I am wondering if there is a way in SQL Server to sort a table which holds numbers in a varchar column. I went and cast the number (in my case House Numbers) to Int and use
order by cast([sano]%2 as int), cast([sano] as Int)
which actually creates the output of 2,4,6,8...,1,3,5,7,9 and so on. but I need to get the output like 2,4,6,8..9,7,5,3,1 so even is asc and then the odd is desc.
One trick is to use a case expression to multiply odd numbers by -1, and thus get the ones with the largest absolute value first in an ascending order:
ORDER BY CAST([sano] % 2 AS INT),
CAST([sano] AS INT) * CASE CAST([sano] % 2 AS INT) WHEN 0 THEN 1 ELSE -1 END
Assuming that there is a reasonable upper bound on a house number, you can use the following:
declare #Samples as Table ( HouseNumber Int );
insert into #Samples ( HouseNumber ) values
( 1 ), ( 2 ), ( 3 ), ( 4 ), ( 5 ), ( 6 ), ( 7 ), ( 8 ), ( 9 );
select HouseNumber,
case HouseNumber % 2 when 0 then HouseNumber else 1000000 - HouseNumber end as SortValue
from #Samples
order by case HouseNumber % 2 when 0 then HouseNumber else 1000000 - HouseNumber end;
For even values it uses the house number. By flipping the sign of odd numbers they are sorted in the opposite order, but an offset is needed to have them sort after the even values.
This seems to work, but I have no idea why
select *
from test
order by CASE WHEN sano%2=0 THEN sano%2 END ASC
I am testing and investigating this behaviour
Related
I am trying to write a query that will return data sorted by an alphanumeric column, Code.
Below is my query:
SELECT *
FROM <<TableName>>
CROSS APPLY (SELECT PATINDEX('[A-Z, a-z][0-9]%', [Code]),
CHARINDEX('', [Code]) ) ca(PatPos, SpacePos)
CROSS APPLY (SELECT CONVERT(INTEGER, CASE WHEN ca.PatPos = 1 THEN
SUBSTRING([Code], 2,ISNULL(NULLIF(ca.SpacePos,0)-2, 8000)) ELSE NULL END),
CASE WHEN ca.PatPos = 1 THEN LEFT([Code],
ISNULL(NULLIF(ca.SpacePos,0)-0,1)) ELSE [Code] END) ca2(OrderBy2, OrderBy1)
WHERE [TypeID] = '1'
OUTPUT:
FFS1
FFS2
...
FFS12
FFS1.1
FFS1.2
...
FFS1.1E
FFS1.1R
...
FFS12.1
FFS12.2
FFS.12.1E
FFS12.1R
FFS12.2E
FFS12.2R
DESIRED OUTPUT:
FFS1
FFS1.1
FFS1.1E
FFS1.1R
....
FFS12
FFS12.1
FFS12.1E
FFS12.1R
What am I missing or overlooking?
EDIT:
Let me try to detail the table contents a little better. There are records for FFS1 - FFS12. Those are broken into X subs, i.e., FFS1.1 - FFS1.X to FFS12.1 - FFS12.X. The E and the R was not a typo, each sub record has two codes associated with it: FFS1.1E & FFS1.1R.
Additionally I tried using ORDER BY but it sorted as
FFS1
...
FFS10
FFS2
This will work for any count of parts separated by dots. The sorting is alphanumerical for each part separately.
