Char limit on vlookup AND index/match combination - vba

I created a table/sheet of items consolidated from different lists. All items of the different lists are added and then duplicates are deleted. Then i add a empty column for each of the single lists after the first column. I used vlookup to write "X" in every row of the corresponding column if the item is in this specific list. Each list has a own sheet where i previously wrote an extra column with X in every row, so vlookup can output the 2nd column containing just the x's. At the end i get a table of which list has the item, q
The formula i used: =Iferror(vlookup(A2;'sheetListA'!A:B;2;false);" ")
Apparently vlookup stops working if the looked up value contains more than 255 characters (across different sheets). I now tried for quite a while to rebuild my formula with INDEX and MATCH but without success. I managed to make a working formula but it has the same problem as vlookup and stops working when there are more than 255 chars in the cell.
Another formula not working: =INDEX('630'!A:B;MATCH(A02;'sheetListA'!A:A;0);2)

Rory aswered my question in the comments:
Try: =LOOKUP(2;1/(A2='sheetListA'!A2:A1000);'sheetListA'!B2:B1000) Do
not use entire column references
. – Rory Aug 16 at 12:56
Change sheetListA to whatever your sheet name actually is.
Rory Aug 16 at 14:50

Here is a custom VLOOKUP like function that can search characters over 255 characters.
Function VLOOKUPPLUS(SearchCell, LookUpArray As Range, ColNum As Long) As Variant
For Each cell In LookUpArray.Columns(1).Cells
If cell = SearchCell Then
VLOOKUPPLUS = cell.Offset(0, ColNum - 1)
Exit For
End If
VLOOKUPPLUS = "N/A"
Next
End Function

Related

Return values from other workbook

Have a question about formula which will resolve my issue.
In my main workbook I need to compare data from two sources.
One of the columns must retrieve data(amounts) from other workbook.
I want formula which will search for all amounts in column G and will skip all blank cells. Tried to use VLOOKUP, INDEX and SMALL functions but no effect.
Each day amounts are different and I need to match them in main file and find exeptions.
Any ideas?
How about an array formula such as the following?
=INDEX($G$2:$G$20,SMALL(IF(($G$2:$G$20)=0,"",ROW($G$2:$G$20)),ROW()-1)-ROW($G$2:$G$20)+1)
The formula would have to be placed into cell I2 as an array formula (which must be entered pressing Strg + Shift + Enter). Then you can drag down the formula to get all the other values.
It doesn't have to be in column I but it has to be in row 2 because this formula get's the n-th Number from the list which is not = 0. The n-th place is (in this formula) row()-1. So for row 2 it will be 2-1=1 and thus the 1st number. By dragging down the formula you get the 2nd, 3rd, etc. number. If you start with the formula in cell I5 instead then it would have to be adjusted to be as follows:
=INDEX($G$2:$G$20,SMALL(IF(($G$2:$G$20)=0,"",ROW($G$2:$G$20)),ROW()-4)-ROW($G$2:$G$20)+1)
You could loop through the column and store each value >0 in an array and then compare or you loop through the column and compare directly...
something like:
Dim i as Integer = 0
Foreach value in Maintable
Do
If otherworkbook.cells(i,7) = value Then '7 for G
do your stuff
End If
i = i + 1
While i < otherworkbook.rows.count
Next
I think that could be the right approach

Removing a row in a table if it doesn't contain keyword

Right now I have a really long table in a Word doc which I populated from an Excel worksheet. It has 6 columns and I'm trying to code something in Word VBA that will go through all the rows in the table and delete the entire row if the cell in the first column DOES NOT start with an equal sign ("=").
For example, I'm only trying to keep the rows that has texts like,
"=1+S -03F7", "=1+M -06M1", etc. etc.
How would I code this? I can't give the code anything specific to look for since the parts after the equal sign will be different for every row.
So this wouldn't work, right?:
If Not ActiveDocument.Tables(83).Columns(1).Range.Text = "=" Then
EntireRow.Select
Selection.Delete
I guess I should reference to cells in column 1, not the column itself... Also, it doesn't work because it's only looking for things with just the equal sign... And I don't know how I can get it to select the row if it find the cell without the equal sign. I don't know how to match by case in the cell of the first column.
You can loop through the rows in the table using the Rows property. You can then find the first cell in that Row using the Cells property. You can then check just the first character of the Range:
Sub DeleteUnwantedRows()
Dim t As Table
Dim r As Row
Set t = ActiveDocument.Tables(1)
For Each r In t.Rows
If r.Cells(1).Range.Characters(1) <> "=" Then r.Delete
Next r
End Sub

