I have the following query in BigQuery:
#Standard SQL
SELECT *
FROM `Table_1`
LEFT JOIN `Table_2` ON (timestamp BETWEEN TimeStampStart AND TimeStampEnd)
But I get the following Error:
Error: LEFT OUTER JOIN cannot be used without a condition that is an equality of fields from both sides of the join.
If I use JOIN instead of LEFT JOIN, it works, but I want to keep all the rows from Table_1 (so also the ones which aren't matched to Table_2)
How to achieve this?
This is absolutely stupid... but the same query will work if you add a condition that matches a column from table1 with a column from table2:
WITH Table_1 AS (
SELECT CAST('2018-08-15' AS DATE) AS Timestamp, 'Foo' AS Foo
UNION ALL
SELECT CAST('2018-09-15' AS DATE), 'Foo'
), Table_2 AS (
SELECT CAST('2018-08-14' AS DATE) AS TimeStampStart, CAST('2018-08-16' AS DATE) AS TimeStampEnd, 'Foo' AS Bar
)
SELECT *
FROM Table_1
LEFT JOIN Table_2 ON Table_1.Foo = Table_2.Bar AND Table_1.Timestamp BETWEEN Table_2.TimeStampStart AND Table_2.TimeStampEnd
See if you have additional matching criteria that you can use (like another column that links table1 and table2 on equality).
A LEFT JOIN is always equivalent to the UNION of :
the INNER JOIN between the same two arguments on the same join predicate, and
the set of rows from the first argument for which no matching row is found (and properly extended with null values for all columns retained from the second argument)
That latter portion can be written as
SELECT T1.*, null as T2_C1, null as T2_C2, ...
FROM T1
WHERE NOT EXISTS (SELECT * FROM T2 WHERE )
So if you spell out the UNION you should be able to get there.
Interesting. This works for me in standard SQL:
select *
from (select 1 as x) a left join
(select 2 as a, 3 as b) b
on a.x between b.a and b.b
I suspect you are using legacy SQL. Such switch to standard SQL. (And drop the parentheses after the between.)
The problem is:
#(Standard SQL)#
This doesn't do anything. Use:
#StandardSQL
Hi as per the documentation, "(" has a special meaning, so please try without the brackets.
SELECT * FROM Table_1
LEFT JOIN Table_2 ON Table_1.timestamp >= Table_2.TimeStampStart AND Table_1.timestamp <= Table_2.TimeStampEnd
Documentation here
Related
I have two tables.
Table1 is 1591 rows. Table2 is 270 rows.
I want to fetch specific column data from Table2 based on some condition between them and also exclude duplicates which are in Table2. Which I mean to join the tables but get only one value from Table2 even if the condition has occurred more than time. The result should be exactly 1591 rows.
I tried to make Left,Right, Inner joins but the data comes more than or less 1591.
Example
Table1
type,address,name
40,blabla,Adam
20,blablabla,Joe
Table2
type,currency
40,usd
40,gbp
40,omr
Joining on 'type'
Result
type,address,name,currency
40,blabla,name,usd
20,blblbla,Joe,null
try this it has to work
select *
from
Table1 h
inner join
(select type,currency,ROW_NUMBER()over (partition by type order by
currency) as rn
from
Table2
) sr on
sr.type=h.type
and rn=1
Try this. It's standard SQL, therefore, it should work on your rdbms system.
select * from Table1 AS t
LEFT OUTER JOIN Table2 AS y ON t.[type] = y.[type] and y.currency IN (SELECT MAX(currency) FROM Table2 GROUP BY [type])
If you want to control which currency is joined, consider altering Table2 by adding a new column active/non active and modifying accordingly the JOIN clause.
You can use outer apply if it's supported.
select a.type, a.address, a.name, b.currency
from Table1 a
outer apply (
select top 1 currency
from Table2
where Table2.type = a.type
) b
I typical way to do this uses a correlated subquery. This guarantees that all rows in the first table are kept. And it generates an error if more than one row is returned from the second.
