I would like to be able to remove whitespace and newlines for a block of code/text.
A single line is sometimes easier to copy paste into cli tools.
I currently do this using find and replace on whitespace and newlines, but is there a faster way?
Found this after a bit of digging in the keymap:
Join lines: Ctrl+Shift+J
It even handles multi-line comments.
Related
In vue, is there a way to have a value span multiple lines in an .env file. Ex:
Instead of:
someValue=[{"someValue":"Here is a really really long piece which should be split into multiple lines"}]
I want to do something like:
someValue=`[{"someValue":"Here is a really
really long piece which
should be split into multiple lines"}]`
Doing the latter gives me a JSON parsing error if I try to do JSON.parse(someValue) in my code
I don't know if this will work, but I can't format a comment appropriately enough to get the point across so see if this will work:
someValue=[{"someValue":"Here is a really\
really long piece which\
should be split into multiple lines"}]
Where "\" should escape the newline similar to how you can write long bash commands while escaping the newline. I'm not certain the .env interpreter will support it though.
EDIT
Looks like this won't work. This syntax was actually proposed, but I don't think it was incorporated. See motdotla/dotenv#333 (which is what Vue uses to parse .env).
Like #zero298 said, this isn't possible. Likely you could delimit the entry with a character that wouldn't show up normally in the text (^ is a good candidate), then parse it within the application using string.replace('^', '\n');
There is a large file where the last symbols are \r\n. I need to remove them. It seems to be equivalent to removing the last line(?).
UPD: no, it's not: a file have only one line, which ends with \r\n.
I know two ways, but both don't work for AIX:
sed 's/\r\n$//' file # I don't why it doesn't work
head -c-2 # head doesn't work with negative numbers
Is there any solution for AIX? A lot of large files must be processed, so performance is important.
Usually, if you need to edit a file via a script in place, I use ed due to historical reasons. For example:
ed - /tmp/foo.txt <<EOF
g/^$/d
w
q
EOF
ed is more than a bit cantankerous. Note also that you did not really remove the empty lines at the bottom of the file but rather all of the empty lines. With ed and some practice you can probably achieve deleting only the empty lines at the bottom of the file. e.g. go to the bottom of the file, search up for a non-empty line, then move down a line and delete from that point to the end of the file. ed command scripts act (pretty much) as you would expect.
Also, if they really do have \r\n, then those are not going to be considered empty lines but rather lines with a control-M (\r) in them. You may need to adjust your pattern if that is the case.
My answer https://stackoverflow.com/a/46083912/3220113 to the duplicate question should work here too. Another solution is using
awk ' (NR>1) { print s }
{s=$0}
END { printf("%s",substr($2, 1, length($2)-1) ) }
' inputfile
Probably quite a niche question, but I believe in the power of a big community: Is it possible to set up jEdit in way, that it automatically inserts a comment character (//, #, ... depending on the edit mode) at the beginning of a new line, if the line before the wrap was a comment?
Sample:
# This is a comment spanning multiple lines. If I continue to type here, it
# wraps around automatically, but I have to manually add a `#` to each line.
If I continue to type after the . the third line should start with the # automatically. I searched in the plugin repository but could not find anything related.
Background: jEdit has the concepct of soft and hard wrap. While soft wrap only breaks lines visually at a character limit, it does not insert line breaks in the file. Hard wrap on the other hand inserts \n into the file at the desired character count.
This is not exactly what you want: I use the macros Enter_with_Prefix.bsh to automatically insert the prefix (e.g., #, //) at the beginning of the new line.
Description copied from Enter_with_Prefix.bsh:
Enter_with_Prefix.bsh - a Beanshell macro for jEdit
that starts a new line continuing any recognized
sequence that started the previous. For example,
if the previous line beings with "1." the next will
be prefixed with "2.". It supports alpha lists (a., b., etc...),
bullet lists (+, =, *, etc..), comments, Javadocs,
Java import statements, e-mail replies (>, |, :),
and is easy to extend with new sequence types. Suggested
shortcut for this macro is S+ENTER (SHIFT+ENTER).
I know there are a lot of resources with regex for it. But I could not find the one I want.
My problem is:
I want to remove one line comments (//) from obj-c sources, but I don't want to break the code in it. For instance, with this regex: #"//.*" I can remove all comments, but it also corrupts string literal:
#"bsdv//sdfsdf"
I played with non-capturing parentheses (?:(\"*\")*+), but without success.
Also I found this expression for Python:
r'(\".*?\"|\'.*?\')|(/\*.*?\*/|//[^\r\n]*$)'
It should cover my case, but I've not figure out how to make it work with obj-c.
Please, help me to build proper regex.
UPDATE: Yeah, that's a tough one, I know there're a lot of caveats, other than the one I described. I would appreciate if someone post regex that only fix my issue. Anyway, I gonna post my solution, without regex soon, I hope it will be helpful for anyone who struggling with such problem too.
Try this regex:
(?:^|.*;(?!.*")|#(?:define|endif|ifn?def|import|undef|...).*)\s*(//[^\r\n]+$)
Demo
http://regex101.com/r/jT4xC8
Description
Discussion
Besides all the warnings expressed in the comments, I assume that a single line can appear in two distinct cases:
Case 1: Alone on its line preceded or not by blank chars
Case 2: Not Alone on its line preceded or not by blank chars, and other chars.
In the first case, we match the beginning of the line (^ with /m flag). Then we search zero or more blank chars (\s*) and finally the single line comment: //[$\r\n]+$.
In the second case, if there are other chars on the line, they form statements. Any statement is ended by a semicolon ;. So we search the last statement and its corresponding semicolon .*;(?!.*"). Then we search the single line comment. Those other chars can be also preprocessor statements. In this case, they are introduced by a sharp #.
One important keypoint is that I assume the code passed to the regex is a code that compiles.
There is more
Don't forget also to add some other pre-processor directives that may apply in your case. Check this SO answer: https://stackoverflow.com/a/18014883/363573
Our company uses an old app which reads TSQL from a .INI file. Due to how the app process the INI file the TSQL has to be all on one line. I use Poor Mans TSQL Formatter to get everything nice and tidy for things like SPs, but am wondering if there's something out there to do the reverse - take nicely formatted TSQL and shove it all onto one line (removing carriage returns , line breaks etc).
I'm working in SSMS but also use Notepad++, and will happily use some other editor if it has the functionality.
Using Notepad++ (Without any plugin)
After lot's of googling I found that there are no plugins like TextFX and PoorMansTSqlFormatter are available in x64 bit version of notepad++ even not needed.
Notepad++ --> Write Query --> Edit --> Blank Options --> Remove Unnecessary Blank and EOL.
That's it.
Using Notepad++
Select the statement that is over multiple lines then on the menu: TextFX>TextFX Edit>Unwrap Text
And for even greater ease you can assign it to a keyboard shortcut using the shortcut mapper (Settings>Shortcut Mapper)
You can use the minify comment to remove all the unnecessary space in the Poor Mans TSQL Formatter
[minify]
[/minify]
I like Martin's answer and that is probably the way to go. But I'll point out that you can just use string manipulation to turn carriage returns and line feeds into spaces. This is particularly easy in the later versions of SSMS that enable limted use of regex in the find/replace dialog.
In SQL Server 2012:
Highlight the selected text and use 'Find and Replace' (ctrl + h)
Check: use Regular Expressions
Find: \n
Replace with: LEAVE BLANK