In a table containing Order information (call it Order) we have the following fields:
OrderId int
OrderDate Date
BindingTime int
Binding time is in months.
An order is called "Active" between its OrderDate and DATEADD(mm, BindingTime, OrderDate).
What I'd like to do is to group the orders by year so that if an order is "active" on the first day of a year it would be taken into account. The aim is to calculate each year's inbound and outbound orders. So the query result will be COUNT of orders and the year. And by year we mean the number of orders which were active on the first day of that year.
Mind that, we would like to have all the years between two given numbers in our results. E.g. If there was no active order on the first day of 2016 we would still like to to have a row for (0, 2016).
I've used a recursive CTE to generate a range of years, so that a 'zero' year will not be omitted
declare #YEAR1 as date = '20110101';
declare #YEAR2 as date = '20190101';
WITH YEARS AS (SELECT #YEAR1 y
UNION ALL
SELECT dateadd(year,1,y) FROM YEARS WHERE y < #YEAR2)
SELECT YEARS.y,count(0) YearStartActiveOrders FROM YourTable
CROSS JOIN YEARS
WHERE YEARS.y BETWEEN CAST(orderdate as date)
AND CAST(DATEADD(mm, BindingTime, OrderDate) as date)
GROUP BY Years.y
Seems like what you need is a Date table (having a list of all days per year) and left joining that table with your grouped data (active order count, per day of the year).
You can use this date table from Aaron Bertrand. I generated the #dim table with the following params, to only generate two years data (2015, 2016):
DECLARE #StartDate DATE = '20150101', #NumberOfYears INT = 2;
Then you can do the following:
with ordertable as
(
select 1 as orderid, '20160101' as orderdate, 2 as bindingtime union all
select 2, '20160305', 3 union all
select 3, '20160305', 5 union all
select 4, '20150305', 5
)
select d.year, isnull(count(orderid), 0) nrActiveOrdersFirstDayOfYear
from #dim d
left join ordertable g on d.year = year(g.orderdate)
and g.orderdate = d.date
and d.FirstOfYear between g.orderdate and DATEADD(mm, g.bindingtime, OrderDate)
group by d.year
With the sample data I took as an example, you would get the result:
year nrActiveOrdersFirstDayOfYear
2015 0
2016 1
Working demo here.
Related
I want to merge these two tables into one. The idea is to create a table by month and show: month, number of unique customers who bought, number of invoices, number of products, total income, total income from product A
I'm having trouble adding the total income from product A per month since the table has two rows while the other results have four.
Example of table:
CustomerID
InvoiceID
ProductId
Date
Income
1
101
A
1/11/2016
600
2
103
B
12/10/2015
300
My query so far:
SELECT
MONTH(date) AS month,
COUNT (DISTINCT customerId) AS numOfCustomers,
SUM(income) AS sumOfIncome,
COUNT(invoiceId) AS numOfInvoice,
COUNT(productId) AS numOfProduct
FROM
x
WHERE
YEAR(date) = 2016
GROUP BY
MONTH(date)
SELECT
MONTH(date) AS month,
SUM(income) AS sumOfIncomeA
FROM
x
WHERE
(productId) = 'A'
AND YEAR(date) = 2016
GROUP BY
MONTH(date)
Here's a solution that first creates a big list of months. You can modify the "months" CTE to go back as far as you need. By default, this query will go back 83 years from today. After you have a good list of months, then you can join your data to it so that you are guaranteed to have all the months, and only sales data if present.
--First CTE "x" is used to create a sequence of 10 numbers.
WITH x as (
SELECT * FROM (VALUES (0),(1),(2),(3),(4),(5),(6),(7),(8),(9)) as x(a)
)
--Second CTE "y" creates a sequence of 1000 numbers.
, y as (
SELECT ROW_NUMBER() OVER(ORDER BY hundreds.a, tens.a, ones.a) as row_num
FROM x as ones, x as tens, x as hundreds
)
--Third CTE "months" creates a sequence of months going back in time from today.
--To go farther back than 1000 months, modify the "y" CTE to have a "thousands" (or more) table(s).