DECLARE #YourValues TABLE(ID INT IDENTITY, SomeVal VARCHAR(100));
INSERT INTO #YourValues VALUES
('FFS1')
,('FFS2')
,('FFS12')
,('FFS1.1')
,('FFS1.2')
,('FFS1.1E')
,('FFS1.1R')
,('FFS12.1')
,('FFS12.2')
,('FFS.12.1E')
,('FFS12.1R')
,('FFS12.2E')
,('FFS12.2R');
--The query
WITH Splittable AS
(
SELECT ID
,SomeVal
,CAST(N'<x>' + REPLACE(SomeVal,'.','</x><x>') + N'</x>' AS XML) AS Casted
FROM #YourValues
)
,Parted AS
(
SELECT Splittable.*
,ROW_NUMBER() OVER(ORDER BY (SELECT NULL)) AS PartNmbr
,A.part.value(N'text()[1]','nvarchar(max)') AS Part
FROM Splittable
CROSS APPLY Splittable.Casted.nodes(N'/x') AS A(part)
)
,AddSortCrit AS
(
SELECT ID
,SomeVal
,(SELECT LEFT(x.Part + REPLICATE(' ',10),10) AS [*]
FROM Parted AS x
WHERE x.ID=Parted.ID
ORDER BY PartNmbr
FOR XML PATH('')
) AS SortColumn
FROM Parted
GROUP BY ID,SomeVal
)
SELECT ID
,SomeVal
FROM AddSortCrit
ORDER BY SortColumn;
The result
ID SomeVal
10 FFS.12.1E
1 FFS1
4 FFS1.1
6 FFS1.1E
7 FFS1.1R
5 FFS1.2
3 FFS12
8 FFS12.1
11 FFS12.1R
9 FFS12.2
12 FFS12.2E
13 FFS12.2R
2 FFS2
Some explanation:
The first CTE will transform your codes to XML, which allows to address each part separately.
The second CTE returns each part toegther with a number.
The third CTE re-concatenates your code, but each part is padded to a length of 10 characters.
The final SELECT uses this new single-string-per-row in the ORDER BY.
Final hint:
This design is bad! You should not store these values in concatenated strings... Store them in separate columns and fiddle them together just for the output/presentation layer. Doing so avoids this rather ugly fiddle...
I have the below table named SAXTION_EG and it this table contain various colulms out of which there is one column named STR_RATE and in this columncontain values like
STR_RATE
1.11317
123.08546759
8.49111
now please advise me the oracle query by which i can select the maximum value in terms of decimal point for example in the above mentioned case the value 123.08546759 has highest decinal count so it has 8 digits count after decimal, as my objective is to fetch the value having highest digit count after decimal
You can try some thing like this. Logic is first get the position of the decimal point. Then get the string after the decimal. After that count the no of chars in that substring. Then use the MAX to get the aggregated max value
SELECT MAX(LENGTH(SUBSTR(STR_RATE, INSTR(STR_RATE, '.')+ 1)))
FROM your_table
In the solution below, I assume str_rate is of data type NUMBER, so it must be converted to character first. I added a couple of sample values to check that integer values are treated correctly, and to illustrate a case when two values have the same, highest number of decimal digits. In this case the solution returns both such values (see result set at the bottom).
with
saxtion_eg ( str_rate ) as (
select 1.11317 from dual union all
select 123.08546759 from dual union all
select 8.49111 from dual union all
select 582 from dual union all
select 0.00000001 from dual
),
prep ( str_rate, char_rate, pos ) as (
select str_rate, to_char(str_rate), instr(to_char(str_rate), '.')
from saxtion_eg
),
final ( char_rate, dec_digits, max_dec_digits ) as (
select char_rate,
case pos when 0 then 0 else length(char_rate) - pos end,
max(case pos when 0 then 0 else length(char_rate) - pos end) over ()
from prep
)
select char_rate as str_rate
from final
where dec_digits = max_dec_digits
;
STR_RATE
----------------
123.08546759
.00000001
This query return the maximum value in terms of decimal point:
select max(STR_RATE) keep (dense_rank last order by length(STR_RATE-trunc(STR_RATE)))
from SAXTION_EG
I have a table that looks like this:
ID Value
1 1,10
2 7,9
I want my result to look like this:
ID Value
1 1
1 2
1 3
1 4
1 5
1 6
1 7
1 8
1 9
1 10
2 7
2 8
2 9
I'm after both a range between 2 numbers with , as the delimiter (there can only be one delimiter in the value) and how to split this into rows.
