Input String: 201801
Output String format: 01.2018
I tried using following but it's not working, I also looked up for string to date convesrion/coercion table in "Type Coercion Table" https://docs.mulesoft.com/mule-user-guide/v/3.8/dataweave-types#type-coercion-table. I did not find something to help me with this.
as :date {format: "yyyyww"} as :string {format: "ww.yyyy"}
Appreciate if anyone has any ideas to share.
If you don't mind a bit of string hackery you could just move the various parts of the input string around:
%dw 1.0
%output application/json
%var inputDate = "201801"
---
{
outputDate: inputDate[4..5] ++ "." ++ inputDate[0..3]
}
The output of that is
{
"outputDate": "01.2018"
}
The above isn't null safe though, if there is a chance that the input date string is empty, or if it is shorter than 6 characters you will get a runtime error. You could work around that by checking the date in the DW, something like
outputDate: (inputDate[4..5] ++ "." ++ inputDate[0..3]) when inputDate != null and ( sizeOf inputDate ) == 6 otherwise null
Related
I want to remove the extra lines or "\n\r" & "\n" from the array but my solution is not working. Please provide the correct function or dataweave for this.
input (json array format):
[{"m":"a\n\r",
"a":"b\n"},
{"m":"a\r\n",
"a":"b\n"}]
expected output(json array format):
[{"m":"a",
"a":"b"},
{"m":"a",
"a":"b"}]
code:
%dw 2.0
var someSpaceJson = write(payload, "application/json", {"indent":false})
output application/json
---
someSpaceJson replace "\n\r" with ""
You need to specify \\ instead of \ to represent the escape char.
%dw 2.0
var someSpaceJson = write(payload, "application/json", {"indent":false})
output application/json
---
read((someSpaceJson replace "\\r" with "" replace "\\n" with ""),"application/json")
This should give you your desired output.
If you want to preserve the new lines between the values and only want to remove the trailing \r's and \n's you can use the following. This will also avoid converting JSON to string and back which generally should be avoided.
%dw 2.0
output application/json
---
payload map ($ mapObject ($$): trim($))
However, you need to make sure that all values are string or null. If that is not the case you can add those conditions in the mapObject function itself.
%dw 2.0
import * from dw::core::Binaries
output application/json
var userCredentials = vars.userCredentials.userName as String ++ ":" ++ vars.userCredentials.password as String
---
"Basic "++ toBase64(userCredentials as String)
Error [MULE:EXPRESSION] while running test 'get-authorization-token-test-success':"Cannot coerce Null (org.mule.weave.v2.model.values.NullValue$#799da78a) to String
1| %dw 2.0 import * from dw::core::Binaries output application/json var userCredentials = vars.userCredentials.userName as String ++ ":" ++ vars.userCredentials.password as String --- "Basic "++ toBase64(userCredentials as String)
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
Trace:
at ++ (line: 1, column: 89)
at ++ (line: 1, column: 129)
at main (line: 1, column: 136)" evaluating expression: "%dw 2.0 import * from dw::core::Binaries output application/json var userCredentials = vars.userCredentials.userName as String ++ ":" ++ vars.userCredentials.password as String --- "Basic "++ toBase64(userCredentials as String)".
I'll assume that the question is what is causing the error shown. The error is self describing really: You can not concatenate a null with a String. The underlined part of the script indicates the location of the issue. The problem seems to be that either the variable vars.userCredentials is null or it doesn't contain an attribute called userName. You'll have to figure why it reaches the script with a null value and fix it.
Double check the value stored in the vars.userCredentials. This error comes when this value or its elements userName or password are null.
In your data weave, you have written the statement vars.userCredentials.userName as String, which in runtime gets executed as null as String ==> and hence Mule runtime engine is throwing an error.
Hi i have a Date field which is coming as
{
"noteDate": "2013-12-18T00:00:00"
}
My Dataweave function is
%dw 2.0
output application/json
---
payload.noteDate as String {"format": "uuuu-MM-dd"}
//formattedDate: |2020-10-01T23:57:59| as String {format: "uuuu-MM-dd"}, // This is in Documentation
The output i am getting is
"2013-12-18T00:00:00"
Expected Output is
"2013-12-18"
How i can do it.
%dw 2.0
output application/json
---
payload.noteDate as Date
That is coming in as a string, not as a date. JSON has no concept of dates.
If you wanted to treat it as a DateTime and then apply a string format you could convert it first (shown below) but just casting it to a Date will do the same.
%dw 2.0
output application/json
---
(payload.noteDate as DateTime) as String { format: "uuuu-MM-dd" }
%output application/json
%var EmpIds=flowVars.empIDMap.EmpIds
---
payload map using(eNumber=$.EMPLOYEE) {
content: EmpIds.eNumber,
}
If i add value within double quotes i am getting value for example EmpIds."6" for
Need to append the first and last with " double quotes to get the value from EmpIds based on eNumber.
empIDMap data is :: {EmpIds={6=2, 19=3, 21=4, 36=5, 168421=6, 167727=7, 167729=8, 161759=9, 162052=10, 157633=11}}
can you please help on this.
To get value as string try eNumber= $.EMPLOYEE ++ "". This works fine.
I tried expression like below in mule dataweave but I am getting error.
pdate : "2017-06-22T12:45:55" as:datetime{format : "yyyy-Mm-dd'T'hh:mm:ss"} as :string{format: "MM/DD/yyyy"}
Can you please help on this if I missed anything to write.
try this:
%dw 1.0
%output application/json
---
{
pdate: "2017-06-22T12:45:55" as :localdatetime { format: "yyyy-MM-dd'T'HH:mm:ss" } as :string { format: "MM/dd/yyyy" }
}
changes compared to your version:
replace Mm with MM in first format string, thx #Dai
replace hh with HH in first format string
replace DD with 'dd' in second format string