Sort dates order between dates - sql

I have two dates as a parameters and list of current dates and same periods of previous years . I need partition list between parameters. Logic is if date between '20171201' AND '20180301' then 1, if date between '20161201' and '20170301' then 2 and so on. But count of periods in list not static, like:
DECLARE #DateEnd DATE = '20180331'
, #DateBeg DATE = '20171201'
DECLARE #tab TABLE([date] DATE)
INSERT INTO #tab ([date])
VALUES('2014-12-01')
, ('2015-01-01')
, ('2015-02-01')
, ('2015-03-01')
, ('2015-12-01')
, ('2016-01-01')
, ('2016-02-01')
, ('2016-03-01')
, ('2016-12-01')
, ('2017-01-01')
, ('2017-02-01')
, ('2017-03-01')
, ('2017-12-01')
, ('2018-01-01')
, ('2018-02-01')
, ('2018-03-01')
Result should be
Date Cnt
2014-12-01 4
2015-01-01 4
2015-02-01 4
2015-03-01 4
2015-12-01 3
2016-01-01 3
2016-02-01 3
2016-03-01 3
2016-12-01 2
2017-01-01 2
2017-02-01 2
2017-03-01 2
2017-12-01 1
2018-01-01 1
2018-02-01 1
2018-03-01 1

use CASE WHEN satetement to check for the date and return the value accordingly
select *,
Cnt = CASE
WHEN date BETWEEN '20171201' AND '20180331' THEN 1
WHEN date BETWEEN '20161201' AND '20170331' THEN 2
WHEN date BETWEEN '20151201' AND '20160331' THEN 3
WHEN date BETWEEN '20141201' AND '20150331' THEN 4
END
from #tab
EDIT :
Or maybe this is what you want ?
this will gives you the begining of the financial year
dateadd(month, - month(date) % 12, date)
your Cnt is no of years between the financial year and today ?
select *,
Cnt = datediff(year, dateadd(month, - month(date) % 12, date), getdate())
from #tab

Using dateadd() within a case expression should enable this:
select
datecol
, case when datecol between #DateBeg and #DateEnd then 1
when datecol between dateadd(year,-1,#DateBeg) and dateadd(year,-1,#DateEnd) then 2
when datecol between dateadd(year,-2,#DateBeg) and dateadd(year,-2,#DateEnd) then 3
when datecol between dateadd(year,-3,#DateBeg) and dateadd(year,-3,#DateEnd) then 4
end
from #tab
also see: http://rextester.com/BTF82190