Splitting the comma separated numbers is a small part of this problem. The parsing should be done in the application and the range stored in separate columns. For more than one reason: Storing numbers as strings is a bad idea. Storing two attributes in a single column is a bad idea. And, actually, storing unsanitized user input in the database is also often a bad idea.
In any case, one way to generate the list of numbers is to use a recursive CTE:
with t as (
select t.*, cast(left(value, charindex(',', value) - 1) as int) as first,
cast(substring(value, charindex(',', value) + 1, 100) as int) as last
from table t
),
cte as (
select t.id, t.first as value, t.last
from t
union all
select cte.id, cte.value + 1, cte.last
from cte
where cte.value < cte.last
)
select id, value
from cte
order by id, value;
You may need to fiddle with the value of MAXRECURSION if the ranges are really big.
Any table that a field with multiple values such as this is a problem in terms of design. The only way to deal with these records as it is is to split the values on the delimiter and put them into a temporary table, implement custom splitting code, integrate a CTE as noted, or redesign the original table to put the comma-delimited fields into separate fields, eg
ID LOWLIMIT HILIMIT
1 1 10
similar with Gordon Linoff variant, but has some difference
--create temp table for data sample
DECLARE #Yourdata AS TABLE ( id INT, VALUE VARCHAR(20) )
INSERT #Yourdata
( id, VALUE )
VALUES ( 1, '1,10' ),
( 2, '7,9' )
--final query
;WITH Tally
AS ( SELECT MIN(CONVERT(INT, SUBSTRING(y.VALUE, 1, CHARINDEX(',', y.value) - 1))) AS MinV ,
MAX(CONVERT(INT, SUBSTRING(y.VALUE, CHARINDEX(',', y.value) + 1, 18))) AS MaxV
FROM #yourdata AS y
UNION ALL
SELECT MinV = MinV + 1 , MaxV
FROM Tally
WHERE MinV < Maxv
)
SELECT y.id , t.minV AS value
FROM #yourdata AS y
JOIN tally AS t ON t.MinV BETWEEN CONVERT(INT, SUBSTRING(y.VALUE, 1, CHARINDEX(',', y.value) - 1))
AND CONVERT(INT, SUBSTRING(y.VALUE, CHARINDEX(',', y.value) + 1, 18))
ORDER BY id, minV
OPTION ( MAXRECURSION 999 ) --change it if required
output
I have a table with two columns: col_order (int), and name (text). I would like to retrieve ordered rows such that, when col_order is not null, it determines the order, but when its null, then name determines the order. I thought of an order by clause such as
order by coalesce( col_order, name )
However, this won't work because the two columns have different type. I am considering converting both into bytea, but: 1) to convert the integer is there a better method than just looping moding by 256, and stacking up individual bytes in a function, and 2) how do I convert "name" to insure some sort of sane collation order (assuming name has order ... well citext would be nice but I haven't bothered to rebuild to get that ... UTF8 for the moment).
Even if all this is possible (suggestions on details welcome) it seems like a lot of work. Is there a better way?
EDIT
I got an excellent answer by Gordon, but it shows I didn't phrase the question correctly. I want a sort order by name where col_order represents places where this order is overridden. This isn't a well posed problem, but here is one acceptable solution:
col_order| name
----------------
null | a
1 | foo
null | foo1
2 | bar
Ie -- here if col_order is null name should be inserted after name closest in alphabetical order but less that it. Otherwise, this could be gotten by:
order by col_order nulls last, name
EDIT 2
Ok ... to get your creative juices flowing, this seems to be going in the right direction:
with x as ( select *,
case when col_order is null then null else row_number() over (order by col_order) end as ord
from temp )
select col_order, name, coalesce( ord, lag(ord,1) over (order by name) + .5) as ord from x;
It gets the order from the previous row, sorted by name, when there is no col_order. It isn't right in general... I guess I'd have to go back to the first row with non-null col_order ... it would seem that sql standard has "ignore nulls" for window functions which might do this, but isn't implemented in postgres. Any suggestions?
