summing dynamic rows using over partition by postgres - sql

Question

on postgres 9.2
| payer| effective_status | 1 | 2 | 3 | 4+
+------+ -----------------+-------+--------+-----+-----
| p1 | foo | 8 | 6000 | 4| 1
| p1 | bar | 10 | 5200 | 9| 2
| p1 | baz | 11 | 5200 | 11| 2
| p1 | zip | 9 | 4500 | 14| 4
| p1 | zap | 7 | 4200 | 45| 5
| p1 | status_n | 2 | 3900 | 71| 1
suppose the above query output (minus the ??s). i am trying to sum columns 1, 2, 3, and 4+ by payer and effective status. so for p1 there would be a column total including all effective_statuses, and then p2 would have a group total.
| p1 | effective_status | 1 | 2 | 3 | 4+| 1 total | 2 total|3 total| 4+ total
+------+ -----------------+-------+--------+-----+---+---------+--------+-------+----------
| | foo | 8 | 6000 | 4| 1| 94 | 6230 | 154 | 15
| | bar | 10 | 5200 | 9| 2| 94 | 6230 | 154 | 15
| | baz | 11 | 5200 | 11| 2| 94 | 6230 | 154 | 15
| | zip | 9 | 4500 | 14| 4| 94 | 6230 | 154 | 15
| | zap | 7 | 4200 | 45| 5| 94 | 6230 | 154 | 15
| | status_n | 2 | 3900 | 71| 1| 94 | 6230 | 154 | 15
how would i calculate the ??s? my I ave tried:
payer
,effective_status
,status_check1
,SUM(status_check1) OVER (PARTITION BY payer) AS status_check1_total
,status_check2
,SUM(status_check2) OVER (PARTITION BY payer) AS status_check2_total
,status_check3
,SUM(status_check3) OVER (PARTITION BY payer) AS status_check3_total
,status_check4
,SUM(status_check4) OVER (PARTITION BY payer) AS status_check4_total
which seems to work, most of the time. on occasion there are wrong totals. is this the correct approach?

Answer 1

If I understand correctly, you can use UNION ALL to combine total result set and your original table. then use order by by the grp order.
CREATE TABLE T(
payer varchar(50),
effective_status varchar(50),
status_check1 int,
status_check2 int,
status_check3 int,
status_check4 int
);
INSERT INTO T VALUES ('p1', 'foo',8 ,6000,4,1);
INSERT INTO T VALUES ('p1', 'bar',10,5200,9,2);
INSERT INTO T VALUES ('p1', 'baz',11,5200,11,2);
INSERT INTO T VALUES ('p1', 'zip',9 ,4500,14,4);
INSERT INTO T VALUES ('p1', 'zap',7 ,4200,45,5);
INSERT INTO T VALUES ('p1', 'status_n',2 ,3900,71,1);
INSERT INTO T VALUES ('p2', 'foo',5 ,3500,12,2);
INSERT INTO T VALUES ('p2', 'zip',1 ,5000,1,1);
Query 1:
SELECT *
FROM (
SELECT t1.payer
,effective_status
,status_check1
,status_check2
,status_check3
,status_check4
,1 grp
FROM T t1
UNION ALL
SELECT payer,
'',
SUM(status_check1),
SUM(status_check2),
SUM(status_check3),
SUM(status_check4),
2
FROM T
GROUP BY payer
) t1
ORDER BY payer,grp
Results:
| payer | effective_status | status_check1 | status_check2 | status_check3 | status_check4 | grp |
|-------|------------------|---------------|---------------|---------------|---------------|-----|
| p1 | foo | 8 | 6000 | 4 | 1 | 1 |
| p1 | bar | 10 | 5200 | 9 | 2 | 1 |
| p1 | baz | 11 | 5200 | 11 | 2 | 1 |
| p1 | zip | 9 | 4500 | 14 | 4 | 1 |
| p1 | zap | 7 | 4200 | 45 | 5 | 1 |
| p1 | status_n | 2 | 3900 | 71 | 1 | 1 |
| p1 | | 47 | 29000 | 154 | 15 | 2 |
| p2 | foo | 5 | 3500 | 12 | 2 | 1 |
| p2 | zip | 1 | 5000 | 1 | 1 | 1 |
| p2 | | 6 | 8500 | 13 | 3 | 2 |

Answer 2

I'm not sure why you are using window functions. This would appear to be union all:
select payer, effective_status, status_check1, status_check2, status_check3, status_check4
from t
union all
select payer, null, sum(status_check1), sum(status_check2), sum(status_check3), sum(status_check4)
order by payer, effective_status nulls last;
Postgres 9.5 supports grouping sets which simplifies such logic.

Answer 3

Actually, I didn't get clearly what you are trying to do, but if you want to have result grouped by payer and effective_status it possibly would look like this
select
payer as p,
effective_status as es,
(sum(col1) + sum(col2) + sum(col3) + sum(col4)) as sum
from table_name
group by p, es
So, hope it will help you