I have a table in SQL Server 2017. In this table date stores as a decimal in next format:
20180717164540.2200000
YYYYMMDDhhmiss.nnnnnnn
4 digits for the year, 2 digits for a calendar month, 2 digits for a day of a month, 2 digits for a 24-hour based hour of the day in UTC, 2 digits for a minute of an hour, 2 digits for seconds of a minute, and fractional seconds.
My aim is to transform this format into DateTime and store it in another table in a database.
So my question is how to convert this format to DateTime format in SQL Server. As far as I know, you can not create custom date format like in Oracle.
I tried a lot of times with FORMAT AND CONVERT MSSQL functions but it not gonna work.
SELECT FORMAT(CONVERT(NVARCHAR(22), DECIMALCOLUMN), 'YYYYMMDDhhmiss') FROM SOURCE-TABLE;
Thank you for your help!
You were really close with your FORMAT idea. FORMAT gives you an NVARCHAR output, which you can explicitly CAST as a DATETIME2(7) (which maintains your precision level).
DECLARE #dateWannaBe DECIMAL(21,7) = 20180717164540.2200000;
SELECT CAST(FORMAT(#dateWannaBe,'####-##-## ##:##:##.#######', 'en-US') AS DATETIME2(7)) AS ActualDateTime2;
+-----------------------------+
| ActualDateTime2 |
+-----------------------------+
| 2018-07-17 16:45:40.2200000 |
+-----------------------------+
EDIT: Added the culture parameter to the FORMAT function per #JeroenMostert's comment.
a lot of stuffing
declare #dt decimal(30,8) = 20180717164540.2200000
select #dt, convert(datetime2,
stuff(
stuff(
stuff(
convert(varchar(30), #dt),
9, 0, ' '),
12, 0, ':'),
15, 0, ':')
)
/* RESULT
20180717164540.22000000 2018-07-17 16:45:40.2200000
*/
Try this:
DECLARE #date DECIMAL (30,7) =20180717164540.2200000
SELECT CONVERT(DATETIME, SUBSTRING(CONVERT(VARCHAR, #date),1,4) + '-' + SUBSTRING(CONVERT(VARCHAR, #date),5,2)
+ '-' + SUBSTRING(CONVERT(VARCHAR, #date),7,2) + ' ' + SUBSTRING(CONVERT(VARCHAR, #date),9,2) + ':' +
SUBSTRING(CONVERT(VARCHAR, #date),11,2) + ':' + SUBSTRING(CONVERT(VARCHAR, #date),13,2) + '.' + SUBSTRING(CONVERT(VARCHAR, #date),16,2))
You need SUBSTRING() function with stuff() :
select dateadd(ss, datediff(ss, 0, cast(stuff(stuff(substring(cast(#date as varchar(30)), 9, 20), 3, 0, ':'), 6, 0, ':') as datetime2)),
substring(cast(#date as varchar(10)), 1, 8)
)
. . .
DECLARE #TIME DECIMAL(38,8)
SET #TIME = '20180717164540.2200000'
SELECT CAST([DT] AS DATETIME) FROM(
SELECT LEFT(CAST(#TIME AS VARCHAR),4) +
SUBSTRING(CAST(#TIME AS VARCHAR),5,2) +
SUBSTRING(CAST(#TIME AS VARCHAR),7,2) + ' ' +
SUBSTRING(CAST(#TIME AS VARCHAR),9,2) + ':'+
SUBSTRING(CAST(#TIME AS VARCHAR),11,2) + ':' +
SUBSTRING(CAST(#TIME AS VARCHAR),13,2) AS DT
) AS X
Another approach, using LEFT, SUBSTRING and RIGHT
DECLARE #str nvarchar(22) = '20180717164540.2200000'
SELECT CONVERT(datetime2,
LEFT(#str,4)+
SUBSTRING(#str,5,2)+
SUBSTRING(#str,7,2)+' '+
SUBSTRING(#str,9,2)+':'+
SUBSTRING(#str,11,2)+':'+
SUBSTRING(#str,13,2)+'.'+
RIGHT(#str,7))
You could stuff and use DateTime2 instead of DateTime:
select
cast(stuff(stuff(stuff(
cast(mydate as varchar(30)),
13,0,':'),
11,0,':'),
9,0,' ') as datetime2) as myDateTime from myTable;
Related
I have a SQL Server column which is called DATE with this sample data 19452801102747.
