I have the following tables:
TABLE 1 TABLE 2
Col 1 Col2 A $100
Rpt1 (A + B(1-D))/C B $200
Rpt2 -A C $300
Rpt3 C+D D $400
I want to write a PL-SQL code that reads both the tables and give me the below dynamically.
Rpt 1 = (100 +200(1-400))/300
Rpt 2 = - 100
Rpt 3 = 300+400
Table 1 can have any type of formula. I need to read that formula and replace it with the amount present in table 2.
Any thoughts?
Since you asked for PL/SQL, here's a nested loop solution:
create table table1 (col1, col2) as
select 'Rpt1', '(A + B(1-D))/C' from dual union all
select 'Rpt2', '-A' from dual union all
select 'Rpt3', 'C+D' from dual;
create table table2 (col1, col2) as
select 'A', 100 from dual union all
select 'B', 200 from dual union all
select 'C', 300 from dual union all
select 'D', 400 from dual;
set serveroutput on
declare
result varchar2(100);
begin
for r1 in (select col1, col2 from table1)
loop
result := r1.col2;
for r2 in (select col1, col2 from table2 where result like '%' || col1 || '%')
loop
result := replace(result, r2.col1, r2.col2);
end loop;
dbms_output.put_line(r1.col1 || ' = ' || result);
end loop;
end;
/
Rpt1 = (100 + 200(1-400))/300
Rpt2 = -100
Rpt3 = 300+400
PL/SQL procedure successfully completed.
I've assumed that the dollar signs aren't actually present in table2; if they are then you'll need to trim them off if you don't want then in the output.
Related
I have following Block which has a cursor and a select query. I want to pass the output of select, which is comma separated into
the cursor's select statement, into the where clause.
I know below code will throw an error because of SQL query in Declare section but how I achieve this using array or collection.
here, id column is number
code snippet:
declare
test varchar2(30);
SELECT LISTAGG(value, ', ') WITHIN GROUP (ORDER BY value2) into test from table3 where value2=12;
cursor c1 (select * from table where id in (test))
begin
for i in c1 loop
null;
end loop;
end;
Why would you ever do this?
You can simple write you select as:
Select * from table where id in (select value from table3 where value2=12)
Edit:
Also you need to open your cursor c1, for it to work AFAIK.
You can use a collection and the MEMBER OF operator:
Oracle Setup:
CREATE TYPE IntegerList AS TABLE OF NUMBER(8,0);
/
CREATE TABLE table1 ( value, value2 ) AS
SELECT 1, 1 FROM DUAL UNION ALL
SELECT 3, 4 FROM DUAL UNION ALL
SELECT 5, 3 FROM DUAL UNION ALL
SELECT 7, 2 FROM DUAL;
CREATE TABLE table2 ( id, value ) AS
SELECT 1, 11 FROM DUAL UNION ALL
SELECT 2, 22 FROM DUAL UNION ALL
SELECT 3, 33 FROM DUAL UNION ALL
SELECT 7, 77 FROM DUAL;
PL/SQL:
DECLARE
test IntegerList;
c1 SYS_REFCURSOR;
BEGIN
SELECT value
BULK COLLECT INTO test
FROM table1;
FOR r IN ( SELECT * FROM table2 WHERE id MEMBER OF test ) LOOP
DBMS_OUTPUT.PUT_LINE( r.id || ', ' || r.value );
END LOOP;
END;
/
Output:
1, 11
3, 33
7, 77
db<>fiddle here
I have to write a query which does below. I tried but couldn't write. Please help me.
I have table which returns below result set.
select *
from table1; --(rowid and ColumnName are columns of the table)
Output:
rowid ColumnName
------------------------------
1 Segment1
2 Segment2
I have another table which has below structure : (Segment1 and Segment2 are columns here)
select *
from table2;
Output:
appId Segment1 Segment2 Segment3
---------------------------------------------
a1 fld1 fld2 per
a2 cmp1 hcd4 klp
I need to write a query, which reads the "ColumnName" values from first table and retrieves column values in the second table.
That means, from the table1, I will know what are the available columns I the table2 and from table2, I will know what is the data stored against those columns.
Please let me know if I am not clear.
