SQL Sum of numbers from a string - sql

Question

I have a string like this:)
"<"FOSTIMON 75 M.J.>|4|4|4|3|3|3|3|3|3|3|3|3||||||||||||||||||||||||||||"
I need the sum of the numbers (4+4+4+3+...+3), expected result = 39
Thank you for the help!

Answer 1

THIS ANSWERS THE ORIGINAL QUESTION BEFORE EDITING.
Most databases support executing some form of prepared statement. In your case, probably the simplest method is to construct a SQL statement and then execute it dynamically.
The syntax for this varies dramatically from database to database. Out of randomness, I'm choosing SQL Server, but the functionality (although not the syntax) is available in almost any database:
declare #str nvarchar(max) = '|4|4|4|3|3|3|3|3|3|3|3|3||||||||||||||||||||||||||||';
set #str = 'select ' + replace(#str, '|', '+') + ' + 0';
exec sp_executesql #str;
Here is a rextester for this particular version.
Note that this works because + is a unary (numeric) operator, analogous to - but it does not change the sign.

Answer 2

Try this
Assuming the first part of the string upto the first "|" can be ignored
Not sure what version of SQL you're using but if its less than SQL2016 then use this string splitter
DECLARE #s NVARCHAR(50) = '<"FOSTIMON 75 M.J.>|4|4|4|3|3|3|3|3|3|3|3|3||||||||||||||||||||||||||||'
SELECT
SUM(CONVERT(INT, S.[Value]))
FROM dbo.DelimitedSplit8K(#s, '|') S
WHERE S.RN >= 2 AND S.RN <= 13
If you're on SQL2012 + then you can utilise TRY_PARSE and get rid of the WHERE clause altogether
SELECT
SUM(
CASE
WHEN TRY_PARSE(S.[Value] AS INT) IS NOT NULL
THEN CONVERT(INT, S.[Value])
ELSE 0
END
--CONVERT(INT, S.[Value])
)
FROM dbo.DelimitedSplit8K(#s, '|') S
If you're using SQL2016 + then use the inbuilt function, String_Split
SELECT
SUM(
CASE
WHEN TRY_PARSE(S.[Value] AS INT) IS NOT NULL
THEN CONVERT(INT, S.[Value])
ELSE 0
END
)
FROM STRING_SPLIT(#s, '|') S