Sorting like excel in postgres - sql

I have a column in a table whose values are,
a100,a7,a20,16,17,bbb,ccc,15kk,24dd
I want to sort this column and expected result (same like excel) is,
16,17,15kk,24dd,bbb,ccc,a7,a20,a100
i.e.:
Empty first then numeric then alpha-numeric then alphabetical then alphanumeric.
I have tried multiple solutions from google but all failed. Most of the solution are mixing numeric and alpha-numeric together like 15kk, 16, 17.

Something like this:
with data (nr) as (
values ('a100'),('a7'),('a20'),('16'),('2'),('17'),('bbb'),('ccc'),('15kk'),('24dd')
)
select *
from data
order by case
when nr ~ '^[0-9]+$' then 1
when nr ~ '^[0-9]+[a-z]+$' then 2
when nr ~ '^[^0-9]+$' then 3
when nr ~ '^[a-z]+[0-9]+' then 4
end,
case
when nr ~ '^[0-9]+$' then nr::integer
when nr ~ '^[0-9]+[a-z]+$' then regexp_replace(nr, '[^0-9]+', '', 'g')::integer
else 0
end,
nr;
The above returns:
nr
----
2
16
17
15kk
24dd
bbb
ccc
a100
a20
a7
The first case creates "groups" based on the structure of the value,
The second case makes sure that the "real" numbers are sorted according to their numeric values to make '16' sort after '2'.
And the final nr sorts the alphanumeric values inside the groups
Online example: http://rextester.com/JMG51196

Related

Get value in string after 4th space SQL

Related question so now I have a table Test with 3 columns id, value and term
TEST
id
value
Item
1
AB CD EF GH IJ KL
1 4 78 78 10 9
I will like a query to get the value in the Item column after the 4th space. In this case that will correspond to 'IJ' in the value column and in the "Item' column it will return '10'
This is what i tried
select
substring(item(REGEXP_COUNT( SPLIT( TRIM(REGEXP_REPLACE(value, '[^[:digit:]]', ' ')), 'IJ')[0] , ' ')
from Test
Use split_part()
select split_part('AB CD EF GH IJ KL', ' ',5);
This function split the string on the chosen character and allows you to choose which one you'd like to return as a string. In this case, the 5th part.

SQL How to search text field for 2nd without matching 22nd, etc?

I want to query for numbered street names that can occur anywhere within a text column, and filter out matches for numbered street names with more digits, i.e. 2nd but not 42nd, 182nd, etc. Is there any method more graceful or simplified than combination of:
WHERE col LIKE '2nd%' OR col LIKE '% 2nd%'
As long as the 2nd doesn't occur at the beginning of the string, you can just check that the character before it is not a digit using
col LIKE '%[^0-9]2nd%'
For example:
select col, case when col like '%[^0-9]2nd%' then 'second' else 'not' end as test
from (values ('12 2nd st'), ('45 42nd st'), ('128 22nd st')) test(col)
Output:
col test
12 2nd st second
45 42nd st not
128 22nd st not
Nick's answer is very good, but it doesn't handle the case when '2nd' appears at the beginning of a string. This is easily handled by pre-pending a character on the column being compared:
' ' + col LIKE '%[^0-9]2nd%'

SQL Server: How to display a specific character based on position in a column

So I'm attempting to display a single character based on its position in a string from one column. Since this is grid data, there is a simple math to it. The grid has 24 rows 'A-X', and 44 columns.
So lets say I want to see the value in D9. I already know the expected value should be a 'A1', so that means the character length is '2'. If I do the math: (A + B + C = 3 x 44, + 9). That two-character value for D9 starts at the 141st position of that string in Col2. I attempted to use SUBSTRING with no success
SELECT
Col1 , SUBSTRING('Col2',141,2)
FROM Table1
Query result displays data in Col1, but for Col2 its just blank. What am I missing?
Asked too soon. Figured out I had to remove the ' from the column name
SELECT
Col1 , SUBSTRING('Col2',141,2)
FROM Table1
Didn't work
SELECT
Col1 , SUBSTRING(Col2,141,2)
FROM Table1
Works

Sorting varchar column by number, character [duplicate]

