How to insert 3.5k ints to array in Oracle DB - sql

Question

I have custom type:
create or replace type integer_varray as varray (4000) of int;
Then table which uses this array:
create table plan_capacities
(
id int generated by default as identity not null constraint plan_capacities_pkey primary key,
line_id int references lines (id) on delete cascade,
model_id int references models (id) on delete cascade,
plan_id int references plans (id) on delete cascade,
capacity integer_varray
);
And then some data I would like to insert in. The problem is that in Oracle I can't use more than 1000 items (I have 3 500 items) in the array "constructor" so simple statement
INSERT INTO plan_capacities ("model_id", "line_id", "plan_id", "capacity") VALUES (1,1,1,integer_varray(1,2,3.....35000))
Is not possible to use. (data are some capacities and the have to be in the specific order).
Data that should be inserted into array are in a string I have to put into script. -> {1,10,11,10,20,0,0,0,1,10 ....}
How can I insert that load of data?
I tried to insert them into temp table and then filling array with them - this works but that sql script has 3500 rows (to create just one records to plan_capacities) which is awful and big.

Answer 1

You can use your array as a table to insert its values into a table with a single SQL statement; for example:
declare
vArray integer_varray;
begin
-- some code to populate vArray
insert into someTable(col)
select column_value from table(vArray);
end;
If you can populate your array with a query, you don't need the array, simply using your query as a data source for the insert statement; for example:
insert into someTable(col)
select something
from someOtherTable
If you need a way to create a set of numbers, say 1, 2, ... 3500, this is a commonly used way:
select level
from dual
connect by level <= 3500
About a way to build a set of numbers from a string, this is a quite usual way:
SQL> create or replace type integer_varray as varray (4000) of int
2 /
Type created.
SQL> create table someTable(n number);
Table created.
SQL> declare
2 vString varchar2(32000) := '1,10,11,10,20,0,0,0,1,10';
3 vArray integer_varray;
4 begin
5 insert into someTable(n)
6 select to_number(regexp_substr(vString, '[^,]+', 1, level))
7 from dual
8 connect by instr(vString, ',', 1, level - 1) > 0;
9 end;
10 /
PL/SQL procedure successfully completed.
SQL> select * from someTable;
N
----------
1
10
11
10
20
0
0
0
1
10
10 rows selected.
SQL>

Answer 2

So my final solution is following:
create or replace type integer_varray as varray (4000) of int;
/
create or replace type varchar_varray as varray (10) of varchar(32767);
/
declare
data_to_be_stored varchar_varray := varchar_varray(
'0,0,0,0,.....',
'0,0,0,0,0,0....',
'0,0,0,0,0,0....'
);
array_to_store integer_varray := integer_varray();
begin
for i in 1 .. data_to_be_stored.COUNT loop
for j in (select to_number(trim(regexp_substr(data_to_be_stored(i), '[^,]+', 1, LEVEL))) value
from dual
connect by LEVEL <= regexp_count(data_to_be_stored(i), ',') + 1
) loop
array_to_store.extend;
array_to_store(array_to_store.count) := j.value;
end loop;
end loop;
insert into table_with_that_array (array) values (array_to_store);
end;
\
I had to you use varchar_varraybecause my data/strings are bigger than max capacity of varchar2so I split it into multiple strings in array.