Related

SQL how to count census points occurring between date records

I’m using MS-SQL-2008 R2 trying to write a script that calculates the Number of Hospital Beds occupied on any given day, at 2 census points: midnight, and 09:00.
I’m working from a data set of patient Ward Stays. Basically, each row in the table is a record of an individual patient's stay on a single ward, and records the date/time the patient is admitted onto the ward, and the date/time the patient leaves the ward.
A sample of this table is below:
Ward_Stay_Primary_Key | Ward_Start_Date_Time | Ward_End_Date_Time
1 | 2017-09-03 15:04:00.000 | 2017-09-27 16:55:00.000
2 | 2017-09-04 18:08:00.000 | 2017-09-06 18:00:00.000
3 | 2017-09-04 13:00:00.000 | 2017-09-04 22:00:00.000
4 | 2017-09-04 20:54:00.000 | 2017-09-08 14:30:00.000
5 | 2017-09-04 20:52:00.000 | 2017-09-13 11:50:00.000
6 | 2017-09-05 13:32:00.000 | 2017-09-11 14:49:00.000
7 | 2017-09-05 13:17:00.000 | 2017-09-12 21:00:00.000
8 | 2017-09-05 23:11:00.000 | 2017-09-06 17:38:00.000
9 | 2017-09-05 11:35:00.000 | 2017-09-14 16:12:00.000
10 | 2017-09-05 14:05:00.000 | 2017-09-11 16:30:00.000
The key thing to note here is that a patient’s Ward Stay can span any length of time, from a few hours to many days.
The following code enables me to calculate the number of beds at both census points for any given day, by specifying the date in the case statement:
SELECT
'05/09/2017' [Date]
,SUM(case when Ward_Start_Date_Time <= '05/09/2017 00:00:00.000' AND (Ward_End_Date_Time >= '05/09/2017 00:00:00.000' OR Ward_End_Date_Time IS NULL)then 1 else 0 end)[No. Beds Occupied at 00:00]
,SUM(case when Ward_Start_Date_Time <= '05/09/2017 09:00:00.000' AND (Ward_End_Date_Time >= '05/09/2017 09:00:00.000' OR Ward_End_Date_Time IS NULL)then 1 else 0 end)[No. Beds Occupied at 09:00]
FROM
WardStaysTable
And, based on the sample 10 records above, generates this output:
Date | No. Beds Occupied at 00:00 | No. Beds Occupied at 09:00
05/09/2017 | 4 | 4
To perform this for any number of days is obviously onerous, so what I’m looking to create is a query where I can specify a start/end date parameter (e.g. 1st-5th Sept), and for the query to then evaluate the Ward_Start_Date_Time and Ward_End_Date_Time variables for each record, and – grouping by the dates defined in the date parameter – count each time the 00:00:00.000 and 09:00:00.000 census points fall between these 2 variables, to give an output something along these lines (based on the above 10 records):
Date | No. Beds Occupied at 00:00 | No. Beds Occupied at 09:00
01/09/2017 | 0 | 0
02/09/2017 | 0 | 0
03/09/2017 | 0 | 0
04/09/2017 | 1 | 1
05/09/2017 | 4 | 4
I’ve approached this (perhaps naively) thinking that if I use a cte to create a table of dates (defined by the input parameters), along with associated midnight and 9am census date/time points, then I could use these variables to group and evaluate the dataset.
So, this code generates the grouping dates and census date/time points:
DECLARE
#StartDate DATE = '01/09/2017'
,#EndDate DATE = '05/09/2017'
,#0900 INT = 540
SELECT
DATEADD(DAY, nbr - 1, #StartDate) [Date]
,CONVERT(DATETIME,(DATEADD(DAY, nbr - 1, #StartDate))) [MidnightDate]
,DATEADD(mi, #0900,(CONVERT(DATETIME,(DATEADD(DAY, nbr - 1, #StartDate))))) [0900Date]
FROM
(
SELECT
ROW_NUMBER() OVER ( ORDER BY c.object_id ) AS nbr
FROM sys.columns c
) nbrs
WHERE nbr - 1 <= DATEDIFF(DAY, #StartDate, #EndDate)
