SQL Server : show campaigns that a phone number appears in - sql

Question

I'm trying to get a report done within SQL Server that shows each sales campaign that a phone number appears in.
The desired result:
Phonenumber | Area Code | Campaign 1 | Campaign 2 (if applicable) etc...
I have the following code:
with cids as
(
select distinct
a.outbound_cid as [CID],
a.areacode as [AreaCode],
a.campaign_id as [Campaign]
from
vicislave...vicidial_campaign_cid_areacodes a
join
LDS_SALES_CAMPAIGNS b on a.campaign_id = b.campaign_id
)
select *
from cids
order by cid
Which returns this result (data example):
In this example, I would get
2012444340 201 ZEPTR ZEACC ZBEASTC ZEPRR InBnd2 ZEPSC ZEJCC ZEJSC ZEPCC ZEASC
I've not worked with cross-tabbing before, but it appears to be something that may work, but I have not been able to make it work like I can. Obviously, I can do the MIN and MAX of each of these, but I don't know of a way to get the data into the one row, even using things like Excel, without manually doing it, which with 1110 results with these, I don't really have time to do it.
Not to ape the help that I got from below, here is the exact code that worked:
select distinct
a.outbound_cid as [CID],
a.areacode as [AreaCode],
a.campaign_id as [Campaign]
into
#CIDs
from
vicislave...vicidial_campaign_cid_areacodes a
join
LDS_SALES_CAMPAIGNS b on a.campaign_id = b.campaign_id
select distinct
CID,
areacode,
Campaign = stuff((select ', ' + c2.campaign
from #CIDs c2
where c2.CID = c.CID
for xml path(''), type).value('.', 'nvarchar(MAX)'), 1, 1, '')
from
#cids c
drop table #CIDs

Answer 1

If you use SQL server, you can use STUFF function. You can follow my sample. Hope to help, my friend!
Create table Test(CID nvarchar(10)
, AreaCode nvarchar(10)
, Campaign nvarchar(10))
Insert into Test(CID, AreaCode, Campaign)
values('2012', '201', 'ABC')
Insert into Test(CID, AreaCode, Campaign)
values('2012', '201', 'XYZ')
Insert into Test(CID, AreaCode, Campaign)
values('2014', '201', 'aaa')
Insert into Test(CID, AreaCode, Campaign)
values('2014', '201', 'bbb')
-----------
SELECT distinct CID
, Campaign = STUFF((
SELECT ',' + t2.Campaign
FROM Test t2
WHERE t.CID = t2.CID
FOR XML PATH(''), TYPE).value('.', 'NVARCHAR(MAX)'), 1, 1, '')
FROM Test t
ORDER BY t.CID

Answer 2

To obtain a single record from any table "TABLE" with a field "field" you have to do
SELECT ';'+rtrim(field)
FROM TABLE FOR XML PATH('')
Tha will return a single record with all the fields concatenated with ";"
in your case you should do :
select ';'+campaign from cids FOR XML PATH('')
order by cid
of course you can even group by CID Column if you need...
SELECT C.CID, (
select ';'+campaign from cids
where cids.CID=C.CID
FOR XML PATH(''))
from CIDS C
group by CID
that would do the trick