When I perform an export_responses call to the API, I get the questions and values.
For combo type questions, I get the ID of the selected option, but not the description.
How can I access the descriptions of these values?
Thank you in advance!
The parameter sResponseType in the API allows you to choose if you want to get the Answer Codes or the Answer Texts.
Please see https://api.limesurvey.org/classes/remotecontrol_handle.html#method_export_responses
Export token response in a survey.
export_responses_by_token(string
$sSessionKey, integer $iSurveyID, string $sDocumentType, string
$sToken, string $sLanguageCode = null, string $sCompletionStatus =
'all', string $sHeadingType = 'code', string $sResponseType = 'short',
array $aFields = null) : array|string
...
...
sResponseType (optional)'short' or 'long' Optional defaults to 'short'
Related
I try to save some data that it brings me from my view, which is a table, but I don't know why it throws me that error with the insert.
result of insert
this is my view:
table of view
this is my controller:
$checked_array = $_POST['id_version'];
foreach ($request['id_version'] as $key => $value) {
if (in_array($request['id_version'][$key], $checked_array))
{
$soft_instal = new Software_instalacion;
$soft_instal->id_instalacion = $instalaciones->id;
$soft_instal->id_historial = $historial->id;
$soft_instal->id_usuario = $request->id_usuario;
$soft_instal->id_version = $_POST['id_version'][$key];
$soft_instal->obs_software = $_POST['obs_software'][$key];
$soft_instal->id_tipo_venta = $_POST['id_tipo_venta'][$key];
$soft_instal->save();
}
}
id_tipo_venta seems to be an empty string which is apparently not valid.
You can try debugging what you get in :
var_dump($_POST['id_tipo_venta'][$key]);
die;
Your database field expects to receive an integer. Therefore, using the intval() function can solve your problem.
Indeed, I think your code returns an alphanumeric string.
Therefore, the code below will return 0 in all cases if no version is returned (not set, string or simply null):
$soft_instal->id_tipo_venta = intval($_POST['id_tipo_venta'][$key]);
On the other hand, intval() will always convert to int, so a decimal will be converted, example :
intval("1.1") // returns 1
intval("v1.1") // returns 0
If this is not the desired behavior, maybe you should think about changing your database type.
EDIT :
Of course, you can also set the value as null if you prefer to 0. You must allow nullable values in your database.
id_tipo_venta can not be empty, try with some number or change type column to varchar in the database
I'm starting to use karate for testing. I need to validate one json response.
JSON Schema Design:
response{
id* Integer Not null
Name* String can be null
}
now i need to verified id and name with below constraints,
id should be integer and should not be null.
Name can either in string or can be null.
what equation we can use in Karate.
Thanks in Advances
def jsonValidate = {name: '#integer',Name: '#present'}
so if i use Present here ,it means Name can be null or can have value of any data type. but i need to check Name can be either String or Null Value only
Read the docs, and try this: https://github.com/intuit/karate#optional-fields
* def jsonValidate = { id: '#number', name: '##string' }
I have a object that I want to print it into string [key1=value1&key2=value2...etc] without the null value key value pair and comma into &.
So first of all i think of putting it into a map but it won't work and I don know how it work either.
val wxPayOrderObj = WxPayOrder(appid = "wx0b6dcsad20b379f1", mch_id =
"1508334851", nonce_str = UUID.randomUUID().toString(),sign = null,
body = "QQTopUp", out_trade_no = "20150806125346", total_fee = req.total_fee,
spbill_create_ip = "123.12.12.123",
trade_type = "JSAPI", openid = "oUpF8uMuAJO_M2pxb1Q9zNjWeS6o")
so the output will be
appid=wx0b6dc78d20b379f1&mch_id=150788851&nonce_str=UUID.randomUUID().toString()&
body=QQTopUp&out_trade_no=20150806125346&total_fee=req.total_fee&
spbill_create_ip=123.12.12.123&trade_type=JSAPI&openid=oUpF8uMuAJO_M2pxb1Q9zNjWeS6o
anyone please help me, thanks in advances.