EDIT 3
The following would seem close -- but doesn't work. Perhaps window evaluation is a bit strange with recursive queries.
with recursive x(col_order, name, n) as (
select col_order, name, case when col_order is null then null
else row_number() over (order by col_order) * t end from temp, tot
union all
select col_order, name,
case when row_number() over (order by name) = 1 then 0
else lag(n,1) over (order by name) + 1 end from x
where x.n is null ),
tot as ( select count(*) as t from temp )
select * from x;
Just use multiple clauses:
order by (case when col_order is not null then 1 else 2 end),
col_order,
name
When col_order is not null, then 1 is assigned for the first sort key. When it is null, then 2 is assigned. Hence, the not-nulls will be first.
Ok .. the following seems to work -- I'll leave the question "unanswered" though pending criticism or better suggestions:
Using the last_agg aggregate from here:
with
tot as ( select count(*) as t from temp ),
x as (
select col_order, name,
case when col_order is null then null
else (row_number() over (order by col_order)) * t end as n,
row_number() over (order by name) - 1 as i
from temp, tot )
select x.col_order, x.name, coalesce(x.n,last_agg(y.n order by y.i)+x.i, 0 ) as n
from x
left join x as y on y.name < x.name
group by x.col_order, x.n, x.name, x.i
order by n;
I have a VARCHAR column in a SQL Server 2000 database that can contain either letters or numbers. It depends on how the application is configured on the front-end for the customer.
When it does contain numbers, I want it to be sorted numerically, e.g. as "1", "2", "10" instead of "1", "10", "2". Fields containing just letters, or letters and numbers (such as 'A1') can be sorted alphabetically as normal. For example, this would be an acceptable sort order.
1
2
10
A
B
B1
What is the best way to achieve this?
One possible solution is to pad the numeric values with a character in front so that all are of the same string length.
Here is an example using that approach:
select MyColumn
from MyTable
order by
case IsNumeric(MyColumn)
when 1 then Replicate('0', 100 - Len(MyColumn)) + MyColumn
else MyColumn
end
The 100 should be replaced with the actual length of that column.
There are a few possible ways to do this.
One would be
SELECT
...
ORDER BY
CASE
WHEN ISNUMERIC(value) = 1 THEN CONVERT(INT, value)
ELSE 9999999 -- or something huge
END,
value
the first part of the ORDER BY converts everything to an int (with a huge value for non-numerics, to sort last) then the last part takes care of alphabetics.
Note that the performance of this query is probably at least moderately ghastly on large amounts of data.
select
Field1, Field2...
from
Table1
order by
isnumeric(Field1) desc,
case when isnumeric(Field1) = 1 then cast(Field1 as int) else null end,
Field1
This will return values in the order you gave in your question.
Performance won't be too great with all that casting going on, so another approach is to add another column to the table in which you store an integer copy of the data and then sort by that first and then the column in question. This will obviously require some changes to the logic that inserts or updates data in the table, to populate both columns. Either that, or put a trigger on the table to populate the second column whenever data is inserted or updated.
SELECT *, CONVERT(int, your_column) AS your_column_int
FROM your_table
ORDER BY your_column_int
OR
SELECT *, CAST(your_column AS int) AS your_column_int
FROM your_table
ORDER BY your_column_int
Both are fairly portable I think.
you can always convert your varchar-column to bigint as integer might be too short...
select cast([yourvarchar] as BIGINT)
but you should always care for alpha characters
where ISNUMERIC([yourvarchar] +'e0') = 1
the +'e0' comes from http://blogs.lessthandot.com/index.php/DataMgmt/DataDesign/isnumeric-isint-isnumber
this would lead to your statement
SELECT
*
FROM
Table
ORDER BY
ISNUMERIC([yourvarchar] +'e0') DESC
, LEN([yourvarchar]) ASC
the first sorting column will put numeric on top.
