i want to get only the first 10 records from this select statement
SELECT SUM([Order].[Quantity]) As Quantity , [Order].ProductSKU_FK
FROM [Order]
WHERE [Order].[Status] !='Fulfilled'
GROUP BY [Order].[ProductSKU_FK]
ORDER BY Quantity DESC;
Use TOP?
SELECT TOP 10
SUM([Quantity]) As Quantity,
ProductSKU_FK
FROM [Order]
WHERE [Status] != 'Fulfilled'
GROUP BY ProductSKU_FK
ORDER BY Quantity DESC;
Related
I would like to receive top 5 selling products in quantity in an order from NorthWind database.
The database has a bunch of tables like Order, OrderDetails, Customers, etc. I was suggested to use Orders Details table below:
Now, I tried the following:
WITH cte AS (
SELECT
OrderID,
Quantity,
ProductID,
ROW_NUMBER() OVER(PARTITION BY OrderID ORDER BY OrderID) as row_num
FROM [Order Details]
)
SELECT *
FROM cte
WHERE row_num IN (SELECT row_num FROM cte WHERE row_num <=10)
ORDER BY OrderID;
Thought this retrieves 10 rows now for each order, they are not ordered based on sold quantities and top sold products are not retrieved properly as for some orders the top sold was beyond the first top 10 rows based on row number I got with ROW_NUMBER() function in SQL.
Edit: For example, if I have 10 orders each with 20 products, then I want top 5 each each product, so the result table should have 50 rows total.
After your edits:
WITH cte AS (
SELECT
OrderID,
Quantity,
ProductID,
ROW_NUMBER() OVER(PARTITION BY OrderID ORDER BY Quantity DESC) as row_num
FROM [Order Details]
)
SELECT *
FROM cte
WHERE row_num <= 5
ORDER BY OrderID;
You should do a
SELECT DISTINCT productid FROM OrderDetails ORDER BY quantity GROUP BY productId LIMIT 5
At least this is the mysql syntax.
I am trying to display the productid for the product that has been sold the most (i.e, that has been sold in the highest quantity)
I have tried multiple different versions of code but every time it says cannot nest aggregated operations
SELECT productid
FROM soldvia
GROUP BY productid
WHERE productid IN (SELECT MAX(SUM(noofitems)) FROM soldvia GROUP BY productid);
I expect the output to be
PRODUCTID
3x3
4x4
You can't nest aggregations.
Use ORDER BY with TOP :
SELECT TOP 1 productid
FROM soldvia
GROUP BY productid
ORDER BY SUM(noofitems) DESC
Please try below query for your exact answer.
select productid, sum(noofitems) as max_sold,
convert(varchar,productid) +' x '+ convert(varchar,sum(noofitems)) as
output_sold from soldvia group by productid order by sum(noofitems) desc
Output will be
ProductId NoOfItemSold Output_Sold
1 7 1x7
2 4 2x4
3 1 3x1
In Teradata, you can use the qualify clause:
SELECT productid
FROM soldvia
GROUP BY productid
QUALIFY ROW_NUMBER() OVER (ORDER BY COUNT(*) DESC) = 1;
This is handy. You can get duplicates by changing ROW_NUMBER() to RANK(). Actually, RANK() is more consistent with the code in your question.
The answer by #forpas is probably the way to go but this one is a little closer to yours:
SELECT productid
FROM soldvia
GROUP BY productid
HAVING SUM(noofitems) = (
SELECT MAX(items)
FROM (
SELECT SUM(noofitems) AS items
FROM soldvia
GROUP BY productid
) x
)
I am trying to retrieve the product with the highest price:
SELECT ProductName, Price
FROM [Products]
ORDER BY Price DESC
LIMIT 1
I wanted to know if there is another way of doing this in a more efficient way, with MAX for example.