I don't really get your question, but you want to convert object to string (to a format that you want)?
Override the object's toString() to return "[key1=value1&key2=value2...etc]"
example
override fun toString(){
// make sure you compute the data first
val answer = "[key1=$value1&key2=$value2...etc]"
return answer
}
The $ is used in string templates (That's directly writing the name of a variable, the value will be used later to be concatenated) with other strings)
I have a table that holds links to websites about particular theaters. I want to retrieve the first link for a given theater. My code to set the variable:
Dim link As String = TheaterLinks.Where(Function(x) x.TheaterID = TheaterID).FirstOrDefault().Link
If there are no results (some theaters won't have any links), then I get:
Object reference not set to an instance of an object.
How do I do this? I tried:
Dim link As String = Links.Where(Function(x) x.TheaterID = TheaterID.DefaultIfEmpty().First().Link
But I can't figure out what to put inside DefaultIfEmpty(). I tried DefaultIfEmpty("") and DefaultIfEmpty(blankstringvariable) but then I get:
Value of type 'String' cannot be converted to type 'TheaterLink'.
The problem is that FirstOrDefault() is allowed to return null, in which case accessing Link property would throw an exception.
If you use VB.NET 14, add question mark for automatic null checking:
Dim link As String = TheaterLinks.Where(Function(x) x.TheaterID = TheaterID).FirstOrDefault()?.Link
(see ?.Link instead of .Link)
Otherwise, do it in two stages: first, get the object using FirstOrDefault, then null-check it manually with an If statement.
For my original example, I just had to add a question mark:
Dim link As String = Links.Where(Function(x) x.ID = id).FirstOrDefault()?.Link
I tried doing this in my model and got a "Nullable object must have a value" error, so I did the two-stage approach:
Dim eventDate = Events.Where(Function(x) x.ID = id).FirstOrDefault()?.EventDate
If eventDate.HasValue Then
'some code
Else
'some code
End If
I want to get the string character from an ObjectId object. I use pymongo.
eg: ObjectId("543b591d91b9e510a06a42e2"), I want to get "543b591d91b9e510a06a42e2".
I see the doc, It says ObjectId.toString(), ObjectId.valueOf().
So I make this code: from bson.objectid import ObjectId.
But when I use ObjectId.valueOf(), It shows:
'ObjectId' object has no attribute 'valueOf'.
How can I get it? Thanks.
ObjectId.toString() and ObjectId.valueOf() are in Mongo JavaScript API.
In Python API (with PyMongo) proper way is to use pythonic str(object_id) as you suggested in comment, see documentation on ObjectId.
ObjectId.toString() returns the string representation of the ObjectId() object.
In pymongo str(o) get a hex encoded version of ObjectId o.
Check this link.
What works for me is to "sanitize" the output so Pydantic doesn't get indigestion from an _id that is of type ObjectId...here's what works for me...
I'm converting _id to a string before returning the output...
# Get One
#router.get("/{id}")
def get_one(id):
query = {"_id": ObjectId(id)}
resp = db.my_collection.find_one(query)
if resp:
resp['_id'] = str(resp['_id'])
return resp
else:
raise HTTPException(status_code=404, detail=f"Unable to retrieve record")
Use str(ObjectId), as already mentined in the comment by #Simon.
#app.route("/api/employee", methods=['POST'])
def create_employee():
json = request.get_json()
result = employee.insert_employee(json)
return { "id": str(result.inserted_id) }
This is an old thread, but as the existing answers didn't help me:
Having run
new_object = collection.insert_one(doc)
I was able to get the ObjectID with the inserted_id property:
print(f"{new_object.inserted_id}")
In python (Pymongo) there's no inbuilt method to do it so iterate over the result you fetched from db and then typecast _id to str(_id)
result = collection.find({query})
for docs in result:
docs[_id] = str(docs[_id])
first you have to assign the Object Id value to a variable
for example:
let objectId = ObjectId("543b591d91b9e510a06a42e2");
then use the toString method like this
let id = objectId.toString();