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Hi tensorflow beginner here... I'm trying to get the value of a certain elements in an 2 dim tensor, in my case class scores from a probability matrix.
The probability matrix is (1000,81) with batchsize 1000 and number of classes 81. ClassIDs is (1000,) and contains the index for the highest class score for each sample. How do I get the corresponding class score from the probability matrix using tf.gather?
class_ids = tf.cast(tf.argmax(probs, axis=1), tf.int32)
class_scores = tf.gather_nd(probs,class_ids)
class_scores should be a tensor of shape (1000,) containing the highest class_score for each sample.
Right now I'm using a workaround that looks like this:
class_score_count = []
for i in range(probs.shape[0]):
prob = probs[i,:]
class_score = prob[class_ids[i]]
class_score_count.append(class_score)
class_scores = tf.stack(class_score_count, axis=0)
Thanks for the help!
You can do it with tf.gather_nd like this:
class_ids = tf.cast(tf.argmax(probs, axis=1), tf.int32)
# If shape is not dynamic you can use probs.shape[0].value instead of tf.shape(probs)[0]
row_ids = tf.range(tf.shape(probs)[0], dtype=tf.int32)
idx = tf.stack([row_ids, class_ids], axis=1)
class_scores = tf.gather_nd(probs, idx)
You could also just use tf.reduce_max, even though it would actually compute the maximum again it may not be much slower if your data is not too big:
class_scores = tf.reduce_max(probs, axis=1)
you need to run the tensor class_ids to get the values
the values will be a bumpy array
you can access numpy array normally by a loop
you have to do something like this :
predictions = sess.run(tf.argmax(probs, 1), feed_dict={x: X_data})
predictions variable has all the information you need
tensorflow only returns those tensor values which you run explicitly
I think this is what the batch_dims argument for tf.gather is for.
I want to know how BatchNormalization works in keras, so I write the code:
X_input = keras.Input((2,))
X = keras.layers.BatchNormalization(axis=1)(X_input)
model1 = keras.Model(inputs=X_input, outputs=X)
the input is a batch of two dimenstions vector, and normalizing it along axis=1, then print the output:
a = np.arange(4).reshape((2,2))
print('a=')
print(a)
print('output=')
print(model1.predict(a,batch_size=2))
and the output is:
a=
array([[0, 1],
[2, 3]])
output=
array([[ 0. , 0.99950039],
[ 1.99900079, 2.9985013 ]], dtype=float32)
I can not figure out the results. As far as I know, the mean of the batch should be ([0,1] + [2,3])/2 = [1,2], the var is 1/2*(([0,1] - [1,2])^2 + ([2,3]-[1,2])^2) = [1,1]. Finally, normalizing it with (x - mean)/sqrt(var), therefore the results are [-1, -1] and [1,1], where am I wrong?
BatchNormalization will substract the mean, divide by the variance, apply a factor gamma and an offset beta. If these parameters would actually be the mean and variance of your batch, the result would be centered around zero with variance 1.
But they are not. The keras BatchNormalization layer stores these as weights that can be trained, called moving_mean, moving_variance, beta and gamma. They are initialized as beta=0, gamma=1, moving_mean=0 and moving_variance=1. Since you don't have any train steps, BatchNorm does not change your values.
So, why don't you get exactly your input values? Because there is another parameter epsilon (a small number), which gets added to the variance. Therefore, all values are divided by 1+epsilon and end up a little bit below their input values.
I have two tensors of shape [1,4] say,
[1,2,3,4]
[0.2,0.3,0.4,0.5]
Now I want to merge them in merge layer (perhaps using some custom function using Tensorflow backend) so that they become
[1,0.2,2,0.3,3,0.4,4,0.5]
How can I achieve this? The shape of the tensor is fixed. Thank you for your time.
A possible solution is to concatenate the tensors along the axis 0 and then gather the values according to the indices, like that
import tensorflow as tf
from itertools import chain
A = tf.constant([1, 2, 3, 4])
B = tf.constant([0.2, 0.3, 0.4, 0.5])
# Cast A to be compatible with B
A = tf.cast(A, tf.float32)
# Concat AB one next to the other
AB = tf.concat([A, B], axis=0)
# Generate a list of values in this sequence
# 0, 4, 1, 5, ... in other to indicize the tensors
# use gather to collect values in the specified positions
NEW = tf.gather(AB,
list(
chain.from_iterable((i, i + A.shape[0].value)
for i in range(A.shape[0].value))))
with tf.Session() as sess:
print(sess.run([NEW]))
Using Tensorflow, you can use reshape and concat. These operations are also available in the keras backend.
a = tf.constant([1,2,3,4])
b = tf.constant([10,20,30,40])
c = tf.reshape(tf.concat([tf.reshape(a,(-1,1)), tf.reshape(b, (-1,1))], 1), (-1,))
I don't know if there exists a more straightforward way to accomplish this.
Edit: There exists a simpler solution using tf.stack instead of tf.concat.
c = tf.reshape(tf.stack([a, b], 1),(-1,))
I'm trying to writting a layer to merge 2 tensors with such a formula
The shapes of x[0] and x[1] are both (?, 1, 500).
M is a 500*500 Matrix.
I want the output to be (?, 500, 500) which is theoretically feasible in my opinion. The layer will output (1,500,500) for every pair of inputs, as (1, 1, 500) and (1, 1, 500). As the batch_size is variable, or dynamic, the output must be (?, 500, 500).
However, I know little about axes and I have tried all the combinations of axes but it doesn't make sense.
I try with numpy.tensordot and keras.backend.batch_dot(TensorFlow). If the batch_size is fixed, taking a =
(100,1,500) for example, batch_dot(a,M,(2,0)), the output can be (100,1,500).