This question already has answers here:
How to do sorting on irregular Alphanumeric data in postgres sql
(2 answers)
Closed 10 years ago.
I have a varchar column [flat_number] which has some values as
A1A1A
A1A2A
A1A101A
A3A5A
12
A2
A3
I wish to get the results sorted by number and then by characters first
like
12
A2
A3
A1A1A
A1A2A
A1A101A
A3A5A
I have managed to sort it by number (if the column only contains digits 0-9 using regex, I treat it as a number), then I sort it by character, but it dosent seem to work for column values as A1A101A (having multiple combinations of number and character)
CASE
WHEN length(flat_number) < 10 AND flat_number SIMILAR TO '[0-9]+'
THEN
flat_number::int
END
ELSE
NULL
END,
( SELECT COALESCE( match[1], NULL ) FROM regexp_matches( flat_number, '[^0-9]+' ) AS match ),
( SELECT COALESCE( left( match[1], 9), NULL ) FROM regexp_matches( flat_number, '([0-9]+$)' ) AS match )::int
The current query works as
If the column contains only numbers [0-9] I convert it to int and sort it
ElSE, I split the column into 2 parts and try to extract the column character at the start and the number at the end.
Is there a better wait to do so and also make sure the expected output is returned
I think the following will work:
order by (case when flat_number ~ '^[0-9]+$' then 0 else 1 end),
(case when flat_number ~ '^[0-9]+$' then length(flat_number) end),
flat_number
This orders the number first, uses a trick to put them in numeric order, and then orders the rest of the numbers.