This query is in Oracle SQL
As mentioned in the comment you need a PLSQL block with dynamic sql. See below an example:
Tables:
create table table1 (row_id number,
ColumnName varchar2(100))
create table table2 (appId number,
Segment1 varchar2(100),
Segment2 varchar2(100),
Segment3 varchar2(100));
Insert all
into TABLE1 (ROW_ID, COLUMNNAME) Values (1, 'Segment1')
into TABLE1 (ROW_ID, COLUMNNAME) Values (2, 'Segment2')
into TABLE2 (APPID, SEGMENT1, SEGMENT2, SEGMENT3) Values (1, 'RRR', 'KKK', 'MMM')
into TABLE2 (APPID, SEGMENT1, SEGMENT2, SEGMENT3) Values (2, 'ZZZ', 'PPP', 'QQQ')
into TABLE2 (APPID, SEGMENT1, SEGMENT2, SEGMENT3) Values (3, 'LLL', 'NNN', 'DDD')
select * from dual;
Code:
DECLARE
var VARCHAR2 (1000);
v_sql VARCHAR2 (2000);
TYPE x_var IS TABLE OF VARCHAR2(1000);
z_var x_var;
num number:=0;
BEGIN
FOR rec IN ( SELECT DISTINCT columnname
FROM table1
ORDER BY 1)
LOOP
num := num +1;
if num = 1 then
var:= rec.columnname;
else
var := var || ' || '' , ''||' || rec.columnname;
end if;
END LOOP;
var := RTRIM (LTRIM (var, ','), ',');
v_sql := 'select '|| var ||' from table2';
EXECUTE IMMEDIATE v_sql BULK COLLECT INTO z_var;
FOR i IN 1 .. z_var.COUNT
LOOP
DBMS_OUTPUT.put_line (z_var(i));
END LOOP;
END;
Output:
SQL> /
RRR , KKK
ZZZ , PPP
LLL , NNN
Dynamic columns in a SQL statement are almost always a bad idea. There's usually a way to avoid these kind of problems and build a simpler solution.
But if this is one of those rare times when you really need to run dynamic SQL in SQL then you'll need to install and run something like my open source project Method4.
For example:
create table table1 as
select 1 id, 'Segment1' columnName from dual union all
select 2 id, 'Segment2' columnName from dual;
create table table2 as
select 'a1' appId, 'fld1' Segment1, 'fld2' Segment2, 'per' Segment3 from dual union all
select 'a2' appId, 'cmp1' Segment1, 'hcd4' Segment2, 'klp' Segment3 from dual;
select * from table(method4.dynamic_query(
q'[
select
'select appID, '
||listagg(columnName, ',') within group (order by id)
||' from table2'
sql_statement
from table1
]'
));
APPID SEGMENT1 SEGMENT2
----- -------- --------
a1 fld1 fld2
a2 cmp1 hcd4
There are a lot of downsides to running this way. The code is complicated, slow, and has some odd behavior. For an explanation of how this works, see this article
by Adrian Billington.
Will the below PL SQL block help your requirement.
BEGIN
FOR iter IN (
SELECT column_name
FROM all_tab_columns
WHERE upper(table_name) = 'table1'
AND UPPER(column_name) LIKE 'SEGMENT%'
)
LOOP
SELECT iter.column_name INTO temp_table FROM table1
dbms_output.put_line(temp_table.column_name);
END LOOP;
END;
/
Say you have tables like the following:
SQL> select * from someTable;
COLUMN1 COLUMN2 COLUMN3
---------- ---------- ----------
1 2 3
2 4 6
3 6 9
SQL> select * from tableOfColumns;
COLUMNN
-------
column1
column3
You may need something like the following:
SQL> declare
2 type tListOfResults is table of varchar2(1000);
3 vSQL varchar2(1000);
4 vResult tListOfResults ;
5 begin
6 select 'select ' || listagg (columnName, ' || '', '' || ') within group (order by columnName) || ' from someTable'
7 into vSQL
8 from tableOfColumns;
9 --
10 execute immediate vSQL bulk collect into vResult;
11 if vResult.count() > 0 then
12 for i in vResult.first .. vResult.last loop
13 dbms_output.put_line(vResult(i));
14 end loop;
15 end if;
16 end;
17 /
1, 3
2, 6
3, 9
PL/SQL procedure successfully completed.
I have column in my database where the values are coming like the following:
3862,3654,3828
In dummy column any no. of comma separated values can come. I tried with following query but it is creating duplicate results.
select regexp_substr(dummy,'[^,]+',1,Level) as dummycol
from (select * from dummy_table)
connect by level <= length(REGEXP_REPLACE(dummy,'[^,]+'))+1
I am not understanding the problem. Can anyone can help?
Works perfectly for me -
SQL> WITH dummy_table AS(
2 SELECT '3862,3654,3828' dummy FROM dual
3 )
4 SELECT trim(regexp_substr(dummy,'[^,]+',1,Level)) AS dummycol
5 FROM dummy_table
6 CONNECT BY level <= LENGTH(REGEXP_REPLACE(dummy,'[^,]+'))+1
7 /
DUMMYCOL
--------------
3862
3654
3828
SQL>
There are many other ways of achieving it. Read Split single comma delimited string into rows.