I have this code
SELECT REPLACE(CONVERT(CHAR(10), [DATE], 103), '/', '')
I can get the date okay, is the final part of converting HH:MM:SS.
I am using SSMS 2018 and I would like to have two column separate; columns as shown on below image (DATE(DD:MM:YYYY))(TIME(HH:MM:SS))
Many thanks for your help.
We can use a simple substring to add date time separator in your varchar string,
because we cannot directly convert varchar to datetime..
DECLARE #date varchar(50) = '19452801102747' declare #date1 varchar(50)
SET
#date1 = SUBSTRING(#date, 1, 4) + '-' + substring(#date, 7, 2) + '-' + substring(#date, 5, 2) + ' ' + substring(#date, 9, 2) + ':' + substring(#date, 11, 2) + ':' + substring(#date, 13, 2)
SELECT convert(datetime, #date1)
First of all: You should not store datetime values in a non-appropriate datatype.
Your example looks like YYYYddMMHHmmss. There is no out of the box conversion for this...
The following will perform a number of string methods in order to transform your own format to a standard format. In this case I chose ISO8601, which is YYYY-MM-ddTHH:mm:ss:
DECLARE #YourDate VARCHAR(100)='19452801102747';
SELECT CONVERT(DATETIME,STUFF(LEFT(#YourDate,4) + STUFF(STUFF(STUFF(STUFF(SUBSTRING(#YourDate,7,1000),7,0,':'),5,0,':'),3,0,'T'),1,0,'-'),8,0,'-' + SUBSTRING(#YourDate,5,2)),126);
The STUFF() calls will insert some characters in the right position. Furthermore some string cutting will swap your ddMM to MMdd.
I have in my table a varchar column with bunch of dates in the following format dd-MM-yyyy
31-12-2018
01-01-2019
02-01-2019
I need to write a date based query that gets all the dates before 01-01-2019.
I have tried using both CAST and CONVERT to convert these table values without luck.
Using CAST, my code is below:
SELECT
CAST('''' + SUBSTRING(arc_billed_to_date, 4, 2) + '-' + SUBSTRING(arc_billed_to_date, 1, 2) + SUBSTRING(arc_billed_to_date, 6, 5)+ '''' AS date),
CAST('''' + SUBSTRING(arc_billed_to_date, 7, 5) + '-' + SUBSTRING(arc_billed_to_date, 1, 2) + '-' + SUBSTRING(arc_billed_to_date, 4, 2) + '''' AS date),
CAST('''' + SUBSTRING(arc_billed_to_date, 7, 5) + '-' + SUBSTRING(arc_billed_to_date, 4, 2) + '-' + SUBSTRING(arc_billed_to_date, 1, 2) + '''' AS DATE),
CONVERT(DATE, '12-31-2018') AS x
FROM
wkpol
Using Convert
select Convert(datetime,'''' + SUBSTRING(arc_billed_to_date,7,5) + '-' + SUBSTRING(arc_billed_to_date,4,2) + '-' + SUBSTRING(arc_billed_to_date,1,2)+ '''',105) as x from wkpol
The error I get is
Conversion failed when converting date and/or time from character string.
Any help is appreciated.
SELECT *
FROM wkpol
WHERE convert(date, arc_billed_to_date, 103) < convert(date, '01/01/2019');
Well you are going to get many blames for using varchar field for date. Anyway, assuming it is a matter of another thread you can do the conversion like:
select * from myTable
where cast(right(arc_billed_to_date,4) +
substring(arc_billed_to_date,4,2) +
left(arc_billed_to_date,2) as date) < '20190101';
You wouldn't be using any index either.