Newbie for Keras, sorry for such a stupid question but I have spent 2 days to figure out and it drove me crazy :(
def call(self,x):
input1 = x[0]
input2 = x[1]
#self.M is defined in build function
output = K.batch_dot(...)
return output
Update:
Sorry for being late. I try Daniel's answer with TensorFlow as Keras's backend and it still raises a ValueError for unequal dimensions.
I try the same code with Theano as backend and now it works.
>>> import numpy as np
>>> import keras.backend as K
Using Theano backend.
>>> from keras.layers import Input
>>> x1 = Input(shape=[1,500,])
>>> M = K.variable(np.ones([1,500,500]))
>>> firstMul = K.batch_dot(x1, M, axes=[1,2])
I don't know how to print tensors' shape in theano. It's definitely harder than tensorflow for me... However it works.
For that I scan 2 versions of codes for Tensorflow and Theano. Following are differences.
In this case, x = (?, 1, 500), y = (1, 500, 500), axes = [1, 2]
In tensorflow_backend:
return tf.matmul(x, y, adjoint_a=True, adjoint_b=True)
In theano_backend:
return T.batched_tensordot(x, y, axes=axes)
(If following changes of out._keras_shape don't make influence on out's value.)
Your multiplications should select which axes it uses in the batch dot function.
Axis 0 - the batch dimension, it's your ?
Axis 1 - the dimension you say has length 1
Axis 2 - the last dimension, of size 500
You won't change the batch dimension, so you will use batch_dot always with axes=[1,2]
But for that to work, you must ajust M to be (?, 500, 500).
For that define M not as (500,500), but as (1,500,500) instead, and repeat it in the first axis for the batch size:
import keras.backend as K
#Being M with shape (1,500,500), we repeat it.
BatchM = K.repeat_elements(x=M,rep=batch_size,axis=0)
#Not sure if repeating is really necessary, leaving M as (1,500,500) gives the same output shape at the end, but I haven't checked actual numbers for correctness, I believe it's totally ok.
#Now we can use batch dot properly:
firstMul = K.batch_dot(x[0], BatchM, axes=[1,2]) #will result in (?,500,500)
#we also need to transpose x[1]:
x1T = K.permute_dimensions(x[1],(0,2,1))
#and the second multiplication:
result = K.batch_dot(firstMul, x1T, axes=[1,2])
I prefer using TensorFlow so I tried to figure it out with TensorFlow in past few days.
The first one is much similar to Daniel's solution.
x = tf.placeholder('float32',shape=(None,1,3))
M = tf.placeholder('float32',shape=(None,3,3))
tf.matmul(x, M)
# return: <tf.Tensor 'MatMul_22:0' shape=(?, 1, 3) dtype=float32>
It needs to feed values to M with fit shapes.
sess = tf.Session()
sess.run(tf.matmul(x,M), feed_dict = {x: [[[1,2,3]]], M: [[[1,2,3],[0,1,0],[0,0,1]]]})
# return : array([[[ 1., 4., 6.]]], dtype=float32)
Another way is simple with tf.einsum.
x = tf.placeholder('float32',shape=(None,1,3))
M = tf.placeholder('float32',shape=(3,3))
tf.einsum('ijk,lm->ikl', x, M)
# return: <tf.Tensor 'MatMul_22:0' shape=(?, 1, 3) dtype=float32>
Let's feed some values.
sess.run(tf.einsum('ijk,kl->ijl', x, M), feed_dict = {x: [[[1,2,3]]], M: [[1,2,3],[0,1,0],[0,0,1]]})
# return: array([[[ 1., 4., 6.]]], dtype=float32)
Now M is a 2D tensor and no need to feed batch_size to M.
What's more, now it seems such a question can be solved in TensorFlow with tf.einsum. Does it mean it's a duty for Keras to invoke tf.einsum in some situations? At least I find no where Keras calls tf.einsum. And in my opinion, when batch_dot 3D tensor and 2D tensor Keras behaves weirdly. In Daniel's answer, he pads M to (1,500,500) but in K.batch_dot() M will be adjusted to (500,500,1) automatically. I find tf will adjust it with Broadcasting rules and I'm not sure Keras does the same.
I am using Keras (tensorflow as backend). What I want to do is to write a lambda layer that gets 2 tensor input and compare every combination of 2 column of them using Indicator function and produce a new tensor with 0-1 value. Here is an example.
Input: x = K.variable(np.array([[1,2,3],[2,3,4]])),
y = K.variable(np.array([[1,2,3],[2,3,4]]))
Output
z=K.variable(np.array[[1,0],[0,1]])
As far as I know, tensorflow provides tf.equal() to compare tensor in a elementwise way. But if I apply it here, I get
>>> z=tf.equal(x,y)
>>> K.eval(z)
array([[True, True, True],
[True, True, True]], dtype=bool)
It only compares tensor in same position.
So my questions are:
1. Is there a tensorflow API to get my desired output or if I need to write my own function to complete it?
2. If it is the latter one, then there is another problem. I noticed that in keras the input is mini-batch, so the input format looks like: (None, m, n). When writing my own method, how can I tackle with the first dimension, which is None?
Any reply would be appreciated!
You could use broadcasting.
import numpy as np
import tensorflow as tf
x = tf.constant(np.array([[1,2,3],[2,3,4]]))
y = tf.constant(np.array([[1,2,3],[2,3,4]]))
x_ = tf.expand_dims(x, 0)
y_ = tf.expand_dims(y, 1)
res = tf.reduce_all(tf.equal(x_, y_), axis=-1)
sess = tf.Session()
sess.run(res)