Select from all_tab_columns where table has > 0 rows - sql

Question

I need to search in a large DB a table that matches with a column name, but this table must have more than 0 rows.
Here is the query by the way:
SELECT * FROM all_tab_columns WHERE column_name LIKE '%ID_SUPPORT%';

Answer 1

You could use single query to filter names and get actual number of rows:
SELECT owner, table_name, cnt
FROM all_tab_columns, XMLTABLE('/ROWSET/ROW' passing
(dbms_xmlgen.getxmltype(REPLACE(REPLACE(
'select COUNT(*) AS cnt from <owner>.<table_name>', '<owner>', owner)
, '<table_name>', table_name))) COLUMNS cnt INT)
WHERE column_name LIKE '%ID_SUPPORT%' AND cnt > 0;
DBFiddle Demo
Any chance this can be expanded/tweaked to yield the values of the first few rows for all tables?
Yes, by flattening row using JSON_ARRAYAGG(JSON_OBJECT(*)) Oracle 19c:
-- generic approach Oracle 19c
SELECT owner, table_name, cnt, example
FROM all_tab_columns, XMLTABLE('/ROWSET/ROW' passing
(dbms_xmlgen.getxmltype(REPLACE(REPLACE(
'select COUNT(*) AS cnt,
MAX((SELECT JSON_ARRAYAGG(JSON_OBJECT(*))
FROM <owner>.<table_name>
WHERE rownum < 10) -- taking up to 10 rows as example
) as example
from <owner>.<table_name>', '<owner>', owner)
, '<table_name>', table_name)))
COLUMNS cnt INT
, example VARCHAR2(1000))
WHERE column_name LIKE '%ID_SUPPORT%'
AND cnt > 0;
Demo contains hardcoded column list inside JSON_OBJECT. Oracle 19c and JSON_OBJECT(*) would allow any column list per table.
db<>fiddle demo
How it works:
find all tables that have column named '%ID_SUPPORT'
run query per table using dbms_xml_gen.getxmltype
in sub query count the rows, flatten few rows an example to JSON
return rows that have at least one record table

Answer 2

One way:
SELECT * FROM all_tables WHERE num_rows > 0
AND table_name in (SELECT table_name FROM all_tab_columns WHERE column_name LIKE '%ID_SUPPORT%')

Answer 3

If your DB is periodically analyzed the direct way is to use the following SQL :
SELECT *
FROM all_tables t
WHERE t.table_name LIKE '%ID_SUPPORT%'
and t.num_rows > 0;
More precise way to determine is using the following :
declare
v_val pls_integer := 0;
begin
for c in (
SELECT *
FROM all_tables t
WHERE t.table_name LIKE '%ID_SUPPORT%'
)
loop
execute immediate 'select count(1) from '||c.owner||'.'||c.table_name into v_val;
if v_val > 0 then
dbms_output.put_line('Table Name : '||c.table_name||' with '||v_val||' rows ');
end if;
end loop;
end;
I'm confused with the word matches. If you mean column, but not table, you may use the following routine to get the desired tables with columns whose names are like ID_SUPPORT :
declare
v_val pls_integer := 0;
begin
for c in (
SELECT t.*
FROM all_tab_columns c
JOIN all_tables t on ( c.table_name = t.table_name )
WHERE c.column_name LIKE '%ID_SUPPORT%'
)
loop
execute immediate 'select count(1) from '||c.owner||'.'||c.table_name into v_val;
if v_val > 0 then
dbms_output.put_line('Table Name : '||c.table_name||' with '||v_val||' rows ');
end if;
end loop;
end;