The stumbling block I’ve hit is how to join the cte to the WardStays dataset, because there’s no appropriate key… I’ve tried a few iterations of using a subquery to make this work, but either I’m taking the wrong approach or I’m getting my syntax in a mess.
In simple terms, the logic I’m trying to create to get the output is something like:
SELECT
[Date]
,SUM (case when WST.Ward_Start_Date_Time <= [MidnightDate] AND (WST.Ward_End_Date_Time >= [MidnightDate] OR WST.Ward_End_Date_Time IS NULL then 1 else 0 end) [No. Beds Occupied at 00:00]
,SUM (case when WST.Ward_Start_Date_Time <= [0900Date] AND (WST.Ward_End_Date_Time >= [0900Date] OR WST.Ward_End_Date_Time IS NULL then 1 else 0 end) [No. Beds Occupied at 09:00]
FROM WardStaysTable WST
GROUP BY [Date]
Is the above somehow possible, or am I barking up the wrong tree and need to take a different approach altogether? Appreciate any advice.
I would expect something like this:
WITH dates as (
SELECT CAST(#StartDate as DATETIME) as dte
UNION ALL
SELECT DATEADD(DAY, 1, dte)
FROM dates
WHERE dte < #EndDate
)
SELECT dates.dte [Date],
SUM(CASE WHEN Ward_Start_Date_Time <= dte AND
Ward_END_Date_Time >= dte
THEN 1 ELSE 0
END) as num_beds_0000,
SUM(CASE WHEN Ward_Start_Date_Time <= dte + CAST('09:00' as DATETIME) AND
Ward_END_Date_Time >= dte + CAST('09:00' as DATETIME)
THEN 1 ELSE 0
END) as num_beds_0900
FROM dates LEFT JOIN
WardStaysTable wt
ON wt.Ward_Start_Date_Time <= DATEADD(day, 1, dates.dte) AND
wt.Ward_END_Date_Time >= dates.dte
GROUP BY dates.dte
ORDER BY dates.dte;
The cte is just creating the list of dates.
What a cool exercise. Here is what I came up with:
CREATE TABLE #tmp (ID int, StartDte datetime, EndDte datetime)
INSERT INTO #tmp values(1,'2017-09-03 15:04:00.000','2017-09-27 06:55:00.000')
INSERT INTO #tmp values(2,'2017-09-04 08:08:00.000','2017-09-06 18:00:00.000')
INSERT INTO #tmp values(3,'2017-09-04 13:00:00.000','2017-09-04 22:00:00.000')
INSERT INTO #tmp values(4,'2017-09-04 20:54:00.000','2017-09-08 14:30:00.000')
INSERT INTO #tmp values(5,'2017-09-04 20:52:00.000','2017-09-13 11:50:00.000')
INSERT INTO #tmp values(6,'2017-09-05 13:32:00.000','2017-09-11 14:49:00.000')
INSERT INTO #tmp values(7,'2017-09-05 13:17:00.000','2017-09-12 21:00:00.000')
INSERT INTO #tmp values(8,'2017-09-05 23:11:00.000','2017-09-06 07:38:00.000')
INSERT INTO #tmp values(9,'2017-09-05 11:35:00.000','2017-09-14 16:12:00.000')
INSERT INTO #tmp values(10,'2017-09-05 14:05:00.000','2017-09-11 16:30:00.000')
DECLARE
#StartDate DATE = '09/01/2017'
,#EndDate DATE = '10/01/2017'
, #nHours INT = 9
;WITH d(OrderDate) AS
(
SELECT DATEADD(DAY, n-1, #StartDate)
FROM (SELECT TOP (DATEDIFF(DAY, #StartDate, #EndDate) + 1)
ROW_NUMBER() OVER (ORDER BY [object_id]) FROM sys.all_objects) AS x(n)
)
, CTE AS(
select OrderDate, t2.*
from #tmp t2
cross apply(select orderdate from d ) d
where StartDte >= #StartDate and EndDte <= #EndDate)
select OrderDate,
SUM(CASE WHEN OrderDate >= StartDte and OrderDate <= EndDte THEN 1 ELSE 0 END) [No. Beds Occupied at 00:00],
SUM(CASE WHEN StartDTE <= DateAdd(hour,#nHours,CAST(OrderDate as datetime)) and DateAdd(hour,#nHours,CAST(OrderDate as datetime)) <= EndDte THEN 1 ELSE 0 END) [No. Beds Occupied at 09:00]
from CTE
GROUP BY OrderDate
This should allow you to check for any hour of the day using the #nHours parameter if you so choose. If you only want to see records that actually fall within your date range then you can filter the cross apply on start and end dates.

