import numpy as np
import os.path
from skimage.io import imread
from skimage import data_dir
img = imread(os.path.join(data_dir, 'checker_bilevel.png'))
import matplotlib.pyplot as plt
#plt.imshow(img, cmap='Blues')
#plt.show()
imgT = img.T
plt.figure(1)
plt.imshow(imgT,cmap='Greys')
#plt.show()
imgR = img.reshape(20,5)
plt.figure(2)
plt.imshow(imgR,cmap='Blues')
plt.show(1)
I read that plt.figure() will create or assign the image a new ID if not explicitly given one. So here, I have given the two figures, ID 1 & 2 respectively. Now I wish to see only one one of the image.
I tried plt.show(1) epecting ONLY the first image will be displayed but both of them are.
What should I write to get only one?
plt.clf() will clear the figure
import matplotlib.pyplot as plt
plt.plot(range(10), 'r')
plt.clf()
plt.plot(range(12), 'g--')
plt.show()
plt.show will show all the figures created. The argument you forces the figure to be shown in a non-blocking way. If you only want to show a particular figure you can write a wrapper function.
import matplotlib.pyplot as plt
figures = [plt.subplots() for i in range(5)]
def show(figNum, figures):
if plt.fignum_exists(figNum):
fig = [f[0] for f in figures if f[0].number == figNum][0]
fig.show()
else:
print('figure not found')
Related
I create a heatmap with the following snippet:
import numpy as np
import matplotlib.pyplot as plt
d = np.random.normal(.4,2,(10,10))
plt.imshow(d,cmap=plt.cm.RdBu)
plt.colorbar()
plt.show()
The result is plot below:
Now, since the middle point of the data is not 0, the cells in which the colormap has value 0 are not white, but rather a little reddish.
How do I force the colormap so that max=blue, min=red and 0=white?
Use a DivergingNorm.
Note: From matplotlib 3.2 onwards DivergingNorm is renamed to TwoSlopeNorm.
import numpy as np
import matplotlib.pyplot as plt
import matplotlib.colors as mcolors
d = np.random.normal(.4,2,(10,10))
norm = mcolors.DivergingNorm(vmin=d.min(), vmax = d.max(), vcenter=0)
plt.imshow(d, cmap=plt.cm.RdBu, norm=norm)
plt.colorbar()
plt.show()
A previous SO post (Change colorbar gradient in matplotlib) wanted a solution for a more complicated situation, but one of the answers talked about the MidpointNormalize subclass in the matplotlib documentation. With that, the solution becomes:
import matplotlib as mpl
import numpy as np
import matplotlib.pyplot as plt
class MidpointNormalize(mpl.colors.Normalize):
## class from the mpl docs:
# https://matplotlib.org/users/colormapnorms.html
def __init__(self, vmin=None, vmax=None, midpoint=None, clip=False):
self.midpoint = midpoint
super().__init__(vmin, vmax, clip)
def __call__(self, value, clip=None):
# I'm ignoring masked values and all kinds of edge cases to make a
# simple example...
x, y = [self.vmin, self.midpoint, self.vmax], [0, 0.5, 1]
return np.ma.masked_array(np.interp(value, x, y))
d = np.random.normal(.4,2,(10,10))
plt.imshow(d,cmap=plt.cm.RdBu,norm=MidpointNormalize(midpoint=0))
plt.colorbar()
plt.show()
Kudos to Joe Kington for writing the subclass, and to Rutger Kassies for pointing out the answer.
I have the following snippet in the first cell of a Jupyter notebook:
import matplotlib.pyplot as plt
import pandas as pd
import ipywidgets as widgets
import numpy as np
out = widgets.Output()
data = pd.DataFrame(np.random.normal(size = 50))
plt.ioff()
with out:
fig, axes = plt.subplots()
data.hist(ax = axes)
display(fig)
plt.ion()
display(out)
If I restart the kernel and run this first cell, I see this output:
<Figure size 640x480 with 1 Axes>
However, if I run this first cell a second time, I see a matplotlib figure as I intended. This behavior also shows up if I move everything after the import of matplotlib to a second cell, restart the kernel, and rerun the entire notebook.
Is this difference in behavior intentional?
The code rearranging and adding magic command '%matplotlib notebook' work for me.
