc. Just compare weeks mon to sun
SInce you havea a specifc defintion of when the week starts that is differnt that the standard used by the db, I think a weeks table is the solution to your problem. For each year create a table that defines the dates contained in each week and the week number. Then by joining to that table as well as the relevant other tables, you can ask for just the data for week 17.
Table structure
Date Week
20090102 1
20090103 1
etc.
I needed to create a query that shows BOTH year AND week numbers, like 2014-52. The year shows correct when you use the Datepart() formula to convert week 53 to week 52 in the previous year, but shows the wrong year for the week that was week 1 previously that should be week 52 now. It show that week as 2015-52 instead of 2014-52.
Furthermore, it sorts the data wrong if you only use only the week number, eg:
2014-1,2014-11,2014-2
To overcome this I created the following query to insert a 0 and also to check for days in week 1 that should still fall under week 52.
ActualWeek: IIf(DatePart("ww",[SomeDate],1,3)=52 And DatePart("ww",[SomeDate])=1, DatePart("yyyy",[SomeDate],1,3)-1,DatePart("yyyy",[SomeDate],1,3)) & "-" & IIf(DatePart("ww",[SomeDate],1,3)<10,"0" & DatePart("ww",[SomeDate],1,3),DatePart("ww",[SomeDate],1,3))