Function to count if X amount amount of days as a full month

We offer services for clients and each client has an Authorization for 90 days
I want to create a function which counts 15 days as full months.
For example, let’s say a client get Authorization on 10/17/2017. It’s means it’s less than 15 days for October so that Authorization will not count for October, but it has to count for November, December and January 2018.
;WITH CTE AS (
select
d.ClientId,
LOC
datediff(day, l.DecisionOn, d.duedate) 'Days',
l.DecisionOn,
d.duedate
from code d
join codeloc l on d.curdocversionid = l.docversionid
join codeaccess a on a.docversionid = d.curdocversionid
where codeid = 69999
and aoca in ('68','69','70','71','72','74')
),
T AS (
SELECT ClientId, LOC, COUNT(*) CNT FROM CTE
WHERE [Days] > 15
AND AuthorizedDecisionOn > DATEADD(MONTH, (CASE WHEN DAY(GETDATE()) > 15 THEN 1 ELSE 0 END) , CAST( GETDATE() as date))
AND duedate < DATEADD(MONTH,3 + (CASE WHEN DAY(GETDATE()) > 15 THEN 1 ELSE 0 END) , CAST( GETDATE() as date))
GROUP BY ClientId, LOC
)
Here's an inline table valued function (iTvf) that will give you what you need.
(note: I use iTvf's because they outperform scalar udfs)
CREATE FUNCTION dbo.monthsBetweenMinDay
(
#fromDate date,
#toDate date,
#minDays tinyint
)
RETURNS TABLE WITH SCHEMABINDING AS RETURN
SELECT Months = m.mb +
CASE WHEN DATEDIFF(day,d.fd,dateadd(month, -m.mb, d.td)) >= #minDays THEN 1 ELSE 0 END
FROM (VALUES (#fromDate, #toDate)) d(fd,td) -- from date and todate
CROSS APPLY (VALUES(
CASE WHEN d.fd > d.td THEN NULL
WHEN DATEPART(day, d.fd) > DATEPART(day, d.td) THEN DATEDIFF(month, d.fd, d.td)-1
ELSE DATEDIFF(month, d.fd, d.td) END)) m(mb);
Here's an example of the function in action:
-- sample data
CREATE TABLE #dates (date1 date, date2 date);
INSERT #dates
SELECT dt.dt, CAST(DATEADD(day, [days].d, DATEADD(month, months.m, dt.dt)) as date)
FROM (VALUES ('20170101')) dt(dt), (VALUES (4),(15),(25)) [days](d), (VALUES(0),(1),(4)) months(m);
-- solution
SELECT *
FROM #dates d
CROSS APPLY dbo.monthsBetweenMinDay(d.date1, d.date2, 15);
Results
date1 date2 Months
---------- ---------- -----------
2017-01-01 2017-01-05 0
2017-01-01 2017-01-16 1
2017-01-01 2017-01-26 1
2017-01-01 2017-02-05 1
2017-01-01 2017-02-16 2
2017-01-01 2017-02-26 2
2017-01-01 2017-05-05 4
2017-01-01 2017-05-16 5
2017-01-01 2017-05-26 5

Count data for last 10 days including days without any entries

I want to count all data for each of last 10 days where some column have specific value. I manage to do this:
declare #start datetime = CAST(getdate() as date)
declare #end datetime = dateadd(day, -10, #start)
;with amonth(day) as
(
select #end as day
union all
select day + 1
from amonth where day < CAST(#start as date)
)
select CAST(amonth.day as date) as dat, count(vrijeme) as c
from amonth
left join Dnevnik on CAST(vrijeme as date) = CAST(amonth.day as date)
group by CAST(amonth.day as date) order by dat
It gives me a result like this:
dat c
2017-01-21 0 <--- day without any record
2017-01-22 1
2017-01-23 1
2017-01-24 1
2017-01-25 1
2017-01-26 0 <--- day without any record
2017-01-27 27
2017-01-28 125
2017-01-29 190
2017-01-30 127
2017-01-31 319
But I don't want to count all data for each day, I want to count data where one column has specific value. So I thought it might be something like this (I added where clause):
declare #start datetime = CAST(getdate() as date)
declare #end datetime = dateadd(day, -10, #start)
;with amonth(day) as
(
select #end as day
union all
select day + 1
from amonth
where day < CAST(#start as date)
)
select CAST(amonth.day as date) as dat, count(vrijeme) as c
from amonth
left join Dnevnik on CAST(vrijeme as date) = CAST(amonth.day as date)
where tipZapisa = 6
group by CAST(amonth.day as date) order by dat
but this code gives me results without those empty days (where count is 0)
dat c
2017-01-22 1
2017-01-27 9
2017-01-28 67
2017-01-29 33
2017-01-30 46
2017-01-31 37
In the last result, I just want to include days which doesn't have any records.
Thanks in advance
Keep your join LEFT , stop using LEFT columns in NULL -prohibiting predicates in WHERE. Include it in ON
with amonth(day) as
(
select #end as day
union all
select day + 1
from amonth
where day < CAST(#start as date)
)
select CAST(amonth.day as date) as dat, count(vrijeme) as c
from amonth
left join Dnevnik on CAST(vrijeme as date) = CAST(amonth.day as date)
and tipZapisa = 6
group by CAST(amonth.day as date) order by dat
pre populate #START with the date of the 10th matching record, then feed it into your second query
SELECT #START = MIN(DQ.dat) FROM (select DISTINCT TOP 10 CAST(amonth.day as date) as dat
from Dnevnik WHERE tipZapisa = 6 ORDER BY amonth.day as date DESC) DQ
then you should be able to return the actual 10 days with the matching condition

