I'm new here and I'm writing my first php code. I want to prepare a multiple choice quiz in which, after click on a button at the end of the page, the radios button (the choices of the test) will remain checked and unchangeable. I simplify the code in this way:
<?php
$choice1 = "a";
$choice2 = "b";
?>
<form method="post" name="testForm" id="testForm">
<ul>
<li><input type="radio" name="q1" value="a"
<?php if(isset($_POST['test-result']) && $radioVal==$choice1){ echo "disabled='disabled' checked";}?>
<?php if(isset($_POST['test-result']) && $radioVal<>$choice1){ echo "disabled='disabled'";}?>>
<?php echo "<span id='question'>". $choice1 ."</span>";?> </li>
<li><input type="radio" name="q1" value="b"
<?php if(isset($_POST['test-result']) && $radioVal==$choice2){ echo "disabled='disabled' checked";}?>
<?php if(isset($_POST['test-result']) && $radioVal<>$choice2){ echo "disabled='disabled'";}?>>
<?php echo "<span id='question'>". $choice2 ."</span>";?> </li>
</ul><br>
<button class='button' name='test-result'>Finaliza el test</button>
</form>
<?php
if (isset($_POST['test-result']))
{
$radioVal = $_POST["q1"];
}
?>
However, after click on the button, all radios remain uncheged (and this is ok) but the choices made are not checked. Can someone help me? Thanks in advance!
Checkbox is not showing checked because variable $radioVal is set after input box. To resolve your issue could you please set $radioVal before from.
Related
I have created a JQuery DataTable from mysql row as below
with the help of PHP.
What I want is to display the button of the last Column
depending on a certain value of the $row['Status'] so I am not using JSON Data
in order to use the data object inside the DataTable variable.
Any suggestions?
<td>'.$row['Status'].'</td>
<td><button id="'.$row['ticket_id'].'" onclick="showDetails(this)" class="btn btn-default" type="submit" data-toggle="modal" data-target="#CommentModal">Edit</button></td>';
Considering you only want to show the button with id id="'.$row['ticket_id'].'"
you may just can use a simple if and concatenate echoes the result like this :
<td>'.$row['Status'].'</td>
<td>';
<?php
if($row['Status'] == 'active'){
?>
<button id="'.$row['ticket_id'].'" onclick="showDetails(this)" class="btn
btn-default" type="submit" data-toggle="modal" data-target="#CommentModal">Edit</button>
<?php
}else{
?>
<p>The status is inactive <?php echo $row['Status']; ?> </p>
<?php
}
?>
'</td>';
Considerign your $row['Status']" have the status active
Hope this suggestion helps you.
I have a problem which I am unable to fix, maybe somebody can help?
I have a dijit.layout.ContentPane at the top of my page, this sits in a dijit.layout.BorderContainer. On page load the contents of the container shift right and down by about 15px. All other elements work fine.
I have isolated the issue to dijit.layout.ContentPane. In side the container I am running some php if statements and drawing some simple buttons:
<!-- Here are the common buttons above the tabs -->
<div id="toolPane" dojoType="dijit.layout.ContentPane" region="top" >
<?php
if($this->restrict == 1){
if($this->teammembers == 1 || $this->newleaders == 1 || $this->newadminleaders == 1){
if ($this->mayUpdateSummary){
?><span style="white-space:nowrap;" ><?php echo $this->issueActionLink($issue, 'Create report', 'report', 'reportLink'); ?></span>
<span style="white-space:nowrap;" ><a class="emailLink" href="mailto:?subject=Task%20%23<?php echo $issue->id; ?>&body=<?php echo urlencode($this->serverUrl(true)); ?>">Share link</a></span><?php
}
}
}else if($this->restrict == 2){
if ($this->mayUpdateSummary){
?><span style="white-space:nowrap;" ><?php echo $this->issueActionLink($issue, 'Create report', 'report', 'reportLink'); ?></span>
<span style="white-space:nowrap;" ><a class="emailLink" href="mailto:?subject=Task%20%23<?php echo $issue->id; ?>&body=<?php echo urlencode($this->serverUrl(true)); ?>">Share link</a></span><?php
}
}
?>
<?php if ($this->mayUpdateSummary): ?>
<span style="white-space:nowrap;" ><?php echo $this->issueActionLink($issue,'Edit summary', 'progress-summary', 'editbutton'); ?></span>
<?php endif; ?>
<?php if ($closeButton): ?>
<span style="white-space:nowrap;" ><?php echo $closeButton; ?></span>
<?php endif; ?>
<?php if ($reopenButton): ?>
<span style="white-space:nowrap;" ><?php echo $reopenButton; ?></span>
<?php endif; ?>
</div>
Ok, we have decided to hide the page until the dijit elements have loaded. To do this we have added this script which fades in the page giving it time to sort itself out before it is displayed:
<script type="text/javascript">
$(document).ready(function(){
$(".content").hide();
});
$(window).load(function(){
$(".content").fadeIn("fast");
});
</script>
<div class="content">
[faded in content goes here]
</div>
i want to implement this html code into yii format.