Use MAX and GROUP BY
SELECT ProductName, MAX(Price) [Price]
FROM [Products]
GROUP BY ProductName
ORDER BY MAX(Price) DESC
LIMIT 1;
I've always done it with the following
SELECT top 1 Name
FROM tableName
ORDER BY Price DESC
You can use TOP 1 but you always have to consider the possibility of having a tie, so:
SELECT TOP 1 WITH TIES ProductName, Price
FROM [Products]
ORDER BY Price DESC
select top 1 * from [Products] order by Price desc
How do i combine a SUM and MAX in a single query?
Lets say i have a orderrule:
ProductID \ Quantity
I Could say:
Select ProductID,SUM(Quantity) AS Sold
FROM Orderrule
GROUP BY ProductID
ORDER BY SUM(Quantity) Desc
However that would return all sales, and not just the most sold product (with quantity).
Try this
SELECT TOP(1)
*
FROM
(
Select
ProductID,
MAX(Quantity) As MaxQuantity,
SUM(Quantity) AS Sold
FROM Orderrule
GROUP BY ProductID
)AS X
ORDER BY Sold DESC
So there are two ways to do it - first to have a limit on the number of results, something likes:
select * from (your_select) where rownum = 1
the other one is to pick the one with the the highest value, which will require a subselect, something like:
having sum(quantity) =
(select max(sum_quan) from (select sum(Quantity) from orderrule group by Product_id))
SELECT TOP 1 ProductID, Sold FROM
(
SELECT ProductID, SUM(Quantity) AS Sold
FROM Orderrule
GROUP BY ProductID
) totals
ORDER BY Sold DESC
I have written a query for sales by customers in groups it is as follows:
SELECT customerid,
SUM (salestax1)As total_salestax1,
SUM(total_payment_received) As total_payment_recieved,
COUNT (orderid)as order_qty,
SUM(paymentamount)As paymentamount
FROM Orders_74V94W6D22$
WHERE orderdate between '7/6/2011 16:35' and '2/3/2012 11:53'
GROUP BY customerid
but this query shows only 5 fields but I need to show following fields:
orderid billingcompanyname billingfirstname billinglastname
billingcountry shipcountry paymentamount creditcardtransactionid
orderdate creditcardauthorizationdate orderstatus
total_payment_received tax1_title salestax1
then how to deal with it?
you need to understand what GROUP BY means.
If you are grouping by customerId, you will have only one customer because all data is grouped into it.
How do you want to group by orderid and display the orderid on your result set? If you have 10 order ids, do you expect 10 rows on the result? If yes, fine, group by it but I don't think that's what you want
EDIT:
Well, this is NOT a good idea, your table structure is WRONG and I dont think you fully understand that a group by means, BUT I think this query will get your result:
SELECT customerid,
(select top 1 [column1] from Orders_74V94W6D22$ where customerid = ORD.customerid),
(select top 1 [column2] from Orders_74V94W6D22$ where customerid = ORD.customerid),
(select top 1 [column3] from Orders_74V94W6D22$ where customerid = ORD.customerid),
SUM (salestax1)As total_salestax1,
SUM(total_payment_received) As total_payment_recieved,
COUNT (orderid)as order_qty,
SUM(paymentamount)As paymentamount
FROM Orders_74V94W6D22$ ORD
WHERE orderdate between '7/6/2011 16:35' and '2/3/2012 11:53'
GROUP BY customerid
To select more about the customer, you need to use your query as a sub query, something like:
Select distinct c.[column1], c.[column2], c.[column3], tbl.*
From Orders_74V94W6D22$ c inner join (
SELECT customerid,
SUM (salestax1)As total_salestax1,
SUM(total_payment_received) As total_payment_recieved,
COUNT (orderid)as order_qty,
SUM(paymentamount)As paymentamount
FROM Orders_74V94W6D22$
WHERE orderdate between '7/6/2011 16:35' and '2/3/2012 11:53'
GROUP BY customerid
) as tbl on tbl.customerid = c.customerid
but you cant logically select something about 1 order as youve grouped multiple orders