T/SQL - Group/Multiply records

Source date:
CREATE TABLE #Temp (ID INT Identity(1,1) Primary Key, BeginDate datetime, EndDate datetime, GroupBy INT)
INSERT INTO #Temp
SELECT '2015-06-05 00:00:00.000','2015-06-12 00:00:00.000',7
UNION
SELECT '2015-06-05 00:00:00.000', '2015-06-08 00:00:00.000',7
UNION
SELECT '2015-10-22 00:00:00.000', '2015-10-31 00:00:00.000',7
SELECT *, DATEDIFF(DAY,BeginDate, EndDate) TotalDays FROM #Temp
DROP TABLE #Temp
ID BeginDate EndDate GroupBy TotalDays
1 6/5/15 0:00 6/8/15 0:00 7 3
2 6/5/15 0:00 6/12/15 0:00 7 7
3 10/22/15 0:00 10/31/15 0:00 7 9
Desired Output:
ID BeginDate EndDate GroupBy TotalDays GroupCnt GroupNum
1 6/5/15 0:00 6/8/15 0:00 7 3 1 1
2 6/5/15 0:00 6/12/15 0:00 7 7 1 1
3 10/22/15 0:00 10/29/15 0:00 7 9 2 1
3 10/29/15 0:00 10/31/15 0:00 7 9 2 2
Goal:
Group the records based on ID/BeginDate/EndDate.
Based on the GroupBy number (# of days) and TotalDays (days diff),
if the GroupBy => TotalDays, keep a single group record
else multiply the group records (1 record per GroupBy count) while staying within TotalDays limit.
Apologies if it's confusing but basically, in the above example, there should be one record for each group (ID/BeginDate/EndDate) for the record where days diff b/w Begin/End date = 7 or less (GroupBy).
If the days diff goes above 7 days, create another record (for every additional 7 days diff).
So since 1st two records have days diff of 7 days or less, there's only one record.
The 3rd record has days diff of 9 (7 + 2). Therefore, there should be 2 records (1st for the first 7 days and 2nd for the additional 2 days).
GroupCNT = how many records there're of the grouped records after applying the above records.
GroupNum is basically row number of the group.
GroupBy # can be different for each record. Dataset is huge so performance does matter.
One pattern I was able to figure out was related to the modulus b/w GroupBy and days diff.
When the GroupBy value is < days diff, modulus is always less than GroupBy. When the GroupBy value = days diff, modulus is always 0. And when the GroupBy value > days diff, modulus is always equals GroupBy. I'm not sure if/how to use that to group/multiply records to meet the requirement.
SELECT DISTINCT
ID
, BeginDate
, EndDate
, GroupBy
, DATEDIFF(DAY,BeginDate, EndDate) TotalDays
, CAST(GroupBy as decimal(18,6))%CAST(DATEDIFF(DAY,BeginDate, EndDate) AS decimal(18,6)) Modulus
, CASE WHEN DATEDIFF(DAY,BeginDate, EndDate) <= GroupBy THEN BeginDate END NewBeginDate
, CASE WHEN DATEDIFF(DAY,BeginDate, EndDate) <= GroupBy THEN EndDate END NewEndDate
FROM #Temp
Update:
Forgot to mention/include that the begin/enddate, when the records gets multiplied, will change accordingly. In other words, begin/end date will reflect the GroupBy - desired output shows what I mean more clearly in the 3rd and 4th record.
Also, GroupCnt/GroupNum are not as important to calculate as grouping/multiplying the records.
You could do something like this using a recursive CTE..
;WITH cte AS (
SELECT ID,