, months as (
SELECT
YEAR(DATEADD(month, -1 * y.row_num, GETDATE())) as [year]
, MONTH(DATEADD(month, -1 * y.row_num, GETDATE())) as [month]
, CAST(YEAR(DATEADD(month, -1 * y.row_num, GETDATE())) as nvarchar(6))
+ RIGHT('00' + CAST(MONTH(DATEADD(month, -1 * y.row_num, GETDATE())) as nvarchar(6)),2) as YEAR_MONTH
FROM y
)
--Main select.
--First FROM is a list of months so that we know for a fact we have all the months in the year.
--Then do a LEFT OUER JOIN to your main data. All months will be returned.
--If there is no match in the data table, then the value will be null.
--You can use an ISNULL(SUM(x.income),0) to convert nulls to 0.
SELECT
m.[month] AS month,
COUNT (DISTINCT x.customerId) AS numOfCustomers,
SUM(x.income) AS sumOfIncome,
COUNT(x.invoiceId) AS numOfInvoice,
COUNT(x.productId) AS numOfProduct
FROM months as m
LEFT OUTER JOIN x
ON YEAR(x.[date]) = m.[year]
AND MONTH(x.[date]) = m.[month]
WHERE
x.YEAR([date]) = 2016
GROUP BY
m.MONTH([date])
Like I wrote in the comment, as both tables could not have the same month present you need a FULL OUTER JOIN
so
The COALESCE for month is needed, as it could be that one of the month coulb be NULL
SELECT
COALESCE(t1.month,t2-month),
t1.numOfCustomers,t1.sumOfIncome,t1.numOfInvoice,t1.numOfProduct
,t2.sumOfIncomeA
FROM
(SELECT
MONTH(date) AS month,
COUNT (DISTINCT customerId) AS numOfCustomers,
SUM(income) AS sumOfIncome,
COUNT(invoiceId) AS numOfInvoice,
COUNT(productId) AS numOfProduct
FROM
x
WHERE
YEAR(date) = 2016
GROUP BY
MONTH(date)) t1
FULL OUTER JOIN
(SELECT
MONTH(date) AS month,
SUM(income) AS sumOfIncomeA
FROM
x
WHERE
(productId) = 'A'
AND YEAR(date) = 2016
GROUP BY
MONTH(date)) t2 ON t1.month = t2.month
So I am trying to find count of customers who placed order both in this month and previous month. I have to find this from the beginning of last year. I came up with a query which obviously doesn't work. Can I get some help with this please?
Query:
SELECT DATE_TRUNC('month', month_column), COUNT(DISTINCT(customer_id))
FROM table
WHERE month_column >= '2021-01-01' AND customer_id IN (
SELECT customer_id
FROM table
WHERE month_column = month_column - INTERVAL '1 month')
GROUP BY 1
NOTE: month_column has only month number i.e., '2021-01-01', '2021-02-01' etc.
I am using postgresql.
This is my first stack overflow question. So, if I didn't abide by any rules, I apologize.
To make this trivial, you can use 2 queries. Get customerID's from this month (insert into temp table 1) and customerID's from last month (insert into temp table 2). Lastly just inner join both tables on customerID
something like the below
SELECT customer_id
INTO #thisMonth
FROM customer
WHERE month_column > DATEADD(month, 0, GETDATE())
SELECT customer_id
INTO #prevMonth
FROM customer
WHERE month_column > DATEADD(month, -1, GETDATE())
SELECT COUNT(customer_id)
FROM #thisMonth tm
INNERJOIN #prevMonth pm ON tm.customer_id = pm.customerID
Table
--------
Date CreatedOn
varchar(25) IP
From this table, I want to selected the number of unique IP addresses, by Day.
June 1, 2013 25
June 2, 2013 35
June 3, 2013 0
Note, the third item was added after original question to deal with days with no items. The data will be turned into a chart/graph.
What is the Sql Server 2008R2 SQL for this?
Greg
SELECT Date, COUNT(*)
FROM TableName
GROUP BY Date
ORDER BY date
if you want to have unique count, you need to have DISTINCT, eg. COUNT(DISTINCT IP).
follow-up question: is there a date that has no view? what are you going to do with it?
Since you want to show all dates between two date range according to your comment, you need to have a calendar table or something that generates all the dates between the date range.