In addition to Sean's comments, you can also set the DateFormat as DMY
Example
Declare #YourTable table (SomeCol varchar(50))
Insert Into #YourTable values
('31-12-2018')
,('01-01-2019')
,('02-01-2019')
Set DateFormat DMY
Select AsDate = try_convert(date,SomeCol)
From #YourTable
Returns
AsDate
2018-12-31
2019-01-01
2019-01-02
I have big-int data, and I want to convert it from Big-int to just time, for example I have this value 53006745 for ' 14hrs 43min '
Please help me to write the query in SQL Server, so that will convert big-int into minutes.
If You're looking Pure Time you could try below SQL Query which will give Minutes from Your Integer Value:
DECLARE #value INT = 53006745
SELECT DATEPART(MINUTE, DATEADD(s, CONVERT(BIGINT, #value) / 1000, CONVERT(DATETIME, '1-1-2017 00:00:00'))) [Minutes];
Result :
Minutes
43
You can use this code for yourself in SQL :
SELECT DATEADD(s, CONVERT(BIGINT, 53006745 ) / 1000,
CONVERT(DATETIME,
'1-1-1970 00:00:00'))
This code return 1970-01-01 14:43:26.000 as you like
DECLARE #Value INT = 53006745
SELECT
CONVERT(VARCHAR, #Value/3600000) + ':' -- Hours
+ RIGHT('0' + CONVERT(VARCHAR, #Value%3600000/60000), 2) + ':' -- Minutes
+ RIGHT('0' + CONVERT(VARCHAR, #Value%3600000%60000/1000), 2) + '.' -- Seconds
+ RIGHT('00' + CONVERT(VARCHAR, #Value%1000), 3) -- Milliseconds
I've received a flat file and after parsing and inserting it in a table. I've a column which has dates in a format yyyyMMddhhmmss
Here, yyyy is year, MM is month, dd is day, hh is hours, mm is minute and ss is seconds part
I'm trying to convert this to DateTime type as mentioned below but not working for me
SELECT CAST(StrDate as DateTime) FROM [dbo].[Mytable]
For example:
Column has a value 20150121190941 in Varchar format and it should be converted to DateTime as 2015-01-21 19:09:41.000
I apologize if it's a duplicate one.
You can use select DATETIMEFROMPARTS ( year, month, day, hour, minute, seconds, milliseconds )
declare #dt nvarchar(25) = '20150121190941'
select datetimefromparts(left(#dt,4), substring(#dt,5,2), substring(#dt,7,2),substring(#dt,9,2), substring(#dt,11,2), substring(#dt,13,2), '000')
SQL Server readily recognizes YYYYMMDD as a date. So, converting the first 8 characters to a date is easy. Alas, I don't think there is a time representation without colons.
So, here is one rather brutal method:
select (convert(datetime, left(StrDate, 8)) +
convert(time, substring(StrDate, 9, 2 ) + ':' + substring(StrDate, 11, 2 ) + ':' + substring(StrDate, 13, 2 )
)
)
Declare #dt varchar(50)
set #dt=20150121190941
create table tblDateTbl
(
col1 datetime
)
insert into dt (col1)
select SUBSTRING(#dt,1,4) + '-' + SUBSTRING(#dt,5,2) + '-' + SUBSTRING(#dt,7,2)+ ' ' + SUBSTRING(#dt,9,2)+ ':' + SUBSTRING(#dt,11,2)+ ':' + SUBSTRING(#dt,13,2)+ '.000'
I am trying to convert from "tick" date format to a datetime format.
Example:
0000113326 to 2013-11-22 00:00:00.000
I know how to go the opposite way:
SELECT '00001' + RIGHT(CAST(YEAR(StartDate) AS varCHAR(4)), 2) + RIGHT('000' + CAST(Datepart(dy, StartDate) AS VARCHAR(3)), 3)
FROM table
I just need to reverse engineer it.
Any ideas?
Something like this?
DECLARE #tick varchar(20) = '0000113326'
SELECT dateadd(d, cast(right(#tick, 3) as int) - 1, '20' + substring(#tick, 6, 2) + '0101')