BeginDate,
EndDate,
GroupBy,
DATEDIFF(DAY, BeginDate, EndDate) AS TotalDays,
1 AS GroupNum
FROM #Temp
UNION ALL
SELECT ID,
BeginDate,
EndDate,
GroupBy,
TotalDays,
GroupNum + 1
FROM cte
WHERE GroupNum * GroupBy < TotalDays
)
SELECT ID,
BeginDate = CASE WHEN GroupNum = 1 THEN BeginDate
ELSE DATEADD(DAY, GroupBy * (GroupNum - 1), BeginDate)
END ,
EndDate = CASE WHEN TotalDays <= GroupBy THEN EndDate
WHEN DATEADD(DAY, GroupBy * GroupNum, BeginDate) > EndDate THEN EndDate
ELSE DATEADD(DAY, GroupBy * GroupNum, BeginDate)
END ,
GroupBy,
TotalDays,
COUNT(*) OVER (PARTITION BY ID) GroupCnt,
GroupNum
FROM cte
OPTION (MAXRECURSION 0)
the cte builds out a recordset like this.
ID BeginDate EndDate GroupBy TotalDays GroupNum
----------- ----------------------- ----------------------- ----------- ----------- -----------
1 2015-06-05 00:00:00.000 2015-06-08 00:00:00.000 7 3 1
2 2015-06-05 00:00:00.000 2015-06-12 00:00:00.000 7 7 1
3 2015-10-22 00:00:00.000 2015-10-31 00:00:00.000 7 9 1
3 2015-10-22 00:00:00.000 2015-10-31 00:00:00.000 7 9 2
then you just have to take this and use some case statements to determine what the begin and end date should be.
you should end up with
ID BeginDate EndDate GroupBy TotalDays GroupCnt GroupNum
----------- ----------------------- ----------------------- ----------- ----------- ----------- -----------
1 2015-06-05 00:00:00.000 2015-06-08 00:00:00.000 7 3 1 1
2 2015-06-05 00:00:00.000 2015-06-12 00:00:00.000 7 7 1 1
3 2015-10-22 00:00:00.000 2015-10-29 00:00:00.000 7 9 2 1
3 2015-10-29 00:00:00.000 2015-10-31 00:00:00.000 7 9 2 2
since you're using SQL 2012, you can also use the LAG and LEAD functions in your final query.
;WITH cte AS (
SELECT ID,
BeginDate,
EndDate,
GroupBy,
DATEDIFF(DAY, BeginDate, EndDate) AS TotalDays,
1 AS GroupNum
FROM #Temp
UNION ALL
SELECT ID,
BeginDate,
EndDate,
GroupBy,
TotalDays,
GroupNum + 1
FROM cte
WHERE GroupNum * GroupBy < TotalDays
)
SELECT ID,
BeginDate = COALESCE(LAG(BeginDate) OVER (PARTITION BY ID ORDER BY GroupNum) + GroupBy * (GroupNum - 1), BeginDate),
EndDate = COALESCE(LEAD(BeginDate) OVER (PARTITION BY ID ORDER BY GroupNum) + GroupBy * GroupNum, EndDate),
GroupBy,
TotalDays,
COUNT(*) OVER (PARTITION BY ID) GroupCnt,
GroupNum
FROM cte
OPTION (MAXRECURSION 0)
CREATE TABLE dim_number (id INT);
INSERT INTO dim_number VALUES ((0), (1), (2), (3)); -- Populate this to a large number
SELECT
#Temp.Id,
CASE WHEN dim_number.id = 0
THEN #Temp.BeginDate
ELSE DATEADD(DAY, dim_number.id * #Temp.GroupBy, #Temp.BeginDate)
END AS BeginDate,
CASE WHEN dim_number.id = parts.count
THEN #Temp.EndDate
ELSE DATEADD(DAY, (dim_number.id + 1) * #Temp.GroupBy, #Temp.BeginDate)
END AS EndDate,
#Temp.GroupBy AS GroupBy,
DATEDIFF(DAY, #Temp.BeginDate, #Temp.EndDate) AS TotalDays,
parts.count + 1 AS GroupCnt,
dim_number.id + 1 AS GroupNum
FROM
#Temp
CROSS APPLY
(SELECT DATEDIFF(DAY, #Temp.BeginDate, #Temp.EndDate) / #Temp.GroupBy AS count) AS parts
INNER JOIN
dim_number
ON dim_number.id >= 0
AND dim_number.id <= parts.count

