I'm looking to select the primary key of a row and I've only got a column that contains info (in a substring) that I need to select the row.
E.g. MyTable
ID | Label
------------
11 | 1593:#:#:RE: test
12 | 1239#:#:#some more random text
13 | 12415#:#:#some more random text about the weather
14 | 369#:#:#some more random text about the StackOverflow
The label column has always a delimiter of :#:#:
So really I guess, I'd need to be able to split this row by the delimiter, grab the first part of the label column (i.e. the number I'm looking) to get the id I wanted.
So, If I wanted row with ID of 14, then I'd be:
Select ID from MyTable
where *something* = '369'
Any ideas on how to construct something ..or how best to go about this:)
I'm completely stumped and haven't been able to find how to do this.
Thanks,
How about:
WHERE label LIKE '369#%'?
No reason to get fancy.
Although.. if you are going to do this search often, then maybe pre-split that value out to another column as part of your ETL process and index it.
Related
I'm not sure if my question is really stupid, but I found nothing on the internet...
Is it possible to insert a specific value in a cell of a matrix?
for example I have a dataset like below:
Month Prod Amount
2 X 34$
11 Y 12$
7 Z 150$
and a matrix like:
-------| Month |
Prduct |SUM(Amount)|
So the row group are products and column group are the months of a specific year.
If I want to add an extra column, with a specific value chosen dynamically from the amount (for xample 150$) so to have
-------| Month |columnName
Prduct |SUM(Amount)| 150
is that possible? also if the value is repeated through the column (it would be useful if I wanted the new column to have this specific value added for each value)
thanks a lot!! :D
You can insert a value directly in your matrix but it will be repeated for each record.
The best way is to add a new column with conditional values is to do this in your dataset query. Probably with a CASE statement if you are using SQL.
EDIT: If you can't adjust the query for whatever reason, you can add the new column and use SWITCH function inside your textbox to achieve the same.
What I'm trying to do is add another column to an existing table whose value will depend on an already existing column in the table. For example say I have this table:
Table1
|Letter|
A
C
R
A
I want to create another column (for example, numbers) that is chosen based on the letters. So let's say A corresponds with 10, C with 3 and R with 32 (this was chosen at random). My resulting table should be like this:
|Letter| Number |
A | 10
C | 3
R | 32
A | 10
Can anyone help me write a query that does this..I have over 20 different cases, so the simpler it looks the better.
Thanks in advance!
Options:
Build a table that associates [Letter] with the numeric value. Include this table in query by joining on the common [Letter] fields.
A very long Switch() expression. However, query design grid cell has a limit of 1024 characters.
Better to provide example with your real data and criteria.
I have a column that stores 2 values. Example below:
| Column 1 |
|some title1 =ExtractThis ; Source Title12 = ExtractThis2|
I want to remove 'ExtractThis' into one column and 'ExtractThis2' into another column. I've tried using a substring but it doesn't work as the data in column 1 is variable and therefore it doesn't always carve out my intended values. SQL below:
SELECT substring(d.Column1,13,24) FROM dbo.Table d
This returns 'Extract This' but for other columns it either takes too much or too little. Is there a function or combination of functions that will allow me to split consistently on the character? This is consistent in my column unlike my length count.
select substring(col1,CHARINDEX('=',col1)+1,CHARINDEX (';',col1)-CHARINDEX ('=',col1)-1) Val1,
substring(col1,CHARINDEX('=',col1,CHARINDEX (';',col1))+1,LEN(col1)) Val2
from #data
there is duplicate calculation that can be reduced from 5 to 3 to each line.
but I want to believe this simple optimization done by SQL SERVER.
I have a table which contains geometry lines (ways).There are lines that have a unique geometry (not repeating) and lines which have the same geometry (2,3,4 and more). I want to list only unique ones. If there are, for example, 2 lines with the same geometry I want to drop them. I tried DISTINCT but it also shows the first result from duplicated lines. I only want to see the unique ones.
I tried window function but I get similar result (I get a counter on first line from the duplicating ones). Sorry for a newbie question but I'm learning :) Thanks!
Example:
way|
1 |
1 |
2 |
3 |
3 |
4 |
Result should be:
way|
2 |
4 |
That actually worked. Thanks a lot. I also have other tags in this table for every way (name, ref and few other tags) When I add them to the query I loose the segregation.
select count(way), way, name
from planet_osm_line
group by way, name
having count(way) = 1;
Without "name" in the query I get all unique values listed but I want to keep "name" for every line. With this example I stilll get all the lines in the table listed.
To expound on #Nithila answer:
select count(way), way
from your_table
group by way
having count(way) = 1;
You first calculate the rows you want, and then search for the rest of the fields. So the aggregation doesnt cause you problems.