-- let's say
-- start date = June 1, 2013
-- end date = June 5, 2013
WITH DateTimeSequence
AS
(
SELECT CAST('20130601' as datetime) AS [datetime] -- Start Date
UNION ALL
SELECT DATEADD(d, 1, [datetime])
FROM DateTimeSequence
WHERE DATEADD(d, 1, [datetime]) <= CAST('20130605' as datetime) -- End Date
)
SELECT a.[datetime],
COUNT(DISTINCT b.[ipaddress]) uniqueIP_Count
FROM DateTimeSequence a
LEFT JOIN TableName b
ON a.[datetime] = b.[date]
GROUP BY a.[datetime]
SQLFiddle Demo
SELECT CreatedOn,
COUNT(DISTINCT IP)
FROM Table
GROUP BY CreatedOn
My problem:
Table: trans_detail:
PhoneNo | Datetime
01234 | 2013-01-05 20:40:10
01245 | 2013-04-02 21:00:13
05678 | 2013-04-16 01:24:07
04567 | 2013-07-23 07:00:00
etc | etc
I want to get all phoneNo that appears at least once for every month in the last X month (X month can be any month between 1-12).
For example: get all phone no. that appears at least once for Every Month in the last 3 months.
I am using SQL Server 2005.
Here is a quick query that comes close to what you want:
select PhoneNo
from trans_detail d
where d.datetime >= dateadd(mm, -#X, getdate())
group by PhoneNo
having count(distinct year(datetime)*12+month(datetime)) = #X
The where clause filters the data to only include rows in the last #X months. the having clause checks that each month is in the data, by counting the number of distinct months.
The above version of the query assumes that you mean calendar months. So, it has boundary condition problems. If you run it on June 16th, then it looks back one month and makes sure that the phone number appears at least once since May 16th. I am unclear on whether you want to insist that the number appear twice (once in May and once in June) or if once (once during the time period). The solution to this is to move the current date back to the end of the previous month:
select PhoneNo
from trans_detail d cross join
(select cast(getdate() - day(getdate) + 1 as date) as FirstOfMonth const
where d.datetime >= dateadd(mm, -#X, FirstOfMonth) and
d.datetime < FirstOfMonth
group by PhoneNo
having count(distinct year(datetime)*12+month(datetime)) = #X
Here it is. First two CTEs are to find and prepare last X months, third CTE is to group your data by phones and months. At the end just join the two and return where number of matching rows are equal to number of months.
DECLARE #months INT
SET #Months = 3
;WITH CTE_Dates AS
(
SELECT GETDATE() AS Dt
UNION ALL
SELECT DATEADD(MM,-1,Dt) FROM CTE_Dates
WHERE DATEDIFF(MM, Dt,GETDATE()) < #months-1
)
, CTE_Months AS
(
SELECT MONTH(Dt) AS Mn, YEAR(Dt) AS Yr FROM CTE_Dates
)
, CTE_Trans AS
(
SELECT PhoneNo, MONTH([Datetime]) AS Mn, YEAR([Datetime]) AS Yr FROM dbo.trans_detail
GROUP BY PhoneNo, MONTH([Datetime]), YEAR([Datetime])
)
SELECT PhoneNo FROM CTE_Months m
LEFT JOIN CTE_Trans t ON m.Mn = t.Mn AND m.Yr = t.Yr
GROUP BY PhoneNo
HAVING COUNT(*) = #months
SQLFiddle Demo - with added some more data that will match for last 3 months
SQL Server 2005
I have an SQL Function (ftn_GetExampleTable) which returns a table with multiple result rows
EXAMPLE
ID MemberID MemberGroupID Result1 Result2 Result3 Year Week
1 1 1 High Risk 2 xx 2011 22
2 11 4 Low Risk 1 yy 2011 21
3 12 5 Med Risk 3 zz 2011 25
etc.
Now I do a count and group by on a table above this for Result 2 for instance so I get
SELECT MemberGroupID, Result2, Count(*) AS ExampleCount, Year, Week
FROM ftn_GetExampleTable
GROUP BY MemberGroupID, Result2, Year, Week
MemberGroupID Result2 ExampleCount Year Week
1 2 4 2011 22
4 1 2 2011 21
5 3 1 2011 25
Now imagine when I go to graph this new table between Weeks 20 and 23 of Year 2011, you'll see that it won't graph 20 or 23 or certain groups or even certain results in this example as they are not in the included data, so I need "false data" inserted into this table which has all the possibilities so they at least show on a graph even if the count is 0, does this make sense?
I am wondering on the easiest and kind of most dynamic way as it could be Result1 or Result3 I want to Graph on (different column types).