Update Regarding the duplicates when the column is used instead of a single string value. Saw the use of DBMS_RANDOM in the PRIOR clause to get rid of the cyclic loop here
Try the following,
SQL> WITH dummy_table AS
2 ( SELECT 1 rn, '3862,3654,3828' dummy FROM dual
3 UNION ALL
4 SELECT 2, '1234,5678' dummy FROM dual
5 )
6 SELECT trim(regexp_substr(dummy,'[^,]+',1,Level)) AS dummycol
7 FROM dummy_table
8 CONNECT BY LEVEL <= LENGTH(REGEXP_REPLACE(dummy,'[^,]+'))+1
9 AND prior rn = rn
10 AND PRIOR DBMS_RANDOM.VALUE IS NOT NULL
11 /
DUMMYCOL
--------------
3862
3654
3828
1234
5678
SQL>
Update 2
Another way,
SQL> WITH dummy_table AS
2 ( SELECT 1 rn, '3862,3654,3828' dummy FROM dual
3 UNION ALL
4 SELECT 2, '1234,5678,xyz' dummy FROM dual
5 )
6 SELECT trim(regexp_substr(t.dummy, '[^,]+', 1, levels.column_value)) AS dummycol
7 FROM dummy_table t,
8 TABLE(CAST(MULTISET
9 (SELECT LEVEL
10 FROM dual
11 CONNECT BY LEVEL <= LENGTH (regexp_replace(t.dummy, '[^,]+')) + 1
12 ) AS sys.OdciNumberList)) LEVELS
13 /
DUMMYCOL
--------------
3862
3654
3828
1234
5678
xyz
6 rows selected.
SQL>
Giving a PL/SQL example where parsing over a table with an ID and column name. This will parse and print out each ID and the parsed value which could then be inserted into a new table or used in some other way.
Input
Column_ID Column_Name
123 (3862,3654,3828)
Output
Column_ID Column_Name
123 3862
123 3654
123 3828
PL/SQL Code
declare
table_name1 varchar2(1000);
string_to_parse varchar2(2000); -- assign string to table name
string_length number := 0; -- string length for loop
string_value varchar2(2000); -- string value to store value in
column_id number;
begin
--some table in the format '123' as column_id, '(3862,3654,3828)' as column_name
--remove the parenthesis or other special characters if needed
update some_table t
set t.column_name = regexp_replace(t.column_name,'\(|\)','');
commit;
for i in (
select * from some_table
) loop
column_id := i.column_id; --assign the id of the colors
string_to_parse := i.column_name; -- assign string to be parsed
if string_to_parse is null then
--at this point insert into a new table, or do whatever else you need
dbms_output.put_line(column_id || ' ' || string_value);
else
--String to parse is the comma
string_to_parse := string_to_parse||',';
string_length := length(string_to_parse) - length(replace(string_to_parse,',',''));
-- Loop through string from parameter
for i in 1 .. string_length loop
-- [^,] matches any character except for the ,
select regexp_substr(string_to_parse,'[^,]+',1,i)
into string_value -- stores value into string_value
from dual; -- dual is a dummy table to work around
--at this point insert into a new table, or do whatever else you need
dbms_output.put_line(column_id || ' ' || string_value);
--clear out the string value
string_value := null;
end loop;
end if;
end loop;
end;
I have column in my database where the values are coming like the following:
3862,3654,3828
In dummy column any no. of comma separated values can come. I tried with following query but it is creating duplicate results.
select regexp_substr(dummy,'[^,]+',1,Level) as dummycol
from (select * from dummy_table)
connect by level <= length(REGEXP_REPLACE(dummy,'[^,]+'))+1
I am not understanding the problem. Can anyone can help?
Works perfectly for me -
SQL> WITH dummy_table AS(
2 SELECT '3862,3654,3828' dummy FROM dual
3 )
4 SELECT trim(regexp_substr(dummy,'[^,]+',1,Level)) AS dummycol
5 FROM dummy_table
6 CONNECT BY level <= LENGTH(REGEXP_REPLACE(dummy,'[^,]+'))+1
7 /
DUMMYCOL
--------------
3862
3654
3828
SQL>
There are many other ways of achieving it. Read Split single comma delimited string into rows.