WITH singleRow as (
select count(way), way
from planet_osm_line
group by way
having count(way) = 1
)
SELECT P.*
FROM planet_osm_line P
JOIN singleRow S
ON P.way = S.way
you can group by way and while taking the data out check the count=1.It will give non duplicating data.
#voyteck
As I understood your question you need to get only non duplicating records of way column and for each row you need to show the name is it
If so, you have to put all the column in select statement, but no need to group by all the columns.
select count(way), way, name
from planet_osm_line
group by way
having count(way) = 1;
I have a Hive table, titled 'UK.Choices' with a column, titled 'Fruit', with each row as follows:
AppleBananaAppleOrangeOrangePears
BananaKiwiPlumAppleAppleOrange
KiwiKiwiOrangeGrapesAppleKiwi
etc.
etc.
There are 2.5M rows and the rows are much longer than the above.
I want to count the number of instances that the word 'Apple' appears.
For example above, it is:
Number of 'Apple'= 5
My sql so far is:
select 'Fruit' from UK.Choices
Then in chunks of 300,000 I copy and paste into Excel, where I'm more proficient and able to do this using formulas. Problem is, it takes upto an hour and a half to generate each chunk of 300,000 rows.
Anyone know a quicker way to do this bypassing Excel? I can do simple things like counts using where clauses, but something like the above is a little beyond me right now. Please help.
Thank you.
I think I am 2 years too late. But since I was looking for the same answer and I finally managed to solve it, I thought it was a good idea to post it here.
Here is how I do it.
Solution 1:
+-----------------------------------+---------------------------+-------------+-------------+
| Fruits | Transform 1 | Transform 2 | Final Count |
+-----------------------------------+---------------------------+-------------+-------------+
| AppleBananaAppleOrangeOrangePears | #Banana#OrangeOrangePears | ## | 2 |
| BananaKiwiPlumAppleAppleOrange | BananaKiwiPlum##Orange | ## | 2 |
| KiwiKiwiOrangeGrapesAppleKiwi | KiwiKiwiOrangeGrapes#Kiwi | # | 1 |
+-----------------------------------+---------------------------+-------------+-------------+
Here is the code for it:
SELECT length(regexp_replace(regexp_replace(fruits, "Apple", "#"), "[A-Za-z]", "")) as number_of_apples
FROM fruits;
You may have numbers or other special characters in your fruits column and you can just modify the second regexp to incorporate that. Just remember that in hive to escape a character you may need to use \\ instead of just one \.
Solution 2:
SELECT size(split(fruits,"Apple"))-1 as number_of_apples
FROM fruits;
This just first split the string using "Apple" as a separator and makes an array. The size function just tells the size of that array. Note that the size of the array is one more than the number of separators.
This is straight-forward if you have any delimiter ( eg: comma ) between the fruit names. The idea is to split the column into an array, and explode the array into multiple rows using the 'explode' function.
SELECT fruit, count(1) as count FROM
( SELECT
explode(split(Fruit, ',')) as fruit
FROM UK.Choices ) X
GROUP BY fruit
From your example, it looks like fruits are delimited by Capital letters. One idea is to split the column based on capital letters, assuming there are no fruits with same suffix.
SELECT fruit_suffix, count(1) as count FROM
( SELECT
explode(split(Fruit, '[A-Z]')) as fruit_suffix
FROM UK.Choices ) X
WHERE fruit_suffix <> ''
GROUP BY fruit_suffix
The downside is that, the output will not have first letter of the fruit,
pple - 5
range - 4
I think you want to run in one select, and use the Hive if UDF to sum for the different cases. Something like the following...
select sum( if( fruit like '%Apple%' , 1, 0 ) ) as apple_count,
sum( if( fruit like '%Orange%', 1, 0 ) ) as orange_count
from UK.Choices
where ID > start and ID < end;
instead of a join in the above query.
No experience of Hive, I'm afraid, so this may or may not work. But on SQLServer, Oracle etc I'd do something like this:
Assuming that you have an int PK called ID on the row, something along the lines of:
select AppleCount, OrangeCount, AppleCount - OrangeCount score
from
(
select count(*) as AppleCount
from UK.Choices
where ID > start and ID < end
and Fruit like '%Apple%'
) a,
(
select count(*) as OrangeCount
from UK.Choices
where ID > start and ID < end
and Fruit like '%Orange%'
) o
I'd leave the division by the total count to the end, when you have all the rows in the spreadsheet and can count them there.
However, I'd urgently ask my boss to let me change the Fruit field to be a table with an FK to Choices and one fruit name per row. Unless this is something you can't do in Hive, this design is something that makes kittens cry.
PS I'd missed that you wanted the count of occurances of Apple which this won't do. I'm leaving my answer up, because I reckon that my However... para is actually a good answer. :(