Humanized or natural number sorting of mixed word-and-number strings

Following up on this question by Sivaram Chintalapudi, I'm interested in whether it's practical in PostgreSQL to do natural - or "humanized" - sorting " of strings that contain a mixture of multi-digit numbers and words/letters. There is no fixed pattern of words and numbers in the strings, and there may be more than one multi-digit number in a string.
The only place I've seen this done routinely is in the Mac OS's Finder, which sorts filenames containing mixed numbers and words naturally, placing "20" after "3", not before it.
The collation order desired would be produced by an algorithm that split each string into blocks at letter-number boundaries, then ordered each part, treating letter-blocks with normal collation and number-blocks as integers for collation purposes. So:
'AAA2fred' would become ('AAA',2,'fred') and 'AAA10bob' would become ('AAA',10,'bob'). These can then be sorted as desired:
regress=# WITH dat AS ( VALUES ('AAA',2,'fred'), ('AAA',10,'bob') )
regress-# SELECT dat FROM dat ORDER BY dat;
dat
--------------
(AAA,2,fred)
(AAA,10,bob)
(2 rows)
as compared to the usual string collation ordering:
regress=# WITH dat AS ( VALUES ('AAA2fred'), ('AAA10bob') )
regress-# SELECT dat FROM dat ORDER BY dat;
dat
------------
(AAA10bob)
(AAA2fred)
(2 rows)
However, the record comparison approach doesn't generalize because Pg won't compare ROW(..) constructs or records of unequal numbers of entries.
Given the sample data in this SQLFiddle the default en_AU.UTF-8 collation produces the ordering:
1A, 10A, 2A, AAA10B, AAA11B, AAA1BB, AAA20B, AAA21B, X10C10, X10C2, X1C1, X1C10, X1C3, X1C30, X1C4, X2C1
but I want:
1A, 2A, 10A, AAA1BB, AAA10B, AAA11B, AAA20B, AAA21B, X1C1, X1C3, X1C4, X1C10, X1C30, X2C1, X10C10, X10C2
I'm working with PostgreSQL 9.1 at the moment, but 9.2-only suggestions would be fine. I'm interested in advice on how to achieve an efficient string-splitting method, and how to then compare the resulting split data in the alternating string-then-number collation described. Or, of course, on entirely different and better approaches that don't require splitting strings.
PostgreSQL doesn't seem to support comparator functions, otherwise this could be done fairly easily with a recursive comparator and something like ORDER USING comparator_fn and a comparator(text,text) function. Alas, that syntax is imaginary.
Update: Blog post on the topic.
Building on your test data, but this works with arbitrary data. This works with any number of elements in the string.
Register a composite type made up of one text and one integer value once per database. I call it ai:
CREATE TYPE ai AS (a text, i int);
The trick is to form an array of ai from each value in the column.
regexp_matches() with the pattern (\D*)(\d*) and the g option returns one row for every combination of letters and numbers. Plus one irrelevant dangling row with two empty strings '{"",""}' Filtering or suppressing it would just add cost. Aggregate this into an array, after replacing empty strings ('') with 0 in the integer component (as '' cannot be cast to integer).
NULL values sort first - or you have to special case them - or use the whole shebang in a STRICT function like #Craig proposes.
Postgres 9.4 or later
SELECT data
FROM alnum
ORDER BY ARRAY(SELECT ROW(x[1], CASE x[2] WHEN '' THEN '0' ELSE x[2] END)::ai
FROM regexp_matches(data, '(\D*)(\d*)', 'g') x)
, data;
db<>fiddle here
Postgres 9.1 (original answer)
Tested with PostgreSQL 9.1.5, where regexp_replace() had a slightly different behavior.
SELECT data
FROM (
SELECT ctid, data, regexp_matches(data, '(\D*)(\d*)', 'g') AS x
FROM alnum
) x
GROUP BY ctid, data -- ctid as stand-in for a missing pk
ORDER BY regexp_replace (left(data, 1), '[0-9]', '0')
, array_agg(ROW(x[1], CASE x[2] WHEN '' THEN '0' ELSE x[2] END)::ai)
, data -- for special case of trailing 0
Add regexp_replace (left(data, 1), '[1-9]', '0') as first ORDER BY item to take care of leading digits and empty strings.
If special characters like {}()"', can occur, you'd have to escape those accordingly.
#Craig's suggestion to use a ROW expression takes care of that.
BTW, this won't execute in sqlfiddle, but it does in my db cluster. JDBC is not up to it. sqlfiddle complains:
Method org.postgresql.jdbc3.Jdbc3Array.getArrayImpl(long,int,Map) is
not yet implemented.
This has since been fixed: http://sqlfiddle.com/#!17/fad6e/1
I faced this same problem, and I wanted to wrap the solution in a function so I could re-use it easily. I created the following function to achieve a 'human style' sort order in Postgres.
CREATE OR REPLACE FUNCTION human_sort(text)
RETURNS text[] AS
$BODY$
/* Split the input text into contiguous chunks where no numbers appear,
and contiguous chunks of only numbers. For the numbers, add leading
zeros to 20 digits, so we can use one text array, but sort the
numbers as if they were big integers.
For example, human_sort('Run 12 Miles') gives
{'Run ', '00000000000000000012', ' Miles'}
*/
select array_agg(
case
when a.match_array[1]::text is not null
then a.match_array[1]::text
else lpad(a.match_array[2]::text, 20::int, '0'::text)::text
end::text)
from (
select regexp_matches(
case when $1 = '' then null else $1 end, E'(\\D+)|(\\d+)', 'g'
) AS match_array
) AS a
$BODY$
LANGUAGE sql IMMUTABLE;
tested to work on Postgres 8.3.18 and 9.3.5
No recursion, should be faster than recursive solutions
Can be used in just the order by clause, don't have to deal with primary key or ctid
Works for any select (don't even need a PK or ctid)
Simpler than some other solutions, should be easier to extend and maintain
Suitable for use in a functional index to improve performance