%matplotlib notebook
import matplotlib.pyplot as plt
import pandas as pd
import ipywidgets as widgets
import numpy as np
out = widgets.Output()
plt.ioff()
fig, axes = plt.subplots()
plt.ion()
data = pd.DataFrame(np.random.normal(size = 50))
data.hist(ax = axes)
display(out)
with out:
display(fig)
I typically don't have problems with matplotlib legend, but this is the first time I am using it with multiple seaborn plots, and the following does not work.
fig = plt.figure(figsize=(10,6))
a =sns.regplot(x='VarX', y='VarY1', data=data)
b = sns.regplot(x='VarX', y='VarY2', data=data)
c = sns.regplot(x='VarX', y='VarY3', data=data)
fig.legend(handles=[a, b, c],labels=['First','Second','Third'])
fig.show()
What am I doing wrong?
seaborn.regplot returns an axes. You cannot create a legend proxy handle from an axes. However this is not even necessary. Remove the handles from the legend and it should give the desired plot.
import matplotlib.pyplot as plt
import numpy as np; np.random.seed(1)
import pandas as pd
import seaborn as sns
data=pd.DataFrame({"VarX" : np.arange(10),
'VarY1': np.random.rand(10),
'VarY2': np.random.rand(10),
'VarY3': np.random.rand(10)})
fig = plt.figure(figsize=(10,6))
sns.regplot(x='VarX', y='VarY1', data=data)
sns.regplot(x='VarX', y='VarY2', data=data)
sns.regplot(x='VarX', y='VarY3', data=data)
fig.legend(labels=['First','Second','Third'])
plt.show()
import matplotlib.pyplot as plt
import numpy as np
ydata = [55,60,65,70,75,80]
xdata = [1,2,3,4,5,6]
plt.plot(xdata, ydata)
set(plt.gca,'XTickLabel',{'Jan','Feb','Mar','April','May','June'})
plt.show()
I am using matplotlib and trying to add text values to appear on the x axis.
I have tried to use the following code but get the following error message
set(plt.gca,'XTickLabel',
{'Jan','Feb','Mar','April','May','June'})
TypeError: set expected at most 1 arguments, got 3 I am not sure what this
is referring get current access I have set the value
Sets are a Python data structure, it has nothing to do with what you want here, you only need to use ax.set_xticklabels and ax.set_xticks to ensure all of them show in the plot:
import matplotlib.pyplot as plt
import numpy as np
fig, ax = plt.subplots()
ydata = [55,60,65,70,75,80]
xdata = [1,2,3,4,5,6]
ax.set_xticks(xdata)
ax.set_xticklabels(['Jan','Feb','Mar','April','May','June'])
plt.plot(xdata, ydata)
plt.show()
I ran the following code to get two plots next to each other (it is a minimal working example that you can copy):
import pandas as pd
import numpy as np
from matplotlib.pylab import plt
comp1 = np.random.normal(0,1,size=200)
values = pd.Series(comp1)
plt.close("all")
f = plt.figure()
plt.show()
sp1 = f.add_subplot(2,2,1)
values.hist(bins=100, alpha=0.5, color="r", normed=True)
sp2 = f.add_subplot(2,2,2)
values.plot(kind="kde")
Unfortunately, I then get the following image:
This is also an interesting layout, but I wanted the figures to be next to each other. What did I do wrong? How can I correct it?
For clarity, I could also use this:
import pandas as pd
import numpy as np
from matplotlib.pylab import plt
comp1 = np.random.normal(0,1,size=200)
values = pd.Series(comp1)
plt.close("all")
fig, axes = plt.subplots(2,2)
plt.show()
axes[0,0].hist(values, bins=100, alpha=0.5, color="r", normed=True) # Until here, it works. You get a half-finished correct image of what I was going for (though it is 2x2 here)
axes[0,1].plot(values, kind="kde") # This does not work
Unfortunately, in this approach axes[0,1] refers to the subplot that has a plot method but does not know kind="kde". Please take into consideration that the in the first version plot is executed on the pandas object, whereas in the second version plot is executed on the subplot, which does not work with the kind="kde" parameter.
use ax= argument to set which subplot object to plot:
import pandas as pd
import numpy as np
from matplotlib.pylab import plt
comp1 = np.random.normal(0,1,size=200)
values = pd.Series(comp1)
plt.close("all")
f = plt.figure()
sp1 = f.add_subplot(2,2,1)
values.hist(bins=100, alpha=0.5, color="r", normed=True, ax=sp1)
sp2 = f.add_subplot(2,2,2)
values.plot(kind="kde", ax=sp2)