Excel: Check if cell string value exists in column, and get all cell references to that string

I suspect this may be a job for VBA, which is beyond my abilities. But here's the scenario:
Column A in Sheet 1 (CAS1) contains x rows of text values
Column A in Sheet 2 (CAS2) contains x rows of text values
Part A - For each row value in CAS1, I need to know if the string is contained in any of the cells in CAS2. Not exact match, the string can be only part of the searched cells.
Part B - I need to know the cell value of each cell in CAS2 that contains the CAS1 value (if they do exist, they can be listed in the cells adjacent to the cell being searched in CAS1).
I've tried the following to attempt Part A, all to no avail:
vlookup(A1,sheet2!A:A,1,false)
NOT(ISNA(MATCH(A1,sheet2!A:A,0)))
ISNUMBER(MATCH(A1,sheet2!A:A,0))
COUNTIF(sheet2!A:A,A1)>0
IF(ISERROR(MATCH(A1,sheet2!A:A, 0)), "No Match", "Match")
I know some of the cell values in CAS2 contain the cell values in CAS1, so I don't know why they return false or No Match. I suspect it may be down to the nature of the text content. So here's some sample data:
CAS1
LQ056
RV007H
RV008
RV009H
TSN304
TSN305
CAS2
RV009-satin-nickel-CO.jpg
STR314.jpg
STR315.jpg
HCY001.jpg
RV008-oval-rad-CO.jpg
HCY001-BRAC006.jpg
Any help would be appreciated.
This problem can be faced through VBA (at least, I imagine the VBA solution much more easily than the possible Excel one). You need a macro that, for each row in CAS1, search the content in each row of CAS2 and returns you the address.
For Each cell In Sheets("CAS1").Range("A1:A" & Sheets("CAS1").Range("A1").End(xlDown).Row) '<-- check each cell of the range A1:A? of sheet CAS1 (adapt "A" and "1" if they're different)
recFound = 0 '<-- count how many findings there are
For Each cell2 In Sheets("CAS2").Range("A1:A" & Sheets("CAS2").Range("A1").End(xlDown).Row) '<-- check in each cell of the range A1:A? of sheet CAS2 (adapt "A" and "1" if they're different)
If InStr(cell2.Value, cell.Value) <> 0 Then '<-- if the value in cell is contained in the value in cell2..
recFound = recFound + 1 '<-- account the new finding
cell.Offset(0, recFound) = Split(cell2.Address, "$")(1) & Split(cell2.Address, "$")(2) '<--write the address on the right of the currently searched cell
End If
Next cell2
Next cell
All the above should be enclosed in a macro, e.g. Sub makeMySearch(), that should be run to get the results. As commented in my code, I'm assuming that data are in A1:A? of both sheets; but they of course might be, for example, in B5:B? of the sheet 1 and in C7:C? of the sheet 2. You need clearly to adapt the code to your current data.
There's no need for VBA. Some simple array-formulas can do the job.
To see if the entry in CAS1 is present in CAS2:
=OR(ISNUMBER(SEARCH(A2,CAS2_)))
will return TRUE or FALSE. BUT this formula has to be entered by holding down CTRL-SHIFT while hitting ENTER If you do this correctly, Excel will place braces {...} around the formula that you can see in the formula bar.
The SEARCH function returns an array of results, which will be either the #VALUE! error, or a number.
In order to return the address, the following array-formula can be entered adjacent to a cell in CAS1:
=IFERROR(ADDRESS(LARGE(ISNUMBER(SEARCH($A2,CAS2_))*ROW(CAS2_),COLUMNS($A:A)),1),"")
Fill right for the maximum number of addresses possible, then select the group and fill down.
In this case, the array being returned is a string of either 0's, or 1 * the row number (i.e. the row number). I assumend the data in CAS2 was in column A, but you can change the column number if needed (or even compute it if necessary, by replacing the 1 in the ADDRESS function with COLUMN(CAS2_))
CAS1_ and CAS2_ are either named ranges, or absolute range references to the two text groups.