the second sorts by length, so 10 will preceed 0001 (which is stupid?!)
this leads to the second version:
SELECT
*
FROM
Table
ORDER BY
ISNUMERIC([yourvarchar] +'e0') DESC
, RIGHT('00000000000000000000'+[yourvarchar], 20) ASC
the second column now gets right padded with '0', so natural sorting puts integers with leading zeros (0,01,10,0100...) in correct order (correct!) - but all alphas would be enhanced with '0'-chars (performance)
so third version:
SELECT
*
FROM
Table
ORDER BY
ISNUMERIC([yourvarchar] +'e0') DESC
, CASE WHEN ISNUMERIC([yourvarchar] +'e0') = 1
THEN RIGHT('00000000000000000000' + [yourvarchar], 20) ASC
ELSE LTRIM(RTRIM([yourvarchar]))
END ASC
now numbers first get padded with '0'-chars (of course, the length 20 could be enhanced) - which sorts numbers right - and alphas only get trimmed
I solved it in a very simple way writing this in the "order" part
ORDER BY (
sr.codice +0
)
ASC
This seems to work very well, in fact I had the following sorting:
16079 Customer X
016082 Customer Y
16413 Customer Z
So the 0 in front of 16082 is considered correctly.
This seems to work:
select your_column
from your_table
order by
case when isnumeric(your_column) = 1 then your_column else 999999999 end,
your_column
This query is helpful for you. In this query, a column has data type varchar is arranged by good order.For example- In this column data are:- G1,G34,G10,G3. So, after running this query, you see the results: - G1,G10,G3,G34.
SELECT *,
(CASE WHEN ISNUMERIC(column_name) = 1 THEN 0 ELSE 1 END) IsNum
FROM table_name
ORDER BY IsNum, LEN(column_name), column_name;
This may help you, I have tried this when i got the same issue.
SELECT *
FROM tab
ORDER BY IIF(TRY_CAST(val AS INT) IS NULL, 1, 0),TRY_CAST(val AS INT);
The easiest and efficient way to get the job done is using TRY_CAST
SELECT my_column
FROM my_table
WHERE <condition>
ORDER BY TRY_CAST(my_column AS NUMERIC) DESC
This will sort all numbers in descending order and push down all non numeric values
SELECT FIELD FROM TABLE
ORDER BY
isnumeric(FIELD) desc,
CASE ISNUMERIC(test)
WHEN 1 THEN CAST(CAST(test AS MONEY) AS INT)
ELSE NULL
END,
FIELD
As per this link you need to cast to MONEY then INT to avoid ordering '$' as a number.
SELECT *,
ROW_NUMBER()OVER(ORDER BY CASE WHEN ISNUMERIC (ID)=1 THEN CONVERT(NUMERIC(20,2),SUBSTRING(Id, PATINDEX('%[0-9]%', Id), LEN(Id)))END DESC)Rn ---- numerical
FROM
(
SELECT '1'Id UNION ALL
SELECT '25.20' Id UNION ALL
SELECT 'A115' Id UNION ALL
SELECT '2541' Id UNION ALL
SELECT '571.50' Id UNION ALL
SELECT '67' Id UNION ALL
SELECT 'B48' Id UNION ALL
SELECT '500' Id UNION ALL
SELECT '147.54' Id UNION ALL
SELECT 'A-100' Id
)A
ORDER BY
CASE WHEN ISNUMERIC (ID)=0 /* alphabetical sort */
THEN CASE WHEN PATINDEX('%[0-9]%', Id)=0
THEN LEFT(Id,PATINDEX('%[0-9]%',Id))
ELSE LEFT(Id,PATINDEX('%[0-9]%',Id)-1)
END
END DESC