How can I select the colors for a linear gradient in svg-edit?
The "Change fill color" popup lets me select a gradient, which seems to be based on the current solid color of the shape. But there is no color-picker for either vertex.
Double-click the circled "start" and "end" points in the screenshot:
Related
I have an image and I want to see how many pixels are in different parts of the image. Is there a software I can use to do this?
In Gimp, the "Histogram" dialog applies to the selection, so the pixel count displayed is the pixels in the selection (weighted by their selection level):
In the image below the selection covers the black circle which has a 100px radius. The Pixels value is close to 100²*Pi (314000 instead of 314159).
The Count is the number of pixels between the two values indicated by the handles at the bottom of the histogram.
Of course the selection can have any shape and be obtained with various tools.
I assume PS has something equivalent.
I'm using python to create boxplots seen here:
The filers are 'o' markers, but the width of the circles are too thick.
I want to know how to show hollow instead of solid dots.
Can SSRS make a graded colour scale (like Excel). I am attatching an image to explain what I mean.
Regards.
Yes, but it's not very easy. You can use an expression to dynamically set the fill color of a cell. The colors can be specified with their hex representation like "#AC9494". You will have to come up with a formula to define which colors the scale goes through.
Red is "#FF0000" and green is "#00FF00". So your formula would have to scale the amount of green and red (and maybe some blue) you want, convert that to hex, and then concatenate them into this format. If you search for terms like "smooth color gradient" you will get some helpful examples to point you in the right direction.
I need to know how to get the inverse color by lesscss.
Example: I have #000, i need #FFF.
And i need the detail explanation of spin(). And necessary links where i can see a color wheel where i can understand how spin() works.
Thanks.
Why it is not working as you expect
The spin() function only deals with hue (color), not value (grey scale changes are a value change). Take a look at Figures 9 and 10 on this page from North Carolina State University's site. Those figures help show the difference. The spin() function is rotating only in the two dimensional space of the hue circle of color, not along the axis of the third dimensional space dealing with saturation; i.e. the gray scale itself, which is what differentiates white from black, both of which have no color saturation).
This is why on the LESS site we read of spin() (emphasis added):
Note that colors are passed through an RGB conversion, which doesn't
retain hue value for greys (because hue has no meaning when there is
no saturation)
And
Colors are always returned as RGB values, so applying spin to a grey
value will do nothing.
Getting what you want (Color Inversion)
See #seven-phases-max's answer.
The spin function changes the Hue property of a colour. Shades of grey (incl. white and black) are achromatic colours (i.e. they have the same "undefined" hue value).
To simply invert a colour use either difference function:
difference(white, #colour)
or the simple colour arithmetic:
(#fff - #colour)
In order to emphasize data, I try to draw a box from top to down of the graphpane. This works well as long I stay with a linear axis.
When I change to a log axis the height of the box will not fit. How do I calculate the right height of such a box for log scales?
Change the coordinate frame for your box object. Use the XAxisYChartFraction, and (0,1) as the Y coordinates. This should do the trick.