SQL query to compare the amount - sql

I have a Claim table that holds the claim amount. I need to write a query to compare if the amount is the same or not.
SELECT
CLAIM_NO, SUM(TRAN_AMOUNT) AS Amount
FROM
CLMTABLE
WHERE
TRTYPE = 0
GROUP BY
CLAIM_NO
UNION ALL
SELECT
CLAIM_NO, SUM(TRAN_AMOUNT) AS Amount
FROM
CLMTABLE
WHERE
TRTYPE <> 0
GROUP BY
CLAIM_NO
OUTPUT
CLAIM_NO AMOUNT
-----------------
1234567890 883.00
1234567890 883.00
1234567891 990.00
1234567891 990.00
1234567892 883.00
1234567892 893.00
The last record the amount is not the same, i want to be able to spot the claim that the amount doesn't match.
Thanks, any help will be appreciated

Please use below query to find all such transaction:
SELECT CLAIM_NO,SUM(CASE WHEN TRTYPE=0 THEN ISNULL(TRAN_AMOUNT,0) ELSE 0 END) As Amount,
SUM(CASE WHEN TRTYPE<>0 THEN ISNULL(TRAN_AMOUNT,0) ELSE 0 END) AS Amount2
FROM CLMTABLE
GROUP BY CLAIM_NO
HAVING SUM(CASE WHEN TRTYPE=0 THEN ISNULL(TRAN_AMOUNT,0) ELSE 0 END) <> SUM(CASE WHEN TRTYPE<>0 THEN ISNULL(TRAN_AMOUNT,0) ELSE 0 END)

Use a CASE inside a SUM func to retrieve the difference between amount of different types.
SELECT claim_no, SUM(CASE WHEN trtype = 0 THEN tran_amount
ELSE -1*tran_amount
END) as delta
FROM clmtable
GROUP BY claim_no

Related

how to sum two column within single case statement

The query below returns 2 rows, but actually I need only one;
select Datename(month, m.CreatedDate) as [Ay], sum(case when h.Cinsiyet=1 then 1 else 0 end) as [Group1], sum(case when h.Cinsiyet=2 then 1 else 0 end) as [Group2] from Muayene.Muayene m with(nolock)
join Ortak.Hasta h with(nolock) on m.HastaTc = h.HastaTc
group by h.Cinsiyet, Datename(month, m.CreatedDate)
result:
MonthName Group1 Group2
April 4500 0
April 0 9000
Expected Result:
MonthName Group1 Group2
April 4500 9000
I know I can do it wrapping the query with another select statement and Group by month and Sum these results.. But its not efficient and looks dirty code.
How can I make a trick to get expected result without make another sum statement?
FIx the GROUP BY:
select Datename(month, m.CreatedDate) as [Ay],
sum(case when h.Cinsiyet = 1 then 1 else 0 end) as [Group1],
sum(case when h.Cinsiyet = 2 then 1 else 0 end) as [Group2]
from Muayene.Muayene m join
Ortak.Hasta h
on m.HastaTc = h.HastaTc
group by Datename(month, m.CreatedDate);

infuse a sum of the value in the another column with a different filter than the total count column

First here's a sample table.
enter image description here
Provider_name patient date status length
AF AGUIR00001 07/05/2018 3 30
AF ABBOT00001 07/05/2018 30
BB ADAMS00001 07/05/2018 3 30
BB ACEVE00001 07/06/2018 3 30
I have created a query that lets me count the total number of appointments versus the number of appointments with a certain status(eg checked out). I was able to create it and group it by provider.
select provider_name,
count(patient) total,
sum(case when status = 3 then 1 else 0 end) as Checkedout
from appointment
group by provider_name
Then I moved on to the next phase which was to get the total length of those appointments with checkedout status. I made this query but it does not break down into each provider.
select provider_name,
count(patient) total,
sum(case when status = 3 then 1 else 0 end) as Checkedout,
(select sum(length) from appointment where status = 3
and date between '06/01/2018' and '07/06/2018')
from appointment where date between '06/01/2018' and '07/06/2018'
group by provider_name
I need it so that the last column in the query is segregated per provider_name.
Thank you in advance for helping me out.
Actually, you were on the right way, try this:
select provider_name,
count(patient) total,
sum(case when status = 3 then 1 else 0 end) as Checkedout,
sum(case when status = 3 then length else 0 end) as len_status3
from appointment
where date between '2018-01-06' and '2018-06-07'
group by provider_name;
According to your last comment, you need a WITH ROLLUP modifier for GROUP BY as in the following :
select coalesce(provider_name,'Total') as provider_name,
count(patient) total,
sum(case when status = 3 then 1 else 0 end) as Checkedout,
sum(case when status = 3 then length else 0 end) as len_status3
from appointment
where date between '2018-01-06' and '2018-06-07'
group by provider_name with rollup;
SQL Fiddle Demo
you shoul do as for checkedoutout
select provider_name,
count(patient) total,
sum(case when status = 3 then 1 else 0 end) as Checkedout,
sum( case when status = 3 then length else 0 ) as total_length
from appointment where date between '06/01/2018' and '07/06/2018'
group by provider_name