Thanks in advance
It looks like your dimensions are: MemberGroupID,Result2, and week (Year,Week).
One approach to solving this is to generate a list of all values you want for all the dimensions, and produce a cartesian product of them. As an example,
SELECT m.MemberGroupID, n.Result2, w.Year, w.Week
FROM (SELECT MemberGroupID FROM ftn_GetExampleTable GROUP BY MemberGroupID) m
CROSS
JOIN (SELECT Result2 FROM ftn_GetExampleTable GROUP BY Result2 ) n
CROSS
JOIN (SELECT Year, Week FROM myCalendar WHERE ... ) w
You don't necessarily need a table named myCalendar. (That approach does seem to be the popular one.) You just need a row source from which you can derive a list of (Year, Week) tuples. (There are answers to the question elsewhere in Stackoverflow, how to generate a list of dates.)
And the list of MemberGroupID and Result2 values doesn't have to come from the ftn_GetExampleTable rowsource, you could substitute another query.
With a cartesian product of those dimensions, you've got a complete "grid". Now you can LEFT JOIN your original result set to that.
Any place you don't have a matching row from the "gappy" result query, you'll get a NULL returned. You can leave the NULL, or replace it with a 0, which is probably what you want if it's a "count" you are returning.
SELECT d.MemberGroupID
, d.Result2
, d.Year
, d.Week
, IFNULL(r.ExampleCount,0) as ExampleCount
FROM ( <dimension query from above> ) d
LEFT
JOIN ( <original ExampleCount query> ) r
ON r.MemberGroupID = d.MemberGroupID
AND r.Result2 = d.Result2
AND r.Year = d.Year
AND r.Week = d.Week
That query can be refactored to make use of Common Table Expressions, which makes the query a little easier to read, especially if you are including multiple measures.
; WITH d AS ( /* <dimension query with no gaps (example above)> */
)
, r AS ( /* <original query with gaps> */
SELECT MemberGroupID, Result2, Count(*) AS ExampleCount, Year, Week
FROM ftn_GetExampleTable
GROUP BY MemberGroupID, Result2, Year, Week
)
SELECT d.*
, IFNULL(r.ExampleCount,0)
FROM d
LEFT
JOIN r
ON r.Year=d.Year AND r.Week=d.Week AND r.MemberGroupID = d.MemberGroupID
AND r.Result2 = d.Result2
This isn't a complete working solution to your problem, but it outlines an approach you can use.
Whenever I need to generate a sequence within SQL-Server I use the sys.all_objects table along with the ROW_NUMBER function, then maninpulate it as required:
SELECT ROW_NUMBER() OVER(ORDER BY Object_ID) AS Sequence
FROM Sys.All_Objects
So for the list of year and week numbers I would use:
DECLARE #StartDate DATETIME,
#EndDate DATETIME
SET #StartDate = '20110101'
SET #EndDate = '20120601'
SELECT DATEPART(YEAR, Date) AS YEAR,
DATEPART(WEEK, Date) AS WeekNum
FROM ( SELECT DATEADD(WEEK, ROW_NUMBER() OVER(ORDER BY Object_ID) - 1, #StartDate) AS Date
FROM Sys.All_Objects
) Dates
WHERE Date < #endDate
Where the dates subquery provides a list of dates at one week intervals between your start and end dates.
So in your example the end result would be something like:
DECLARE #StartDate DATETIME,
#EndDate DATETIME
SET #StartDate = '20110101'
SET #EndDate = '20120601'
;WITH Data AS
( SELECT MemberGroupID,
Result2,
Count(*) AS ExampleCount,
Year,
Week
FROM ftn_GetExampleTable
GROUP BY MemberGroupID, Result2, Year, Week
), Dates AS
( SELECT DATEPART(YEAR, Date) AS YEAR,
DATEPART(WEEK, Date) AS WeekNum
FROM ( SELECT DATEADD(WEEK, ROW_NUMBER() OVER(ORDER BY Object_ID) - 1, #StartDate) AS Date
FROM Sys.All_Objects
) Dates
WHERE Date < #endDate
)
SELECT YearNum,
WeeNum,
MemberID,
Result2,
COALESCE(ExampleCount, 0) AS ExampleCount
FROM Dates
LEFT JOIN Data
ON YearNum = Data.Year
AND WeekNum = Data.Week