Update Regarding the duplicates when the column is used instead of a single string value. Saw the use of DBMS_RANDOM in the PRIOR clause to get rid of the cyclic loop here
Try the following,
SQL> WITH dummy_table AS
2 ( SELECT 1 rn, '3862,3654,3828' dummy FROM dual
3 UNION ALL
4 SELECT 2, '1234,5678' dummy FROM dual
5 )
6 SELECT trim(regexp_substr(dummy,'[^,]+',1,Level)) AS dummycol
7 FROM dummy_table
8 CONNECT BY LEVEL <= LENGTH(REGEXP_REPLACE(dummy,'[^,]+'))+1
9 AND prior rn = rn
10 AND PRIOR DBMS_RANDOM.VALUE IS NOT NULL
11 /
DUMMYCOL
--------------
3862
3654
3828
1234
5678
SQL>
Update 2
Another way,
SQL> WITH dummy_table AS
2 ( SELECT 1 rn, '3862,3654,3828' dummy FROM dual
3 UNION ALL
4 SELECT 2, '1234,5678,xyz' dummy FROM dual
5 )
6 SELECT trim(regexp_substr(t.dummy, '[^,]+', 1, levels.column_value)) AS dummycol
7 FROM dummy_table t,
8 TABLE(CAST(MULTISET
9 (SELECT LEVEL
10 FROM dual
11 CONNECT BY LEVEL <= LENGTH (regexp_replace(t.dummy, '[^,]+')) + 1
12 ) AS sys.OdciNumberList)) LEVELS
13 /
DUMMYCOL
--------------
3862
3654
3828
1234
5678
xyz
6 rows selected.
SQL>
Giving a PL/SQL example where parsing over a table with an ID and column name. This will parse and print out each ID and the parsed value which could then be inserted into a new table or used in some other way.
Input
Column_ID Column_Name
123 (3862,3654,3828)
Output
Column_ID Column_Name
123 3862
123 3654
123 3828
PL/SQL Code
declare
table_name1 varchar2(1000);
string_to_parse varchar2(2000); -- assign string to table name
string_length number := 0; -- string length for loop
string_value varchar2(2000); -- string value to store value in
column_id number;
begin
--some table in the format '123' as column_id, '(3862,3654,3828)' as column_name
--remove the parenthesis or other special characters if needed
update some_table t
set t.column_name = regexp_replace(t.column_name,'\(|\)','');
commit;
for i in (
select * from some_table
) loop
column_id := i.column_id; --assign the id of the colors
string_to_parse := i.column_name; -- assign string to be parsed
if string_to_parse is null then
--at this point insert into a new table, or do whatever else you need
dbms_output.put_line(column_id || ' ' || string_value);
else
--String to parse is the comma
string_to_parse := string_to_parse||',';
string_length := length(string_to_parse) - length(replace(string_to_parse,',',''));
-- Loop through string from parameter
for i in 1 .. string_length loop
-- [^,] matches any character except for the ,
select regexp_substr(string_to_parse,'[^,]+',1,i)
into string_value -- stores value into string_value
from dual; -- dual is a dummy table to work around
--at this point insert into a new table, or do whatever else you need
dbms_output.put_line(column_id || ' ' || string_value);
--clear out the string value
string_value := null;
end loop;
end if;
end loop;
end;
HI am new to stored procedure.
Am using a dynamic sql with
select * from table into var
var is a variable.the var contains more than one value ,when i try to run the proc with inputs i get an error:
ORA-01422: exact fetch returns more than requested number of rows
Is there a way such that the variable can hold more than one row using dynamic sql.
Use collection variables:
DECLARE
TYPE tt_int IS TABLE OF INTEGER;
var tt_int;
BEGIN
SELECT id
BULK COLLECT
INTO var
FROM table;
END;
You have to bulk collect the result set into a table of type if you're going to select multiple rows.
declare
type record_type is table of <table_name>;
var_records record_type;
begin
select *
bulk collect into var_records
from <table_name>;
end;
/
See also my answer to PL SQL how to select all columns
you can also return the results to a ref cursor
set serveroutput on
DECLARE
REFEXAMPLE SYS_REFCURSOR;
VAR NUMBER ;
col varchar2(50);
BEGIN
OPEN REFEXAMPLE FOR --Here you open the cursor and fill it
SELECT *
FROM (
SELECT 1 VAR, 'a' COL FROM DUAL
UNION ALL
SELECT 2 VAR, 'b' COL FROM DUAL
UNION ALL
SELECT 3 VAR, 'c' COL FROM DUAL
UNION ALL
SELECT 4 VAR, 'd' COL FROM DUAL
UNION ALL
SELECT 5 VAR, 'e' COL FROM DUAL
) EXAMPLETABLE ;
DBMS_OUTPUT.PUT_LINE('var ' || 'col');
DBMS_OUTPUT.PUT_LINE('---------');
LOOP
FETCH REFEXAMPLE INTO VAR, col; --now loop through
EXIT WHEN REFEXAMPLE%NOTFOUND;
DBMS_OUTPUT.PUT_LINE(var || ' ' || col || ' ');
END LOOP;
CLOSE REFEXAMPLE;
end ;
/
var col
---------
1 a
2 b
3 c
4 D
5 e
You can use a table variable, which provides you with an in-memory table of your results. You declare a table variable similar to a standard variable:
declare #MyVar table (col1 col1type, col2 col2type, etc.)