Auto Fill Row B with the last four characters of Row A

So basicly i want a VBA script to fill Row B with the last four characters that are in Row A
RowA contains a telephone number with around 12 numbers in it.
Assuming that you meant to say
I have a series of telephone numbers in column A. I would like to
create a second column in which I have just the last four digits of
these numbers. I am new to Excel. Could someone please help me get
started on this?"
The answer would go like this:
In Excel you can create formulas that compute "something" - often based on the contents of other cells. For your specific situation, there is a function called RIGHT(object, length) which takes two arguments:
object = a string (or a reference to a string)
length = the number of characters (starting from the right) that you want.
You can see this for yourself by typing the following in a cell:
=RIGHT("hello world", 5)
When you hit <enter>, you will see that the cell shows the value world.
You can extend this concept by using a cell reference rather than a fixed string. Imagine you have "hello world" in cell A1. Now you can put the following in cell B1:
=RIGHT(A1, 5)
and you will see the value "world" in B1.
Now here is the cool trick. Assume you have a bunch of numbers in column A (say starting at row 2, since row 1 contains some header information - the title of the column). Then you can write the following in cell B2:
=RIGHT(A2, 4)
to get the last four digits. Now select that cell, and double-click on the little box in the bottom right hand corner:
Like magic, Excel figures out "you want to do this with all the cells in this column, for as many rows as there is data in Column A. I can do that!" - and your formula will propagate to all cells in column B, with the row number adjusted (so in row 3, the formula will be
=RIGHT(A3, 4)
etc.
Try
Dim ws As Worksheet
Set ws = Worksheets("Sheet1")
With ws.Range("B2:B99")
.Formula = "=Right(A2, 4)"
.Value = .Value
End With

Search through column in excel for specific strings where the string is random in each cell

I am working in excel with a datasheet that is 1000 rows and 15 columns. Currently, in one of the columns, I have a lot of data mixed in with people names (see below for an example). I want to see how many times each person's name appears in the datasheet, so I can use it in a pivot table. There is no particular format or order to the way names appear. It is random. Is there a way to code in excel to search through that whole column and give me a count of the amount of times each person's name appears?
Column D
21421Adam14234
2323xxx Bob 66
23 asjdxx Jacob 665
43 Tim 5935539
2394Bob 88
After some trial and error, I can generate a list of names, one per row and place them in a different column for comparison sake, if that makes it easier.
I know you have got your answer but why not use COUNTIF with Wild Cards? You don't need VBA for this :)
See this example
=COUNTIF($A$1:$A$5,"*"&C1&"*")
SNAPSHOT
You don't have VBA tagged, but I don't know if there is a way to do this without it. I've built a custom function below. To implement it, take the following steps.
1) List desired names starting at column E1.
2) Insert this function into VBA Editor
A) Presss Alt + F11
B) Click Insert > Module from menu bar
C) Copy this code into Module
Option Explicit
Function findString(rngString As Range, rngSearch As Range) As Long
Dim cel As Range
Dim i As Integer
i = 0
For Each cel In rngSearch
If InStr(1, cel.Text, rngString.Value) > 0 Then
cel.offset(,-1) = rngString.Value 'places the name in cell to right of search range
i = i + 1
End If
Next
findString = i
End Function
3) In F1 type the following formula
=findstring(E1,$D$1:$D$5)
4) Run the formula down column F to get the count of each desired name.