How should a GraphQL request for file upload look like? - file-upload

Question

I use Graphene on the server side with similar code to the one from documentation:
class UploadFile(graphene.ClientIDMutation):
class Input:
pass
# nothing needed for uploading file
# your return fields
success = graphene.String()
#classmethod
def mutate_and_get_payload(cls, root, info, **input):
# When using it in Django, context will be the request
files = info.context.FILES
# Or, if used in Flask, context will be the flask global request
# files = context.files
# do something with files
return UploadFile(success=True)
It's all clear, but how should the request look like ?
I've seen people suggesting multipart/form-data, but AFAIK that requires additional layer to parse the multipart request, so that's probably not what I need.. or is it ? :
curl -X "POST" "http://127.0.0.1:5001/graphql" \
-H 'Content-Type: multipart/form-data; boundary=----GraphQLFileUpload' \
-F "operations={\"query\":\"mutation ($files: [Upload!]!) {uploadFile(selfie: $file) {status}}\",\"variables\":{}}" \
-F "map={\"x\":[\"variables.files.x\"]}" \
-F "x=#/tmp/dummy.jpg "

Answer 1

I'll reply myself. The curl code I had was based on an external library that confused the hell out of me.
Here's my solution that doesn't require any additional library:
Python server code (graphene):
class UploadImage(graphene.Mutation):
class Arguments(object):
file = graphene.String(required=True)
status = graphene.Boolean()
def mutate(self, info, file):
img = info.context.files[file].read()
# more stuff
return UploadImage(status=True)
Curl request (multipart form)
curl -X POST http://localhost:5001/graphql \
-H 'content-type: multipart/form-data; boundary=----GraphQlFileUpload' \
-F 'query=mutation {uploadImage(file: "photo") {status}}' \
-F 'photo=#selfie.jpg'