How to separate the Positive and negative record from a query which is calculate the all balance sum......?

select account
, SUM(balance) as bal
from Main_report
Group BY account
How can I separate the positive and negative records from the above query?
I want to combine this query with the cases listed below.
select (case when bal < 0 then bal else 0 end) as debits,
(case when bal > 0 then bal else 0 end) as credits from Main_report
Group BY account
Just use your two cases and sum the result of those:
SELECT account
, SUM(CASE WHEN balance < 0 THEN balance ELSE 0 END) as debits
, SUM(CASE WHEN balance > 0 THEN balance ELSE 0 END) as credits
FROM Main_report
GROUP BY account

Select multiple COUNTs for every day

I got a table of Visitors.
Visitor has the following columns:
Id
StartTime (Date)
Purchased (bool)
Shipped (bool)
For each day within the last 7 days, I want to select 3 counts of the Visitors who have that day as StartTime:
The count of total visitors
The count of total visitors where Purchased = true
The count of total visitors where Shipped = true
Ideally the returned result would be:
Day Total TotalPurchased TotalShipped
1 100 67 42
2 82 61 27
etc...
I am used to .NET Linq so this has proved to be quite a challenge for me.
All I have come up with so far is the following:
SELECT COUNT(*) AS Total
FROM [dbo].[Visitors]
WHERE DAY([StartTime]) = DAY(GETDATE())
It selects the total of the current day just fine, however I feel pretty stuck right now so it'd be nice if someone could point me in the right direction.
For the last 7 days use the query proposed by Stanislav but with this WHERE clause
SELECT DAY([StartTime]) theDay,
COUNT(*) AS Tot,
SUM(CASE WHEN Purchased=true THEN 1 ELSE 0 END) as TotPurch,
SUM(CASE WHEN Shipped=true THEN 1 ELSE 0 END) as TotShip
FROM [dbo].[Visitors]
WHERE [StartTime] BETWEEN GETDATE()-7 AND GETDATE()
GROUP BY DAY([StartTime])
SELECT COUNT(*) AS Total,
SUM(CASE WHEN Purchased=true THEN 1 ELSE 0 END) as TotalPurchased,
SUM(CASE WHEN Shipped=true THEN 1 ELSE 0 END) as TotalShipped
FROM [dbo].[Visitors]
WHERE DAY([StartTime]) = DAY(GETDATE())
and add GROUP BY DAY([StartTime]) as jarlh mentioned
Here's a simple select that will give you the dataset you want
SELECT DATEDIFF(day,StartTime, getdate())+1 as [Day], -- Add 1 to display 1 to 7 instead of 0 to 6
COUNT(*) as Total,
SUM(CASE WHEN Purchased = 1 THEN 1 ELSE 0 END) as TotalPurchased,
SUM(CASE WHEN Shipped = 1 THEN 1 ELSE 0 END) AS TotalShipped
FROM Visitors
WHERE DATEDIFF(day,startTime,GETDATE()) < 6
GROUP BY DATEDIFF(day,startTime,GETDATE())
ORDER BY 1
This query will not take into consideration the time component of the date.

How to separate positive and negative numbers into their own columns?

I have a table with the following columns and data:
activity_dt | activity_amt
2009-01-01 | -500
2009-01-01 | 750
Can I write a query that looks at the sign of activity_amt and puts it in the credits column if it's positive, and the debits column if it's negative? (I'm using Sybase)
activity_dt | debits | credits
2009-01-01 | -500 | 750
select activity_dt,
sum(case when activity_amt < 0 then activity_amt else 0 end) as debits,
sum(case when activity_amt > 0 then activity_amt else 0 end) as credits
from the_table
group by activity_dt
order by activity_dt
I'm not sure about the exact syntax in Sybase, but you should be able to group on the date and sum up the positive and negative values:
select
activity_dt,
sum(case when activity_amt < 0 then activity_amt else 0 end) as debits,
sum(case when activity_amt >= 0 then activity_amt else 0 end) as credits
from
theTable
group by
activity_dt
I found a new answer to this problem using the DECODE function.
I hope this turns out to be useful for everyone.
select activity_dt,
sum((DECODE(activity_amt /-ABS(activity_amt), 1, activity_amt, 0))) as credits,
sum((DECODE(activity_amt /-ABS(activity_amt), -1, activity_amt, 0))) as debits
from the_table
group by activity_dt
order by activity_dt;
select (select JV_GroupsHead.GroupTitle
from JV_GroupsHead
whereJV_GroupsHead.Id=jv.GroupId) as 'GroupName'
,jv.Revenue
,jv.AccountNo
,jv.AccountNoTitle
,(case when jv.Revenue < 0 then jv.Revenue else 0 end) as 'debits'
,(case when jv.Revenue> 0 then jv.Revenue else 0 end) as 'credits'
from JVFunction1('2010-07-08','2010-08-08') as jv