SQL - creating a list of custom dates between two dates

I am having trouble compiling a query than can do the following:
I have a table which has a startDate and endDate [tblPayments]
I have a column which stores a specific paymentDay [tblPayments]
Data
paymentID startDate endDate paymentDay
1 2016-01-01 2016-12-31 25
2 2015-06-01 2016-06-30 16
I am trying to generate a SELECT query which will split this specific table into separate lines based on the amount of months between these two dates, and set the paymentDay as the day for these queries
Example Output
paymentID expectedDate
1 2016-01-25
1 2016-02-25
1 2016-03-25
1 2016-04-25
1 2016-05-25
1 2016-06-25
1 2016-07-25
1 2016-08-25
1 2016-09-25
1 2016-10-25
1 2016-11-25
1 2016-12-25
2 2015-06-16
2 2015-07-16
2 2015-08-16
2 2015-09-16
2 2015-10-16
2 2015-11-16
2 2015-12-16
2 2016-01-16
2 2016-02-16
2 2016-03-16
2 2016-04-16
2 2016-05-16
I have found a query which will select the months between these dates but its adapting it to my table above, and multiple startDates and endDates I am struggling with
spliting the months
declare #start DATE = '2015-01-01'
declare #end DATE = '2015-12-31'
;with months (date)
AS
(
SELECT #start
UNION ALL
SELECT DATEADD(MM,1,date)
from months
where DATEADD(MM,1,date)<=#end
)
select Datename(MM,date) from months
This query is limited to just one startDate and endDate, so I haven't expanded it to change the DAY of the date.
Use a date table and a simple inner join
DECLARE #tblPayments table (paymentID int identity(1,1), startDate date, endDate date, paymentDay int)
INSERT #tblPayments VALUES
('2016-01-01', '2016-12-31', 25),
('2015-06-01', '2016-06-30', 16)
;WITH dates AS -- Build date within the range of startDate and endDate
(
SELECT MIN(startDate) AS Value, MAX(endDate) AS MaxDate FROM #tblPayments
UNION ALL
SELECT DATEADD(DAY, 1, Value), MaxDate
FROM dates WHERE DATEADD(DAY, 1, Value) <= MaxDate
)
SELECT pay.paymentID, dates.Value AS expectedDate
FROM
#tblPayments pay
INNER JOIN dates ON
dates.Value BETWEEN pay.startDate AND pay.endDate
AND DAY(dates.Value) = paymentDay
OPTION (maxrecursion 0)
I would create an in memory calendar table and then perform a simple query by joining to that:
-- Create a table with all the dates between the min and max dates in the
-- data table
DECLARE #Calendar TABLE
(
[CalendarDate] DATETIME
)
DECLARE #StartDate DATETIME
DECLARE #EndDate DATETIME
SELECT #StartDate = MIN(startdate), #EndDate = MAX(enddate) FROM YourDataTable
WHILE #StartDate <= #EndDate
BEGIN
INSERT INTO #Calendar (CalendarDate)
SELECT #StartDate
SET #StartDate = DATEADD(dd, 1, #StartDate)
END
-- Join to return only dates between the start and end date that match the Payment Day
SELECT D.PaymentId, C.CalendarDate FROM YourDataTable D
INNER JOIN #Calendar C ON C.CalendarDate BETWEEN D.StartDate AND D.EndDate
AND DATEPART(day, C.CalendarDate) = D.PaymentDay