Works on Postgres v8.3 or higher
Allows an unlimited number of text/number alternations in the input
Uses just one regex, should be faster than versions with multiple regexes
Numbers longer than 20 digits are ordered by their first 20 digits
Here's an example usage:
select * from (values
('Books 1', 9),
('Book 20 Chapter 1', 8),
('Book 3 Suffix 1', 7),
('Book 3 Chapter 20', 6),
('Book 3 Chapter 2', 5),
('Book 3 Chapter 1', 4),
('Book 1 Chapter 20', 3),
('Book 1 Chapter 3', 2),
('Book 1 Chapter 1', 1),
('', 0),
(null::text, 0)
) as a(name, sort)
order by human_sort(a.name)
-----------------------------
|name | sort |
-----------------------------
| | 0 |
| | 0 |
|Book 1 Chapter 1 | 1 |
|Book 1 Chapter 3 | 2 |
|Book 1 Chapter 20 | 3 |
|Book 3 Chapter 1 | 4 |
|Book 3 Chapter 2 | 5 |
|Book 3 Chapter 20 | 6 |
|Book 3 Suffix 1 | 7 |
|Book 20 Chapter 1 | 8 |
|Books 1 | 9 |
-----------------------------
Adding this answer late because it looked like everyone else was unwrapping into arrays or some such. Seemed excessive.
CREATE FUNCTION rr(text,int) RETURNS text AS $$
SELECT regexp_replace(
regexp_replace($1, '[0-9]+', repeat('0',$2) || '\&', 'g'),
'[0-9]*([0-9]{' || $2 || '})',
'\1',
'g'
)
$$ LANGUAGE sql;
SELECT t,rr(t,9) FROM mixed ORDER BY t;
t | rr
--------------+-----------------------------
AAA02free | AAA000000002free
AAA10bob | AAA000000010bob
AAA2bbb03boo | AAA000000002bbb000000003boo
AAA2bbb3baa | AAA000000002bbb000000003baa
AAA2fred | AAA000000002fred
(5 rows)
(reverse-i-search)`OD': SELECT crypt('richpass','$2$08$aJ9ko0uKa^C1krIbdValZ.dUH8D0R0dj8mqte0Xw2FjImP5B86ugC');
richardh=>
richardh=> SELECT t,rr(t,9) FROM mixed ORDER BY rr(t,9);
t | rr
--------------+-----------------------------
AAA2bbb3baa | AAA000000002bbb000000003baa
AAA2bbb03boo | AAA000000002bbb000000003boo
AAA2fred | AAA000000002fred
AAA02free | AAA000000002free
AAA10bob | AAA000000010bob
(5 rows)
I'm not claiming two regexps are the most efficient way to do this, but rr() is immutable (for fixed length) so you can index it. Oh - this is 9.1
Of course, with plperl you could just evaluate the replacement to pad/trim it in one go. But then with perl you've always got just-one-more-option (TM) than any other approach :-)
The following function splits a string into an array of (word,number) pairs of arbitrary length. If the string begins with a number then the first entry will have a NULL word.
CREATE TYPE alnumpair AS (wordpart text,numpart integer);
CREATE OR REPLACE FUNCTION regexp_split_numstring_depth_pairs(instr text)
RETURNS alnumpair[] AS $$
WITH x(match) AS (SELECT regexp_matches($1, '(\D*)(\d+)(.*)'))
SELECT
ARRAY[(CASE WHEN match[1] = '' THEN '0' ELSE match[1] END, match[2])::alnumpair] || (CASE
WHEN match[3] = '' THEN
ARRAY[]::alnumpair[]
ELSE
regexp_split_numstring_depth_pairs(match[3])
END)
FROM x;$$ LANGUAGE 'sql' IMMUTABLE;
allowing PostgreSQL's composite type sorting to come into play:
SELECT data FROM alnum ORDER BY regexp_split_numstring_depth_pairs(data);
and producing the expected result, as per this SQLFiddle. I've adopted Erwin's substitution of 0 for the empty string in all strings beginning with a number so that numbers sort first; it's cleaner than using ORDER BY left(data,1), regexp_split_numstring_depth_pairs(data).
While the function is probably horrifically slow it can at least be used in an expression index.
That was fun!
create table dat(val text)
insert into dat ( VALUES ('BBB0adam'), ('AAA10fred'), ('AAA2fred'), ('AAA2bob') );
select
array_agg( case when z.x[1] ~ E'\\d' then lpad(z.x[1],10,'0') else z.x[1] end ) alnum_key
from (
SELECT ctid, regexp_matches(dat.val, E'(\\D+|\\d+)','g') as x
from dat
) z
group by z.ctid
order by alnum_key;
alnum_key
-----------------------
{AAA,0000000002,bob}
{AAA,0000000002,fred}
{AAA,0000000010,fred}
{BBB,0000000000,adam}
Worked on this for almost an hour and posted without looking -- I see Erwin arrived at a similar place. Ran into the same "could not find array type for data type text[]" trouble as #Clodoaldo. Had a lot of trouble getting the cleanup exercise to not agg all the rows until I thought of grouping by the ctid (which feels like cheating really -- and doesn't work on a psuedo table as in the OP example WITH dat AS ( VALUES ('AAA2fred'), ('AAA10bob') )
...). It would be nicer if array_agg could accept a set-producing subselect.
I'm not a RegEx guru, but I can work it to some extent. Enough to produce this answer.
It will handle up to 2 numeric values within the content. I don't think OSX goes further than that, if it even handles 2.
WITH parted AS (
select data,
substring(data from '([A-Za-z]+).*') part1,
substring('a'||data from '[A-Za-z]+([0-9]+).*') part2,
substring('a'||data from '[A-Za-z]+[0-9]+([A-Za-z]+).*') part3,
substring('a'||data from '[A-Za-z]+[0-9]+[A-Za-z]+([0-9]+).*') part4
from alnum
)
select data
from parted
order by part1,
cast(part2 as int),
part3,
cast(part4 as int),
data;
SQLFiddle
The following solution is a combination of various ideas presented in other answers, as well as some ideas from the classic solution:
create function natsort(s text) returns text immutable language sql as $$
select string_agg(r[1] || E'\x01' || lpad(r[2], 20, '0'), '')
from regexp_matches(s, '(\D*)(\d*)', 'g') r;
$$;
The design goals of this function were simplicity and pure string operations (no custom types and no arrays), so it can easily be used as a drop-in solution, and is trivial to be indexed over.
Note: If you expect numbers with more than 20 digits, you'll have to replace the hard-coded maximum length 20 in the function with a suitable larger length. Note that this will directly affect the length of the resulting strings, so don't make that value larger than needed.