So:
select t1.*,
(select t2.currency
from table2 t2
where t2.type = t1.type
fetch first 1 row only
) as currency
from table1 t1;
You don't specify what database you are using, so this uses standard syntax for returning one row. Some databases use limit or top instead.
I've got 2 tables in BigQuery that I'd like to join. Table 1 has integers, and table 2 has non-overlapping integer ranges (start, end). I'd like to join table 1 and 2 to give me something like this:
-- table 1
value
1
4
9
10
-- table 2
start, end
0,5
6,9
10,15
-- joined
value,start,end
1,0,5
4,0,5
9,6,9
10,10,15
I thought this query would work:
SELECT *
FROM
[table1] a
INNER JOIN [table2] b
ON a.value BETWEEN b.start AND b.end
But that gives me this error
ON clause must be AND of = comparisons of one field name from each
table, with all field names prefixed with table name
I can get the correct result with this CROSS JOIN query:
SELECT *
FROM
[table1] a
CROSS JOIN [table2] b
WHERE a.value BETWEEN b.start AND b.end
But the docs say this should be avoided if possible:
CROSS JOIN operations do not allow ON clauses. CROSS JOIN can return a
large amount of data and might result in a slow and inefficient query
or in a query that exceeds the maximum allowed per-query resources.
Such queries will fail with an error. When possible, prefer queries
that do not use CROSS JOIN
So, is it possible to do an INNER JOIN with a between, or improve the CROSS JOIN some other way?
This is a limitation for BigQuery Legacy SQL.
You should use BigQuery Standard SQL instead:
#standardSQL
SELECT *
FROM
`table1` a
INNER JOIN `table2` b
ON a.value BETWEEN b.start AND b.end
In standard SQL - you should use back-ticks instead of brackets.
Also keep in mind that end is a reserved keyword, so to make above work you need to enclose it in back-ticks also.
See below (along with dummy data from your question):
#standardSQL
WITH table1 AS (
SELECT value
FROM UNNEST([1, 4, 9, 10]) AS value
),
table2 AS (
SELECT chunk.start, chunk.`end`
FROM UNNEST([STRUCT<start INT64, `end` INT64>(0,5),(6,9),(10,15)]) AS chunk
)
SELECT *
FROM `table1` a
INNER JOIN `table2` b
ON a.value BETWEEN b.start AND b.`end`
-- ORDER BY value
In postgresql I can use subquery in join condition
SELECT *
FROM table1 LEFT JOIN table2
ON table1.id1 = (SELECT id2 FROM table2 LIMIT 1);
But when I try to use it in Access
SELECT *
FROM table1 LEFT JOIN table2
ON table1.id1 = (SELECT TOP 1 id2 FROM table2);
I get syntax error. Is it actually impossible in Access or just my mistake?
I know that I can get the same result with WHERE, but my question is about possibilities of JOIN in Access.
It's not possible, per the MSDN documentation:
Syntax
FROM table1 [ LEFT | RIGHT ] JOIN table2 ON table1.field1 compopr table2.field2
And (emphasis mine):
field1, field2: The names of the fields that are joined. The fields must be of the same data type and contain the same kind of data, but they do not need to have the same name.
It appears you can't even have hard-coded values in your join; you must specify the column name to join against.
In your case, you would want:
SELECT *
FROM Table1
LEFT JOIN (
SELECT DISTINCT TOP 1 ID
FROM Table2
ORDER BY ID
) Table2Derived ON Table1.ID = Table2Derived.ID
I want to select all records from a table T1 where the values in columns A and B has no matching tuple for the columns C and D in table T2.
In mysql “Where not in” using two columns I can read how to accomplish that using the form select A,B from T1 where (A,B) not in (SELECT C,D from T2), but that fails in T-SQL for me resulting in "Incorrect syntax near ','.".
So how do I do this?
Use a correlated sub-query:
...
WHERE
NOT EXISTS (
SELECT * FROM SecondaryTable WHERE c = FirstTable.a AND d = FirstTable.b
)
Make sure there's a composite index on SecondaryTable over (c, d), unless that table does not contain many rows.
You can't do this using a WHERE IN type statement.