<input type="checkbox" name="" class="checkbox1" onclick="" id=""/>
<label class="gender" for="" id="">Female</label>
i tried to implement this code.
$form->checkBox($model,'gender',array('class'=>'gen'),array('template'=>'{label}')
but i don't know how to assign gender css class to label field? could please suggest me how to implement above html code in right way.
Please refer this Different Checkbox Properties. you will get answer from there...
if you want to use Chtml::checkBox...
<?php
echo CHtml::checkBox('gender',
array(''),array('class'=>'checkbox1')); ?>
<label style="width:150px;"class="gender">
<?php echo 'Gender' ;?>
</label>
if you want to use $form->checkBox...
<?php
echo $form->checkBox($model,'gender', array('class'=>'checkbox1'));
?>
<label style="width:150px;"class="gender">
<?php echo 'Gender';?>
</label>
Try it's working i have tried in my form...
CHtml::checkBox() gives you only the input tag
To create a <label> you should use CHtml::label() method. There you can set class property for this tag.
Edited:
I do this:
<?php echo $form->checkBox($model, 'gender', array('class'=>'checkbox1')); ?>
<?php echo $form->labelEx($model,'gender', array('class'=>'genger')); ?>
You just can add labelOptions array value to control label:
echo $form->checkBoxList(
$model,
'attr',
array('ggg','hhh'),
'htmlOptions' => array(
'labelOptions' => array(
//put here what you want
)
)
);
I have a form and I want to upload a file. here is my code:
<div class="form">
<?php $form=$this->beginWidget('CActiveForm', array(
'id'=>'show-form',
'enableAjaxValidation'=>false,
'htmlOptions' => array('enctype' => 'multipart/form-data'),
)); ?>
<fieldset>
<legend>DATI TECNICI</legend>
<div class="row">
<?php echo $form->labelEx($model,'tec_data_file'); ?>
<?php echo $form->fileField($model,'tec_data_file',array('size'=>45,'maxlength'=>45)); ?>
<?php echo $form->error($model,'tec_data_file'); ?>
</div>
</fieldset>
<?php $this->endWidget(); ?>
</div><!-- form -->
There was nothing added to the database after submitting, I did a bit of debuging with firebug and figured out that filefield generates a code like this:
<input id="ytShow_tec_data_file" type="hidden" name="Show[tec_data_file]" value="">
<input id="Show_tec_data_file" type="file" name="Show[tec_data_file]" maxlength="45" size="45">
and two data are sent by $_POST for tec_data_file (which is my file field in db). The first var is empty (I think it is related to first hidden input). and the second one contains my file. and when I'm assigning the variables to my model for saving:
$modelPhoto->attributes = $_POST['Photo'];
the tec_data_file gets an empty string! So nothing gets uploaded to my db. Anyone have an idea how to solve this? If you need more i
You need something like:
$model = new Photo;
$model->attributes = $_POST['Photo'];
$model->image = CUploadedFile::getInstance($model,'file');
where file is the name of the field.
I haven't tested this, it's from the documentation.
hello friends I am newbie to YII. I have an image . After calling that image in Yii its code like is this
<img class="deals_product_image" src="<?php echo MPFunctions::uploaded_image_url($data->item_display_image()->file_ufilename); ?>" alt="<?php echo $data->name; ?>" />
in general html it is doing like this
<img alt="women jackets" src="files/items/images/4db3b3b6a7c06/womens-jacket-thumb.jpg" class="deals_product_image">
Now I want that this image should be a href link like
<a href="files/items/images/4db3b3b6a7c06/womens-jacket-thumb.jpg img src="files/items/images/4db3b3b6a7c06/womens-jacket-thumb.jpg class="deals_product_image"/> </a>
so for this I used code like this
<?php echo CHtml::link('', array('items/viewslug', 'slug'=>$data->slug)); ?>
But it is not showing any link tag like <a href="">
so can any one tell me what should I do?What should I write in between '' tags?
You should simply give the html for the <img> tag as the first parameter:
$imageUrl = MPFunctions::uploaded_image_url($data->item_display_image()->file_ufilename);
$image = '<img class="deals_product_image" src="'.$imageUrl.'" alt="'.$data->name.'" />';
echo CHtml::link($image, array('items/viewslug', 'slug'=>$data->slug));
By the way, you can use CHtml::image to create the <img> tag as well:
$imageUrl = MPFunctions::uploaded_image_url($data->item_display_image()->file_ufilename);
$image = CHtml::image($imageUrl, $data->name, array('class' => 'deals_product_image'));
echo CHtml::link($image, array('items/viewslug', 'slug'=>$data->slug));