DATETIME gives date without time in SQL Server - sql

Question

I have a SQL query which should convert a datetime. I have tried it in different ways but in every way something goes wrong.
INSERT INTO SETTLEMENT_WIN (COUNTRY,
COMMODITY,
MARKET_PLACE,
START_TIME,
END_TIME)
VALUES ('BE', 'EL', NULL, CONVERT(datetime, '2015-12-14 15:45', 'YYYY-MM-DD HH24:MI'), CONVERT(datetime, '2015-12-14 16:00', 'YYYY-MM-DD HH24:MI'));
gives the error:
Msg 8116, Level 16, State 1, Line 1 Argument data type varchar is
invalid for argument 3 of convert function.
INSERT INTO SETTLEMENT_WIN (COUNTRY,
COMMODITY,
MARKET_PLACE,
START_TIME,
END_TIME)
VALUES ('BE', 'EL', NULL, CONVERT(datetime, '2008-12-14 15:45', 120), CONVERT(datetime, '2015-12-14 16:00', 120));
Inserts the row but in START_TIME and END_TIME there is only the date but not the time
Then I tried to only insert the time but even then only the date was inserted (I am not allowed to change the date format).
Declare #Date1 datetime ='2008-12-14 15:45';
Declare #Date2 datetime ='2015-12-14 16:00';
INSERT INTO SETTLEMENT_WIN (COUNTRY,
COMMODITY,
MARKET_PLACE,
START_TIME,
END_TIME)
VALUES ('BE', 'EL', NULL, CONVERT(datetime, #Date1, 108), CONVERT(datetime, #Date2, 108));
What am I doing wrong? I am using Microsoft SQL Server Management Studio 17.
The CREATE statement for my table is:
CREATE TABLE [SETTLEMENT_WIN] ([SW_ID] [numeric](18, 0) IDENTITY(1, 1) NOT NULL,
[COUNTRY] [varchar](32) NOT NULL,
[COMMODITY] [varchar](32) NOT NULL,
[MARKET_PLACE] [varchar](32),
[START_TIME] [date] NOT NULL,
[END_TIME] [date] NOT NULL,
CONSTRAINT [SW_PK]
PRIMARY KEY ([SW_ID]));

Answer 1

Exactly as I suspected:
[START_TIME] [date] NOT NULL,
[END_TIME] [date] NOT NULL,
If you provide a datetime value to a date datatype the time part of the value will be lost. Try:
DECLARE #d date;
SET #d = '2018-08-02T11:15:59.462'
SELECT #d;
Note it returns 2018-08-02. A date is just that, a date. A datetime, datetime2 or datetimeoffset needs to be used to store a date and time. You'll need to fix your table to resolve this:
ALTER TABLE dbo.SETTLEMENT_WIN ALTER COLUMN [START_TIME] datetime2(0) NOT NULL;
ALTER TABLE dbo.SETTLEMENT_WIN ALTER COLUMN [END_TIME] datetime2(0) NOT NULL;
Then you can insert a date and time value in your table.

Answer 2

#SilverFullbuster, you will need the datatype column in START_TIME and END_TIME changed from date to [datetime].
from:
CREATE TABLE [SETTLEMENT_WIN] ([SW_ID] [numeric](18, 0) IDENTITY(1, 1) NOT NULL,
[COUNTRY] [varchar](32) NOT NULL,
[COMMODITY] [varchar](32) NOT NULL,
[MARKET_PLACE] [varchar](32),
[START_TIME] [date] NOT NULL,
[END_TIME] [date] NOT NULL,
CONSTRAINT [SW_PK]
PRIMARY KEY ([SW_ID]));
to
CREATE TABLE [SETTLEMENT_WIN] ([SW_ID] [numeric](18, 0) IDENTITY(1, 1) NOT NULL,
[COUNTRY] [varchar](32) NOT NULL,
[COMMODITY] [varchar](32) NOT NULL,
[MARKET_PLACE] [varchar](32),
[START_TIME] [datetime] NOT NULL,
[END_TIME] [datetime] NOT NULL,
CONSTRAINT [SW_PK]
PRIMARY KEY ([SW_ID]));
and you can pull the starttime/endtime by extracting from the datetime column like this:
SELECT
SW_ID,
COUNTRY,
COMMODITY,
MARKET_PLACE,
START_TIME=convert(varchar(8), START_TIME, 108),
END_TIME=convert(varchar(8), END_TIME, 108)
FROM
SETTLEMENT_WIN
and results will be like this: