I have a column group nested in row groups. I want for the column group to only show a row for each item in the row group.
Is there any way to do this?
I resolved this by adding a row group inside the column group. I grouped the Results column using row group and it worked!
Related
I have a table that contains the columns name age and Dept. I am new to report builder and wanted to know if there is a way possible to create dynamic tables based on distinct departments in the base table
Below is the base data
and this is how I want this to be represented in SSRS dynamically based on distinct items in the Dept. column
Thanks in advance!
Just add a Row Group to your table that grouped by Dept.
If you click the existing table you should see one of more row groups in the groups panel below the main design window. There might be just a single "Details" row group. Right click the row group and add a parent group, select Dept as the column to group by and that's it.
Figured this out.
Can use a list and add the desired table in there and then add in a group for the column required in the Group properties of the row
Is there any way to sum a column in rdlc by matching previous column? Let say I have a Code_No column and the Value of this column may be duplicate. I want to sum its left column only if the value of this Code_No column are different.
I have data like this -
I want to create one more column name Pattern and it looks like this -
How to create this column -
It is based on the column 'NAME'. It should Rank Starting from the Row having Parent_ID=(ContentID of the row having Parent ID 1)
It should increase by one and should make the same Group if it get's 'Only For'/'Not For' in the column NAME.
It will work on the group of Jill_Equipment_ID,Req_Group,Operand..
As my complete data in broken into these groups and it will have multiple Jill_Equipment_ID and for each ID multiple Req_Group and for each group multiple Operands.
Please help me in getting it solved. Thanks in advance.
I know there has to be a simple answer to this question, but I am a total SQL noob. In my result set I have multiple results in one column that have one specific value that is repeated several times. In another column there is another value that needs to be added. Please see the attached photo for clarification.
I want to be able to find all of the values in Column B that correspond to 'A' and add them up for one result like shown. I want to be sure to delete the duplicates in Column A. Any help is greatly appreciated.
You're trying to SUM the values in column B and you're trying to group them by (GROUP BY) the value in column A when you do that. This is accomplished like so:
SELECT
col_a,
SUM(col_b)
FROM
My_Table
GROUP BY
col_a
What happens when each column value in a table is divided with the total table row count. What function is basically performed by sql server? Can any one help?
More specifically: what is the difference between sum(column value ) / row count and column value/ row count. for e.g,
select cast(officetotal as float) /count(officeid) as value,
sum(officetotal)/ count(officeid) as average from check1
where officeid ='50009' group by officeid,officetotal
What is the operation performed on both select?
In your example both will be allways the same value because count(officeid) is allways equal to 1 because officeid is contained in the WHERE clause and officetotal is also contained in GROUP BY clause. So the example will not work because no grouping will be applied.
When you remove officetotal from the GROUP BY, you will get following message:
Column 'officetotal' is invalid in the select list because it is not
contained in either an aggregate function or the GROUP BY clause.
It means that you cannot use officetotal and SUM(officetotal) in one select - because SUM is meant to work for set of values and it is pointless to SUM only one value.
It is just not possible to write it this way in SQL using GROUP BY. If you look for something like first or last value from a group, you will have to use MIN(officetotal) or MAX(officetotal) or some other approach.