Instead you could LEFT JOIN to the target table (T2) and select where T2.ID is NULL.
For example
SELECT
T1.*
FROM
T1 LEFT OUTER JOIN T2
ON T1.A = T2.C AND T1.B = T2.D
WHERE
T2.PrimaryKey IS NULL
will only return rows from T1 that don't have a corresponding row in T2.
I Used it in Mysql because in Mysql there isn't "EXCLUDE" statement.
This code:
Concates fields C and D of table T2 into one new field to make it easier to compare the columns.
Concates the fields A and B of table T1 into one new field to make it easier to compare the columns.
Selects all records where the value of the new field of T1 is not equal to the value of the new field of T2.
SQL-Statement:
SELECT T1.* FROM T1
WHERE CONCAT(T1.A,'Seperator', T1.B) NOT IN
(SELECT CONCAT(T2.C,'Seperator', T2.D) FROM T2)
Here is an example of the answer that worked for me:
SELECT Count(1)
FROM LCSource as s
JOIN FileTransaction as t
ON s.TrackingNumber = t.TrackingNumber
WHERE NOT EXISTS (
SELECT * FROM LCSourceFileTransaction
WHERE [LCSourceID] = s.[LCSourceID] AND [FileTransactionID] = t.[FileTransactionID]
)
You see both columns exist in LCSourceFileTransaction, but one occurs in LCSource and one occurs in FileTransaction and LCSourceFileTransaction is a mapping table. I want to find all records where the combination of the two columns is not in the mapping table. This works great. Hope this helps someone.
Hi I have 2 tables. I want to list
all records in table1 which are present in
table2
all records in table2 which are not present in table1 with a where condition
Null rows will be returned by table1 in second condition but I am unable to get the query working correctly. It is only returning null rows
SELECT
A.CLMSRNO,A.CLMPLANO,A.GENCURRCODE,A.CLMNETLOSSAMT,
A.CLMLOSSAMT,A.CLMCLAIMPRCLLOSSSHARE
FROM
PAKRE.CLMCLMENTRY A
RIGHT OUTER JOIN (
SELECT
B.CLMSRNO,B.UWADVICETYPE,B.UWADVICENO,B.UWADVPREMCURRCODE,
B.GENSUBBUSICLASS,B.UWADVICENET,B.UWADVICEKIND,B.UWADVYEAR,
B.UWADVQTR,B.ISMANUAL,B.UWCLMNOREFNO
FROM
PAKRE.UWADVICE B
WHERE
B.ISMANUAL=1
) r
ON a.CLMSRNO=r.CLMSRNO
ORDER BY
A.CLMSRNO DESC;
Which OS are you using ?
Table aliases are case sensistive on some platforms, which is why your join condition ON a.CLMSRNO=r.CLMSRNO fails.
Try with A.CLMSRNO=r.CLMSRNO and see if that works
I'm not understanding your first attempt, but here's basically what you need, I think:
SELECT *
FROM TABLE1
INNER JOIN TABLE2
ON joincondition
UNION ALL
SELECT *
FROM TABLE2
LEFT JOIN TABLE1
ON joincondition
AND TABLE1.wherecondition
WHERE TABLE1.somejoincolumn IS NULL
I think you may want to remove the subquery and put its columns into the main query e.g.
SELECT A.CLMSRNO, A.CLMPLANO, A.GENCURRCODE, A.CLMNETLOSSAMT,
A.CLMLOSSAMT, A.CLMCLAIMPRCLLOSSSHARE,
B.CLMSRNO, B.UWADVICETYPE, B.UWADVICENO, B.UWADVPREMCURRCODE,
B.GENSUBBUSICLASS, B.UWADVICENET, B.UWADVICEKIND, B.UWADVYEAR,
B.UWADVQTR, B.ISMANUAL, B.UWCLMNOREFNO
FROM PAKRE.CLMCLMENTRY A
RIGHT OUTER JOIN PAKRE.UWADVICE B
ON A.CLMSRNO = B.CLMSRNO
WHERE B.ISMANUAL = 1
ORDER
BY A.CLMSRNO DESC;